Solucion problema 69 capitulo 13

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COSMOS: Complete Online Solutions Manual Organization System Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. Chapter 13, Solution 69. (a) 0, 0 C C v T = = 2 1 2 B B T mv = ( ) 2 1 0.2 kg 2 B B T v = 2 0.1 B B T v = ( ) ( ) C C C e g V V V = + arc BC BC L R θ =∆ = ( )( ) ( ) 0.3 m 30 180 BC L π = ° ° 0.15708 m BC L = ( ) ( ) ( )( ) 2 2 1 1 40 N/m 0.15708 m 0.49348 J 2 2 C BC e V k L = = = ( ) ( ) ( ) ( ) ( )( ) 2 1 cos 0.2 kg 9.81 m/s 0.3 m 1 cos30 C g V WR θ = = ° ( ) 0.078857 J C g V = ( ) ( ) 0.49348 J 0.078857 J 0.57234 J C C C e g V V V = + = + = ( ) ( ) 0 0 0 B B B e g V V V = + = + = 2 ; 0 0.57234 0.1 C C B B B T V T V v + = + + = 2 2 2 5.7234 m /s B v = 2.39 m/s B v = ! (b) 2 B R mv F F W R Σ = = ( ) ( ) ( ) 2 2 5.7234 m /s 1.962 N 0.2 kg 0.3 m R F = + 1.962 N 3.8156 N 5.7776 N R F = + = 5.78 N R F = !

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Hola aquí la solucion al problema numero 69 del capitulo 13 del beer de cinematica.Espero que les sea de ayuda

Transcript of Solucion problema 69 capitulo 13

  • COSMOS: Complete Online Solutions Manual Organization System

    Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell 2007 The McGraw-Hill Companies.

    Chapter 13, Solution 69.

    (a) 0, 0C Cv T= =

    212B B

    T mv=

    ( ) 21 0.2 kg2B B

    T v=

    20.1B BT v= ( ) ( )C C Ce gV V V= + arc BCBC L R= =

    ( )( ) ( )0.3 m 30180BC

    L

    =

    0.15708 mBCL =

    ( ) ( ) ( )( )2 21 1 40 N/m 0.15708 m 0.49348 J2 2C BCe

    V k L= = =

    ( ) ( ) ( )( )( )( )21 cos 0.2 kg 9.81 m/s 0.3 m 1 cos30C gV WR = = ( ) 0.078857 JC gV =

    ( ) ( ) 0.49348 J 0.078857 J 0.57234 JC C Ce gV V V= + = + = ( ) ( ) 0 0 0B B Be gV V V= + = + =

    2; 0 0.57234 0.1C C B B BT V T V v+ = + + =

    2 2 25.7234 m /sBv = 2.39 m/sBv = !

    (b)

    2B

    RmvF F W

    R = =

    ( ) ( )( )2 25.7234 m /s

    1.962 N 0.2 kg0.3 mR

    F = +

    1.962 N 3.8156 N 5.7776 NRF = + = 5.78 NRF = !