Singular Third-Order Multipoint Boundary Value Problem at Resonance

4
@ IJTSRD | Available Online @ www ISSN No: 245 Inte R Singular Th Valu G. Pushpalatha Assistant Professor, Department of M Vivekanandha College of Arts and S Women, Tiruchengode, Namakkal, Tam ABSTRACT The present paper is particularly exhib derive results of a third-order singul boundary value problem at resonance us degree arguments. Keywords: The present paper is particu about the derive results of a third-o multipoint boundary value problem using coindence degree arguments. INTRODUCTION This paper derive the existence for t singular multipoint boundary value resonance of the form ′′′ = (), (), (), ′′ ()) + (0) = 0, ′′ (0) = 0, (1) = ሧ , ,ୀଵ Where ∶ [0,1] × is caratheodo (i.e., for each (, ) ∈ the function measurable on [0,1]; for almost everyw the function (, . , . ) is continuous ∈ (0,1), , = 1,2, … , − 3, and 1, where and have singularity at = In [1] Gupta et al. studied the above equ and have no singularity and ,ୀଵ obtained existence of a [0,1] solutio w.ijtsrd.com | Volume – 2 | Issue – 3 | Mar-Apr 56 - 6470 | www.ijtsrd.com | Volum ernational Journal of Trend in Sc Research and Development (IJT International Open Access Journ hird-Order Multipoint Bounda ue Problem at Resonance Mathematics, Sciences for milnadu, India S. K. Re Research Scholar, Departm Vivekanandha College of A Women, Tiruchengode, Nama ibits about the ular multipoint sing coindence ularly exhibits order singular at resonance the third-order problem at + () ory’s function n (. , , ) is where ∈ [0,1], on ). Let = ,ୀଵ =1. uation when ≠ 1. They on by utilizing Letay-Schauder continuation correspond to the nonresonan this article is therefore to obta when =1 ,ୀଵ (the res and have a singularity at Definition 1 Let and be real Banach s linear operator : ⊂ mapping of index zero if Ke finite dimension, where d Note We will require the continuou : → such that Im P = =Ker L Ker , | : dom L isomorphism. Definition 2 Let be a Fredholm mapping bounded open subset of U such Ω . The map M: on , if the map (Ω ) is bo compact, where one denotes b the generaliz addition is -completely co on every bounded Ω ⊂ . r 2018 Page: 623 me - 2 | Issue 3 cientific TSRD) nal ary eka ment of Mathematics, Arts and Sciences for akkal, Tamilnadu, India principle. These results nce case. The scope of ained the survive results sonance case) and when = 1. spaces. One says that the is a Fredholm er and / are of denotes the image of . us projections : → , = Ker L,Ker Q = Im L, =Im L Im Q, ker Im Iis an of index zero and Ω a h that dom is called -compact unded and ( − ) is by ∶ Im → zed inverse of . In ontinuous if it -compact

description

The present paper is particularly exhibits about the derive results of a third order singular multipoint boundary value problem at resonance using coindence degree arguments. G. Pushpalatha | S. K. Reka "Singular Third-Order Multipoint Boundary Value Problem at Resonance" Published in International Journal of Trend in Scientific Research and Development (ijtsrd), ISSN: 2456-6470, Volume-2 | Issue-3 , April 2018, URL: https://www.ijtsrd.com/papers/ijtsrd11058.pdf Paper URL: http://www.ijtsrd.com/mathemetics/other/11058/singular-third-order-multipoint-boundary-value-problem-at-resonance/g-pushpalatha

Transcript of Singular Third-Order Multipoint Boundary Value Problem at Resonance

Page 1: Singular Third-Order Multipoint Boundary Value Problem at Resonance

@ IJTSRD | Available Online @ www.ijtsrd.com

ISSN No: 2456

InternationalResearch

Singular ThirdValue Problem

G. Pushpalatha Assistant Professor, Department of Mathematics, Vivekanandha College of Arts and Sciences for

Women, Tiruchengode, Namakkal, Tamilnadu, India

ABSTRACT The present paper is particularly exhibits about the derive results of a third-order singular multipoint boundary value problem at resonance using coindence degree arguments.

Keywords: The present paper is particularly exhibits about the derive results of a third-order singular multipoint boundary value problem at resonance using coindence degree arguments.

