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Table of Contents

· Questions from Released PARCC Test

· Triangle Sum Theorem

· Exterior Angle Theorem

· Triangles

· Inequalities in Triangles

· Similar Triangles

Click on the topic to go to that section

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Geometry

Triangles




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Return to Tableof Contents

Triangles

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Geometric Figures

Euclid now makes the transitions to geometric figures, which are created by a boundary which separates space into that which is within the figure and that which is not.

Definition 13. A boundary is that which is an extremity of anything.

Definition 14. A figure is that which is contained by any boundary or boundaries.

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Geometric Figures

His definitions from 15 to 18 relate to circles, which we will discuss later. In this chapter, we will be discussing triangles, which are an example of a rectilinear figure: a figure bounded by straight lines.

A triangle is bounded by three lines.

Definition 19. Rectilinear figures are those which are contained by straight lines, trilateral figures being those contained by three, quadrilateral those contained by four, and multilateral those contained by more than four straight lines.

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Parts of a TriangleEach triangle has three sides and three vertices.

Each vertex is where two sides meet.

A pair of sides and the vertex define an angle, so each triangle includes three angles.

Write "side" next to each side and circle the vertices on the triangle below.

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1 The letter on this triangle that corresponds to a side is:

A

B

C

(Answer) / 210

1 The letter on this triangle that corresponds to a side is:

A

B

C

[This object is a pull tab]

Ans

wer

C

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2 The letter on this triangle that represents a vertex is:

AB

C

(Answer) / 210

2 The letter on this triangle that represents a vertex is:

AB

C


Ans

wer

A

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Parts of a Triangle

C

A B

Each vertex is named with a letter.

The sides can then be named with the letters of the two vertices on either side of it.

The triangle is named with a triangle symbol Δ in front followed by the three letters of its vertices.

Name the 3 sides of this triangle

______ ______ ______

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3 What is the name of the side shown in red?

A ABB BCC AC

C

A B

(Answer) / 210


A ABB BCC AC

C

A B[This object is a pull tab]

Ans

wer

C

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A AB

B BC

C AC

C

A B

(Answer) / 210


A AB

B BC

C AC

C

A B


Ans

wer

A

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5 Which of the following are names of this triangle?

A ΔABCB ΔBCAC ΔACB

C

A B

D ΔCABE all of these

(Answer) / 210

5 Which of the following are names of this triangle?

A ΔABCB ΔBCAC ΔACB

C

A B

D ΔCABE all of these


Ans

wer

E

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Parts of a Triangle

C

A B

In the above, the red side is ________________ A,

while the green sides are ________________ to A.

A side is opposite an angle if it does not touch it. Otherwise, it is adjacent to the angle.

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6 Which side is opposite angle B?

A AB

B CA

C BC

D None

C

A B

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6 Which side is opposite angle B?

A AB

B CA

C BC

D None

C


Ans

wer

B

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7 Which side is opposite angle A?

A AB B CA

C BC D None

C

A B

(Answer) / 210

7 Which side is opposite angle A?

A AB B CA

C BC D None

C


Ans

wer

C

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8 Which sides are adjacent to angle C?

A AB & BC

B CA & BA

C BC & CAD None

C

A B

(Answer) / 210

8 Which sides are adjacent to angle C?

A AB & BC

B CA & BA

C BC & CAD None

C

A B


Ans

wer

C

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9 Which sides are adjacent to angle B?

A AB & BCB CA & BA C BC & CAD None

C

A B

(Answer) / 210

9 Which sides are adjacent to angle B?

A AB & BCB CA & BA C BC & CAD None

C


Ans

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A

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Types of Triangles

In general, a triangle can have sides of all different lengths and angles of all different measure.

However, there are names given to triangles which have specific or special angles or some number of equal sides or angles.

Euclid defined the names for a number of these in his definitions.

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Definition 20: Of trilateral figures, an equilateral triangle is that which has its three sides equal, an isosceles triangle is that which has two of its sides alone equal, and a scalene triangle is that which has its three sides unequal

Classifying Triangles

Triangles can be classified by their sides or by their angles.

In this definition, Euclid used the sides.

In his next definition, Euclid uses the angles.

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Definition 21: Further, of trilateral figures, a right-angled triangle is that which has a right angle, an obtuse-angled triangle is that which has an obtuse angle, and an acute-angled triangle is that which has

its three angles acute.


We will draw from both definitions, since in several cases both definitions apply to the same triangle.

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Acute Triangles

In an acute triangle, every angle of a triangle is acute.

Notice that no angle is equal to or greater than 90º in this triangle.


Definition 21: "...an acute-angled triangle is that which has its three angles acute."

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Right Triangles

A right triangle has one right angle and two acute angles.

Notice that one angle is 90º, which means that the other two sum to 90º; and they are acute.

The side opposite the right angle is called the hypotenuse and the other two sides are called the legs.


Definition 21: "...a right-angled triangle is that which has a right angle..."

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Isosceles Triangles

An isosceles triangle has two sides with equal length.

The angles opposite those equal sides are of equal measure.

x x


Definition 20: "...an isosceles triangle is that which has two of its sides alone equal..."

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Isosceles Triangles

The equal angles, of measure x in this diagram, are called the base angles. The side between them is called the base.

The other two sides, opposite the base angles and congruent to each other are called the legs.

This is a special case of an acute triangle.

x x


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Obtuse Triangles

An obtuse triangle has one angle which is greater than 90º and two acute angles.

Notice that one angle is greater than 90º, which means that the other two sum to less than 90º; and they are acute..


Definition 21: "...an obtuse-angled triangle is that which has an obtuse angle..."

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Equiangular / Equilateral Triangles

An equiangular, or equilateral, triangle has angles of equal measure and sides of equal length.

Definition 20: "...an equilateral triangle is that which has its three sides equal..."

All the angles are of equal measure and all the sides are of equal length.

Each angle measures 60º.

This is a special acute triangle.x x

x


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Scalene Triangles

None of the sides or angles of a scalene triangle are congruent with one another.

Definition 20: "...a scalene triangle is that which has its three sides unequal..."

Note that in this triangle none of the sides or angles are equal.

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10 An isosceles triangle is _______________ an equilateral triangle.

A SometimesB AlwaysC Never

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10 An isosceles triangle is _______________ an equilateral triangle.



Ans

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C

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11 An obtuse triangle is _______________ an isosceles triangle.


