SISCO IP Address
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TASK 1Find : IP Address > 172.25.114.250Network Mask > 255.255.0.0 (/16)Answer : IP Address127.25.114.25010101100000110011001000001111101
Network Mask255.255.0.011111111111111110000000000000000
Total Number of Host Bit16
Number of Host65534
Work Sheet :1. IP Address
172/2 = 86 = 025/2 = 12 = 1144/2 = 72 = 0250/2 = 125 = 0
86/2 = 43 = 012/2 = 6 = 072/2 = 36 = 0125/2 = 62 = 1
43/2 = 21 = 16/2 = 3 = 036/2 = 18 = 062/2 = 31 = 0
21/2 = 10 =13/2 = 1 = 118/2 = 9 = 031/2 = 15 = 1
10/2 = 5 = 01/2 = 0 = 19/2 = 4 = 115/2 = 7 = 1
5/2 = 2 = 10/2 = 0 = 04/2 = 2 = 07/2 = 3 = 1
2/2 = 1 = 00/2 = 0 = 02/2 = 1 = 03/2 = 1 = 1
1/2 = 0 = 10/2 = 0 = 01/2 = 0 = 11/2 = 0 = 1
10101100000110011001000011111010
2. Network Mask255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 00/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 00/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 10/2 = 0 = 00/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 10/2 = 0 = 00/2 = 0 = 0
15/2 = 7 =115/2 = 7 =10/2 = 0 = 00/2 = 0 = 0
7/2 = 3 =17/2 = 3 =10/2 = 0 = 00/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 10/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 00/2 = 0 = 0
11111111111111110000000000000000
3. Number of Host
Number of Host = 32 16= 16= 2^16 2= 65534
TASK 2PROBLEM 1 Host IP Address > 172.30.1.33Network Mask > 255.255.0.0(/16)Answer :IP Address 172.30.1.3310101100000111100000000100100001
Network Mask255.255.0.011111111111111110000000000000000
Network Address172.30.0.010101100000111100000000000000000
Network Broadcast Address172.30.255.25510101100000111101111111111111111
Total Number of Host Bit16
Number of Host65536 or 65534
Work Sheet : STEP11. Changing the IP address and network mask into binary numbers .
172/2 = 86 = 030/2 = 15 = 01/2 = 0 = 133/2 = 16 = 1
86/2 = 43 = 015/2 = 7 = 10/2 = 0 = 016/2 = 8 = 0
43/2 = 21 = 17/2 = 3 = 10/2 = 0 = 08/2 = 4 = 0
21/2 = 10 = 13/2 = 1 = 10/2 = 0 = 04/2 = 2 = 0
10/2 = 5 = 01/2 = 0 = 10/2 = 0 = 02/2 = 1 = 0
5/2 = 2 = 10/2 = 0 = 00/2 = 0 = 01/2 = 0 = 1
2/2 = 1 = 00/2 = 0 = 00/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 10/2 = 0 = 00/2 = 0 = 00/2 = 0 = 0
10101100000111100000000100100001
255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 00/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 00/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 10/2 = 0 = 00/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 10/2 = 0 = 00/2 = 0 = 0
15/2 = 7 =115/2 = 7 =10/2 = 0 = 00/2 = 0 = 0
7/2 = 3 =17/2 = 3 =10/2 = 0 = 00/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 10/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 00/2 = 0 = 0
11111111111111110000000000000000
STEP2
2.Looking for Network Address , by adding binary digits of the IP Address and Network Mask using the AND operator . Note; 1 AND 1 = 1, whereas if there is a 0 on the right AND the result is 0 .
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 172.30.0.0= 10101100. 00011110. 00000000. 00000000
STEP3
3. Finding the Broadcast Address by replacing the whole numbers from 0 to number the host becomes number 1 .
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 172.30.0.0= 10101100. 00011110. 00000000. 00000000Broadcast Address> 172.30.255.255= 10101100. 00011110. 11111111. 11111111
STEP4
4. By counting the number of host bits then we can find the Total Number of Host Bits . Host Bits = 16, then 2^16 = 65536, 65536-2 = 65534
PROBLEM 2 Host IP Address > 172.30.1.33Network Mask > 255.255.255.0(/24)Answer :IP Address 172.30.1.3310101100000111100000000100100001
Network Mask255.255.255.011111111111111111111111100000000
Network Address172.30.1.010101100000111100000000100000000
Network Broadcast Address172.30.1.25510101100000111100000000111111111
Total Number of Host Bit8
Number of Host256 or 254
Work Sheet : STEP 11. Changing the IP address and network mask into binary numbers .
