Standard to Vertex Form Conversion

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Standard to Vertex form Procedure y = -0.00211x 2 + 1.06x (1) Step 1) Firstly, you set equaion (1) to zero(0) -0.00211x 2 + 1.06x = 0 (2) Step 2) Secondly, you divide equation (2) by -0.00211(to make the coefficient of x 2 equal 1 x 2 - 502.4x = 0 (4) Step 3) x 2 -502.4x + (-502.4/2) 2 = 0 + (-502.4/2) 2 (5) x 2 - 502.4x + 63,093.8 = 63,093.8 (6) Step 4) Now, factorize equation (6). (x-502.4) 2 = 63,093.8 (7) Step 5) rearrange equation (7). (x-502.4) 2 - 63,093.8 = 0 ( This is the vertex form) The equation (4) above is in the form Ax + B + C = 0, where A = 1, B= -502.4, and C = 0 Now, divide B by two and square it. Add the result to both sides of equation (4) above .ଶଵଵ௫ మ .ଶଵଵ + ଵ.௫ .ଶଵଵ = 0 (3)

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This is a descriptive method of converting an equation from standard to vertex form

Transcript of Standard to Vertex Form Conversion

Page 1: Standard to Vertex Form Conversion

Standard to Vertex form Procedure

y = -0.00211x2 + 1.06x (1)

Step 1) Firstly, you set equaion (1) to zero(0) -0.00211x2 + 1.06x = 0 (2)

Step 2) Secondly, you divide equation (2) by -0.00211(to make the coefficient of x 2 equal 1

x2 - 502.4x = 0 (4)

Step 3)

x2 -502.4x + (-502.4/2)2 = 0 + (-502.4/2)2 (5)x2 - 502.4x + 63,093.8 = 63,093.8 (6)

Step 4) Now, factorize equation (6).(x-502.4)2 = 63,093.8 (7)

Step 5) rearrange equation (7).(x-502.4)2 - 63,093.8 = 0 ( This is the vertex form)

The equation (4) above is in the form Ax + B + C = 0, where A = 1, B= -502.4, and C = 0

Now, divide B by two and square it. Add the result to both sides of equation (4) above

ି.ଶଵଵ௫మ

ି.ଶଵଵ+ ଵ.௫

ି.ଶଵଵ = 0 (3)

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