Series

Reasoning & Quantitative aptitude course series

SITAMS Page 1

SREENIVASA INSTITUTE OF TECHNOLOGY AND

MANAGEMENT STUDIES

Murukambattu Post,Chittoor 517 127 (A.P)

AFFILIATED TO JAWAHARLAL NEHRU TECHNOLOGICAL UNIVERSITY

ANANTAPUR,

Course material

For

Reasoning and Quantative Aptitude

Module Name: Series


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OBJECTIVE :NON VERBAL REASONING

Non verbal reasoning tests measure your ability to recognize patterns, analogies andclassifications in diagrams. They offer multiple choice questionnaires. You are not requiredspecific language skills to solve the problems. Even your acquired knowledge in some particularfield is not tested.

The non verbal reasoning tests have been showing a high level of reliability and a goodpredictive validity. They are considered culturally free IQ tests. They are not only used in jobscreening process but also to recruit students for different academic trainings.

What is non verbal reasoning?

Simply put non verbal reasoning is all reasoning that is not verbal reasoning and verbalreasoning is the ability of reasoning by using concepts framed in words. So actually non verbalreasoning is a term which stands for a broad range of reasoning skills like e.g. abstract reasoning,diaghrammatic reasoning, spatial reasoning, numerical reasoning and many more.

Non-verbal reasoning involves drawing conclusions based on a set of facts either fictional or nonfictional. Exercises include activities like describing the similarities and differences between twopictures, finding the shape that does not belong in a sequence of shapes, predicting what shapeshould next appear in the sequence, and so on. Non-verbal reasoning exercises can also includenumerical and aural activities, where non-speech sounds must be matched, differentiated, orcompared and contrasted and even some syllogisms can be categorized as non verbal reasoning.Fibonicci contains a broad range of these non verbal reasoning problems for you to practice:abstract reasoning testsspatial reasoning testsinstrument comprehension testsnumber sequences tests

Non verbal reasoning in everyday life

But also in the everyday life even though speech is the most obvious form of communication.Ones non verbal reasoning skills are an invaluable asset, since people are constantly bombardedby non verbal impulses, signals and gestures. Actually people use their non verbal intelligencemuch more then their verbal intelligence. Almost everything you will encounter in life you willfirst judge by visual interpretation, because this is simply the easiest, fastest and it can be donewithout drawing attention to oneself. So your first impression of something or somebody isalmost always based on your non verbal reasoning skills. For example if you try to judgesomebody on their looks you are actually using non verbal reasoning to do this.


SITAMS Page 3

Solved Examples:Select a figure from amongst the Answer Figures which will continue the same series asestablished by the five Problem Figures.

Problem Figures: Answer Figures:

(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

1.

A.1 B.2C.3 D.4E.5Answer: Option C

Explanation:

In each step, element at the upper-right position gets enlarged, inverts vertically and reachesthe lower-left corner; the existing element at the lower-left position, is lost and a new smallelement appears at the upper-right position

Select a figure from amongst the Answer Figures which will continue the same series asestablished by the five Problem Figures.


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

2.

A.1 B.2C.3 D.4E.5

Answer: Option B

Explanation:

In each step, the elements move in the sequence.

3. Select a figure from amongst the Answer Figures which will continue the same series asestablished by the five Problem Figures.



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(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2C.3 D.4E.5

Answer: Option D

Explanation:

In each step, the CW-end element moves to the ACW-end position.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

4.

A.1 B.2C.3 D.4E.5

Answer: Option A

Explanation:

Both the larger and the smaller squares move to the adjacent corner ACW in each turn. Also,the shading in the smaller square moves 1, 2, 3, 4, 5, ... steps ACW sequentially and theshading in the larger square moves 1, 2, 3, 4, 5,.... steps CW sequentially.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)


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A.1 B.2C.3 D.4E.5

Answer: Option A

Explanation:

One, two, three, one, two, three.....arcs get inverted sequentially. This inversion takes place inan ACW direction.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

6.

