Skema Set 1 P2 - Megatech Internationalmegatech.edu.my/.../FIZIK-SET-1-KERTAS-2-JAWAPAN.pdf ·...
Transcript of Skema Set 1 P2 - Megatech Internationalmegatech.edu.my/.../FIZIK-SET-1-KERTAS-2-JAWAPAN.pdf ·...
Skema Set 1 P2
SECTION A
Question 1 Part Mark Answer Note
(a)
(b)(i)
(b)(ii)
(c)
1
1
1
1
Name the container X correctly Lead container / concrete container
Underlining thee correct phrase in the box correctly
a beta particle
Give the reason correctly
Negatively charge
Give the reason correctly
The mass of ray P < ray Q // The speed f ray P > ray Q
Total 4
Question 2
Question 3
Section Marks Answer Catatan
(a) 1 There is no net flow of heat between two objects and
they have same temperature
(b) 1 45 0C
(c) 1
1
The heat from block P transfer to the water
Until the rate of heat transfer between P and water
become equal
(d)
1
1
E = mcӨ
= 0.3 x 900 x 55
= 14 850 J
6
marks
Question 4 No 4
4 a)
1M
1M
v = 5 x 0.8
= 4 ms -1
4 b) 1M
1M
The wave are circular
Wavelength remains unchanged
4 c) 1M Diffraction
No 2
2 a)
1M Quantity matters in a material //An object at rest tends to
remain at rest // an object in motion tends to stay in motion
2 b) 1M The car
2 c) 1M Mass // Inertia is smaller
2 d) 1M
1M
v2 = u
2 + 2as
02 = 15
2 + 2a(375)
- 0.3 ms -2
Skema Set 1 P2
4 d) 1M
1M
Waves pass through an aperture or round a small obstacle
Waves spread out.
Question 5
Q 5 / S 5
(a)(i) 1 Density is the mass per volume
(b)(i)
(ii)
(iii)
1
1
1
Level of the boat is higher in the sea than in the river.
Water displaced in the sea is less than in the river.
Density of sea water is higher than river water.
(c)(i)
(ii)
1
1
The lower the density of water, the greater /higher the
volume of water displaced.
Weight of the boat = Weight of the water displaced
(d) 1 Archimedes’ principle // Bouyancy’s law
(e) 1
2
Ballast tank filled by sea water
Weight of submarine > upthrust
Maximum
1 mark
(Any one
mark)
Tot/Jum : 8
QUESTION 6
Part Mark Answer Note
(a)
(b)
(c)
(c)
(d)
1
1
1
1
1
1
1
1
Name the current I1 correctly Base current
Name the current I2 correctly
Collector current
State two observations correctly
I1 < I2 // I1 = 0 and I2 = 0
The small changing of I1 give the large changing of I2 or I1 is directly
proportional to I2
Give the reason correctly
The mass of ray P < ray Q // The speed f ray P > ray Q
Complete the circuit correctly
The two resistors in series
One of the resistor in base circuit
State the correct function of the two resistors
As the voltage divider
Total 8
Skema Set 1 P2
QUESTION 7
Part Mark Answer Note
(a)(i)
(a)(ii)
(a)(iii)
(b)(i)
1
1
1
1
1
Complete the ray diagram in Diagram 7.2 correctly
Two reflected rays are shown (diagram)
Angle of incidence = Angle of reflection (diagram)
State the phenomenon involved correctly
Reflection
State the problem that happens correctly
The driver in car P cannot see car Q // field of view very small
Name the curve mirror correctly
Convex mirror
Skema Set 1 P2
Part Mark Answer Note
(b)(ii)
(b)(iii)
(a)(iii)
(b)(i)
(c)(i)
(c)(ii)
1
1
1
1
1
1
1
Complete the ray diagram in Diagram 7.3 correctly
Two reflected rays are shown (diagram)
Angle of incidence = Angle of reflection (diagram)
State the solution of the problem in (a) (iii) correctly
The convex mirror increase the field of view
State the problem that happens correctly
The driver in car P cannot see car Q // field of view very small
Name the curve mirror correctly
Convex mirror
Give the correct answer
Unchanged
Give the reason correctly
The characteristics of image of a convex mirror not depends on the focal
length
Skema Set 1 P2
Total 10
Question 8
Bhg Markah Jawapan Catatan
(a) 1 Isotope that are not stable
Isotop yang nukleusnya tidak stabil
(b) 1
1
D
The reading of ratemeter is highest
Bacaan meter kadar paling tinggi
(c) (i) 1
1
226
88 Ra 222
86 Rn + 4
2 He
Symbol alfa betul - 1
Persamaan seimbang
-1
(c) (ii) 1
1
1
1
100% → 50% → 25% → 12.5%
Sodium-24 : 3T = 45
T = 15 hours
Cobalt-60 : T = 15.9/3 = 5.3 years
Radium-226 : T = 4860/3 = 1620 years
(d) 1
1
1
Sodium-24
Half life is short @ activity decreases faster
Setengah hayat pendek @ keaktifan cepat
berkurang
Emmits beta rays @ can penetrate ground but
can’t penetrate pipe
Memancarkan sinar beta @ boleh menembusi
tanah tetapi tidak boleh menembusi paip
Skema Set 1 P2
12 markah
SECTION B
Question 9
Bhgn. Markah Jawapan Catatan
Soalan 9
(a)(i)
(ii)
1
1
1
1
1
1
Area per unit square // P = F / A
200 / 0.2
= 1000 N m-2
800 / 0.8
= 1000 N m-2
Pressure at P = Q =R
Force is directly proportional to the surface area
Define symbols used
With unit
Accept without unit
(b) 1
1
1
1
Pressure is applied to the toothpaste (tube)
The toothpaste carry and apply the pressure of the
equal magnitude to the whole tube
Pascal’s Principle
(c)
1,2
3,4
modification explanation
piston of bigger cross-
sectional area
Can support greater
force (weight)
Low density material Lightweight // easy to
carry
Accept any
reasonable
Skema Set 1 P2
5,6
7,8
9,10
Non-compressible
liquid
Piston can be lifted up
Longer handle Less effort needed to
press the small piston
Apply released valve
between small and
main reservoir
Liquid can flows into
small reservoir
modification
Question 10
Q10/S10
Sect. Mark
(a)(i)
(b)
1
6
1 State the definition of current correctly
The rate of charge flows.