172/2 = 86 = 030/2 = 15 = 01/2 = 0 = 133/2 = 16 = 1
86/2 = 43 = 015/2 = 7 = 10/2 = 0 = 016/2 = 8 = 0
43/2 = 21 = 17/2 = 3 = 10/2 = 0 = 08/2 = 4 = 0
21/2 = 10 = 13/2 = 1 = 10/2 = 0 = 04/2 = 2 = 0
10/2 = 5 = 01/2 = 0 = 10/2 = 0 = 02/2 = 1 = 0
5/2 = 2 = 10/2 = 0 = 00/2 = 0 = 01/2 = 0 = 1
2/2 = 1 = 00/2 = 0 = 00/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 10/2 = 0 = 00/2 = 0 = 00/2 = 0 = 0
10101100000111100000000100100001
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 10/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 10/2 = 0 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =10/2 = 0 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =10/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 10/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 10/2 = 0 = 0
11111111111111111111111100000000
STEP 22.Looking for Network Address , by adding binary digits of the IP Address and Network Mask using the AND operator . Note; 1 AND 1 = 1, whereas if there is a 0 on the right AND the result is 0.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Network Mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Network Address> 172.30.1.0= 10101100. 00011110. 00000001. 00000000
STEP 33. Finding the Broadcast Address by replacing the whole numbers from 0 to number the host becomes number 1 .
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 172.30.1.0= 10101100. 00011110. 11111111. 00000000Broadcast Address> 172.30.1.255= 10101100. 00011110. 00000001. 11111111
STEP 44. By counting the number of host bits then we can find the Total Number of Host Bits . Host Bits = 8 , then 2^8 =256 , 256-2 = 254
PROBLEM 3Host IP Address > 192.168.10.234Network Mask > 255.255.255.0(/24)Answer :
IP Address192.168.10.23411000000101010000000101011101010
Network Mask255.255.255.011111111111111111111111100000000
Network Address192.168.10.011000000101010000000101000000000
Network Broadcast Address192.168.10.25511000000101010000000101011111111
Total Number of Host Bit8
Number of Host256 or 254
Work Sheet :STEP 11. Changing the IP address and network mask into binary numbers .
192/2 = 96 = 0168/2 = 84 = 010/2 = 5 = 0234/2 = 117 = 0
96/2 = 48 = 084/2 = 42 = 05/2 = 2 = 1117/2 = 58 = 1
48/2 = 24 = 042/2 = 21 = 02/2 = 1 = 058/2 = 29 = 0
24/2 = 12 = 021/2 = 10 = 11/2 = 0 = 129/2 = 14 = 1
12/2 = 6 = 010/2 = 5 = 00/2 = 0 = 014/2 = 7 = 0
6/2 = 3 = 05/2 = 2 = 10/2 = 0 = 07/2 = 3 = 1
3/2 = 1 = 12/2 = 1 = 00/2 = 0 = 03/2 = 1 = 1
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 01/2 = 0 = 1
11000000101010000000101011101010
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 10/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 10/2 = 0 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =10/2 = 0 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =10/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 10/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 10/2 = 0 = 0
11111111111111111111111100000000
STEP 22.Looking for Network Address , by adding binary digits of the IP Address and Network Mask using the AND operator . Note; 1 AND 1 = 1, whereas if there is a 0 on the right AND the result is 0.
IP Address> 192.168.10.234= 11000000. 10101000. 00001010. 11101010Network Mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Network Address> 192.168.10.0= 11000000. 10101000. 00001010. 00000000
STEP 33. Finding the Broadcast Address by replacing the whole numbers from 0 to number the host becomes number 1 .
IP Address> 192.168.10.234= 11000000. 10101000. 00001010. 11101010Network Mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Network Address> 192.168.10.0= 11000000. 10101000. 00001010. 00000000Broadcast Address> 192.168.10.255= 11000000. 10101000. 00001010. 11111111
STEP 44. By counting the number of host bits then we can find the Total Number of Host Bits . Host Bits = 8 , then 2^8 =256 , 256-2 = 254
PROBLEM 4Host IP Address > 172.17.99.71Network Mask > 255.255.0.0(/16)Answer :
IP Address172.17.99.7110101100000100010110001101000111
Network Mask255.255.0.011111111111111110000000000000000
Network Address172.17.0.010101100000100010000000000000000
Network Broadcast Address172.17.255.25510101100000100011111111111111111
Total Number of Host Bit16
Number of Host65536 or 65534
Work Sheet :STEP 11. Changing the IP address and network mask into binary numbers .