INTRODUCTION

This paper derive the existence for the thirdsingular multipoint boundary value problem at resonance of the form

𝑢′′′ = 𝑔(𝑡), 𝑢(𝑡), 𝑢′(𝑡), 𝑢′′(𝑡)) +

𝑢′(0) = 0, 𝑢′′(0) = 0,

𝑢(1) = 𝑎 𝑏 𝑢 𝜍 ,

,

Where 𝑔 ∶ [0,1] × ℝ → ℝ is caratheodory’s function (i.e., for each (𝑢, 𝑣) ∈ ℝ the function measurable on [0,1]; for almost everywhere the function 𝑔(𝑡, . , . ) is continuous on 𝜍 ∈ (0,1), 𝑖, 𝑗 = 1,2, … , 𝑚 − 3, and 1, where 𝑔 and ℎ have singularity at 𝑡=1.

In [1] Gupta et al. studied the above equation when and ℎ have no singularity and ⋁ 𝑎,

obtained existence of a 𝐶 [0,1] solution by utilizing

@ IJTSRD | Available Online @ www.ijtsrd.com | Volume – 2 | Issue – 3 | Mar-Apr 2018

ISSN No: 2456 - 6470 | www.ijtsrd.com | Volume

International Journal of Trend in Scientific Research and Development (IJTSRD)

International Open Access Journal

Third-Order Multipoint BoundaryValue Problem at Resonance

Department of Mathematics, Vivekanandha College of Arts and Sciences for

Women, Tiruchengode, Namakkal, Tamilnadu, India

S. K. RekaResearch Scholar, Department of Mathematics, Vivekanandha College of Arts and Science

Women, Tiruchengode, Namakkal, Tamilnadu, India

The present paper is particularly exhibits about the order singular multipoint

boundary value problem at resonance using coindence

e present paper is particularly exhibits order singular

multipoint boundary value problem at resonance

This paper derive the existence for the third-order multipoint boundary value problem at

) + ℎ(𝑡)

is caratheodory’s function the function 𝑔(. , 𝑢, 𝑣) is

for almost everywhere 𝑡 ∈ [0,1], is continuous on ℝ ). Let

and ⋁ 𝑎 𝑏 =,

=1.

In [1] Gupta et al. studied the above equation when 𝑔 𝑏 ≠ 1. They

solution by utilizing

Letay-Schauder continuation principle. These results correspond to the nonresonance case. The scope of this article is therefore to obtained when ⋁ 𝑎 𝑏 = 1, (the resonance case) and when 𝑔 and ℎ have a singularity at 𝑡

Definition 1

Let 𝑈 and 𝑊 be real Banach spaces. One says that the linear operator 𝐿: 𝑑𝑜𝑚 𝐿 ⊂ 𝑈mapping of index zero if Ker finite dimension, where 𝐼𝑚 𝐿 denotes the image of

Note

We will require the continuous projections 𝑄: 𝑊 → 𝑊 such that Im P = Ker L,Ker Q = Im L, 𝑈 =Ker L ⨁ Ker 𝑃, 𝑊𝐿| ⋂ : dom L ⋂ isomorphism.

Definition 2

Let 𝐿 be a Fredholm mapping of index zero and bounded open subset of U such that dom 𝐿⋂Ω ≠ 𝜙. The map M: 𝑈 → 𝑊on 𝛀, if the map 𝑄𝑁(Ω) is bounded and compact, where one denotes by 𝑑𝑜𝑚 𝐿 ⋂ 𝐾𝑒𝑟 𝑃 the generalized inverse of addition 𝑀 is 𝐿-completely continuous if it on every bounded Ω ⊂ 𝑈.

Apr 2018 Page: 623

6470 | www.ijtsrd.com | Volume - 2 | Issue – 3

Scientific (IJTSRD)

International Open Access Journal

Order Multipoint Boundary

Reka Department of Mathematics,

Vivekanandha College of Arts and Sciences for Women, Tiruchengode, Namakkal, Tamilnadu, India

Schauder continuation principle. These results correspond to the nonresonance case. The scope of this article is therefore to obtained the survive results

(the resonance case) and when 𝑡 = 1.

be real Banach spaces. One says that the 𝑈 → 𝑊 is a Fredholm

if Ker 𝐿 and 𝑊/𝐼𝑚 𝐿 are of denotes the image of 𝐿.