(Answer) / 210

11 An obtuse triangle is _______________ an isosceles triangle.



Ans

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A

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12 A triangle can have more than one obtuse angle.

TrueFalse

(Answer) / 210

12 A triangle can have more than one obtuse angle.

TrueFalse


Ans

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False

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13 A triangle can have more than one right angle.

TrueFalse

(Answer) / 210

13 A triangle can have more than one right angle.

TrueFalse


Ans

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False

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14 Each angle in an equiangular triangle measures 60°

TrueFalse

(Answer) / 210

14 Each angle in an equiangular triangle measures 60°

TrueFalse


Ans

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True

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15 An equilateral triangle is also an isosceles triangle

TrueFalse

(Answer) / 210

15 An equilateral triangle is also an isosceles triangle

TrueFalse


Ans

wer False

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16 This triangle is classified as _____. (Choose all that apply.)

A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

60º8.6

60º

60º8.68.6

(Answer) / 210


A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

60º8.6

60º

60º8.68.6


Ans

wer

A, E, F

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A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

57º

79º 44º

6.1 8.7

7.4

(Answer) / 210


A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

57º

79º 44º

6.1 8.7

7.4[This object is a pull tab]

Ans

wer

A, G

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A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

26°

128° 26°

2.5

2.5

4.5

(Answer) / 210


A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

26°

128° 26°

2.5

2.5

4.5


Ans

wer

C, D

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19 This triangle is classified as _____. Choose all that apply.

A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

4.8 4.8

45° 45°

6.8

(Answer) / 210

19 This triangle is classified as _____. Choose all that apply.

A acute

B right

C isosceles

D obtuse

E equilateral

F equiangular

G scalene

4.8 4.8

45° 45°

6.8[This object is a pull tab]

Ans

wer

B, C

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Measure and Classify the triangle by sides and anglesExample

isosceles, acuteClick for AnswerClick for Answer

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scalene, obtuseClick for AnswerClick for Answer

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scalene, acuteClick for AnswerClick for Answer

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20 Classify the triangle with the given information: Side lengths: 3 cm, 4 cm, 5 cm

A EquilateralB IsoscelesC Scalene

D AcuteE EquiangularF RightG Obtuse

(Answer) / 210





Ans

wer

C Scalene

Bonus: F Right32+42 = 52

9+16 = 25

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(Answer) / 210





Ans

wer

B Isosceles

Bonus: D Acute

3 cm 3 cm

2 cm

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(Answer) / 210





Ans

wer

A Equilateral

Bonus:E Equiangular (all equilateral triangles are equiangular)

D Acute (all angles are 60o )

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23 Classify the triangle with the given information: Angle Measures: 25°, 120°, 35°



(Answer) / 210





Ans

wer

G Obtuse

Bonus: C Scalene (all angles are different, so all sides are different)

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(Answer) / 210





Ans

wer

F Right

Bonus: C Scalene(all angles are different, so all sides are different)

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25 Classify the triangle with the given information: Side lengths: 3 cm, 4 cm, 5 cmAngle measures: 37°, 53°, 90°



(Answer) / 210

25 Classify the triangle with the given information: Side lengths: 3 cm, 4 cm, 5 cmAngle measures: 37°, 53°, 90°




Ans

wer

C ScaleneF Right

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26 Classify the triangle by sides and angles

A EquilateralB IsoscelesC ScaleneD AcuteE EquiangularF RightG Obtuse

AB

120°

C

(Answer) / 210



AB

120°

C[This object is a pull tab]

Ans

wer C Scalene

G Obtuse

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L

MN



(Answer) / 210

L

MN




Ans

wer

B IsoscelesF Right

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H

J

K45°

85°

50°



(Answer) / 210

H

J

K45°

85°

50°




Ans

wer C Scalene

D Acute

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Triangle Sum Theorem


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A

B C

We can use what we learned about parallel lines to determine the sum of the measures of the angles of any triangle.

First, let's draw two parallel lines. The first along the base of the triangle and the other through the opposite vertex.

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And extend AB to make it a transversal.

Then, let's label some of the angles.


A

B C

x

x

y

y

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29 What is the name for the pair of angles labeled x and what is the relationship between them?

A outside exterior, they are unequalB alternate interior, they are unequalC alternate interior, they are equalD outside exterior, they are equal

Is the same true for the pair of angles labeled y?

(Answer) / 210

29 What is the name for the pair of angles labeled x and what is the relationship between them?

A outside exterior, they are unequalB alternate interior, they are unequalC alternate interior, they are equalD outside exterior, they are equal

Is the same true for the pair of angles labeled y?[This object is a pull tab]

Ans

wer

C; yes

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A

B C

Therefore, both angles labeled x are equal and can be called x, and x has the same measure as B.

x

x

Repeat the same process with side AC and find an angle along the upper parallel line equal to angle C


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A

B C

x

x

y

y

Let's just re-label the upper angles with A, B and C.


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A

B C

The sum of those angles along that upper parallel line equals 180º, so A + B + C = 180º

B C

We made no special assumptions about this triangle, so this proof applies to all triangles: the sum of the interior angles of any triangle is 180º


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The measures of the interior angles of a triangle sum to 180°

Click here to go to the lab titled, "Triangle Sum Theorem"


A

B C

https://njctl.org/courses/math/geometry/congruent-triangles/triangle-sum-theorem-lab/

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Example: Triangle Sum Theorem

320

J

K L 200

Find the measure of the missing angle.

(Answer) / 210

Example: Triangle Sum Theorem

320

J

K L 200

Find the measure of the missing angle.


Ans

wer

m∠J + m∠K + m∠L = 180º

32º + m∠K + 20 = 180º

m∠K + 52º = 180º

m∠K = 128º

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30 What is m∠B?

A B

C

52°

53°

(Answer) / 210

30 What is m∠B?

A B

C

52°

53°[This object is a pull tab]

Ans

wer 52 + 53 + m∠B = 180°

105 + m∠B = 180° -105 -105 m∠B = 75°

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31 What is the measurement of the missing angle?

57°L

M

N

(Answer) / 210


57°L

M

N


Ans

wer

90 + 57 + m∠N = 180° 147 + m∠N = 180° -147 -147 m∠N = 33°

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32 In ΔABC, if m∠B is 84° and m∠C is 36°, what is m∠A?