172/2 = 86 = 017/2 = 8 = 199/2 = 49 = 171/2 = 35 = 1
86/2 = 43 = 08/2 = 4 = 049/2 = 24 = 135/2 = 17 = 1
43/2 = 21 = 14/2 = 2 = 024/2 = 12 = 017/2 = 8 = 1
21/2 = 10 = 12/2 = 1 = 012/2 = 6 = 08/2 = 4 = 0
10/2 = 5 = 01/2 = 0 = 16/2 = 3 = 04/2 = 2 = 0
5/2 = 2 = 10/2 = 0 = 03/2 = 1 = 02/2 = 1 = 0
2/2 = 1 = 00/2 = 0 = 01/2 = 0 = 11/2 = 0 = 1
1/2 = 0 = 10/2 = 0 = 00/2 = 0 = 00/2 = 0 = 0
10101100000100010110001101000111
255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 00/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 00/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 10/2 = 0 = 00/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 10/2 = 0 = 00/2 = 0 = 0
15/2 = 7 =115/2 = 7 =10/2 = 0 = 00/2 = 0 = 0
7/2 = 3 =17/2 = 3 =10/2 = 0 = 00/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 10/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 00/2 = 0 = 0
11111111111111110000000000000000
STEP 22.Looking for Network Address , by adding binary digits of the IP Address and Network Mask using the AND operator . Note; 1 AND 1 = 1, whereas if there is a 0 on the right AND the result is 0.
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 172.17.0.0= 10101100. 00010001. 00000000. 00000000
STEP 33. Finding the Broadcast Address by replacing the whole numbers from 0 to number the host becomes number 1 .
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 172.17.0.0= 10101100. 00010001. 00000000. 00000000Broadcast Address> 172.17.255.255= 10101100. 00010001. 11111111. 11111111
STEP 44. By counting the number of host bits then we can find the Total Number of Host Bits . Host Bits = 16 , then 2^16 = 65536 , 65536-2 = 65534
PROBLEM 5 Host IP Address > 192.168.3.219Network Mask > 255.255.0.0(/16)Answer :
IP Address192.168.3.21911000000101010000000001111011011
Network Mask255.255.0.011111111111111110000000000000000
Network Address192.168.0.011000000101010000000000000000000
Network Broadcast Address192.168.255.25511000000101010001111111111111111
Total Number of Host Bit16
Number of Host65536 or 65534
Work Sheet :STEP 11. Changing the IP address and network mask into binary numbers .
192/2 = 96 = 0168/2 = 84 = 03/2 = 1 = 1219/2 = 109 = 1
96/2 = 48 = 084/2 = 42 = 01/2 = 0 = 1109/2 = 54 = 1
48/2 = 24 = 042/2 = 21 = 00/2 = 0 = 054/2 = 27 = 0
24/2 = 12 = 021/2 = 10 = 10/2 = 0 = 027/2 = 13 = 1
12/2 = 6 = 010/2 = 5 = 00/2 = 0 = 013/2 = 6 = 1
6/2 = 3 = 05/2 = 2 = 10/2 = 0 = 06/2 = 3 = 0
3/2 = 1 = 12/2 = 1 = 00/2 = 0 = 03/2 = 1 = 1
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 01/2 = 0 =1
11000000101010000000001111011011
255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 00/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 00/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 10/2 = 0 = 00/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 10/2 = 0 = 00/2 = 0 = 0
15/2 = 7 =115/2 = 7 =10/2 = 0 = 00/2 = 0 = 0
7/2 = 3 =17/2 = 3 =10/2 = 0 = 00/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 10/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 00/2 = 0 = 0
11111111111111110000000000000000
STEP 22.Looking for Network Address , by adding binary digits of the IP Address and Network Mask using the AND operator . Note; 1 AND 1 = 1, whereas if there is a 0 on the right AND the result is 0.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 192.168.0.0= 11000000. 10101000. 00000000. 00000000
STEP 33. Finding the Broadcast Address by replacing the whole numbers from 0 to number the host becomes number 1.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Network Mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Network Address> 192.168.0.0= 11000000. 10101000. 00000000. 00000000Broadcast Address> 192.168.255.255= 11000000. 10101000. 11111111. 11111111
STEP 44. By counting the number of host bits then we can find the Total Number of Host Bits . Host Bits = 16 , then 2^16 = 65536 , 65536-2 = 65534
PROBLEM 6Host IP Address > 192.168.3.219Network Mask > 255.255.255.224(/27)Answer :IP Address192.168.3.21911000000101010000000001111011011
Network Mask255.255.255.22411111111111111111111111111100000
Network Address192.168.3.19211000000101010000000101011000000
Network Broadcast Address192.168.255.25511000000101010000000101011011111
Total Number of Host Bit5
Number of Host32 or 30
Work Sheet :STEP 11. Changing the IP address and network mask into binary numbers .
