SKEMA 7th Tips Physics SPM Success Modul Teknik Menjawab Kertas 2 Dan 3

7/29/2019 SKEMA 7th Tips Physics SPM Success Modul Teknik Menjawab Kertas 2 Dan 3

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SKEMA JAWAPAN MODUL TEMBAK 32 VERSION 4

NO KNOWLEDGE MARKS

1

Elasticity is the property of a substance which enables it toreturn to original shape @ size @ length after an appliedexternal force ( compressive force or stretching force) is

1

2

Electromagnet is a device in which magnetism is produced by anelectric current // temporary magnet made by winding a coilround a soft iron core and magnetic field produce when current

1

3

A phenomenon when light travel in different medium withdifferent densities change in speed and direction // the bendingof light when travelling through different medium

1

4

Thermal equilibrium states that the net rate of heat flow fromone medium to another medium and vice versa is zero//temperature for both medium is the same.

1

5

Density/depth/acceleration due to gravity

1MENGKONSEPSI

1

Current flow in diagram 10.2 is more than 10.1 // vice versa. The amount of iron filing attracted by iron core in Diagram 10.2

is more than 10.1 // vv. The magnetic strength in diagram 10.2 is more than 10.1 // vice

versa. Amount of iron filing attracted increase when current increase The ma netic field stren th increase when current increase

5

2

The refractive index of A < the refractive index of B The refracted angle of medium A > refracted angle of medium B

The density of medium A < density of medium B The greater the refractive index the smaller the angle of

refraction

5

3

Diagram 10.1, the p end of diode is connected to negativeterminal of dry cell // Diagram 10.2 the p end of diode isconnected to positive terminal of dry cell

Bulb in Diagram 10.1 does not lights up No current flow in Diagram 10.1 // Current flow in Diagram 10.2 The bulb will lights up when the p end of diode is connected to

the positive terminal of dry cell // vice versa Current only flow in the circuit when p end of diode is

connected to positive terminal of dry cell or in forward bias

5

UNDERSTANDING

1

A soft ball has a high velocity. A soft ball has a high momentum. The soft ball player move his hand backward to increase time

impact. The higher the time impact will reduce impulsive force. So we will not feel hurt.

4

2

the strong wind above the roof is moving very fast. While the air in the house is at rest. According Bernoulli's principle the higher the velocity the lower

the pressure. So, the pressure above the roof is smaller than pressure inside

the house.

4


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3

When the coil rotates the coil cut across the magnetic fieldlines

Induced current flow in the coil. The current maximum when the coil cut the magnetic field at

right angle // current decreased (become zero) when the coilmove in parallel with magnetic field lines

The direction of current flow determine by using Flemings

right hand rule After 90o the direction of current in the external circuit

4

PROBLEM SOLVING QUALITATIVE

1

ASPECT EXPLANATION

Bigger size of sailProduce bigger different inpressureEasy to cut air resistance

Supporting cable made bysteel wire

not easily breakincrease strength and rigidity

Low densityLighter

Least upward lift is neededWaterproof

Not absorbwater

Hinged structureGlider can easily assembleand folded up fortransportation.

Structure from rigid Lighter

10

2

Aspect ExplanationUse oil Incompressible/no air buble

High boiling point/low

density

Does not evaporate easily/lighter

Small Master piston To produce high pressureBig slave piston To produce a big force on the disc

Aluminium/steel for

tansmision pipe

Strong/does not rust easily

10

3

10

2

DESIGN EXPLANATION

Aerodynamic shape To reduce air resistance

Heat shield / material that is hardto burn

To protect the capsule

High melting point //ceramic Do not melt

Landing in water // air bag Increase time of impact//Reduce impulsive force

Light material / / small mass //low density

-Reduce the inertia //-reduce the momentum //-reduce impuls

Paracute / /Retro rocket To reduce speed

Hard material // stiff composite Not easy to bend


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APLICATION QUANTITATIVE

1

-Atmospheric pressure at both side is equal

-Pressure does not depends on size of arm

Patm + h1y g = P atm + h2x g

( 10 x 10-2

) ( 1 200 ) ( 10 ) = ( 16 x10-2

) ( x ) ( 10 ) x = 750 kgm

-3

1

1

1

11

2

(b)(i) 12V(ii) Eff = Output Power x

10%Input Power

Output Power = 24 x 2= 48 W

Input Power = VI=240 x 2

= 120 W= 48 X 100

120= 40 %

5

SOALAN MAKING DESISION

1

characteristics reasonMade of concrete Stronger / Not easy to break

// metal can rust easilylow density lighter / the structure that hold

the tank able to withstand the

weight of tankthicker wall at the bottom //

Diagram

able to withstand the higher

pressure at the bottomheight from ground is high to produce a greater difference in