We will require the continuous projections 𝑃: 𝑈 → 𝑈, such that Im P = Ker L,Ker Q = Im L,

𝑊 =Im L ⨁ Im Q, ker 𝑃 → Im 𝐿 Iis an

be a Fredholm mapping of index zero and Ω a bounded open subset of U such that dom

𝑊 is called 𝑳-compact is bounded and 𝑅 (𝐼 − 𝑄) is

compact, where one denotes by 𝑅 ∶ Im 𝐿 →the generalized inverse of 𝐿. In

completely continuous if it 𝐿-compact

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Theorem 1

Let 𝐿 be a Fredholm operator of index zero and let 𝑁 be 𝐿-compact on Ω. Assume that the following conditions are satisfied :

(i) 𝐿𝑢 ≠ 𝜅𝑀𝑢 for every (𝑢, 𝜅) ∈[(𝑑𝑜𝑚 𝐿 ∖ 𝐾𝑒𝑟 𝐿) ∩ 𝜕𝜅] × (0,1).

(ii) 𝑀𝑢 ∉ 𝐼𝑚 𝐿, for every 𝑢 ∈ 𝐾𝑒𝑟 𝐿 ∩ 𝜕𝜅. (iii) deg (𝑄𝑀| ∩ , 𝜅 ∩ 𝐾𝑒𝑟 𝐿, 0) ≠ 0,

with 𝑄: 𝑊 → 𝑊 being a continuous projection such that 𝐾𝑒𝑟 𝑄 = 𝐼𝑚 𝐿. then the equation 𝐿𝑢 = 𝑀𝑢 has at least one solution in 𝑑𝑜𝑚 𝐿 ∩ Ω.

Proof :

We shall make use of the following classical spaces, 𝐶[0,1], 𝐶 [0,1], 𝐶 [0,1], 𝐿 [0,1], 𝐿 [0,1],

and 𝐿∞[0,1]. Let 𝐴𝐶[0,1] denote the space of all absolute continuous functions on [0,1], 𝐴𝐶 [0,1] ={𝑢 ∈ 𝐶 [0,1] ∶ 𝑢′′(𝑡) ∈ 𝐴𝐶[0,1]}, 𝐿 [0,1] =

𝑢: 𝑢|[ , ] ∈ 𝐿 [0,1] for every compact interval [0, 𝑑] ⊆ [0,1].

𝐴𝐶 [0,1) = 𝑢: 𝑢|[ , ] ∈ 𝐴𝐶[0,1] .

Let U be the Banach space defined by

𝑈 = {𝑢 ∈ 𝐿 [0,1] ∶ (1 − 𝑡 )𝑢(𝑡) ∈ 𝐿 [0,1]},

With the norm

‖𝑣‖ = (1 − 𝑡 ) |𝑣(𝑡)|𝑑𝑡.

Let 𝑈 be the Banach space

𝑈 = {𝑢 ∈ 𝐶 [0,1): 𝑢 ∈ 𝐶[0,1], lim → (1 −

𝑡 ) 𝑢′′ 𝑒𝑥𝑖𝑠𝑡𝑠} ,

With the norm

‖𝑢‖ = max ‖𝑢‖∞ , (1 − 𝑡 )𝑢′′(𝑡)∞

.

(1)

Where ‖𝑢‖∞ = sup ∈[ , ]|𝑢(𝑡)| .

We denote the norm in 𝐿 [0,1] by ‖. ‖ . we define the linear operator 𝐿: 𝑑𝑜𝑚 𝐿 ⊂ 𝑈 → 𝑊 by

𝐿𝑢 = 𝑢′′′(𝑡), (2)

Where

𝑑𝑜𝑚 𝐿 = 𝑢 ∈ 𝑈 ∶ 𝑢′(0) = 0, 𝑢′′(0) = 0, 𝑢(1)

= 𝑎 𝑏 𝑢(𝜍)

,

And 𝑀: 𝑈 → 𝑊 is defined by

𝐿𝑢 = 𝑔 𝑡, 𝑢(𝑡), 𝑢′(𝑡), 𝑢′′(𝑡) + ℎ(𝑡).

(3)

Then boundary value problem (1) can be written as

𝐿𝑢 = 𝑁𝑢.

