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Transcript of Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc....
![Page 1: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/1.jpg)
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
Chapter 3
Solving Equations
and Problem Solving
![Page 2: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/2.jpg)
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
3.1
Simplifying
Algebraic
Expressions
![Page 3: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/3.jpg)
Martin-Gay, Prealgebra, 6ed 3 3
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
A term that is only a number is called a constant term, or simply
a constant. A term that contains a variable is called a variable
term.
x + 3
Constant
terms Variable
terms
3y2 + (–4y) + 2
Constant and Variable Terms
![Page 4: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/4.jpg)
Martin-Gay, Prealgebra, 6ed 4 4
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
The number factor of a variable term is called the numerical
coefficient. A numerical coefficient of 1 is usually not written.
5x x or 1x –7y 3y
2
Numerical
coefficient is 5.
Numerical
coefficient is –7.
Numerical
coefficient
is 3.
Understood
numerical
coefficient is 1.
Coefficients
![Page 5: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/5.jpg)
Martin-Gay, Prealgebra, 6ed 5 5
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Terms that are exactly the same, except that they may have
different numerical coefficients are called like terms.
Like Terms Unlike Terms
3x, 2x
–6y, 2y, y
–3, 4 7x, 7y
5y, 5
6a, ab
The order of the variables
does not have to be the same.
2ab2, –5b
2a
5x, x 2
Like Terms
![Page 6: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/6.jpg)
Martin-Gay, Prealgebra, 6ed 6 6
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
A sum or difference of like terms can be simplified
using the distributive property.
Distributive Property
If a, b, and c are numbers, then
ac + bc = (a + b)c
Also,
ac – bc = (a – b)c
Distributive Property
![Page 7: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/7.jpg)
Martin-Gay, Prealgebra, 6ed 7 7
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
By the distributive property,
7x + 5x = (7 + 5)x
= 12x
This is an example of combining like terms.
An algebraic expression is simplified when all like terms have been combined.
Distributive Property
![Page 8: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/8.jpg)
Martin-Gay, Prealgebra, 6ed 8 8
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The commutative and associative properties of addition
and multiplication help simplify expressions.
Properties of Addition and Multiplication
If a, b, and c are numbers, then
Commutative Property of Addition
a + b = b + a
Commutative Property of Multiplication
a ∙ b = b ∙ a
The order of adding or multiplying two numbers can be
changed without changing their sum or product.
Addition and Multiplication Properties
![Page 9: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/9.jpg)
Martin-Gay, Prealgebra, 6ed 9 9
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
The grouping of numbers in addition or multiplication
can be changed without changing their sum or product.
Associative Property of Addition
(a + b) + c = a + (b + c)
Associative Property of Multiplication
(a ∙ b) ∙ c = a ∙ (b ∙ c)
Associative Properties
![Page 10: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/10.jpg)
Martin-Gay, Prealgebra, 6ed 10 10
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Examples of Commutative and Associative Properties
of Addition and Multiplication
4 + 3 = 3 + 4
6 ∙ 9 = 9 ∙ 6
(3 + 5) + 2 = 3 + (5 + 2)
(7 ∙ 1) ∙ 8 = 7 ∙ (1 ∙ 8)
Commutative Property of Addition
Commutative Property of Multiplication
Associative Property of Addition
Associative Property of Multiplication
Helpful Hint
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Martin-Gay, Prealgebra, 6ed 11 11
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We can also use the distributive property to multiply
expressions.
2(5 + x) = 2 ∙ 5 + 2 ∙ x = 10 + 2x
or
2(5 – x) = 2 ∙ 5 – 2 ∙ x = 10 – 2x
The distributive property says that multiplication
distributes over addition and subtraction.
Multiplying Expressions
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Martin-Gay, Prealgebra, 6ed 12 12
Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall.
To simply expressions, use the distributive property
first to multiply and then combine any like terms.
3(5 + x) – 17 =
Simplify: 3(5 + x) – 17
= 15 + 3x + (–17)
Apply the Distributive
Property
Multiply
= 3x + (–2) or 3x – 2 Combine like terms
Note: 3 is not distributed to the –17 since –17
is not within the parentheses.
3 ∙ 5 + 3 ∙ x + (–17)
Simplifying Expressions
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Martin-Gay, Prealgebra, 6ed 13 13
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Finding Perimeter
3z feet
9z feet
7z feet
Perimeter = 3z + 7z + 9z
= 19z feet
Don’t forget to insert
proper units.
Perimeter is the distance around the figure.
![Page 14: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/14.jpg)
Martin-Gay, Prealgebra, 6ed 14 14
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Finding Area
A = length ∙ width
= 3(2x – 5)
= 6x – 15 square meters
Don’t forget to insert
proper units.
3 meters
(2x – 5) meters
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Martin-Gay, Prealgebra, 6ed 15 15
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Don’t forget . . .
Area:
• surface enclosed
• measured in square units
Perimeter:
• distance around
• measured in units
Helpful Hint
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3.2
Solving Equations:
Review of the Addition
and Multiplication
Properties
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Martin-Gay, Prealgebra, 6ed 17 17
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Statements like 5 + 2 = 7 are called equations.
An equation is of the form expression = expression.
An equation can be labeled as
Equal sign
left side right side
x + 5 = 9
Equation vs. Expression
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Martin-Gay, Prealgebra, 6ed 18 18
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Addition Property of Equality
Let a, b, and c represent numbers.