pressureR is chosen Made of concrete, low density,

thicker wall at the bottom, height

from ground is high

10

3


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2

characteristics reason

High specific heat capacity Heats up slowly / store more heat

High boiling point Slow to turn into vapour/volume of

liquid decreases slowlyBig fan Sucked a lot of air

A large number of finblades

Increases surface area/releases heatfaster.

Choose R High specific heat capacity, Highboiling point , Big fan, large numberof fin blades

10

3

Properties Explanation

Low specific heat capacity Easily to be hot

High melting point Can sustain high temperature

Low density lighter

Low rate or rusty So that it do not rust

S is chosen Because of low specific heat capaity,high melting point, low density andlow rate of rusty.

10

SOALAN STRUKTUR

Soalan Menkonsepsi 1 Marks

(a)(i) Mass per volume 1

(a) Density of water > oil 1

(b) d1 > d2 1

(b)(iii) Pressure of water > oil // water > oil 1

(c) The higher the density the higher the pressure//As the density

increases the pressure increases

1

(d) The deeper the water the higher the pressureThe pressure in the tank > in the house (in the tap)The difference pressure produce force to flow the water

3

TOTAL 8

Soalan Modification 17 (a) North pole 1 1(b) 1. Increase the number of turns of coil

2. Increase magnitude of current / reduce resistance in therheostat

2

(c) (i) 1. Soft iron rod is attracted to the coils

2. Bar magnet pushed away

2

(ii) 1. X becomes South pole and still attract the iron rod2. Y becomes North pole / same pole as the bar magnet / force ofrepulsion

2

4


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(d) (i) Iron rod is still attracted to the coil 1 1(ii) Bar magnet will oscillate/ vibrate 1 1(e) Relay switch // electric bell etc 1 1

TOTAL 10Soalan Making Dicision 1

8 (a) The power of device is the rate of which it transfers energy 1(b) Electrical energy to light energy and heat energy 2

(c)(i) Heat energy 1(ii) Filament bulb :

- 11.25 x 100 %75 = 15 %

Energy saver bulb :- 10 x 100 %

20 =50 %

4

(iii) Energy saver bulbHigh efficiency // less wasted energy

2

(d) Refrigerator or any other appliancesChoose frost-free refrigerator // not allow frost to accumulate too

thick in the freezer // close the door tightly

2

TOTAL 12

KERTAS 3

Question 1

Marks

Answer

(a)(i) 1 Stating the correct manipulatedvariable.Length of wire// l

(ii) 1 Stating the correct respondingvariable.Potential difference// Voltage// V

(iii) 1 Stating a correct fixed variable.Thickness of wire// resistivity of wire//type of wire

Tabulating results of the experiment (5 marks)1. Labels l and V are shown2. Correct unit for l and V3. All readings ofl are correct to one decimal place

4. Minimum 3 correct readings for V to 1 or 2 decimal place5. All readings of V are correct to 1 decimal place

Length,l /cm

Potentiakl diffr,V/V

20.0 0.4 or 0.40

40.0 0.9 or 0.90

60.0 1.2 or 1.20

80.0 1.6 or 1.60

100.0 1.9 or 1.90

5


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Plotting the l against V graph (5 marks)

1 A. V on the y-axis and l on the x-axis.2 B. Units stated for both l and V correctly3 C. The scales on both axes are regular and not an odd scale.4 D. 5 points plotted correctly from table(reading is wrong, plotting from tablecorrect, mark can be given)

5 E. 3 points plotted correctly from table.6 F. Line of best fit.7 G. Graph size a minImum of 54 (5 boxes on y-axis, 4 boxes on x-axis).