A.1 B.2C.3 D.4E.5

Answer: Option B

Explanation:

Similar figure reappears in every second step. Each time the first figure reappears, the

elements interchange positions in the order : . And, each time the second figure

reappears, the elements interchange positions in the order :



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

7.

A.1 B.2C.3 D.4E.5


SITAMS Page 6

Answer: Option A

Explanation:

In One step, the middle element rotates through 180o and in the next step, the other twoelements rotate through 180o. The two steps are repeated alternately.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

8.

A.1 B.2C.3 D.4E.5

Answer: Option A

Explanation:

The central arrow rotates 90oACW and 45oCW alternately. The half-arrow moves half-a-sideof the square boundary in a CW direction and its head turns to the other side of the line in eachstep.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

9.

A.1 B.2C.3 D.4E.5

Answer: Option D

Explanation:


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The 'T' shaped large element rotates 90oCW in each step. The two small symbols interchangepositions and the symbol that reaches the upper position gets replaced by a new one.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

10.

A.1 B.2C.3 D.4E.5

Answer: Option E

Explanation:

In the first step, the lowermost line segment is converted into a curve. In the second step, thesecond line segment also gets converted into a curve and the (existing curve is inverted. Ineach subsequent step, all the elements (line segments and curves) move in the sequence



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

11.

A.1 B.2C.3 D.4E.5

Answer: Option D

Explanation:

In one step, the existing element enlarges and a new element appears inside this element. Inthe next step, the outer element is lost.

12. Select a figure from amongst the Answer Figures which will continue the same series as


SITAMS Page 8

established by the five Problem Figures.


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2C.3 D.4E.5

Answer: Option E

Explanation:

The number of parts increases by one along with the number of sides in the figure



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

13.

A.1 B.2C.3 D.4E.5

Answer: Option A

Explanation:

In each step, the dot moves one space CW and the arrow moves two spaces CW.




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(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2C.3 D.4E.5

Answer: Option C

Explanation:

One arc and four arcs get inverted alternately.Select a figure from amongst the Answer Figures which will continue the same series asestablished by the five Problem Figures.


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

15.

A.1 B.2C.3 D.4E.5

Answer: Option C

Explanation:

The pin rotates 45oCW and 90oCW alternately and moves one space (each space is equal tohalf-a-side of the square) and two spaces CW alternately. The arrow rotates 90oACW and45oACW alternately and moves two spaces and one space.



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

16.

A.1 B.2C.3 D.4E.5

Answer: Option C


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Explanation:

In each step, the pin rotates 90oCW and the arrow rotates 90oACW.Exercise problems:



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

1.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

2.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

3.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)


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A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

5.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

6.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

7.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)


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A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

8.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

9.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

10.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

11.

A.1 B.2


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C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

12.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

13.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

14.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

15.

A.1 B.2


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C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

16.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

17.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

18.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

19.

A.1 B.2


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C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

20.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

21.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

22.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

23.

A.1 B.2


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C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

24.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

25.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

26.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

27.

A.1 B.2C.3 D.4


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E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

28.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

29.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

30.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

31.

A.1 B.2C.3 D.4


SITAMS Page 18

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

32.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

33.

A.1 B.2C.3 D.4E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

34.

A.1 B.2C.3 D.4E.5




SITAMS Page 19

(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

36.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

37.

A.1 B.2

C.3 D.4

E.5



SITAMS Page 20


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

39.

A.1 B.2

C.3 D.4

E.

5

Select a figure from amongst the Answer Figures which willcontinue the same series as established by the five ProblemFigures.


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

38.

A.1 B.2

C.3 D.4

E.5



SITAMS Page 21



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

41.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

42.

A.1 B.2

C.3 D.4

E.5


SITAMS Page 22



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

43.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

44.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

45.

A.1 B.2

C.3 D.4


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E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

46.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

47.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

48.

A.1 B.2


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C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

49.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

50.

A.1 B.2

C.3 D.4 E.5


SITAMS Page 25

Solutions to Exercise problems:1.Answer: Option C

Explanation:

In each step, the pin rotates 90oCW and the arrow rotates 90oACW

2.Answer: Option B

Explanation:

In one step, the figure gets laterally inverted and one line segment is lost from the upper end ofthe RHS portion of the figure. In the next step, the figure gets laterally inverted and one linesegment is lost from the upper end of the LHS portion of the figure.