(Answer) / 210

32 In ΔABC, if m∠B is 84° and m∠C is 36°, what is m∠A?


Ans

wer

triangle ABC = 180°So, 84 + 36 + m∠A = 180°

m∠A =180° - 120°m∠A = 60°

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33 In ΔDEF, if m∠D is 63° and m∠E is 12°, find m∠F.

(Answer) / 210

33 In ΔDEF, if m∠D is 63° and m∠E is 12°, find m∠F.


Ans

wer

triangle DEF = 180°So, 63 + 12 + m∠F = 180°

m∠F =180° - 75°m∠F = 105°

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Solve for x

55°

(12x+8)°

(8x-3)°P

Q

R

Example

(Answer) / 210

Solve for x

55°

(12x+8)°

(8x-3)°P

Q

R

Example


Ans

wer m∠P + m∠Q + m∠R = 180º

55º + (12x+8) + (8x-3) = 180º20x +60 = 18020x = 120x = 6

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Q

R

S2x° 5x°

8x°34 Solve for x.

Then find: m∠Q =

m∠ R =

m∠S =

(Answer) / 210

Q

R

S2x° 5x°

8x°34 Solve for x.

Then find: m∠Q =

m∠ R =

m∠S =


Ans

wer

2x+5x+8x = 180 15x = 180 x = 12

m∠Q = 24° m∠R = 96° m∠S = 60°

Extension Answer

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35 What is the measure of ∠B?

C

B

A

(3x-17)0

(x+40)0 (2x-5)0

(Answer) / 210

35 What is the measure of ∠B?

C

B

A

(3x-17)0

(x+40)0 (2x-5)0[This object is a pull tab]

Ans

wer

3x-17+2x-5+x+40 = 180 6x + 18 = 180 6x = 162 x = 27 m∠B = 3(27)-17 = 81 - 17 = 64

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Corollary to Triangle Sum TheoremThe acute angles of a right triangle are complementary.

A

B

C

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Given: Triangle ABC is a right triangle

Prove: Its acute angles, Angles B and C, are complementary

A

B

C

Proof of Triangle Sum Theorem Corollary

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36 Which reason applies to step 1?A Subtraction Property of EqualityB Substitution Property of EqualityC GivenD Definition of right triangle E Definition of a right angle

A

B

C

Statement Reason1 Triangle ABC is a right triangle ?

2 Right triangles contain a right angle. ?

3 ? Interior Angles Theorem4 m∠A = 90º ?5 90º + m∠B + m∠C = 180º ?

6 m∠B + m∠C = 90º ?

7 ? Definition of complementary

Ans

wer

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A

B

C



3 ? Interior Angles Theorem4 m∠A = 90º ?5 90º + m∠B + m∠C = 180º ?6 m∠B + m∠C = 90º ?


Ans

wer

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38 Which reason applies to step 3?

A

B

C

A The measure of a straight angle is 180ºB m∠A + m∠B + m∠C = 180ºC m∠B + m∠C = 90ºD m∠B + m∠C = 180ºE ∠A is a right angle




6 m∠B + m∠C = 90º ?


Ans

wer

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A

B

C

Ans

wer





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A

B

C




6 m∠B + m∠C = 90º ?


Ans

wer

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A

B

C





Ans

wer

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42 Which reason applies to step 7?

A

B

C




6 m∠B + m∠C = 90º ?


A The measure of a straight angle is 180ºB The sum of the interior angles of a

triangle is 180ºC The acute angles are complementaryD The acute angles are supplementaryE ∠A is a right angle

Ans

wer

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A

B

C

Given: Triangle ABC is a right triangle

Prove: Its acute angles, Angles B and C, are complementary

Statement Reason1 Triangle ABC is a right triangle Given

2 Right triangles contain a right angle. Definition of right triangle

3 m∠A + m∠B + m∠C = 180º Interior Angles Theorem4 m∠A = 90º Definition of right angle

5 90º + m∠B + m∠C = 180º Substitution Property of Equality

6 m∠B + m∠C = 90º Subtraction Property of Equality

7The acute angles are complementary

Definition of complementary

Proof of Triangle Sum Theorem Corollary

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Example

The measure of one acute angle of a right triangle is five times the measure of the other acute angle.

Find the measure of each acute angle.

(Answer) / 210

Example

The measure of one acute angle of a right triangle is five times the measure of the other acute angle.

Find the measure of each acute angle.


Ans

wer

x + 5x + 90 = 180º6x = 90x = 15

The measures of the angles are 15º and 75º.

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43 In a right triangle, the two acute angles sum to 90°

TrueFalse

(Answer) / 210

43 In a right triangle, the two acute angles sum to 90°

TrueFalse


Ans

wer

True

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57°L

M

N

(Answer) / 210


57°L

M

N


Ans

wer

x+57 = 90ºx = 33º

Note: we solved this problem earlier using the Triangle Sum Theorem. Use the Corollary to the Triangle Sum this time.

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45 Solve for x

A

B CCB

AWhat are the measures of the three angles?

(Answer) / 210

45 Solve for x

A

B CCB

AWhat are the measures of the three angles?


Ans

wer

3x-1+31 = 903x + 30 = 90 3x = 60 x = 20

Challenge Answerm∠A = 59ºm∠B = 90ºm∠C = 31º

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46 Solve for x

What are the measures of the three angles?

(Answer) / 210

46 Solve for x

What are the measures of the three angles?


Ans

wer

2x-2+x+5 = 903x + 3 = 90 3x = 87 x = 29

Challenge Answerm∠D = 90ºm∠E = 56ºm∠F = 34º

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47 m∠1 + m∠2 =

1

23

(Answer) / 210

47 m∠1 + m∠2 =

1

23


Ans

wer

90

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48 m∠1 + m∠3 =

1

23

(Answer) / 210

48 m∠1 + m∠3 =

1

23


Ans

wer

90

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20°

X°

49 Find the value of x in the diagram

(Answer) / 210

20°

X°

49 Find the value of x in the diagram

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Exterior Angle Theorem

Return to Table of Contents

page2svg

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Exterior angles are formed by extending any side of a triangle.

The exterior angle is then the angle between that extended side and the nearest side of the triangle.

One exterior angle is shown below.

Take a moment and draw another.

Exterior Angles

A

B Cx

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Since a triangle has three vertices and two external angles can be drawn at each vertex, it is possible to draw six external angles to a triangle.

Draw the other external angle at Vertex A.

Exterior Angles

A

B C

x

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A

B C

xx

The exterior angles at each vertex are congruent, since they are vertical angles.