192/2 = 96 = 0168/2 = 84 = 03/2 = 1 = 1219/2 = 109 = 1
96/2 = 48 = 084/2 = 42 = 01/2 = 0 = 1109/2 = 54 = 1
48/2 = 24 = 042/2 = 21 = 00/2 = 0 = 054/2 = 27 = 0
24/2 = 12 = 021/2 = 10 = 10/2 = 0 = 027/2 = 13 = 1
12/2 = 6 = 010/2 = 5 = 00/2 = 0 = 013/2 = 6 = 1
6/2 = 3 = 05/2 = 2 = 10/2 = 0 = 06/2 = 3 = 0
3/2 = 1 = 12/2 = 1 = 00/2 = 0 = 03/2 = 1 = 1
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 01/2 = 0 =1
11000000101010000000001111011011
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 1224/2 = 112 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 1112/2 = 56 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 156/2 = 28 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 128/2 = 14 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =114/2 = 7 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =17/2 = 3 = 1
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 13/2 = 1 = 1
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 11/2 = 0 = 1
11111111111111111111111111100000
STEP 22.Looking for Network Address , by adding binary digits of the IP Address and Network Mask using the AND operator . Note; 1 AND 1 = 1, whereas if there is a 0 on the right AND the result is 0.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Network Mask> 255.255.255.244= 11111111. 11111111. 11111111. 11100000Network Address> 192.168.3.192= 11000000. 10101000. 00001010. 11000000
STEP 33. Finding the Broadcast Address by replacing the whole numbers from 0 to number the host becomes number 1.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Network Mask> 255.255.255.224= 11111111. 11111111. 11111111. 11100000Network Address> 192.168.0.0= 11000000. 10101000. 00001010. 11000000Broadcast Address> 192.168.255.255= 11000000. 10101000. 00001010. 11011111
STEP 44. By counting the number of host bits then we can find the Total Number of Host Bits . Host Bits = 5 , then 2^5 = 32 , 32-2 = 30
TASK 3PROBLEM 1Host IP Address > 173.30.1.33Subnet Mask > 255.255.255.0Answer : IP Address173.30.1.3310101100000111100000000100100001
Subnet Mask225.255.255.011111111111111111111111100000000
Number of Subnet Bits8 bits
Number of Subnets2^8 = 256 subnet
Number of Host Bits per subnet256
Number of Usable Hosts per Subnet2^8 2 = 254 host Per Subnet
Subnet Address for This IP Address172.30.1.0
IP Address of First Host on this Subnet172.30.1.1
IP Address of Last Host on This Subnet172.30.1.254
Broadcast Address for This Subnet172.30.1.255
Work Sheet :STEP 11. Changing the IP Address and Subnet Mask into binary numbers.
