INTERCONTINENTAL HOTELS GROUP (IHG) - DESIGN & DEVELOPMENT EUROPE - Article in Sleeper Magazine
Sleeper design
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Input val or e u. d. m. vertical load VL 20.00 kN longitudinal load LL 0.00 kN cross load TL 0.00 kN longitudinal moment LM 0.00 kNm cross moment TM 0.00 kNm slab lenght L 1.2 m slab width B 2 m foundation height H 1.189 m bottom thick S b 0.3 m wall thick S w 0.3 m over-soil support height Δh 0. 28 9 m concrete weight γ cls 25 kN/mc lean concrete thickness t l 0.1 0 m lean concrete overhang s l 0.10 m lean concrete specific weigth γ l 24 kN/m 3 lean concrete weight P l = t l ( L + 2 s l ) ( B + 2 s l ) γ l = 7.39 kN Geotechnical input water weight γ w 10 kN/mc soil weight γ s 19 kN/mc soil internal friction angle φ 15 .0 0 ° drained shear strength c' 0.00 kN/m 2 undrained shear strength S u = c u 15.00 kN/m 2 friction coefficient soil/concrete ξ = 2/3 tan φ = 0.18 < 0.45 elastic modulus E 1.50 N/mm 2 slab depth D = H - ΔH = 0.90 m concrete volume V cls = [ L · s b + ( H - s b ) s w ] B = 1.25mc soil volume V s = ( L - s w ) ( D - s b ) B = 1.08 mc concrete weight P cls = γ cls · V cls = 31 kN soil weight P s = γ s · V s = 21 kN total vertical load P = P cls + P l + VL + P s = 79 kN Sliding check sliding safety factor s s 2 stabilizing force H = P cls ξ = 5. 60 kN security check H / TL = 5597.46> s s verified H / LL = 5597.46 > s s verified stabilizing force H = c u A = 36.00 kN security check H / TL = ####### > s s verified H / LL = ####### > s s verified Overturning check overtuning safety factor s o 2 stabilizing moment M stab = P cls L / 2 = 18.80 kNm overtujning moment M overt = LL · H + LM = 0.00 kNm security check M stab / M overt = 8588.85 > h verified stabilizing moment M stab = P cls · B / 2 = 31.34 kNm overtujning moment M overt = TL · H + TM = 0.00 kNm security check M stab / M overt = ####### > s o verified Allowable soil bearing pressure check pressure safety factor s p 2 horizontal load resultant H = ( LL 2 + TL 2 ) 1/2 0. 00 kN horizontal load angle cos θ = LL / H = 0.71 horizontal load angle sen θ = TL / H = 0.71 eccentricity e' y = ( LM + LL H ) / P = 0.00 m e' x = ( TM + TL H ) / P = 0.00 m reduced width B' = B - 2 e' x = 2.00 m reduced length L' = L - 2 e' y = 1.20 m G e o m e t r y L e a n c o n c r e t e L o a d d r a i n e d c h e c k D i r X D i r Y u n d r a i n e d c h e c k s b LL t l sl
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