Exterior Angles

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The interior angles of this triangle are ∠A, ∠ABC and ∠C.

Once an exterior angle is drawn, one interior angle is adjacent, and the two others are remote.

Since you can draw exterior angles at any vertex, any interior angle can be the remote depending on at which vertex you draw the external angle.

Remote Interior Angles

A

B Cx

In this case, ∠A and ∠C are the remote interior angles and ∠ABC is the adjacent interior angle.

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50 Which are the remote interior angles in this instance?

A ∠A & ∠BB ∠A & ∠CC ∠B & ∠C

A

B C

xx

(Answer) / 210

50 Which are the remote interior angles in this instance?

A ∠A & ∠BB ∠A & ∠CC ∠B & ∠C

A

B C

xx


Ans

wer

C

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51 If line AB is a straight line, what is the sum of ∠2 and ∠1?

1A B

2

(Answer) / 210

51 If line AB is a straight line, what is the sum of ∠2 and ∠1?

1A B

2


Ans

wer

Linear Pair PostulateSince ∠1 & ∠2 are adjacent and lie on the same line, they are a linear pair, which makes them supplementary. Since supplementary angles sum to 180º, these two angles must also sum to 180º.

In this diagram, m∠1 + m∠2 = 180º

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52 In this diagram, what is the sum of angles P, Q and R?

P

R Q

(Answer) / 210

52 In this diagram, what is the sum of angles P, Q and R?

P

R Q


Ans

wer The sum of the angles of a

triangle is 180º

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A

B Cx

D

The measure of any exterior angle of a triangle is equal to the sum of its remote interior angles.

m∠DBA = m∠A + m∠C

or

x = m∠A + m∠C

Exterior Angles Theorem

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Given: ∠DBA is an exterior angle of ΔABC and ∠A and ∠C are remote interior angles.

Prove: m∠DBA = m∠A + m∠C

Proof of Exterior Angles Theorem

A

B Cx

D

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53 Which reason applies to step 2?A Angles that form a linear pair are supplementaryB Definition of complementaryC Interior Angles TheoremD Substitution Property of EqualityE Definition of a right angle

A

B Cx

D

Statement Reason

1∠DBA is an exterior angle of ΔABC and ∠A and ∠C are remote interior angles

Given

2 ∠DBA and ∠ABC are supplementary ?

3 ? Definition of supplementary

4 m∠A+ m∠ABC + m∠C = 180° ?

5 m∠DBA + m∠ABC = m∠A + m∠ABC + m∠C ?

6 ? Subtraction Property of Equality

Ans

wer

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54 Which statement applies to step 3?A m∠DBA + m∠ABC = 180°B m∠DBA = m∠A + m∠C C m∠A + m∠B = 180° D m∠DBA + m∠A = 90°E m∠DBA + m∠A = 180°

A

B Cx

D

Statement Reason


Given



4 m∠A+ m∠ABC + m∠C = 180° ?



Ans

wer

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A

B Cx

D

Statement Reason


Given



4 m∠A+ m∠ABC + m∠C = 180° ?



Ans

wer

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57 Which statement applies to step 6?A m∠DBA + m∠ABC = 180°B m∠DBA = m∠A + m∠C C m∠A + m∠B = 180° D m∠DBA + m∠A = 90°E m∠DBA + m∠A = 180°

A

B Cx

D

Statement Reason


Given



4 m∠A+ m∠ABC + m∠C = 180° ?



Ans

wer

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Statement Reason


Given

2 ∠DBA and ∠ABC are supplementary Angles that form a linear pair are supplementary

3 ∠DBA + m∠ABC = 180° Definition of supplementary

4 m∠A+ m∠ABC + m∠C = 180° Interior Angles Theorem

5 m∠DBA + m∠ABC = m∠A + m∠ABC + m∠C Substitution Property of Equality

6 m∠DBA = m∠A + m∠C Subtraction Property of Equality

Proof of Exterior Angles TheoremGiven: ∠DBA is an exterior angle of ΔABC and ∠A and ∠C are remote interior angles.

Prove: m∠DBA = m∠A + m∠C

A

B Cx

D

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58 In this case, what must be the relationship between the interior angles of ΔPQR and ∠1?

A m∠Q = m∠1B m∠1 = m∠PC m∠1 = m∠Q + m∠RD m∠1 = m∠P + m∠RE m∠1 = m∠Q + m∠P

1

P

R Q

(Answer) / 210



1

P

R Q[This object is a pull tab]

Ans

wer

D

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2P

R Q

(Answer) / 210



2P

R Q


Ans

wer

C

/ 210

Example: Using the Exterior Angle Theorem

140ºXº

Xº

P

QR

What is the value of x?

(Answer) / 210

Example: Using the Exterior Angle Theorem

140ºXº

Xº

P

QR

What is the value of x?


Ans

wer

140o = xo + xo

140 = 2x70 = x

The measure of the exterior angle is equal to the sum of the two angles that are not adjacent to the exterior angle.

/ 210

ExampleSolve for x and y.

21°

34°x° y°

(Answer) / 210


21°

34°x° y°


Ans

wer

Exterior Angles Theoremx = 21 + 34 x = 55º

Triangle Sum Theorem21 + 34 + y = 180º55 + y = 180-55 -55 y = 125º

/ 210

xº yº

75º

50º


(Answer) / 210

xº yº

75º

50º



Ans

wer

Exterior Angles Theoremx = 75 + 50 x = 125o

Triangle Sum Theorem75 + 50 + y = 180 125 + y = 180-125 -125 y = 55o

/ 210

60 Solve for x.

xº yº

60º

55º

(Answer) / 210

60 Solve for x.

xº yº

60º

55º[This object is a pull tab]

Ans

wer

65º

/ 210

61 Solve for y.

xºyº

60º

55º

(Answer) / 210

61 Solve for y.

xºyº

60º

55º


Ans

wer

115º

/ 210

62 Find the value of x.

2xº

yº

60º

94º

(Answer) / 210


2xº

yº

60º

94º


Ans

wer 60 + 2x = 94º

2x = 34x = 17

/ 210


(2x+3)º

yº100º

51º

(Answer) / 210


(2x+3)º

yº100º

51º


Ans

wer 51 + 2x + 3 = 100º2x + 54 = 1002x = 46x = 23

/ 210


(x+2)°

y°(3x-5)°

33°

(Answer) / 210


(x+2)°

y°(3x-5)°

33°[This object is a pull tab]

Ans

wer

33 + x + 2 = 3x - 5x + 35 = 3x - 535 = 2x - 540 = 2x20 = x

/ 210

65 Segment PS bisects ∠RST, what is the value of w?

w

25°

P

S

TR

(Answer) / 210

65 Segment PS bisects ∠RST, what is the value of w?

w

25°

P

S

TR


Ans

wer

25 o115oPR T

25o

65o

S

/ 210

Example

Find the missing angles in the diagram.