If a = b, then
a + c = b + c
and
a – c = b - c
In other words, the same number may be added
to or subtracted from both sides of an equation
without changing the solution of the equation.
![Page 19: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/19.jpg)
Martin-Gay, Prealgebra, 6ed 19 19
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Multiplication Property of Equality
Let a, b, and c represent numbers and let c 0.
If a = b, then
a ∙ c = b ∙ c and
In other words, both sides of an equation may
be multiplied or divided by the same nonzero
number without changing the solution of the
equation.
a b=
c c
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Martin-Gay, Prealgebra, 6ed 20 20
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Solve for x.
x - 4 = 3
To solve the equation for x, we need to rewrite the equation in the form
x = number.
To do so, we add 4 to both sides of the equation.
x - 4 = 3
x - 4 + 4 = 3 + 4 Add 4 to both sides.
x = 7 Simplify.
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Martin-Gay, Prealgebra, 6ed 21 21
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Check
x - 4 = 3 Original equation
7 - 4 = 3 Replace x with 7.
3 = 3 True.
Since 3 = 3 is a true statement, 7 is the solution
of the equation.
To check, replace x with 7 in the original equation.
?
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Martin-Gay, Prealgebra, 6ed 22 22
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Solve for x
4x = 8
To solve the equation for x, notice that 4 is multiplied by x.
To get x alone, we divide both sides of the equation by 4 and then simplify.
4 8
4 4
x= 1∙x = 2 or x = 2
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Martin-Gay, Prealgebra, 6ed 23 23
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Check
To check, replace x with 2 in the original
equation.
4x = 8 Original equation
4 ∙ 2 = 8 Let x = 2.
8 = 8 True.
The solution is 2.
?
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Martin-Gay, Prealgebra, 6ed 24 24
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Using Both Properties to Solve Equations
2(2x – 3) = 10
Use the distributive property to simplify the left side.
4x – 6 = 10
Add 6 to both sides of the equation
x = 4
4x – 6 + 6 = 10 + 6
4x = 16
Divide both sides by 4.
![Page 25: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/25.jpg)
Martin-Gay, Prealgebra, 6ed 25 25
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Check
To check, replace x with 4 in the original equation.
2(2x – 3) = 10 Original equation
2(2 · 4 – 3) = 10 Let x = 4.
2(8 – 3) = 10
(2)5 = 10 True.
The solution is 4.
?
?
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3.3
Solving Linear
Equations in One
Variable
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Martin-Gay, Prealgebra, 6ed 27 27
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Linear Equations in One Variable
3x – 2 = 7 is called a linear equation or first
degree equation in one variable.
The exponent on each x is 1 and there is no variable
below a fraction bar.
It is an equation in one variable because it contains
one variable, x.
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Martin-Gay, Prealgebra, 6ed 28 28
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Make sure you understand which property to use to solve an
equation.
x + 5 = 8
Addition
To undo addition of 5, we
subtract 5 from both sides.
x + 5 – 5 = 8 – 5
Use Addition Property of Equality.
x = 3
3x = 12
Multiplication
To undo multiplication of 3, we
divide both sides by 3.
Use Multiplication Property of Equality
x = 4
Helpful Hint
3 123 3x
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Martin-Gay, Prealgebra, 6ed 29 29
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Steps for Solving an Equation
Step 1: If parentheses are present, use the distributive property.
Step 2: Combine any like terms on each side of the equation.
Step 3: Use the addition property to rewrite the equation so that the variable terms are on one side of the equation and constant terms are on the other side.
Step 4: Use the multiplication property of equality to divide both sides by the numerical coefficient of x to solve.
Step 5: Check the solution in the original equation.
![Page 30: Solving Equations and Problem Solving Notes... · Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Steps for Solving an Equation Step 1: If parentheses are present,](https://reader031.fdocuments.us/reader031/viewer/2022030914/5b5e29697f8b9a164b8bf4cf/html5/thumbnails/30.jpg)
Martin-Gay, Prealgebra, 6ed 30 30
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Key Words or Phrases that translate to an equal sign when writing
sentences as equations.
equals
Gives
is/was/will be
yields
amounts to
is equal to
Key Words
or Phrases Equations Sentences
5 equals 2 plus 3.
The quotient of 8
and 4 gives 2.
x is 5.
Twice x amounts to –8.
y plus 6 yields 15.
36 is equal to 4 times 9.
5 = 2 + 3
x = 5
y + 6 = 15
2x = –8
36 = 4(9)
Phrases for “Equal”
82
4
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3.4
Linear Equations in
One Variable and
Problem Solving
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Martin-Gay, Prealgebra, 6ed 32 32
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1. UNDERSTAND the problem. During this step, become comfortable with the problem. Some ways of doing this are:
Read and reread the problem.
Choose a variable to represent the unknown.
Construct a drawing.
Propose a solution and check it. Pay careful attention to how you check your proposed solution. This will help when writing an equation to model the problem.
Problem-Solving Steps
Continued
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Martin-Gay, Prealgebra, 6ed 33 33
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2. TRANSLATE the problem into an equation.
3. SOLVE the equation.
4. INTERPRET the results. Check the proposed
solution in the stated problem and state your
conclusion.
Problem-Solving Steps
Martin-Gay, Prealgebra, 5ed