(d) 1

Stating the correctrelationshipV is directly proportional to l// V l

(e)(i)(ii)

11

Voltmeter reading decreaseResistance decrease

Question 2

Marks Answer

(a)(i) 1 h is directly proportional to t2 // h t2

(ii) 111

1. Show on graph with appropriate vertical and/or horizontal line corresponding to 44 cm

2. t2 = 0.0883. t = (0.29 -0.30) s

6


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(b) 3 1. Drawing the gradient triangle Triangle size a minimumof 8ver x 8 hor of cm2. Substitution (values from students triangle)3. Answer with correct unit 500 cms-2

(c) (i) (ii) 13

u = 0 ms -11. Show that h = 1/2g t22. Substitution of the gradient g = 500

3. Answer with correct unit. 1000 cms-2 or 10 ms-2

(c) 1 When measuring the values of h, make sure the eyes areperpendicular to the scale on the metre rule to avoidparallax error.

JUMLAH 12

Contoh Set 1Marking Scheme Paper 3 Physics Mid Year SBP 2007

Question

Marks

Marking Scheme

1 a(i)

1 State the manipulated variable correctly ;The distance object

(ii) 1 State the responding variable correctly ;The image distance

(iii) 1 State one fixed variable;The focal length

b1

1

1

1

1

1

Tabulate ,u, v,u

1and

v

1correctly in the table.

A Shows a table which have u, v,u

1and

v

1

B State the correct unit of u/cm, v/cm,u

1/cm-1 and

v

1

/cm-1C All values of v are correct

D Values ofu

1are correct

E Values ofv

1are correct

F All values of are consistent

7

Objectdistance,u, (cm)

Image distance,v, (cm)

u

1,

(cm-1)v

1, (cm-

1)40 24.2 0.025 0.04235 26.3 0.029 0.03830 30.0 0.033 0.03325 37.5 0.040 0.02720 60.0 0.050 0.017


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(c)Draw the graph of Wagainst h.A - Label y-axis and x-axis correctlyB - States the unit at the axis correctlyC - Both axes with the even and uniform scale:D - 5 points correctly plotted:

E - a smooth best straight lineF - minimum size of the graph is 5 x 4Squares of 2 x 2 cm:

d 1 State the correct relationship based on thecandidates graph ( negative gradient striaght

linegraph)

v

1decrease linearly to

u

1

e 1 State ONE correct precaution so as to produce anaccurate result of the experiment

The position of the eye perpendicular when takes thereading to avoid errors due to parallax/systematic error

8

Number of Score6 55 43-4 3

2 21 1


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Total 16 Marks

SOALAN 1 QUESTION 2NO Marking Scheme MARKS

2(a)

2(b) (i)

2(b)(ii )

2(c)

2(d)(i )

2(d)(ii)

2(e)

Show on the graphState the value ofPatm correctly1.06 x 105 Nm-2

Draw the triangle on the graph(minimum 8cm x 8cm)Show the substitution correctlyCorrect answer[1.30 x105 - 1.35 x105 ]Correct unit.Nm-3

Correct answer[1560 - 1620 ]

Show on the graphState the value with the correct unit1.6 x105 Nm-2

State the changes correctlykwill increase

Give the correct explanationThe pressure exerted by the liquid increases

State the precaution correctlyThe position of Eyes is perpendicular to the scale of readingas to avoid parallax error // Repeate experiment twices and

find the average to increase the accuracy

2

4

1

2

1

1

1

Question 2

Section Mark Marking scheme

(a)(i)(ii)

(iii)

12

1

V decreases linearly with IExtrapolate the graph3.5 VElectromotive forcelle.m.f//d.g.e.

B (ii) 1

1

Draw a sufficient large triangle (minimum size is 8cm x 8 cm) * Correct substitution(follow candidate'striangle)

1.5 -3.51.2

-0(b) I

1Show the vertical line from 1 0,60 A until touch the graphthen horizontal line until it touches he V-axis

V 2.5 V

(c) I1

E = I(R+r)3.5 = 0.6(R+1.67 ) R=4.16

(d) 1 -Repeat the experiment and take average//-switch of the circuit when not taking any reading/!-Eye position must be perpendicular to scale of meter ruler

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total 12

Section B (12 marks)Soalan 1

Inference :The size of the gas bubble depends on the depth of the water.Hypothesis:

The smaller the pressure, the larger is the volume of a fixed mass of gas.Aim :

To investigate the relationship between the pressure and volume for a fixed mass ofgas at a constant temperature.Variables :

Manipulated : Gas volume, VResponding : Gas pressure, PFixed : Gas temperature,T or massof gas, m

Apparatus : Glass syringe, a short rubber tube and Bourdon gaugeArrangement of apparatus: must label

Procedure:1. The apparatus is set up as shown in the diagram above.