Therefore 𝐿 = 𝑁.

Lemma

If ⋁ 𝑎 𝑏 = 1, then

(i) 𝐾𝑒𝑟 𝐿 = {𝑢 ∈ 𝑑𝑜𝑚 𝐿: 𝑢(𝑡) = 𝑐, 𝑐 ∈ ℝ, 𝑡 ∈[0,1]} ;

(ii) 𝐼𝑚 𝐿 =𝑣 ∈ 𝑧:

⋁ 𝑎 𝑏 ∫ ∫ ∫ 𝑣(𝜚)𝑑𝜚𝑑𝑠 = 0,

(iii) 𝐿: 𝑑𝑜𝑚 𝐿 ⊂ 𝑈 → 𝑊 is a Fredholm operator 𝑄: 𝑊 → 𝑊 can be defined by

𝑄𝑣 =𝑒

ℎ𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠

,

,

(4)

Where

ℎ = 𝑎 𝑏

,

𝑒 + 𝜁 + 𝜁 − 𝑒 − 𝑒 − 1

(iv) The linear operator 𝑅 : 𝐼𝑚 𝐿: →

𝑑𝑜𝑚 𝐿 ⋂ 𝐾𝑒𝑟 𝑃 can be defined as

𝑅 = 𝑣(𝜚)𝑑𝜚 (5)

(v) 𝑅 𝑣 ≤ ‖𝑣‖ for all 𝑣 ∈ 𝑊.

Proof :

(i) It is obvious that 𝐾𝑒𝑟 𝐿 = {𝑢 ∈ 𝑑𝑜𝑚 𝐿: 𝑢(𝑡) = 𝑐, 𝑐 ∈ ℝ}.

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(ii) We show that

𝐼𝑚 𝐿 =𝑣 ∈ 𝑊:

⋁ 𝑎 𝑏 ∫ ∫ ∫ 𝑣(𝜚)𝑑𝜚𝑑𝑠 = 0,. (7)

To do this, we consider the problem

𝑤 ′′′(𝑡) = 𝑣(𝑡) (8)

And we show that (5) has a solution 𝑤(𝑡) satisfying

𝑤 ′′(0) = 0, 𝑤 ′(0) = 0, 𝑤(𝑡) = 𝑎 𝑏 𝑤 𝜁 𝜁

,

If and only if

𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠 = 0

,

(9)

Suppose (3) has a solmution 𝑤(𝑡) satisfying

𝑤 ′′(0) = 0, 𝑤 ′(0) = 0, 𝑤(𝑡) = 𝑎 𝑏 𝑤 𝜁 𝜁

,

Then we obtain from (5) that

𝑤(𝑡) = 𝑤(0) + 𝑣(𝜚)𝑑𝜚𝑑𝑠,

(10)

And applying the boundary conditions we get

𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠

,

= 𝑣(𝜚)𝑑𝜚𝑑𝑠, (11)

Since ⋁ 𝑎 𝑏 = 1, , and using (i) and we get

𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠 = 0

,

On the other hand if (6) holds, let 𝑢 ∈ ℝ; then

𝑤(𝑡) = 𝑤(0) + 𝑣(𝜚)𝑑𝜚𝑑𝑠,

Where 𝑣 ∈ 𝑍

𝑤 ′′′(𝑡) = 𝑣(𝑡) (12)

(iii) For 𝑣 ∈ 𝑍, we define the projection 𝑄𝑣 as

𝑄𝑣 =𝑒

ℎ𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠

,

,

𝑡 ∈ [0,1], (13)

Where

ℎ = 𝑎 𝑏

,

𝑒 + 𝜁 + 𝜁 − 𝑒 − 𝑒 − 1 ≠ 0.

We show that 𝑄: 𝑊 → 𝑊 is well defined and bounded.

|𝑄𝑣(𝑡)| ≤|𝑒 |

|ℎ||𝑎 | 𝑏

,

(1 − 𝑠) |𝑣(𝑠)|𝑑𝑠

=1

|ℎ||𝑎 | 𝑏

,

‖𝑣‖ |𝑒 |

‖𝑄𝑣‖ ≤ (1 − 𝑡) |𝑄𝑣(𝑡)|𝑑𝑡

≤1

|ℎ||𝑎 | 𝑏

,

‖𝑣‖ |𝑒 | (1 − 𝑠) 𝑑𝑠

=1

|ℎ||𝑎 | 𝑏

,

‖𝑣‖ ‖𝑒 ‖ .

