SmartPhone Geometry Jonathan Choate Groton School [email protected] .

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SmartPhone Geometry Jonathan Choate Groton School [email protected] www.zebragraph.com

Transcript of SmartPhone Geometry Jonathan Choate Groton School [email protected] .

Page 1: SmartPhone Geometry Jonathan Choate Groton School jchoate@groton.org .

SmartPhone Geometry

Jonathan Choate

Groton School

[email protected]

www.zebragraph.com

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WHAT’S COMING?

• Why are they called Smart Cell phones?• How do you figure out how far you are

from home using your latitude and longitude?

• How does your phone figure out where you are if there is no GPS reception?

• Given tower locations how can you predict the coverage?

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Part 1. Why are they called Cell Phones?

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http://www.google.com/patents?id=nO8tAAAAEBAJ&dq=martin+cooper

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Typical Cell Cluster

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• http://www.doc.ic.ac.uk/~nd/surprise_96/journal/vol1/pr4/article1.html#Cells

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In order to serve the most customers the average cellsize is roughly 10 square miles. Each cell can service approximately 70-80 users at once because

- Each cell is alloted 832 frequencies or channels

- 42 channels are used for control issues

- 790 are available for voice and data transmission.

- Cell phones are duplex devises and need 2 frequencies per user unlike walkie talkies.

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- Each cell is surrounded by 6 other cells so in order to avoid

interference issues there has to be seven separate sets of frequencies.

- 395/7 is roughly 76 so for each cell there are 76 sets of frequencies so each cell can handle 76 users at once.

- In a 7 cell cluster, 532 people can be handled.

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Activity 1. Given that cells are hexagonal in shape, what are the possible cluster sizes that insure no interference occurs between adjacent cells?

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Hexagon Geometry

R

32

R

Cell Area = 23 3

R2

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2H

1H

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Ru

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Let H = distance between two centers of adjacent hexagons.

H = 3R

Let Ru = Distance between two cells with same set of frequences. Using the law of cosines, you get

Ru2 =(2H)2 +(1H)2 −2(2)(1)H2cos(120)

Ru= (2H)2 +(1H)2 +(2)(1)H2

Ru = 7HRu = 7 3R

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Let Rc be the cluster radius. Rc = AB =AD=DE and AE = Ru,

<ADE=120

B

A

D

C

ERc

Rc

RcRc

Rc

Ru

Rc =Ru3

Ru= 3Rc

Rc =Ru3

Ru= 3Rc

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The area of the cluster can be calculated in two ways. Let C be the number of cells in the cluster

2 23 3 3 3R 7R2 2

C =

Therefore, C = 7

23 3 R2

Areaof cluster =C

Areaof cluster =  3 32

Rc2

Rc =Ru3

=7 3R

3== 7R

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This shows that the possible cluster configurations contain i2 + j2 +ij cells where i and j are the displacements used to get to the nearest cell that can have the same set of frequencies.

Ru2 = (iH)2+(jH)2-2(i)(j)H2cos(120)

Ru= (i)2+(j)2+(i)(j) H

Ru= (i)2+(j)2+(i)(j)  3R

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I = 1, j =1 I = 2, j = 0 I = 2 , j =1 I = 3 , j = 0

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i=3, j = 2

9 + 4 + 6 = 19

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Part 2. How do you assign coordinates to locations on the surface of the Earth?

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<PCQ = your longitude<PCG = your latitudeR is the radius of the EarthR = 3,959 Miles<GPR=<PQC=90

Z= GP = R sin(lat)PC=R cos(lat)

X= PQ = PC sin(long) =Rcos(lat)sin(long)

Y = CQ=PC cos(long) = Rcos(lat)cos(long)

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Activity 2. How do you calculate the distance between two points on the surface of the Earth given their latitude and longtitude? How far are you from home?

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MA2029

Part 3: How does your phone figure out where you are?

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A possible arrangement of AT@T towers??? Tower maps can be found at http://www.towerco.com

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• Activity 3 How does Assisted GPS determine your position? Method 1: Trilaterization

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To construct the Symmedian Point S for triangle ABC

1. Construct the centroid G2. Reflect G about the angle bisector of angle

BAC creating point G1. Create ray AG1 and hide the angle bisector.

3. Repeat for vertices B and C, creatingrays BG2 and CG3.4. Rays AG1, BG2 and CG3 are concurrent at

the Symmedian point S

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Method 2: A Slick Construction

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How about an algorithm for a general solution?

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Part 4:Given Tower Locations How Can You Predict Coverage?

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One solution to this problem is to construct for each tower the region formed by all the points nearest to that tower. These are called Vornoi Regions.

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The 2 Tower Case

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The 3 Tower Case

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Activity 4: Construct the Vornoi Regions for the five towers shown on the diagram below.

T2

T1

T3

T4

T5

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Fortune’s Method

• For more than 3 points, finding Vornoi Regions is very hard. In 1986, Steven Fortune came up with an ingenious way of finding them making use of parabolas.

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Given a line D, the directrix and a point F, the Focus, not on D, the set of points

equidistant from F and D form a parabola.

y =yD

( x, y )F( xF , yF  )

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The function you need to plot the parabola with focus at ( xF, yF ) and directrix the line y = yD

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Here’s how to implement Fortune’s Algorithm using Geometer’s Sketchpad

Step 1. Open a file and select the graph option. Plot the points which represent the tower locations

Step 2. Construct a vertical line with a movable point D. Through D construct a

horizontal line. This will serve as a movable Directrix.

Step 3. Create the function which will plot the parabola with the upper most tower point and plot it.

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Cell triangulationhttp://searchengineland.com/cell-phone-triangulation-accuracy-is-all-over-the-map-14790

Tracking GPS Satteliteshttp://www.n2yo.com/?s=36397

Cell and Cluster Design Informationhttp://www.wirelesscommunication.nl/reference/chaptr04/cellplan/reuse.htm

Some Interesting Problemswww.ece.ucdavis.edu/~chuah/classes/eec173B/eec173b-s09/.../hw1.pdf -

Fortune's Algorithmhttp://en.wikipedia.org/wiki/File:Fortunes-algorithm.gif http://www.ams.org/featurecolumn/archive/voronoi.html

Best GPS Informationhttp://www.u-blox.com/images/stories/Resources/gps_compendiumgps-x-02007.pdf

Tower Location Mapshttp://towerco.com

References