60°

7

103°

43°45°

30°

5 43

2 1

(Answer) / 210

Example

Find the missing angles in the diagram.

60°

7

103°

43°45°

30°

5 43

2 1


Teac

her N

ote

Find the measures of all angles togetherm∠1 = 45o

m∠2 = 90o

m∠3 = 60o

m∠4 = 60o

m∠5 = 77o

m∠6 = 77o

m∠7 = 43o

/ 210

40º

1

24 53

60º

66 Find the measure of ∠1.

(Answer) / 210

40º

1

24 53

60º



Ans

wer

40 + m∠1 = 90ºm∠1 = 50º

/ 210


40º

1

24 53

60º

(Answer) / 210


40º

1

24 53

60º


Ans

wer

40 + m∠2 = 180ºm∠2 = 140º

/ 210


40º

1

24 53

60º

(Answer) / 210


40º

1

24 53

60º


Ans

wer

40 + m∠3 = 180ºm∠3 = 140º

/ 210


40º

1

24 53

60º

(Answer) / 210


40º

1

24 53

60º


Ans

wer m∠4 = 40º

vertical angles are congruent

/ 210


40º

1

24 53

60º

(Answer) / 210


40º

1

24 53

60º


Ans

wer

m∠4 = 40º

Interior angles of a triangle add up to 180º, so40+60+m∠5 = 180º100+m∠5 = 180ºm∠5 = 80o

/ 210

Inequalities in Triangles


page2svg

/ 210

Inequalities in one Triangle

To investigate inequalities in one triangle download the sketch, "inequalities in one triangle" and the worksheet, "inequalities in one triangle"

Go to the sketch, "Inequalities in one

triangle."

Go to the worksheet,"Inequalities in one triangle."

https://njctl.org/courses/math/geometry/triangles/inequalities-in-one-triangle-sketch/

https://njctl.org/courses/math/geometry/triangles/inequalities-in-one-triangle-worksheet/

/ 210

Angle Inequalities in a Triangle

The longest side is always opposite the largest angle.

The shortest side is always opposite the smallest angle.

/ 210

71 Name the longest side of this triangle.A ABB BCC CAD They are all equal

AB

C

35°60°

85°

(Answer) / 210

71 Name the longest side of this triangle.A ABB BCC CAD They are all equal

AB

C

35°60°

85°


Ans

wer

A

/ 210

72 Name the shortest side of this triangle.A ABB BCC CAD They are all equal

AB

C

35°60°

85°

(Answer) / 210


AB

C

35°60°

85°


Ans

wer

B

/ 210


AB

C

35° 105°

40°

(Answer) / 210


AB

C

35° 105°

40°


Ans

wer

B

/ 210

74 Name the largest angle of this triangle.ABCD They are all equal

AB

C

10

148

(Answer) / 210

74 Name the largest angle of this triangle.ABCD They are all equal

AB

C

10

148 [This object is a pull

tab]

Ans

wer

B

/ 210

75 Name the smallest angle of this triangle.ABCD They are all equal

AB

C

10

148

(Answer) / 210


AB

C

10

148 [This object is a pull

tab]

Ans

wer

A

/ 210

A

C

1010

10


B

(Answer) / 210

A

C

1010

10


B [This object is a pull tab]

Ans

wer

D

/ 210

Length Inequalities in a Triangle

No side can be longer than the sum of the other two sides.

No side can be less than the difference of the other two sides.

/ 210

Length Inequalities in a Triangle

No side can be longer than the sum of the other two sides.

This follows from the fact that if the two shorter sides cannot be placed at a 180º angle and exceed the length of the longest side, a triangle cannot be made.

As shown below, if the blue side is longer than the sum of the red and the green side, it cannot form a triangle.

Move the sides below and try to form a triangle.

/ 210

Length Inequalities in a TriangleNo side can be less than the difference of the other two sides.

This follows from the fact that if the longer sides cannot, when placed at a 0° angle, reach the end of the shorter side, a triangle cannot be made.

As shown below, if the blue side is too short to reach the red line, even when the red line is at the smallest angle, it cannot form a triangle.

/ 210

77 What is the maximum length of the third side to form a triangle if the other sides are 4 and 6?

(Answer) / 210



Ans

wer

third side < 4 + 6third side < 10

/ 210


(Answer) / 210



Ans

wer third side < 8 + 7

third side < 15

/ 210

79 What is the minimum length of the third side to form a triangle if the other sides are 4 and 6?

(Answer) / 210



Ans

wer 6 < third side + 4

2 < third side

/ 210


(Answer) / 210



Ans

wer 8 < third side + 7

1 < third side

/ 210

Similar Triangles


page2svg

/ 210

Recall that:

Congruence

Two objects are congruent if they can be moved, by any combination of translation, rotation and reflection, so that every part of each object overlaps.

This is the symbol for congruence:

If a is congruent to b, this would be shown as

which is read as "a is congruent to b."

a b

/ 210

Only line segments with the same length are congruent.

Also, all congruent segments have the same length.

We learned earlier that:

Congruent Line Segments

ab

cd

c da b

/ 210

Recall:

Congruent Angles

A B∠ ∠ ∠C ∠D

Two angles are congruent if they have the same measure.

Two angles are not congruent if they have different measures.

AB

C

D

If m∠A = m∠B If m∠C # m∠D

/ 210

Congruent Triangles

Triangles are made up of

three line segments AND three angles

For one triangle to be congruent to another

all three sides AND all three angles must be congruent.

/ 210

Similar Triangles

If all the sides of two triangles are congruent, we will soon show that all the angles are also congruent.

Therefore, the triangles are congruent.

However, two triangles can have all their angles congruent, with all or none of their sides being congruent.

In that case, they are said to be Similar Triangles.

/ 210

Congruent Triangles

Congruent Triangles are also Similar Triangles since their angles are all congruent.