2. The piston of the syringe is adjusted until the volume of air in the syringe is 100 cm3at atmospheric pressure.3. The syringe is connected to a Bourdon gauge and the pressure of the air in thesyringe is observed and recorded.4. The piston is then pushed in so that the volume of air trapped is 90 cm3. Thepressure is again recorded, this procedure is repeated for enclosed volumes of 80cm3,70 cm3 and 60 cm3.

Tabulating data

Volume, V/cm3 Pressure, P/Pa10090807060

Analysing data

10

P/Pa

V/cm3


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Soalan 2/6

Inference: the strength of electromagnetism depends on the current in the coil.

Hypothesis: The larger the current in the coil, the stronger the strength ofelectromagnetism

Aim:To study the relationship between the size of current carried by the coil and thestrength of electromagnetism.

Variable:Manipulated variable: current, IResponding variable: strength of electromagnetism (number of pins collected)Fixed variable: no of turns

Apparatus : pins, soft iron rod, insulated copper wire, connecting wires. Powersupply, ammeter, rheostat , switch, retort stand with clamp.

Arrangment of Apparatus

Procedure:1.The switch is closed and the power supply is switched on . The rheostat is adjustedto obtain the current, I = 0.5 A.2. The no of pins attracted to soft iron rod is counted.3. The values of current I is repeated with I = 1.0A,1.5A, 2.0A and 2.5A

Tabulating data

Current,I/A No pin attract,N0.5

1.01.52.02.5

Analysing data

Soalan 3/7Inference: The buoyont force depent on the volume of an object

Hypothesis: The higher the volume(or depth of iron bar/surface area)the higher the buoyant force

11

N

I/A


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Aim of experiment : To investigate the relationship between volumeand buoyant force

Variables in the experiment:Manipulated variable:VolumeResponding variable:Reading of the spring balance(BF)Fixed/ constant variables:Volume of the water

List of apparatus and materials: Measuring cylinder, a metal rod,spring balance and metre rule, beaker, water, retord stand

Arrangement of apparatus

Procedure1. The meter rule was clipped to the retort stand beside of the ironbar.2. The volume of the iron bar is set at h = 20.0 cm33. The reading of the spring balance is recorded.4. Step 2 and 3 is repeated for the height, h= 25.0 cm, 30.0 cm, 35.0cm and 40.0 cm. Tabulation of data

Tabulating data Analysing data

Volume,V/cm3 Weight, W/N0.51.01.52.02.5

Soalan 8

(a) InferenceThe distances between two consecutive bright fringes depends on the

wavelength of light

1

(b) HypothesisThe higher the wavelength the higher the distance between twoconsecutives bright fringes

1

(c)(i)

AimTo investigate the relationship between the wavelength and thedistances between two consecutives bright fringes.

1

(ii) Variablesa)manipulated : Wavelength of light/colour of lightb)responding : distances between two consecutive bright fringesc)fixed : distance of slit,

1

1

(iii)

List of apparatus and materialsSource of light, colour filter, screen, single slit, double slit and metrerule

1

(iv)

Arrangement of the apparatus 1

12

V/cm3

W/N


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(v) Procedure of the experiment which include the method ofcontrolling the manipulated variable and the method ofmeasuring the responding variable.1) A green (suppose value) filter is placed between the light source

and the slits.The source of light is switched on.2) The distance between two consecutive bright fringes is measured

by using meter ruler3) The experiment is repeated 5 times for with different colour filters ;

red, yellow, blue and violet (state the value)

1

1

1

(vi) Tabulate the data/cmx/cm

1

(vii)

Analyse the data

1

TOTAL 12

x/cm

/cm

SKEMA 7th Tips Physics SPM Success Modul Teknik Menjawab Kertas 2 Dan 3

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