SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7...
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Transcript of SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7...
![Page 1: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/1.jpg)
SIDE GROUP NAME
CONDENCED FORMULA
STRUCTURAL FORMULA
METHYL CH3
ETHYL C2H5
PROPYL C3H7
CHLORO Cl same
BROMO Br same
IODO I same
cH
H
H
cH
H
H cH
H
cH c cHHH
H H H
![Page 2: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/2.jpg)
ALKANES (CnH2n+2)
1.THE INTER CARBON BONDS ARE ALL SINGLE. 2.COMPOSED OF HYDROGEN AND CARBON
(HYDROCARBON).3.DEFINED BY THE EQUATION CnH2n+2
4.NONPOLAR AND INSOLLUBLE IN WATER.5.REACTIONS ARE VERY SLOW.6.FUELS FOR COMBUSTION REACTIONS.7.HYDROGENS CAN BE REMOVED AND
SUBSTITUTED FOR BY HALOGENS FORMMING HALOCARBONS.
8.ALKANES HOLD AS MANY HYDROGENS AS POSSIBLE AND ARE TERMED SATURATED WITH RESPECT TO H.
![Page 3: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/3.jpg)
CH
H
CH
H
HH
LONGEST UNBROKEN CARBON CHAIN:
3 CARBONS
PROP….
♫ note: all carbon to carbon (C-C) are single – alkane!
This compound
follows CnH2n+2( C3H6+2)
CH
H
![Page 4: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/4.jpg)
NAMING ALKANES (CnH2n+2)1. Identify the longest unbroken (by other elements) carbon chain.2. Count the carbons and use table P to get the prefix of the name.3. Identify that the intercarbon bonds are all single, if so the suffix of the
name is --ANE.
CH
H
CH
H
H CH
H
HCH
H
BUT ANEPREFIX SUFFIX
THE LONGEST UNBROKEN CARBON CHAIN IS 4 CARBONS,TABLE P INDICATES THE PREFIX FOR 4 CARBONS IS
BUT
ALL THE INTERCARBON BONDS ARE SINGLE, TABLE R INDICATES AN
ALKANE. ANE
![Page 5: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/5.jpg)
SUBSTITUTED ALKANES
SUBSTITUTION REACTIONS1. HYDROGENS ARE REMOVED AND A HALOGEN IS SUBSTITUTED IN
PLACE OF THE REMOVED HYDROGENS.2. THE PRODUCT WILL HAVE FEWER HYDROGENS THAN THE
REACTANT AND WILL HAVE HALOGEN ATOMS IN THE FORMULA.
C4H10 + Cl2 C4H9Cl + HClAN ALKANE
HALOGEN
HALOHYDROCARBON
HALOGEN ACID
THE HYDROGENS DECREASE FROM 10 TO 9
![Page 6: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/6.jpg)
CH
H
H CH
H
ClCH
H
CH
H
BUT ANEPREFIX SUFFIX
4 3 2 1
CHLORO“SIDE GROUP”
1-CARBON # OF GROUP
ALWAYS NUMBER CARBONS SUCH THAT THE SMALLEST NUMBERS ARE USED IN THE NAME!
![Page 7: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/7.jpg)
CH
HCH
H HC
H
HH C
H
HCH
H
CH
H
CH
H
HCH
H
H CH
HCHH
ISOMERS OF C5H12
n-PENTANE
1234
2- CARBON # OF GROUP
METHYL
“SIDE GROUP”
BUTPREFIX
ANESUFFIX
![Page 8: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/8.jpg)
H
ALKENES (CnH2n)1. THE FUNCTIONAL GROUP IS A DOUBLE BOND.2. THE COMPOUNDS ARE UNSATURATED, THEY CAN BOND TO MORE
HYDROGEN ATOMS BY OPENING THE DOUBLE BOND.
3. THE SUFFIX IS ENE.
CH
H
H CH
H
HC C
H
THE DOUBLE BOND IS THE FUNCTIONAL GROUP OF THE ALKENE.
BUT ENEPREFIX SUFFIX
NONE
“SIDE GROUP”
NONE
CARBON # OF GROUP
2-C # OF FUNCTIONAL GROUP
THIS IS 2-BUTENE BECAUSE THE DOUBLE BOND BEGINS ON THE SECOND CARBON.
4 3 2 1
![Page 9: SIDE GROUP NAME CONDENCED FORMULA STRUCTURAL FORMULA METHYLCH 3 ETHYLC2H5C2H5 PROPYLC3H7C3H7 CHLOROClsame BROMOBrsame IODOIsame c H H H c H H H c H H c.](https://reader036.fdocuments.us/reader036/viewer/2022082418/5697bff61a28abf838cbddd7/html5/thumbnails/9.jpg)
CH
H
H CH
H
CH
CH
H4 3 2 1
BUT ENEPREFIX SUFFIX
NONE
“SIDE GROUP”
NONE
CARBON # OF GROUP
1-C # OF FUNCTIONAL GROUP
♫ NOTE: 1-BUTENE AND 2-BUTENE ARE ISOMERS, THEY HAVE THE SAME FORMULA (C4H8) HOWEVER THEY HAVE
DIFFERENT STRUCTURES.
2 HYDROGENS CAN BE ADDED TO THE DOUBLE BOND,