3.Answer: Option B

Explanation:

The elements move in the sequence's and alternately.

4.Answer: Option D

Explanation:

All the elements move half-a-side of the square boundary in ACW direction in each step. Also,first, third and fifth elements are replaced by new elements in one step and second, fourth andsixth elements are replaced by new elements in the next step. The two steps are repeatedalternately.

5.Answer: Option E

Explanation:

In the first step, the ACW end element moves two spaces (each space is equal to half-a-side ofthe square boundary) in an ACW direction. In the second step, the CW-end element moves three


SITAMS Page 26

spaces ACW. In the third step, the remaining element moves four spaces ACW. The three stepsare repeated to continue the series.

6.Answer: Option C

Explanation:

The symbols move in the sequence in the first step. In each subsequent step, the symbolsmove in the sequence obtained by rotating the previous sequence through 90oACW. Also, ineach step, the symbol that reaches the encircled position gets replaced by a new one.

7.Answer: Option D

Explanation:

In each step, all the elements move to the adjacent corner (of the square boundary) in a CWdirection and the element that reaches the upper-left corner gets vertically inverted.

8.Answer: Option C

Explanation:

In each step, one line segment is lost from the CW-end of the outer element and a new linesegment appears at the ACW-end. Also, the inner 'L' shaped element rotates 90oCW in each step.

9.Answer: Option D

Explanation:

In each step, the first element moves to the third position and gets replaced by a new element; thesecond and the third elements move to the first and the second positions respectively and theentire figure rotates 90oCW.

10.Answer: Option C

Explanation:


SITAMS Page 27

We can label the arcs as shown . The arcs get inverted in the sequence (1 & 2), (3, 4 & 5),(6 & 1), (2, 3 & 4), (5 & 6),...........

11.Answer: Option A

Explanation:

The elements move in the sequences and alternately. Also, in each step, thesymbol that reaches the encircled position, gets replaced by a new symbol.

12.Answer: Option C

Explanation:

In one step, all the elements get vertically inverted and interchange positions in the sequence

. In the next step, the elements interchange positions in the sequence and the thirdelement gets vertically inverted.

13.Answer: Option A

Explanation:

Three elements (encircled in-the figures below) rotate through 90oCW in each step. This rotation

takes place in the following sequence : Thissequence is repeated to continue the series.

14.Answer: Option C

Explanation:

In each step, all the existing arcs get laterally inverted and a new arc is added which is orientedin a direction opposite to that of the last added arc. The arcs are added at various positions in the

following sequences :

15.Answer: Option B


SITAMS Page 28

Explanation:

In each step, one of the elements-gets laterally inverted.

16.Answer: Option B

Explanation:

All the symbols move CW half the side of the square in each step. The symbols are replaced bynew ones sequentially in an ACW direction

17.Answer: Option E

Explanation:

One of the pins gets inverted in each step. The pins get inverted sequentially from right to left.

18.Answer: Option C

Explanation:

The shading moves in the sequence as shown in the figure: The similar upperelement appears in every fourth step. The lower element is replaced by a new element in everysecond step.

19.Answer: Option E

Explanation:

Five line segments are added in each step to complete the squares in an ACW direction.

20.Answer: Option C

Explanation:

The number of symbols added sequentially is 3, 2, 5, 2, 7, 2, .... These symbols are added to forma sequence of 1, 2, 3, 4, 5, 6 identical symbols.

21.Answer: Option E


SITAMS Page 29

Explanation:

Similar figure appears alternately and each time a figure reappears, all the elements move onestep CW.

22.Answer: Option E

Explanation:

One extra line is added in each step in a set order.

23.Answer: Option C

Explanation:

Similar figure reappears in every fourth step and each time a figure reappears, it rotates through90oACW.

24.Answer: Option E

Explanation:

In one step, the elements move in the sequence and in the next step, the elements move in

the sequence The two steps are repeated alternately.