In addition it is easily verified that

𝑄 𝑣 = 𝑄𝑣, 𝑣 ∈ 𝑊. (14)

We therefore conclude that 𝑄: 𝑊 → 𝑊 is a projection. If 𝑣 ∈ 𝐼𝑚 𝐿, then from (6) 𝑄𝑣(𝑡) = 0. Hence 𝐼𝑚 𝐿 ⊆ 𝐾𝑒𝑟 𝑄. Let 𝑣 = 𝑣 − 𝑄𝑣 ; that is, 𝑣 ∈𝐾𝑒𝑟 𝑄. Then

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𝑎 𝑏 𝑣 (𝜚)𝑑𝜚𝑑𝑠

,

= 𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠

,

−1

ℎ𝑣(𝜚)𝑑𝜚𝑑𝑠

,

Here ℎ = 0 we get

𝑎 𝑏 𝑣 (𝜚)𝑑𝜚𝑑𝑠

,

= 𝑎 𝑏 𝑣(𝜚)𝑑𝜚𝑑𝑠

,

Therefore 𝑣 = 𝑣.

Thus 𝑣 ∈ 𝐼𝑚 𝐿 and therefore 𝐾𝑒𝑟 𝑄 ⊆ 𝐼𝑚 𝐿 and hence

𝑊 = 𝐼𝑚 𝐿 + 𝐼𝑚 𝑄 = 𝐼𝑚 𝐿 + ℝ.

It follows that since 𝐼𝑚 𝐿 ∩ ℝ = {0}, then 𝑊 =𝐼𝑚 𝐿 ⨁ 𝐼𝑚 𝑄.

Therefore,

dim 𝐾𝑒𝑟 𝐿 = dim 𝐼𝑚 𝑄 = dim ℝ = 𝑐𝑜𝑑𝑖𝑚 𝐼𝑚 𝐿 = 1.

This implies that 𝐿 is Fredholm mapping of index zero.

(iv) We define 𝑃 ∶ 𝑊 → 𝑊 by 𝑃𝑢 = 𝑢(0), (15)

And clearly 𝑃 is continuous and linear and 𝑃 𝑢 =𝑃(𝑃𝑢) = 𝑃𝑢(0) = 𝑢(0) = 𝑃𝑢 and 𝐾𝑒𝑟 𝑃 ={𝑢 ∈ 𝑈 ∶ 𝑢(0) = 0}. We now show that the generalized inverse 𝐾 = 𝐼𝑚 𝐿 → 𝑑𝑜𝑚 𝐿 ∩ 𝐾𝑒𝑟 𝑃 of 𝐿 is given by

𝑅 𝑣 = 𝑣(𝜚)𝑑𝜚 (16)

For 𝑣 ∈ 𝐼𝑚 𝐿 we have

(𝐿𝑅 )𝑣(𝑡) = 𝑅 𝑣 (𝑡)′′

= 𝑣(𝑡) (17)

And for 𝑢 ∈ 𝑑𝑜𝑚 𝐿 ∩ 𝐾𝑒𝑟 𝑃 we know that

(𝑅 𝐿) 𝑢(𝑡) = 𝑢′′(𝜚)𝑑𝜚𝑑𝑠

= (𝑡 − 𝑠)𝑢′′ 𝑑𝑠 (18)

= 𝑢(𝑡) − 𝑢′(0) 𝑡 − 𝑢(0) = 𝑢(𝑡)

Since 𝑢 ∈ 𝑑𝑜𝑚 𝐿 ∩ 𝐾𝑒𝑟 𝑃, 𝑢(0) = 0, and 𝑃𝑢 = 0.

This shows that 𝑅 = (𝐿| ∩ ) .

(v) 𝑅 𝑣∞

≤ max ∈[ , ] ∫ (𝑡 − 𝑠) |𝑣(𝑠)|𝑑𝑠

≤ (𝑡 − 𝑠) |𝑣(𝑠)|𝑑𝑠

≤ ‖𝑣‖ .

We conclude that

𝑅 𝑣 ≤ ‖𝑣‖ .

References

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