1 State the correct comparison of the type of circuit connection
Diagram 10.1 connected in series and Diagram 10.2 connected in parallel.
2 State the correct comparison of the ammeters reading
The reading of ammeter in Diagram 10.2 is greater than in Diagram 10.1.
3 State the correct comparison of the voltmeters readings
The reading of voltmeter in Diagram 10.1 > Diagram 10.2.
4 State the correct comparison of the effective resistance
The effective resistance in Diagram 10.2 < Diagram 10.1.
5 State the correct relation between the effective resistance and the current flows Effective resistance increases, the current flows decreases.
6 State the correct relation between type of circuit connection and effective
resistance.
Circuit connected in parallel, the effective resistance decreases.
(c) 3 1 State the correct happens of the ammeter reading
The ammeter reading increased
2 State the correct happens of voltmeter reading
The voltmeter reading decreased.
Skema Set 1 P2
3 State the correct reason
Effective resistance in the circuit decreased.
(d) 10
State the correct extra device attached and correct reason
1 Attach one fuse to the live wire in the consumer unit/ fuse box.
2 To break/switch off the circuit when large current before the wire become
hotter and produce fire.
State the correct choosing of wire/cable and correct reason
3 Using the insulating wires // thicker wires
4 To prevent short circuit // To reduce resistance, improve efficiency.
State the correct adjustment of each lamp and the correct reason
5 Attach switch for each lamp.
6 To allows each lamp to be switched on and off independently.
State the correct modification of connection of metal fitting lamp and give the
correct reason
7 Connect the metal fitting lamp to the earth wire/cable.
8 To flows electron (extra) to earth to avoid lethal shock.
State the correct using of bulbs and give the correct reason
9 Using only 240 V light bulb.
10 To ensure the bulbs light up with normal brightness.
Total : 20
SECTION C Question 11
Bhg Mrk Jawapan Catatan
Soalan 11
(a) 1 Aerofoil / airfoil
(b)
(i)
( ii )
1
2
3
1
The shape of cross section of the wing causes the speed of
airflow
Above the wings to be higher than the speed of airflow
below
When the speed of moving air is higher ,the pressure is
lower
Hence air pressure below the wings is higher compare to
above the wings
Bernoulli’s principle
Skema Set 1 P2
( c) 1
2
3
4
5
6
7
8
9
10
A shape of cross section which is upper side is longer than
the bottom
To produced the speed of airflow Above the wings to be
higher than the speed of airflow below
The larger the area of the wing
The larger the lift force
The less density of the wing materials
Less weight // produce more upward resultant force
The higher the difference in speed of air
The higher the difference in pressure
The most suitable choice is P
Because it has
A shape of cross section which is upper side is longer than
the bottom
The larger the area of the wing
The less density of the wing materials
The higher the difference in speed of air
(d)(i)
(ii)
(iii)
1
2
1
2
1
P= F/A
F=PA
F=500 x 40
F = 20000N
Resultant force = 20000 – 900(9.8)
= 11180N
Upward
F =ma
a=F/m
a=12.42ms-2
Total 20
Question 12
Section Mark Answer
12(a) 1 Electric to sound
(b) 1
1
1
1
Current flows and soft iron core is magnetised
Hammer hit the gong
Contacts open
Soft iron core loses its magnetism
(c) 1
1
1
1
1
Size of the hammer is big
Surface area contact is big
Larger distance between the hammer and the gong
The force applied on the gong is greater
The number of turns of the coil is greater
Skema Set 1 P2
1
1
1
1
1
The strength of the magnetism is greater
High curvature of the gong
The area of air molecule vibrate is greater
Q
Size of the hammer is big, Larger distance between
the hammer and the gong, The number of turns of
the coil is greater, High curvature of the gong
(d)(i)
1
1
I =12
10
0.83 A (with unit)
(ii)
1
1
1
PI = 10080
10x
= 12.5 W
I = 240
5.12/ 0.052 A (accept e.c.f)
TOTAL 20 M
section A