25.Answer: Option A

Explanation:

The symbol gets vertically inverted and laterally inverted alternately. It also moves in ACWdirection through distances equal to two half-sides (of square boundary) and three half-sidesalternately.

26.Answer: Option A

Explanation:


SITAMS Page 30

The elements interchange positions in the orders and alternately

27.Answer: Option B

Explanation:

The upper-left element gets laterally inverted in first, third, fifth. .... steps; the upper-rightelement gets rotated through 180o is first, fourth, seventh,.... steps; the lower-left element getslaterally inverted in second, fourth, sixth, ... steps; the lower-right element gets rotated through180o in third, sixth,... steps and the pin at the middle-right position gets laterally inverted in everysecond step.

28.Answer: Option E

Explanation:

Three and two arcs are inverted alternately. The central element rotates 90oACW and 180oalternately.

28.Answer: Option C

Explanation:

All the elements together move one space to the right in each step and once they reach therightmost position, then in the next step, they move to the leftmost position. Also, in the firststep, the first (uppermost) and the third elements interchange positions; in the second step, thesecond and the fourth elements interchange positions and in the third step, none of the elementsinterchange positions. These three steps are repeated to continue the series.

29.Answer: Option C

Explanation:

In each step, the elements move in the order

30.Answer: Option B

Explanation:

All the elements move one space ACW (each space is equal to a quadrant of the circle) and getinverted in each step.

31.Answer: Option C


SITAMS Page 31

Explanation:

In each step, the symbols move in the sequence and the symbol that reaches the encircledposition gets replaced by a new one.

32.Answer: Option C

Explanation:

In each step, one dot is lost while another dot is replaced by a cross.

33.Answer: Option C

Explanation:

The elements move in the sequences and alternately. Also, in each step, theelement that reaches the encircled position, gets replaced by a new element.

34.Answer: Option E

Explanation:

In one step, the two elements interchange positions and the smaller element gets enlarged whilethe larger element gets reduced in size. In the next step, the smaller element is replaced by a newsmall element and the larger element is replaced by a new large element.

35.Answer: Option A

Explanation:

In each step, all the symbols move in the sequence

36.Answer: Option D

Explanation:

The symbols move in the sequences and alternately. In each step, the symbol thatreaches the-encircled position gets replaced by a new symbol.


SITAMS Page 32

37.Answer: Option B

Explanation:

Two, three, four, two, three,..... curves get inverted sequentially.

38.Answer: Option A

Explanation:

The symbols move in the sequence in the first step. In each subsequent step, the symbolsmove in the sequence obtained by rotating the previous sequence through 90oCW. Also, in eachstep, the symbol that reaches the encircled position gets replaced by a new one.

39.Answer: Option A

Explanation:

Two and three half-leaves are added to the figure alternately. The addition of half-leaves takesplace in an ACW direction

40..Answer: Option D

Explanation:

The figure gets laterally inverted and vertically inverted alternately.

41.Answer: Option B

Explanation:

The symbols move in the orders and alternately. Also, the symbol at the encircledposition is replaced by a new one in each step.

42.Answer: Option D

Explanation:

In one step, a half-leaf is added to the figure at the ACW-end. In the next step, two half-leavesare added to the figure - one at the ACW-end and the other at the CW-end. Also, in each step, thefigure rotates 45oACW.

43..Answer: Option D


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Explanation:

The symbols '=', '+' and '*' move one step ACW While the symbols 's', 'c' and 'o' move one stepCW each time.

44. Answer: Option C

Explanation:

Similar figure repeats in every third step and each time a figure reappears it gets verticallyinverted.

45. Answer: Option E

Explanation:

In each step, all the existing elements move to the adjacent side (of the square boundary) in aCW direction. The number of black circles decreases by one in first, third, fifth, .... steps and thenumber of arrows increases by one in second, fourth, sixth,... steps.

46.Answer: Option B

Explanation:

In one step, a black circle is added to the figure at the CW-end of the existing circles and a linesegment is added on the upper side. In the next step, a white circle is added to the figure at theACW-end of the existing circles and a line segment is added on the lower side.