173/2 = 86 = 0
86/2 = 43 = 0
43/2 = 21 = 1
21/2 = 10 = 1
10/2 = 5 = 0
5/2 = 2 = 1
2/2 = 1 = 0
= 0 = 1
10101100000111100000000100100001
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 10/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 10/2 = 0 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =10/2 = 0 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =10/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 10/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 10/2 = 0 = 0
11111111111111111111111100000000
STEP 22. Finding the Subnet Address for this IP address by adding the binary number of IP addresses with the subnet mask using the AND operator, Note: 1 AND 1 = 1, whereas if 0 aggregated using the AND operator, the result is 0IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.0= 10101100. 00011110. 00000001. 00000000
STEP 33. Determine the address bits that contain information that contains information networks and hosts.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.0= 10101100. 00011110. 00000001. 00000000
STEP 44. Determine the subnet range and host range.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.0= 10101100. 00011110. 00000001. 00000000
STEP 55. Determine First Host, Last Host and Broadcast* Determine First Host by replacing the number 0 on the host range of add-most end subnet become number 1
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.0= 10101100. 00011110. 00000001. 00000000First Host> 175.30.1.1= 10101100. 00011110. 00000001. 00000001
* Determine the Last Host by replacing the numbers 0 to 1 on the host range of the subnet add except the very last bit remains 0.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.0= 10101100. 00011110. 00000001. 00000000Last Host> 175.30.1.1= 10101100. 00011110. 00000001. 11111110
* Determine Broadcast by replacing all of the numbers 0 to host subnet range of add become number 1.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.0= 10101100. 00011110. 00000001. 00000000Broadcast> 175.30.1.255= 10101100. 00011110. 00000001. 11111111
STEP 66. Determine the Number of Subnets by counting bits in the subnet counting range is 8. Use the formula 2 to the power n, where n is the number of bits in the subnet counting range.
Number of Subnet Bits> 8 bitsNumber of Subets> 2^8 = 256 Subnets
STEP 77. Determine Number Usable Hosts per Subnet by counting bits in the host range is 8. Use the formula 2 to the power of n minus 2.
Number of Subnet Bits> 8 bitsNumber of Usable Host per Subnet> 2^8 2 = 256 2 = 254 host per subnet
PROBLEM 2Host IP Address > 173.30.1.33Subnet Mask > 255.255.255.252Answer : IP Address173.30.1.3310101100000111100000000100100001
Subnet Mask225.255.255.0111111111111111111111111
Number of Subnet Bits14 bits
Number of Subnets2^14 = 16384 subnet
Number of Host Bits per subnet4
Number of Usable Hosts per Subnet2
Subnet Address for This IP Address172.30.1.32
IP Address of First Host on this Subnet172.30.1.33
IP Address of Last Host on This Subnet172.30.1.34
Broadcast Address for This Subnet172.30.1.35
Work Sheet :STEP 11. Changing the IP Address and Subnet Mask into binary numbers.
10101100000111100000000100100001
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 10/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 10/2 = 0 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =10/2 = 0 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =10/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 10/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 10/2 = 0 = 0
11111111111111111111111100000000
STEP 22. Finding the Subnet Address for this IP address by adding the binary number of IP addresses with the subnet mask using the AND operator, Note: 1 AND 1 = 1, whereas if 0 aggregated using the AND operator, the result is 0IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 172.30.1.32= 10101100. 00011110. 00000001. 00100000
STEP 33. Determine the address bits that contain information that contains information networks and hosts.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111110Subnet Add> 172.30.1.32= 10101100. 00011110. 00000001. 00100000
STEP 44. Determine the subnet range and host range.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 172.30.1.32= 10101100. 00011110. 00000001. 00100000
STEP 55. Determine First Host, Last Host and Broadcast* Determine First Host by replacing the number 0 on the host range of add-most end subnet become number 1
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 172.30.1.32= 10101100. 00011110. 00000001. 00100000First Host> 175.30.1.1= 10101100. 00011110. 00000001. 00100001
* Determine the Last Host by replacing the numbers 0 to 1 on the host range of the subnet add except the very last bit remains 0.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.32= 10101100. 00011110. 00000001. 00100000Last Host> 175.30.1.34= 10101100. 00011110. 00000001. 00100010
* Determine Broadcast by replacing all of the numbers 0 to host subnet range of add become number 1.
IP Address> 172.30.1.33= 10101100. 00011110. 00000001. 00100001Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 172.30.1.32= 10101100. 00011110. 00000001. 00100000Broadcast> 175.30.1.35= 10101100. 00011110. 00000001. 00100011
STEP 66. Determine the Number of Subnets by counting bits in the subnet counting range is 8. Use the formula 2 to the power n, where n is the number of bits in the subnet counting range.
Number of Subnet Bits> 14 bitsNumber of Subets> 2^14 = 16384 Subnets
STEP 77. Determine Number Usable Hosts per Subnet by counting bits in the host range is 8. Use the formula 2 to the power of n minus 2.