1 (a) (i) Refractive index, type of transparent material / n 1
(ii) Refracted angle / r 1
(iii) Incident angle/ i 1
(b) n r /
0 sin r
rsin
1
1.49 19.0 0.3256 3.07
1.92 16.5 0.2840 3.52
2.42 12.5 0.2164 4.62
2.91 10.0 0.1736 5.76
3.50 7.5 0.1305 7.66
Skema Set 1 P2
1. columns n , r , sin r, rsin
1
2. all the units of n , r , sin r, rsin
1are correct
3. all the value of r +/ - 0.5 0
4. Value of r , constant at 1 decimal place
5 Value of sin r , constant at 4 decimal places
6. Value of rsin
1 constant at 2 decimal places
7. All the value of r ,sin r, rsin
1are correct
7
(c) score
1. n at y-axis and rsin
1 at x-axis
2. the units at both axis is correct
3. both axis has initial scale and not ganjil
4. 5 points ploted are correct
5. 3 points plotted are correct
6. smooth line
7. the minimum size is 5 x 4 ( from origin to the last point)
score marks
7 5
5-6 4
3-4 3
2 2
1 1
5 (d) Directly proportional 1
Total 16
2 (a) Straight line from I= 0.40 A
Straight line to Y axis at V = 0.74
0.72 V (with unit)
1
1
1
(b) increase 1
(c) constant 1
(d) (i)
Show a triangle (enough size)
Substitution
1st
2nd
Skema Set 1 P2
(ii)
0.60
0.88
r= 0.68Ω
E = V + Ir
= .0.72 + 0.4 X 0.68 ( V = 0.72V and I =0.68 A)
= 0.9921 V ( 4 decimal point)
3rd
1st &2
nd
3rd
(e) eye position must be perpendicular to scale of ammeter/voltmeter./
The connection must tied
1
Total 12
Section B
Question
Soalan
Answer
Jawapan
Marks
Markah
3. (a)
(b)
(c) (i)
(ii)
State a suitable inference
Acceleration is influenced by the mass
1
State a relevant hypothesis
When the mass increased, the acceleration will be decreased.
1
State the aim of experiment
To investigate the relationship between the acceleration and the mass.
1
State the suitable manipulated variables and responding variable
(Quantity that can be measured)
Manipulated variable : mass
Responding variable : acceleration
1
Skema Set 1 P2
(iii)
(iv)
(v)
State the constant variable
Force applied
1
State the complete list of apparatus and materials
5 Trolleys, ticker timer, ticker tape, a rubber band, a wooden runway,
12 V a.c power supply.
1
Draw the functional arrangement of the apparatus
Trolley rubber band
Ticker
Timer
Ticker tape
Friction compensated runway
Power supply
1
State the method to control the manipulated variable
The apparatus is set up as shown in the diagram.
The ticker-timer is switched on and a trolley is pulled using a rubber
band. The extension of the rubber band is ensured to be of the same
length
1
State the method to measure the responding variable
Acceleration of the trolley is calculated using the ticker-tape , a = ( v-u
) / t
1
Repeat the experiment at least 4 times with the values
Procedure 2 and Procedure 3 are repeated using 2, 3, 4 and 5 trolleys.
(Note : Based on SPM standard , at least five manipulated values
required.)
1
State how the data tabulated with the title MV and RV
Mass / num. of trolley acceleration / cm s-2
1
2
3
4
5
1
State how the data is analysed, plot a graph RV against MV
acceleration / cm s-2
Mass / num. of trolley
1
Total
12
Question
Soalan
Answer
Jawapan
Marks
Markah
4. (a)
(b)
Inference
The rotation speed of the motor influeced on number of battery
1
Hypothesis
If the current increase , then the speed of rotation increase.
1
Aim
To investigate the relationship between the current and distance/speed
1
Skema Set 1 P2
(c) (i)
(ii)
(iii)
Variables
manipulated :current
responding : distance of the rode fixed :strength of magnet/ rod mass
1
1
List of apparatus and materials
2 bar magnet ,iron rod,batteries,ammeter, metere rule
1
Arrangement of the apparatus
1
(iv)
(v)
Procedure of the experiment which include the method
of controlling the manipulated variable and the method of
measuring the responding variable.
The current 0.5 A record from the ammeter. Measured the distance of rod movement .
The experiment is repeated 4 times with the difference current, I = 1.0
A ,
1.2 A, 1.4A ,1.6A and 1.8A
1
1
1
(vi) Tabulate the data
Current,I/A 0.5 1.0 1.2 1.4 1.6 1.8
Distance of the rod/cm
1
(vii) Analyse the data
Distance/cm
Current,I/A
1
Total 12