Congruent triangles are therefore a special case of similar triangles.We will focus on similar triangles first, and then work

with congruent triangles in a later unit.

Similar triangles represent a great tool to solve problems, and are the foundation of trigonometry.

/ 210

Similar triangles have the same shape, but can have different sizes.

If they have the same shape and are the same size, they are both similar and congruent.

A

B

C D

E

F

Similar Triangles Have Proportional Sides Theorem

/ 210

Similar Triangles

This is the symbol for similarity

So, the symbolic statement for

Triangle ABC is similar to Triangle DEF

is:

DEFDEFΔABC Δ

/ 210

Naming Similar Triangles

This statement tells you more than that the triangles are similar.

It also tells you which angles are equal.

In this case, that

m∠A = m∠D m∠B = m∠E m∠C = m∠F

And, thereby which are the corresponding, proportional, sides.

AB corresponds to DEBC corresponds to EFCA corresponds to FD

DEFDEFΔABC Δ

/ 210

Naming Similar Triangles

So, when you are naming similar triangles, the order of the letters matters.

They don't have to be alphabetical.

But they have to be named so that equal angles correspond to one another.

DEFDEFΔABC Δ

/ 210

Proving Triangles Similar

If you can prove that all three angles of two triangles are congruent, you have directly proven that they are similar.

However, there are shortcuts to proving triangles similar.

We will explore three sets of conditions that imply the three angles of two triangles are congruent, meaning that the triangles must be similar.

/ 210

Angle-Angle Similarity Theorem

We know from the Triangle Sum Theorem that the sum of the interior angles of a triangle is always 180o.

So, if two triangles have two pair of congruent angles which sum to x, then the third angle in both triangles must be (180o - x) ....forming three congruent pairs of angles.

One way to prove that two triangles are similar is to prove that two of the angles in each triangle are

congruent.

/ 210

Angle-Angle Similarity TheoremIf two angles of a triangle are congruent to two angles of another triangle, their third angles are congruent and the triangles are similar.

Here's the proof:Statement Reason

1 ∠A and ∠B in ΔABC are ≅ to ∠D and ∠E in ΔDEF

Given

2 m∠A = m∠D; m∠B = m∠E Definition of Congruent Angles

3 m∠A+ m∠B + m∠C = 180ºm∠D+ m∠E + m∠F = 180º


4 m∠C =180º - (m∠A + m∠B) m∠F =180º- (m∠D + m∠E)

Subtraction Property of Equality

5 m∠C =180º - (m∠A + m∠B) m∠F =180º- (m∠A + m∠B)

Substitution Property of Equality

6 m∠C = m∠F Substitution Property of Equality

7 ΔABC and ΔDEF are similar Definition of Similarity

/ 210

If two triangles have their sides proportional, the triangles will be equiangular and will have those angles equal which their corresponding sides subtend.

Euclid - Book Six: Proposition 5

Equiangular triangles are similar, so this states that triangles with proportional sides are similar.

This is a second way to prove triangles are similar:

If you can prove that all three pairs of sides in two triangles are proportional, then you have proven the

triangles similar.

Side-Side-Side Similarity Theorem

/ 210

Side-Side-Side Similarity TheoremThis follows from the way we constructed congruent angles.

We made use of the fact that if angles are congruent, their sides are separating at the same rate as you move away from the vertex. Here's the drawing we used to construct ∠ABC so it would be congruent to ∠FGH.

F

G H

A

CB

/ 210

Side-Side-Side Similarity TheoremIf we draw the green line segments connecting the points where the blue arcs intersect the rays, we can see that the length of that segment would be the same for both angles.

Since the angles are congruent, the line segment opposite those angles will also be congruent, if it intersects both sides of the angle at the same distance from the vertex in both cases.

F

G H

A

CB

D

E

/ 210

Side-Side-Side Similarity TheoremIn this case the segments AC and DE will be congruent since segments GD and GE are also congruent to segments AB and BC.

Therefore ΔDEG is congruent to ΔABC, since all the sides and angles are the same.

Changing the scale of ΔABC won't change the angle measures. The sides would then be in proportion to those of ΔDEG, but not equal.

F

G H

A

CB

D

E

/ 210

A

CB

Side-Side-Side Similarity TheoremThe diagram below shows an expansion of ΔABC and we see that the measures of the angles are unchanged.

They are still similar triangles. The corresponding sides are in proportion.

F

G H

D

E

/ 210

A

CB

Side-Side-Side Similarity TheoremRemoving the arcs and shifting the smaller triangle within the larger makes it clear that all angles are congruent and the sides are in proportion.

So, the second way to prove triangles similar is to show that all their sides are in proportion.

F

D

EG H

/ 210

Side-Angle-Side Similarity Theorem

If two triangles have one angle equal to another and the sides about the equal angle are in proportion, the triangles will be equiangular and will have those angles equal which the corresponding sides subtend.

Euclid's Elements - Book Six: Proposition 6

The third way to prove triangles are similar is to show they share an angle which is equal and the two sides forming that angle are proportional in the two triangles.

/ 210


This directly follows from the work we just did to show that Side-Side-Side proportionality can be used to prove triangles are similar.

If you recall, the line segment which makes up the third side of a triangle is completely defined by its opposite angle and the lengths of the other two sides.

/ 210


If the angles are congruent and the two sides of the angle are in proportion, the third side must also be in proportion.

If all three sides are in proportion, the triangles must be similar due to the Side-Side-Side Theorem.

You can see that on the next page.

/ 210

A

B

C D

E

F

Side-Angle Side Similarity TheoremIf ∠B ≅ ∠E and segments AB and BC are proportional to segments ED and EF, then segment AC must also be proportional to segment DF. Since all the sides are in proportion, the triangles are similar.

/ 210

Common Error

You CANNOT prove triangles similar using Side-Side-Angle.

This is not the same as Side-Angle-Side.

As shown below, two triangles can have two corresponding sides and one corresponding angle congruent, but NOT be similar.