Number of Subnet Bits> 2 bitsNumber of Usable Host per Subnet> 2^2 2 = 4 2 = 2 host per subnet
PROBLEM 3Host IP Address > 192.192.10.234Subnet Mask > 255.255.255.0Answer : IP Address192.192.10.23411000000110000000000101011101010
Subnet Mask225.255.255.011111111111111111111111100000000
Number of Subnet Bits8 bits
Number of Subnets2^8 = 256 subnet
Number of Host Bits per subnet256
Number of Usable Hosts per Subnet254
Subnet Address for This IP Address192.192.10.0
IP Address of First Host on this Subnet192.192.10.1
IP Address of Last Host on This Subnet192.192.10.254
Broadcast Address for This Subnet192.192.10.255
Work Sheet :STEP 11. Changing the IP Address and Subnet Mask into binary numbers.
11000000110000000000101011101010
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 10/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 10/2 = 0 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =10/2 = 0 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =10/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 10/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 10/2 = 0 = 0
11111111111111111111111100000000
STEP 22. Finding the Subnet Address for this IP address by adding the binary number of IP addresses with the subnet mask using the AND operator, Note: 1 AND 1 = 1, whereas if 0 aggregated using the AND operator, the result is 0IP Address> 192.192.10.234= 11000000. 11000000. 00001010. 11101010Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.192.10.0= 11000000. 11000000. 00001010. 00000000
STEP 33. Determine the address bits that contain information that contains information networks and hosts.
IP Address> 192.192.10.234= 11000000. 11000000. 00001010. 11101010Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.192.10.0= 11000000. 11000000. 00001010. 00000000
STEP 44. Determine the subnet range and host range.
IP Address> 192.192.10.234= 11000000. 11000000. 00001010. 11101010Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.192.10.0= 11000000. 11000000. 00001010. 00000000
STEP 55. Determine First Host, Last Host and Broadcast* Determine First Host by replacing the number 0 on the host range of add-most end subnet become number 1
IP Address> 192.192.10.234= 11000000. 11000000. 00001010. 11101010Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.192.10.0= 11000000. 11000000. 00001010. 00000000First Host> 192.192.10.1= 11000000. 11000000. 00001010. 00000001
* Determine the Last Host by replacing the numbers 0 to 1 on the host range of the subnet add except the very last bit remains 0.
IP Address> 192.192.10.234= 11000000. 11000000. 00001010. 11101010Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.192.10.0= 11000000. 11000000. 00001010. 00000000Last Host> 192.192.10.254= 11000000. 11000000. 00001010. 11111110
* Determine Broadcast by replacing all of the numbers 0 to host subnet range of add become number 1.
IP Address> 192.192.10.234= 11000000. 11000000. 00001010. 11101010Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.192.10.0= 11000000. 11000000. 00001010. 00000000Broadcast> 192.192.10.255= 10101100. 00011110. 00000001. 11111111
STEP 66. Determine the Number of Subnets by counting bits in the subnet counting range is 8. Use the formula 2 to the power n, where n is the number of bits in the subnet counting range.
Number of Subnet Bits> 8 bitsNumber of Subets> 2^8 = 256 Subnets
STEP 77. Determine Number Usable Hosts per Subnet by counting bits in the host range is 8. Use the formula 2 to the power of n minus 2.
Number of Subnet Bits> 8 bitsNumber of Usable Host per Subnet> 2^8 2 = 256 2 = 254 host per subnet
PROBLEM 4Host IP Address > 172.17.99.71Subnet Mask > 255.255.0.0Answer : IP Address172.17.99.7110101100000100010110001101000111
Subnet Mask225.255.0.011111111111111110000000000000000
Number of Subnet Bits0 bits
Number of Subnets2^0 = 1 subnet
Number of Host Bits per subnet65536
Number of Usable Hosts per Subnet65534
Subnet Address for This IP Address172.17.0.0
IP Address of First Host on this Subnet172.17.0.1
IP Address of Last Host on This Subnet172.17.255.254
Broadcast Address for This Subnet172.17.255.255
Work Sheet :STEP 11. Changing the IP Address and Subnet Mask into binary numbers.
10101100000100010110001101000111
255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 00/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 00/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 10/2 = 0 = 00/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 10/2 = 0 = 00/2 = 0 = 0
15/2 = 7 =115/2 = 7 =10/2 = 0 = 00/2 = 0 = 0
7/2 = 3 =17/2 = 3 =10/2 = 0 = 00/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 10/2 = 0 = 00/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 10/2 = 0 = 00/2 = 0 = 0
11111111111111110000000000000000
STEP 22. Finding the Subnet Address for this IP address by adding the binary number of IP addresses with the subnet mask using the AND operator, Note: 1 AND 1 = 1, whereas if 0 aggregated using the AND operator, the result is 0IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Subnet mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Subnet Add> 172.17.0.0= 10101100. 00010001. 00000000. 00000000
STEP 33. Determine the address bits that contain information that contains information networks and hosts.
