Section 8.2

14
Section 8.2 Factoring Using the Distributive Property

description

Section 8.2. Factoring Using the Distributive Property. Factor polynomials by using the Distributive Property. Solve quadratic equations of the form ax 2 + bx = 0. factoring. factoring by grouping Zero Products Property roots. Factor by Using the Distributive Property. - PowerPoint PPT Presentation

Transcript of Section 8.2

Page 1: Section  8.2

Section 8.2Factoring Using the Distributive Property

Page 2: Section  8.2

• factoring• factoring by grouping• Zero Products Property• roots

• Factor polynomials by using the Distributive Property.

• Solve quadratic equations of the form ax2 + bx = 0.

Page 3: Section  8.2

Factor by Using the Distributive Property

In Ch.7, you used the distributive property to multiply a polynomialby a monomial.

2a(6a + 8) = 2a(6a) + 2a(8) = 12a² + 16a

You can reverse this process to express a polynomial as the productof a monomial factor and a polynomial factor.

12a² + 16a = 2a(6a) + 2a(8) = 2a(6a + 8)

Factoring a polynomial means to find its completely factored form.

Page 4: Section  8.2

Use the Distributive Property

A. Use the Distributive Property to factor 15x + 25x2.First, find the GCF of 15x + 25x2.

15x = 3 ● 5 ● x Factor each monomial.

25x2 = 5 ● 5 ● x ● x Circle the common prime factors.

GCF: 5 ● x or 5xWrite each term as the product of the GCF and its remaining factors. Then use the Distributive Property to factor out the GCF.15x + 25x2 = 5x(3) + 5x(5 ● x) Rewrite each term using

the GCF.

Page 5: Section  8.2

Use the Distributive Property

= 5x(3) + 5x(5x) Simplify remaining factors.

= 5x(3 + 5x) Distributive Property

Answer: 5x(3 + 5x)

Page 6: Section  8.2

Use the Distributive Property

B. Use the Distributive Property to factor 12xy + 24xy2 – 30x2y4.

12xy =2 ● 2 ● 3 ● x ● y Factor each monomial.

24xy2 = 2 ● 2 ● 2 ● 3 ● x ● y ● y

30x2y4 =2 ● 3 ● 5 ● x ● x ● y ● y ● y ● y

GCF: 2 ● 3 ● x ● y or 6xy

12xy + 24xy2 – 30x2y4 = 6xy(2) + 6xy(4y) + 6xy(–5xy3) Rewrite each term using the GCF.

Circle the common prime factors.

Page 7: Section  8.2

Use the Distributive Property

= 6xy(2 + 4y – 5xy3) Distributive Property

Answer: The factored form of 12xy + 24xy2 – 30x2y4 is 6xy(2 + 4y – 5xy3).

Page 8: Section  8.2

Using the Distributive Property to factor polynomials having four or more terms is called factoring by grouping because pairs of termsare grouped together and factored.

Page 9: Section  8.2

Use Grouping

Factor 2xy + 7x – 2y – 7.

2xy + 7x – 2y – 7 = (2xy – 2y) + (7x – 7)

Group terms with common factors.= 2y(x – 1) + 7(x – 1)Factor the GCF from each grouping.

= (x – 1)(2y + 7) Distributive Property

Answer: (x – 1)(2y + 7)

Page 10: Section  8.2

Recognizing binomials that are additive inverses is often helpful whenfactoring by grouping.

• For example, 7 - y and y – 7 are additive inverses.

• By rewriting 7 - y as -1(y – 7), factoring by grouping is possible

Page 11: Section  8.2

Use the Additive Inverse Property

Factor 15a – 3ab + 4b – 20.15a – 3ab + 4b – 20 = (15a – 3ab) + (4b – 20)

Group terms with common factors.

= 3a(5 – b) + 4(b – 5)Factor GCF from each grouping.

= 3a(–1)(b – 5) + 4(b – 5)5 – b = –1(b – 5)

= –3a(b – 5) + 4(b – 5)3a(–1) = –3a

Answer: = (b – 5)(–3a + 4) Distributive Property

Page 12: Section  8.2

Some equations can be solved by factoring. Consider the following:

6(0) = 0 0(-3) = 0 (5 – 5)(0) = 0 -2(-3 + 3) = 0

Notice that in each case, at least one of the factors is zero.

The solutions of an equation are called the roots of the equation.

Page 13: Section  8.2

A. Solve (x – 2)(4x – 1) = 0. Check the solution.If (x – 2)(4x – 1) = 0, then according to the Zero Product Property, either x – 2 = 0 or 4x – 1 = 0.(x – 2)(4x – 1) = 0 Original equationx – 2 = 0 or 4x – 1 = 0 Set each factor equal to zero. x = 2 4x = 1 Solve each equation.

Solve an Equation

Page 14: Section  8.2

Homework Assignment #43

8.2 Skills Practice Sheet