/ 210

81 Which theorem allows you to prove these two triangles are similar?

A Angle-AngleB Side-Angle-SideC Side-Side-SideD They may not be similar

x

x

E They are not similar

(Answer) / 210



x

x



Ans

wer A

x

x

/ 210


A Angle-AngleB Side-Angle-SideC Side-Side-SideD They may not be similarE They are not similar

(Answer) / 210




Ans

werD; not enough information

/ 210


A Angle-AngleB Side-Angle-SideC Side-Side-Side

D They may not be similar

6

4

88

12


16

(Answer) / 210


A Angle-AngleB Side-Angle-SideC Side-Side-Side

D They may not be similar

6

4

88

12


16[This object is a pull tab]

Ans

wer

C

/ 210



4 8

36

6 10


(Answer) / 210



4 8

36

6 10



Ans

wer

E; the ratios are not the same

/ 210


4 8

36

xx


(Answer) / 210


4 8

36

xx



Ans

wer

B

/ 210



4

3x

8

6

xE They are not similar

(Answer) / 210



4

3x

8

6

xE They are not similar


Ans

wer

D

4

3x

8

6

x

These are NOT similar

4

3x

8

6

x

These are similar

x

x

/ 210



(Answer) / 210




Ans

wer

C

/ 210



(Answer) / 210




Ans

wer

D

x x

x y

These are similar

These are NOT similar

/ 210



(Answer) / 210




Ans

wer

B

/ 210



A

B C

D ENote that BC is parallel to DE.

(Answer) / 210



A

B C

D ENote that BC is parallel to DE.


Ans

wer

A; using any 2 of the 3 angles marked in diagram

A

B C

D E

/ 210

A

B C

D E

Side Splitter Theorem

Any line parallel to a side of a triangle will form a triangle which is similar to the first triangle.

As we will learn later, it also makes all the sides proportional, splitting them...hence the name of the theorem.

/ 210

A

B C

D E

Proof of Side Splitter Theorem

Given: BC is parallel to DE

Prove: ΔABC ~ ΔADE.

/ 210

91 What is the reason for step 2?

A Angle-Angle Similarity TheoremB Side-Side-Side Similarity TheoremC Reflexive Property of Congruence D When two parallel lines are intersected by a transversal,

the corresponding angles are congruent.E When two parallel lines are intersected by a transversal,

the alternate interior angles are congruent.

A

B C

D E

Ans

wer

Statement Reason1 BC is parallel to DE Given2 ∠ABC ≅ ∠D; ∠ACB ≅ ∠E ?3 ∠A ≅ ∠A ?4 ΔABC ~ ΔADE ?

/ 210


A Angle-Angle Similarity TheoremB Side-Side-Side Similarity TheoremC Reflexive Property of Congruence D When two parallel lines are intersected by a transversal,



Ans

wer

A

B C

D E


/ 210


A Angle-Angle Similarity Theorem

B Side-Side-Side Similarity Theorem

C Reflexive Property of Congruence D When two parallel lines are intersected by a transversal,



A

B C

D E


Ans

wer

/ 210

Proof of Side Splitter Theorem

Given: BC is parallel to DE

Prove: ΔABC ~ ΔADE

A

B C

D EStatement Reason

1 BC is parallel to DE Given

2 ∠ABC ≅ ∠D; ∠ACB ≅ ∠EWhen two parallel lines are

intersected by a transvesal, the corresponding angles are congruent

3 ∠A ≅ ∠A Reflexive Property of Congruence

4 ΔABC ~ ΔADE Angle-Angle Similarity Theorem

/ 210

Similar triangles have the same shape, but can have different sizes. If they have the same shape and are the same size, they are congruent.

If they have the same shape and are different sizes, they are similar and their sides are in proportion.

A

B

C D

E

F


/ 210

The converse is also true, and will prove very useful.

If two triangles are similar, all of their corresponding sides are in proportion.

*While Euclid does prove this theorem, his proof relies on other theorems which would have to be proven first and would take us beyond the scope of this course. So, we'll just rely on this theorem and note that the proof is available in The Elements by Euclid - Book Six: Proposition 5.


/ 210

Similar Triangles and Proportionality

A

B

C D

E

F

In the triangles below, if we know that

m∠A = m∠D, m∠B = m∠E, and m∠C = m∠F,

then we know that the triangles are similar.

/ 210


A

B

C D

E

F

We also then know that the corresponding sides are proportional.

The symbol for proportional is the Greek letter, alpha: #

AB α DE, since AB corresponds to DEBC α EF, since BC corresponds to EFAC α DF, since AC corresponds to DF

/ 210

Corresponding Sides

A

B

C D

E

F

Our work with similar triangles and our future work with congruent triangles requires us to identify the corresponding sides.

One way to do that is to locate the sides opposite congruent angles. If we know triangles ABC and EDF are similar and that angle A is congruent to angle D, then the sides opposite A and D are in proportion: BC α EF

/ 210

Corresponding Sides

A

B

C D

E

F

Another way of identifying corresponding sides is to use Euclid's description "...those angles [are] equal which their corresponding sides subtend."

Below, since angle A is equal to angle D and angle B is equal to angle E, then sides AB and DE are in proportion.

/ 210

Corresponding Sides

A

B

C D

E

F

Either approach works; use the one you find easiest.

Identify corresponding sides as the sides connecting equal angles or the sides opposite equal angles...you'll get the same result.

/ 210


A

B

C D

E

F

Another way of saying two sides are proportional is to say that one is a scaled-up version of the other. If you multiply all the sides of one triangle by the same scale factor, k, you get the other triangle. In this case, if ΔABC is k times as big as ΔDEF, then: AB = kDE BC = kEF AC = kDF

/ 210


A

B

C D

E

F

Or, dividing the corresponding sides yields:

AB BC ACDE EF DF = k= =

This property of proportionality is very useful in solving problems using similar triangles, and provides the foundation for trigonometry.

/ 210

94 If m∠A = m∠D, m∠B = m∠E, and m∠C = m∠F, identify which side corresponds to side AB.

A DEB EFC FG

A

B

C D

E

F

(Answer) / 210

94 If m∠A = m∠D, m∠B = m∠E, and m∠C = m∠F, identify which side corresponds to side AB.

A DEB EFC FG

A

B

C D

E

F


Ans

wer

A

/ 210

95 If m∠I = m∠M, m∠H = m∠N, and m∠J = m∠L, identify which side corresponds to side IJ.

A MNB NLC ML

I

J

H

M

N

L

(Answer) / 210

95 If m∠I = m∠M, m∠H = m∠N, and m∠J = m∠L, identify which side corresponds to side IJ.

A MNB NLC ML

I

J

H

M

N

L


Ans

wer

C

/ 210

A

B

C8 D

E

F4

Example - Proportional Sides

Given that ΔABC is similar to ΔDEF, and given the indicated lengths, find the lengths AB and BC.