47.Answer: Option E

Explanation:

The element having trapezium at its end, rotates 135oACW and the trapezium gets inverted ineach step. The other element rotates 135oACW in one step and it rotates 45oCW and the symbolat its end gets replaced by a new element in the next step.

48.Answer: Option E

Explanation:

The number of 'L' shaped elements in the upper part of the figure increases by one in everysecond step. Also, in each step, the existing 'L' shaped elements rotate 90oCW; the lower two


SITAMS Page 34

elements interchange positions and the element that reaches the lower left corner, gets replacedby a new one.

49. Answer: Option B

Explanation:

The elements move in the sequences and alternately. Also, in each step, theelement that reaches the encircled position, gets replaced by a new element.

50.Answer: Option D

Explanation:

In each step, the symbols move in the sequence and the symbol that reaches the encircledposition gets replaced by a new symbol.


SITAMS Page 35

Question bank for mock test:Select a figure from amongst the Answer Figures which will continue the same series asestablished by the five Problem Figures.


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

1.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

2.

A.1 B.2

C.3 D.4

E.5



SITAMS Page 36



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

4.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

5.

A.1 B.2

C.3 D.4

E.5


SITAMS Page 37



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

6.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

7.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

8.

A.1 B.2

C.3 D.4


SITAMS Page 38

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

9.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

10.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

11.

A.1 B.2


SITAMS Page 39

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

12.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

13.

A.1 B.2

C.3 D.4

E.5




SITAMS Page 40

(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

15.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

16.

A.1 B.2

C.3 D.4

E.5



SITAMS Page 41


(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

18.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

19.

A.1 B.2

C.3 D.4

E.5



SITAMS Page 42



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

21.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

22.

A.1 B.2

C.3 D.4

E.5


SITAMS Page 43



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

23.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

24.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

25.

A.1 B.2

C.3 D.4

E.5


SITAMS Page 44



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

26.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

27.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

28.

A.1 B.2

C.3 D.4


SITAMS Page 45

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

29.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

30.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

31.

A.1 B.2


SITAMS Page 46

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

32.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)

33.

A.1 B.2

C.3 D.4

E.5



(A) (B) (C) (D) (E) (1) (2) (3) (4) (5)


SITAMS Page 47

A.1 B.2

C.3 D.4

E.5

35.

A.1 B.2

C.3 D.4

E.5

36.

A.1 B.2

C.3 D.4

E.5

37.

A.1 B.2

C.3 D.4

E.5

38.

A.1 B.2


SITAMS Page 48

C.3 D.4

E.5

39.

A.1 B.2

C.3 D.4

E.5

40.

A.1 B.2

C.3 D.4

E.5

41.

A.1 B.2

C.3 D.4

E.5

42.

A.1 B.2

C.3 D.4

E.5

43.


SITAMS Page 49

A.1 B.2

C.3 D.4

E.5

44 .

A.1 B.2

C.3 D.4

E.5

45.

A.1 B.2

C.3 D.4

E.5

46.

A.1 B.2

C.3 D.4

E.5

47.


SITAMS Page 50

A.1 B.2

C.3 D.4

E.5

48.

A.1 B.2

C.3 D.4

E.5

49.

A.1 B.2

C.3 D.4

E.5

50.

A.1 B.2

C.3 D.4

E.5


SITAMS Page 51

Solutions to the mock test:1.Answer: Option E

Explanation:

The shading moves upwards sequentially from lower-left corner to the upper-right corner of therhombus and once it reaches the upper-right corner, it moves to the lower-left corner in the nextstep. Also, in each step, all the symbols move to the adjacent side (of the rhombus) in a CWdirection and the symbol that reaches the LHS position gets replaced by a new symbol.

2.Answer: Option E

Explanation:

The small line segment attached to the main figure moves 2,1, 3,1, 4,... spaces CW sequentially.

3.Answer: Option C

Explanation:

One dot and one line segment are added to the figure in each step, once to the LHS and next tothe RHS part of the figure.

