Solving Systems of Linear and Quadratic Equations.

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Solving Systems of Linear and Quadratic Equations

Transcript of Solving Systems of Linear and Quadratic Equations.

Solving Systems of Linear and Quadratic Equations

2 8

10

x y

x y

Systems of Linear EquationsWe had 3 methods to solve them.

Method 1 - Graphing

Solve for y.

2 8y x

10y x (6, – 4)

Systems of Linear Equations

Method 2 - Substitution

2 8

10

x y

x y

2 8y x

10x y 10x 2 8x

2 8 10x x 3 18x

6x 6

2 8y x 2( ) 8y 12 8y 4y

(6, – 4)

Systems of Linear Equations

Method 3 - Elimination

2 8

10

x y

x y

2 8

10

x y

x y

3 18x

6x 6

10x y ( ) 10y 4y 4y

(6, – 4) All 3 methods

giving us the

same answer

(6,–4).

Try the following.

1 2,2 3

(12,1)1.

2.

3.

4.

5.

6.(12, – 4)

Many solutionsSame Line!

1 1,6 8

NO solutionParallel Lines!

Solve the System AlgebraicallyUse Substitution

1

12

xy

xy

1 xy( ) 1x

Answer: (0,1) (1,2)

2 1x

02 xx

1 0x x 0 1 0x or x 0 1x or x

0x 20 1

1

y

y

(0, 1)

1x 21 1

2

y

y

(1, 2)

Solve the System AlgebraicallyUse Substitution

2 2y x 2( ) 2 2x x 22 x

Answer: (2,2)

2 2 2y x x 2x

(2, 2)

22

222

xy

xxy

20 4 4x x 0 2 2x x

0 2x 2x

2 2 2

4 2

2

y

y

y

Homework!

• Finish The Circle Worksheet through #14

• Solving Linear-Quadratic Systems Algebraically Worksheet – Both Sides

Solve the System AlgebraicallyUse Substitution

6y x

22 6 26x x 2 2 12 36 26x x x

6

2622

yx

yx

22 12 10 0x x 2 6 5 0x x

5 1 0x x

5 1x or x

5x 5 6

1

1

y

y

y

1x 1 6

5

5

y

y

y

(5, –1)

(1, – 5)

Answer: (5, –1) (1, – 5)

Solve the System AlgebraicallyUse Substitution

3

4y x

22 3

254

x x

2 2925

16x x

2 216 9 400x x 225 400x 2 16x

4x

4x 4 3 4

4 12

3

y

y

y

4x 4 3 4

4 12

3

y

y

y

(4, 3)

(– 4, – 3)

Answer: (4, 3) (–4, – 3)

xy

yx

34

2522

2 2

2 2

3 4 11

13

x y

x y

Solve the System AlgebraicallyUse ????

Now let’s look at the Graphs of these Systems!

Classify each equation as linear/quadratic.

What does the graph of each look like?Line

Parabola

Linear

Quadratic

What is the solution to the system?

Point of Intersection (-2, 0)

Point of Intersection (1, -3 )

Equations must be solved for y!!

6

2622

yx

yx

2 226y x

2 2 26x y

226y x

6

and

y x

The first equation can be entered as two separate entries:

                   

or a "list" notation may be used:                         

Zoom 6: ZStandardZoom 5: ZSquare

Answer: (5, –1) (1, – 5)