5 7

/ 210


Since the triangles are similar we know that the following relationship holds between all the corresponding sides.

First, let's find the constant of proportionality, k, by using the two sides for which we have values: AC and DF

AB BC ACED EF DF = k= =

A

B

C8 D

E

F4

5 7

/ 210

A

B

C

5 7

8 D

E

F4


AB BC ACED EF DF = k = 2= =

AC 8 DF 4= = k = 2

That means that the other two sides of ΔABC will also be twice as large as the corresponding sides of ΔDEF

/ 210

A

B

C

5 7

8 D

E

F4


AB ED = 2 BC

EF = 2

AB 5 = 2

AB = 10

BC 7 = 2

BC = 14

/ 210

96 Given that m∠A = m∠D, m∠B = m∠E, and m∠C = m∠F. If BC = 8, DE = 6, and AB = 4, EF = ?

A

B

C D

E

F

(Answer) / 210

96 Given that m∠A = m∠D, m∠B = m∠E, and m∠C = m∠F. If BC = 8, DE = 6, and AB = 4, EF = ?

A

B

C D

E

F


Ans

wer

4 6

8 x=

4x = 48 4 4x = 12 = EF

/ 210

97 Given that ΔJIH is similar to ΔLMN; find LM.

I

J

H

M

N

L

14

10

12

5

(Answer) / 210

97 Given that ΔJIH is similar to ΔLMN; find LM.

I

J

H

M

N

L

14

10

12

5


Ans

wer

12 x

10 5=

60 = 10x10 10x = 6 = LM

/ 210

98 Given that ΔJIH is similar to ΔLMN; find LN.

I

J

H

M

N

L

14

10

12

5

(Answer) / 210

98 Given that ΔJIH is similar to ΔLMN; find LN.

I

J

H

M

N

L

14

10

12

5


Ans

wer

14 x

10 5=

70 = 10x10 10x = 7 = LN

/ 210

99 Given that BC is parallel to DE and the given lengths, find DE.

A

B C

D E

8

64

(Answer) / 210

99 Given that BC is parallel to DE and the given lengths, find DE.

A

B C

D E

8

64


Ans

wer

8 12

6 x=

8x = 72 8 8x = 9 = DE

/ 210

100 Given that BC is parallel to DE and the given lengths, find DB.

A

B C

D E9

7

3

(Answer) / 210

100 Given that BC is parallel to DE and the given lengths, find DB.

A

B C

D E9

7

3[This object is a pull tab]

Ans

wer

3 9

7 x=

3x = 63 3 3x = 21 = ADBD + 7 = 21BD = 14

/ 210

Example - Similarity & Proportional Sides

D

P

K

12

9

18

R

L

B6

1210

Determine if the triangles are similar. If they are similar write a similarity statement. If they are not similar, explain why.

/ 210


D

P

K

12

9

18

R

L

B6

1210

To identify the corresponding sides without wasting a lot of time, first list all the sides from shortest to longest of both triangles and compare to see if they are all proportional.

Then you can identify corresponding sides and the constant of proportionality.

/ 210


D

P

K

15

9

18

R

L

B6

1210

Side of ΔPDK Length Side of ΔBRL Length Ratio

DK 9 BR 6 1.5

PD 15 RL 10 1.5

PK 18 BL 12 1.5

All corresponding sides are in the ratio of 1.5:1, so the triangles are similar.

This also provides the order of the sides, so we can say that ΔKDP is similar to ΔBRL. Check to make sure that all the sides are in the correct order.

/ 210

101 If these triangles are similar, enter the constant of proportionality, k, between the larger and smaller triangle. If they are not, enter zero.

D

P

K

12

9

18

R

L

B6

1210

(Answer) / 210


D

P

K

12

9

18

R

L

B6

1210


Ans

wer

DK = 9PD = 12PK = 18

BR = 6RL = 10BL = 12

9 6

12 5≠

Not similar; 0

/ 210


52°

1

2

3

R

S

T

52°24

6X

Y

Z

(Answer) / 210


52°

1

2

3

R

S

T

52°24

6X

Y

Z


Ans

wer

RS = 1RT = 2ST = 3

YZ = 2YX = 4ZX = 6

1 2

2 4

3 6= =

1/2 = 0.5 = k

/ 210


P

R

S

3 4.2

6B

C

D

2 2.8

4

(Answer) / 210


P

R

S

3 4.2

6B

C

D

2 2.8

4


Ans

wer

PR = 3RS = 4.2PS = 6

BC = 2CD = 2.8BD = 4

3 2

4.22.8

6 4= =

3/2 = 1.5 = k

/ 210

A

B C

D E

Converse of Side Splitter Theorem

If a line divides the two sides of a triangle proportionally, then the line is parallel to the third side.

/ 210

104 Find the value of x to prove that AB is parallel to ER.

27

x

18 12R

EA

B

D

(Answer) / 210

104 Find the value of x to prove that AB is parallel to ER.

27

x

18 12R

EA

B

D [This object is a pull tab]

Ans

wer

2718

x 12=

324 = 18x 18 18 x = 18

/ 210

105 Find the value of x to prove that FC is parallel to MN.

J

M

NC

F

x 9

6

8

(Answer) / 210

105 Find the value of x to prove that FC is parallel to MN.

J

M

NC

F

x 9

6

8


Ans

wer

8 6

9 x=

8x = 54x 8 8 x = 6.75

/ 210

106 Find the value of y.

6

1012

y

(Answer) / 210


6

1012

y


Ans

wer

12 y

10 6=

72 = 10y10 10 y = 7.2

/ 210


4

14 12

y

(Answer) / 210


4

14 12

y


Ans

wer

14 y

12 4=

56 = 12y12 12 x = 4.6

/ 210


2415y

6

(Answer) / 210


2415y

6


Ans

wer

2124

15 y=

360 = 21y 21 21 x 17.1

/ 210

Questions from Released

PARCC Test


page2svg

/ 210

Question 1/7

/ 210

109 The figure ΔABC ~ ΔDEF with side lengths as indicated. What is the value of x?

F

D

E

95

7

C

BA

27

21

x

(Answer) / 210

109 The figure ΔABC ~ ΔDEF with side lengths as indicated. What is the value of x?

F

D

E

95

7

C

BA

27

21

x


Ans

wer

5 x

9 27 =

9x = 135

5 x

7 21 =

7x = 105OR

x = 15

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