4.Answer: Option D

Explanation:

The line segment rotates through 90o and moves to the adjacent portion of the rhombus in anACW direction in first, third, fifth, ... steps. The other symbol moves to the adjacent portion ofthe rhombus in an ACW direction and also gets replaced by a new symbol in second, fourth,sixth,... steps.

5.Answer: Option D


SITAMS Page 52

Explanation:

The bent pin gets laterally inverted and vertically inverted alternately and moves to the adjacentside (of the square boundary) in a CW direction in each step,. The curved arrow rotates 90oACWand moves to the adjacent side CW in each step. As for the third element - in one step the outer'L' shaped symbol gets laterally inverted and in the next step the element gets vertically inverted.Or, similar figure reappears in every fourth step. So, after fig. (E), the fig. (B) should reappear.

6.Answer: Option C

Explanation:

The elements move in the sequences and alternately. Also, in each step, theelement at the encircled position gets replaced by a new element.

7. Answer: Option D

Explanation:

The diagonals of the hexagon are drawn in a sequence - (1, 3), (1, 4), (1, 5), (2, 4), (2, 5), (2, 6),(3, 5), (3, 6), (4, 6).

8. Answer: Option C

Explanation:

The two elements together move two spaces (each space is equal to half-a-side of the squareboundary) and three space ACW alternately. Also, in one step, the two elements interchangepositions and together rotate 90oCW and in the next step, the two elements interchange positionsand together rotate through 180o.

9.Answer: Option E

Explanation:

In each step, all the elements move to the adjacent corner (of the square boundary) in an ACWdirection. Also, the elements that reach the lower-right and upper-left positions get verticallyinverted alternately.

10.Answer: Option C

Explanation:


SITAMS Page 53

The symbols move in the sequences and alternately.

11.Answer: Option D

Explanation:

In each step, the symbols move in the order and the symbol that reaches the upper-leftposition gets replaced by a new one.

12.Answer: Option C

Explanation:

The '=' sign moves to the adjacent position in a CW direction in each step. The symbol at theACW-end position in fig. (A), moves to the adjacent position in an ACW direction in each stepand gets replaced by a new symbol in first, third, fifth, ... steps. The symbol at the CW-endposition in fig. (A), moves to the adjacent position in an ACW direction in each step and getsreplaced by a new symbol in second, fourth, sixth, ... steps.

13.Answer: Option E

Explanation:

In each step, the elements move in the sequence and the element that reaches theencircled position gets replaced by a new element.

14.Answer: Option A

Explanation:

Two elements are added in each step, be it two lines, two arcs or one line and one arc

15.Answer: Option E

Explanation:

The arrow moves one, two, three, four, .... spaces ACW sequentially. The arrowhead changes inthe sequence: circle -> arc -> triangle -> circle -> ...

16.Answer: Option E


SITAMS Page 54

Explanation:

In each step, all the existing curves get inverted and one of the line segments gets converted to acurve.

17.Answer: Option B

Explanation:

The symbols move in sequences and alternately. In each step, the symbol thatreaches the encircled position gets replaced by a new symbol.

18.Answer: Option B

Explanation:

In the first step, the V sign moves half-a-side of the square boundary in an ACW direction; in thesecond step, the black circle moves half-a-side of the square boundary in an ACW direction andin the third step, the triangle moves half-a-side of the square boundary in an ACW direction. Thethree steps are repeated to continue the series.

19.Answer: Option B

Explanation:

The pin moves 1, 2, 3, 4, 5, .... spaces CW sequentially. The arrow moves two steps ACW eachtime.

20.Answer: Option E

Explanation:In the first step, the elements interchange positions in the sequence . In eachsubsequent step, the elements move in the sequence obtained by rotating the previous sequencethrough 90oCW. Also, in each step, the element that reaches the encircled position gets replacedby a new element.

21. Answer: Option A

Explanation:

Similar figure appears in every second step and each time a figure reappears, it rotates 90oCW.