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Subnet mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Subnet Add> 172.17.0.0= 10101100. 00010001. 00000000. 00000000
STEP 44. Determine the subnet range and host range.
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Subnet mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Subnet Add> 172.17.0.0= 10101100. 00010001. 00000000. 00000000
STEP 55. Determine First Host, Last Host and Broadcast* Determine First Host by replacing the number 0 on the host range of add-most end subnet become number 1
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Subnet mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Subnet Add> 172.17.0.0= 10101100. 00010001. 00000000. 00000000First Host> 172.17.0.1= 10101100. 00010001. 00000000. 00000001
* Determine the Last Host by replacing the numbers 0 to 1 on the host range of the subnet add except the very last bit remains 0.
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Subnet mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Subnet Add> 172.17.0.0= 10101100. 00010001. 00000000. 00000000Last Host> 172.17.255.254= 10101100. 00010001. 11111111. 11111110
* Determine Broadcast by replacing all of the numbers 0 to host subnet range of add become number 1.
IP Address> 172.17.99.71= 10101100. 00010001. 01100011. 01000111Subnet mask> 255.255.0.0= 11111111. 11111111. 00000000. 00000000Subnet Add> 172.17.0.0= 10101100. 00010001. 00000000. 00000000Broadcast> 172.17.255.255= 10101100. 00010001. 11111111. 11111111
STEP 66. Determine the Number of Subnets by counting bits in the subnet counting range is 8. Use the formula 2 to the power n, where n is the number of bits in the subnet counting range.
Number of Subnet Bits> 0 bitsNumber of Subets> 2^0 = 1 Subnets
STEP 77. Determine Number Usable Hosts per Subnet by counting bits in the host range is 8. Use the formula 2 to the power of n minus 2.
Number of Subnet Bits> 16 bitsNumber of Usable Host per Subnet> 2^16 2 = 65536 2 = 65534 host per subnet
PROBLEM 5Host IP Address > 192.168.3.219Subnet Mask > 255.255.255.0Answer : IP Address192.168.3.21911000000101010000000001111011011
Subnet Mask225.255.255.011111111111111111111111100000000
Number of Subnet Bits8 bits
Number of Subnets2^8 = 256 subnet
Number of Host Bits per subnet256
Number of Usable Hosts per Subnet254
Subnet Address for This IP Address192.168.3.0
IP Address of First Host on this Subnet192.168.3.1
IP Address of Last Host on This Subnet192.168.3.254
Broadcast Address for This Subnet192.168.3.255
Work Sheet :STEP 11. Changing the IP Address and Subnet Mask into binary numbers.
11000000101010000000001111011011
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 10/2 = 0 = 0
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 10/2 = 0 = 0
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 10/2 = 0 = 0
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 10/2 = 0 = 0
15/2 = 7 =115/2 = 7 =115/2 = 7 =10/2 = 0 = 0
7/2 = 3 =17/2 = 3 =17/2 = 3 =10/2 = 0 = 0
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 10/2 = 0 = 0
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 10/2 = 0 = 0
11111111111111111111111100000000
STEP 22. Finding the Subnet Address for this IP address by adding the binary number of IP addresses with the subnet mask using the AND operator, Note: 1 AND 1 = 1, whereas if 0 aggregated using the AND operator, the result is 0IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.168.3.0= 11000000. 10101000. 00000011. 00000000
STEP 33. Determine the address bits that contain information that contains information networks and hosts.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.168.3.0= 11000000. 10101000. 00000011. 00000000
STEP 44. Determine the subnet range and host range.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.168.3.0= 11000000. 10101000. 00000011. 00000000
STEP 55. Determine First Host, Last Host and Broadcast* Determine First Host by replacing the number 0 on the host range of add-most end subnet become number 1
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.168.3.0= 11000000. 10101000. 00000011. 00000000First Host> 192.168.3.1= 11000000. 10101000. 00000011. 00000001
* Determine the Last Host by replacing the numbers 0 to 1 on the host range of the subnet add except the very last bit remains 0.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.168.3.0= 11000000. 10101000. 00000011. 00000000Last Host> 192.168.3.254= 10101100. 00010001. 00000011. 11111110
* Determine Broadcast by replacing all of the numbers 0 to host subnet range of add become number 1.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.0= 11111111. 11111111. 11111111. 00000000Subnet Add> 192.168.3.0= 11000000. 10101000. 00000011. 00000000Broadcast> 192.168.3.255= 11000000. 10101000. 00000011. 11111111
STEP 66. Determine the Number of Subnets by counting bits in the subnet counting range is 8. Use the formula 2 to the power n, where n is the number of bits in the subnet counting range.
