Solucion problema 69 capitulo 13
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Transcript of Solucion problema 69 capitulo 13
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COSMOS: Complete Online Solutions Manual Organization System
Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell 2007 The McGraw-Hill Companies.
Chapter 13, Solution 69.
(a) 0, 0C Cv T= =
212B B
T mv=
( ) 21 0.2 kg2B B
T v=
20.1B BT v= ( ) ( )C C Ce gV V V= + arc BCBC L R= =
( )( ) ( )0.3 m 30180BC
L
=
0.15708 mBCL =
( ) ( ) ( )( )2 21 1 40 N/m 0.15708 m 0.49348 J2 2C BCe
V k L= = =
( ) ( ) ( )( )( )( )21 cos 0.2 kg 9.81 m/s 0.3 m 1 cos30C gV WR = = ( ) 0.078857 JC gV =
( ) ( ) 0.49348 J 0.078857 J 0.57234 JC C Ce gV V V= + = + = ( ) ( ) 0 0 0B B Be gV V V= + = + =
2; 0 0.57234 0.1C C B B BT V T V v+ = + + =
2 2 25.7234 m /sBv = 2.39 m/sBv = !
(b)
2B
RmvF F W
R = =
( ) ( )( )2 25.7234 m /s
1.962 N 0.2 kg0.3 mR
F = +
1.962 N 3.8156 N 5.7776 NRF = + = 5.78 NRF = !