22. Answer: Option D

Explanation:


SITAMS Page 55

We shall assign numbers to the pins as : . Then, in each step, the pins at positions 1,3 and5 rotate 90oCW while the pins at positions 2,4 and 6 rotate 90oACW. Also, in each step, a newpin is added to the figure and its orientations are the same as that of the pin in fig. (A).

23.Answer: Option A

Explanation:

In each step, one line disappears from the upper part of the figure and one line is added to thelower part of the figure.

24.Answer: Option D

Explanation:

A new feature is added at each step (in a set order).


Explanation:

The symbols move in the sequences and alternately.

26.Answer: Option A

Explanation:

Two and four 'V' shaped elements get inverted alternately

27.Answer: Option E

Explanation:

In each step, both the elements move one space (each space is equal to half-a-side of the squareboundary) downwards. Once any of the two elements reaches the lowermost position, then in thenext step, it reaches the uppermost position in the next column to the right.

28.Answer: Option A

Explanation:

The V sign moves two spaces (each space is equal to half-a-side of the square boundary) and onespace ACW alternately. The '=' sign moves one space and two spaces ACW alternately.


SITAMS Page 56

29.Answer: Option D

Explanation:

One of the designs (with white triangle at the centre) moves CW while the other design (withblack triangle at the centre) moves ACW.


Explanation:

In each step, the upper element is lost; the middle element reduces in size and becomes the upperelement; the lower element enlarges and becomes the middle element and a new element appearsat the lower position.

31.Answer: Option B

Explanation:

If we label the four elements in the figure as ; then the arrow at position 1-rotates45oACW and 135oACW alternately; the element at position 2 rotates 90oACW and moves toposition 3 in each step; the element at position 3 rotates 90oACW and moves to position 4 ineach step and the element at position 4 moves to position 2 and gets replaced by a new elementin each step.

32.Answer: Option B

Explanation:

In the first step, the elements at the four ends move in the sequence . In each subsequentstep, the elements move in the sequence obtained by rotating the previous sequence through90oACW. Also, in each step, the element that reaches the encircled position gets replaced by anew element.

33.Answer: Option A

Explanation:In one step, one half-leaf is lost from the CW-end and three half-leaves are addedat the ACW-end. In the next step, one half-leaf is lost from the CW-end and two half-leaves areadded at the ACW-end.

34.Answer: Option A


SITAMS Page 57

Explanation: One circle is replaced by a new symbol in each step and this replacement takesplace on either ends alternately. The complete figure rotates 45oACW in each step.

35 Answer: Option E

Explanation: One line is removed from one end of the figure and one line is added to the otherend of the figure, in each step.


Explanation: The shading moves.ACW one, two, three steps sequentially.


Explanation: The line inside the square rotates by 45 degrees and so does the arrow .but eachtime the arrow reverses its direction.

38.Answer: Option A

Explanation: Two identical signs appear while one of the initially existing identical signsdisappears in each step.


Explanation: in one turn, the symbols move one step CW.In the next turn ,they move two stepsCW and a new symbol is added behind the pre-existing symbols. The process repeats.


Explanation: Similar figure appears in alternate steps and each time it reappears, it gets rotatedthrough an angle of 180..


Explanation: Lines are removed from the L.H.S and R.H.S alternately.


Explanation: The circle moves two steps ACW while the arc rotates 90. ACW and moves twosteps CW in each step.


Explanation: The cross moves vertically down in one step and the - sign moves to the left inthe alternate step.


SITAMS Page 58


Explanation: The circle and the square move end to end in an ACW direction, while trianglemoves up and down alternately.

45. Answer: Option B

Explanation: Figure rotates 90 CW in each step. so fig(A) should repeat.


Explanation: The exchange of positions of signs takes place, first up down and then sideways.


Explanation: The small lines at the two ends of the central vertical line first open 45successfully and then converge again by 45 successfully.


Explanation: in each step, the shading moves one step CW and the dot and the arrow move onestep ACW.


Explanation: The similar central figures repeat in alternate steps and the trapezium resting onthe side of the square of the square boundary moves 90 CW in each step.


Explanation: Each time, all the existing arcs get reversed and a new arc is added moving two,Two, one, two.. Steps clockwise sequentially.

.

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