Number of Subnet Bits> 8 bitsNumber of Subets> 2^8 = 256 Subnets
STEP 77. Determine Number Usable Hosts per Subnet by counting bits in the host range is 8. Use the formula 2 to the power of n minus 2.
Number of Subnet Bits> 8 bitsNumber of Usable Host per Subnet> 2^8 2 = 256 2 = 254 host per subnet
PROBLEM 6Host IP Address > 192.168.3.219Subnet Mask > 255.255.255.252Answer : IP Address192.168.3.21911000000101010000000001111011011
Subnet Mask225.255.255.252111111111111111111111111
Number of Subnet Bits14 bits
Number of Subnets2^14 = 16384 subnet
Number of Host Bits per subnet4
Number of Usable Hosts per Subnet2
Subnet Address for This IP Address192.168.3.216
IP Address of First Host on this Subnet192.168.3.217
IP Address of Last Host on This Subnet192.168.3.218
Broadcast Address for This Subnet192.168.3.219
Work Sheet :STEP 11. Changing the IP Address and Subnet Mask into binary numbers.
11000000101010000000001111011011
255/2 = 127 = 1255/2 = 127 = 1255/2 = 127 = 1
127/2 = 63 = 1127/2 = 63 = 1127/2 = 63 = 1
63/2 = 31 = 163/2 = 31 = 163/2 = 31 = 1
31/2 = 15 = 131/2 = 15 = 131/2 = 15 = 1
15/2 = 7 =115/2 = 7 =115/2 = 7 =1
7/2 = 3 =17/2 = 3 =17/2 = 3 =1
3/2 = 1 = 13/2 = 1 = 13/2 = 1 = 1
1/2 = 0 = 11/2 = 0 = 11/2 = 0 = 1
11111111111111111111111111111100
STEP 22. Finding the Subnet Address for this IP address by adding the binary number of IP addresses with the subnet mask using the AND operator, Note: 1 AND 1 = 1, whereas if 0 aggregated using the AND operator, the result is 0IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 192.168.3.216= 11000000. 10101000. 00000011. 11011000
STEP 33. Determine the address bits that contain information that contains information networks and hosts.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 192.168.3.216= 11000000. 10101000. 00000011. 11011000
STEP 44. Determine the subnet range and host range.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 192.168.3.216= 11000000. 10101000. 00000011. 11011000
STEP 55. Determine First Host, Last Host and Broadcast* Determine First Host by replacing the number 0 on the host range of add-most end subnet become number 1
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 192.168.3.216= 11000000. 10101000. 00000011. 11011000First Host> 192.168.3.217= 11000000. 10101000. 00000011. 11011001
* Determine the Last Host by replacing the numbers 0 to 1 on the host range of the subnet add except the very last bit remains 0.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 192.168.3.216= 11000000. 10101000. 00000011. 11011000Last Host> 192.168.3.218= 10101100. 00010001. 00000011. 11011010
* Determine Broadcast by replacing all of the numbers 0 to host subnet range of add become number 1.
IP Address> 192.168.3.219= 11000000. 10101000. 00000011. 11011011Subnet mask> 255.255.255.252= 11111111. 11111111. 11111111. 11111100Subnet Add> 192.168.3.216= 11000000. 10101000. 00000011. 11011000Broadcast> 192.168.3.219= 11000000. 10101000. 00000011. 11011011
STEP 66. Determine the Number of Subnets by counting bits in the subnet counting range is 8. Use the formula 2 to the power n, where n is the number of bits in the subnet counting range.
Number of Subnet Bits> 14 bitsNumber of Subets> 2^14 = 16384 Subnets
STEP 77. Determine Number Usable Hosts per Subnet by counting bits in the host range is 8. Use the formula 2 to the power of n minus 2.
Number of Subnet Bits>2 bitsNumber of Usable Host per Subnet> 2^2 2 = 4 2 = 2 host per subnet