Se Parador Multi Fa Sico 19

INDUACEROPANAMERICANA SUR KM. 4

LATACUNGA - ECUADOR

Item: SEPARADOR MULTIFASICO CAPACIDAD5m3Vessel No: V-3001ACustomer: REPSOL - YPF

O.J.: I-1226Designer: FERNANDO REAL

Date: jueves, diciembre 08, 2011

PREPARED BY: FERNANDO REAL

REVIEWED BY: FERNANDO REAL

ACCEPTED BY: MARIA MORA

Table Of ContentsGeneral Arrangement Drawing1. Nozzle Schedule2. Nozzle Summary3. Pressure Summary4. Revision History5. Settings Summary6. Thickness Summary7. Weight Summary8. Long Seam Summary9. Hydrostatic Test10. Seismic Code11. Wind Code12. Top Head13. Straight Flange on Top Head14. Cylinder #115. Cylinder #216. Straight Flange on Bottom Head17. Bottom Head18. LEVEL TRANSMITER (N1A)19. LEVEL TRANSMITER (N1B)20. OUTLET (N2)21. RELIEF GAS (N3)22. CONDENSATE OUTLET (N4)23. HIGH LEVEL SWITCH (N5B)24. LOW LEVEL SWITCH (N6A)25. LEVEL GAUGE (N7A)26. LEVEL GAUGE (N7B)27. SPARE (N8A)28. SPARE (N8B)29. PRESSURE INDICATOR (N9)30. PRESSURE TRANSMITER (N10)31. TEMPERATURE INDICATOR (N11)32. TEMPERATURE TRANSMITER (N12)33. MANHOLE (N14)34. OUT DRAIN (N16)35. Lifting Lug #136. Lifting Lug #237.

Support Skirt38. Base Ring39. Skirt Opening #140. Skirt Opening #241.

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Nozzle Schedule

Nozzlemark

Service SizeMaterials

Nozzle Impact Norm FineGrain Pad Impact Norm Fine

Grain Flange

N10 PRESSURE TRANSMITER NPS 1 Class 3000 -threaded SA-105 No No No N/A N/A N/A N/A N/A

N11 TEMPERATUREINDICATOR

NPS 1 Class 3000 -threaded SA-105 No No No N/A N/A N/A N/A N/A

N12 TEMPERATURETRANSMITER

NPS 1 Class 3000 -threaded SA-105 No No No N/A N/A N/A N/A N/A

N14 MANHOLE 23,06 IDx0,47 SA-516 70 No No No SA-51670 No No No SO A105 Class

150

N16 OUT DRAIN NPS 4 Sch 40 (Std) SA-106 B Smlspipe No No No SA-516

70 No No No N/A

N1A LEVEL TRANSMITER NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N1B LEVEL TRANSMITER NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N2 OUTLET NPS 6 Sch 40 (Std) SA-106 B Smlspipe No No No SA-516

70 No No No WN A105 Class150

N3 RELIEF GAS NPS 6 Sch 40 (Std) SA-106 B Smlspipe No No No SA-516

70 No No No WN A105 Class150

N4 CONDENSATE OUTLET NPS 4 Sch 40 (Std) SA-106 B Smlspipe No No No SA-516

70 No No No N/A

N5B HIGH LEVEL SWITCH NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N6A LOW LEVEL SWITCH NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N7A LEVEL GAUGE NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N7B LEVEL GAUGE NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N8A SPARE NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N8B SPARE NPS 2 Sch 40 (Std) SA-106 B Smlspipe No No No N/A N/A N/A N/A WN A105 Class

150

N9 PRESSURE INDICATOR NPS 1 Class 3000 -threaded SA-105 No No No N/A N/A N/A N/A N/A

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Nozzle Summary

Nozzlemark

OD(in)

tn(in)

Req tn(in)

A1? A2?Shell Reinforcement

Pad Corr(in)

Aa/A

r(%)Nom t

(in)Design t

(in)User t

(in)Width

(in)tpad(in)

N10 1,75 0,2175 0,0625 Yes Yes 0,5 N/A N/A N/A 0 Exempt



N14 24 0,4724 0,2531 Yes Yes 0,5 0,4561 6 0,5 0,125 100,0

N16 4,5 0,237 0,237 Yes Yes 0,528* 0,528 2 0,5 0 101,1

N1A 2,375 0,154 0,154 Yes Yes 0,5 N/A N/A N/A 0 Exempt

N1B 2,375 0,154 0,154 Yes Yes 0,5 N/A N/A N/A 0 Exempt

N2 6,625 0,28 0,28 Yes Yes 0,5 0,5 2 0,5 0 112,9

N3 6,625 0,28 0,28 Yes Yes 0,5 0,5 2 0,5 0 112,9

N4 4,5 0,237 0,237 Yes Yes 0,528* 0,528 2 0,5 0 114,2








tn: Nozzle thicknessReq tn: Nozzle thickness required per UG-45/UG-16Nom t: Vessel wall thicknessDesign t: Required vessel wall thickness due to pressure + corrosion allowance per UG-37User t: Local vessel wall thickness (near opening)Aa: Area available per UG-37, governing conditionAr: Area required per UG-37, governing conditionCorr: Corrosion allowance on nozzle wall* Head minimum thickness after forming

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Pressure Summary

Pressure Summary for Chamber bounded by Bottom Head and Top Head

IdentifierP

Design( psi)

TDesign

( °F)

MAWP( psi)

MAP( psi)

MDMT( °F)

MDMTExemption

ImpactTested

Top Head 200 150 268,67 351,38 -24,8 Note 1 No

Straight Flange on Top Head 200 150 265,42 348,32 -24,8 Note 2 No

Cylinder #1 200 150 247,12 330,03 -55 Note 3 No

Cylinder #2 200 150 247,12 330,03 -55 Note 3 No

Straight Flange on Bottom Head 200 150 265,42 348,32 -24,8 Note 2 No

Bottom Head 200 150 268,67 351,38 -24,8 Note 4 No

PRESSURE TRANSMITER (N10) 200 150 247,11 330,03 -155 Note 5 No

TEMPERATURE INDICATOR (N11) 200 150 247,11 330,03 -155 Note 5 No

TEMPERATURE TRANSMITER (N12) 200 150 247,11 330,03 -155 Note 5 No

MANHOLE (N14) 200 150 218,36 266,8 -20 Nozzle Note 6 No

Pad Note 7 No

OUT DRAIN (N16) 200 150 298,06 390,35 -33,8 Nozzle Note 8 No

Pad Note 9 No

LEVEL TRANSMITER (N1A) 200 150 247,11 285 -43,4 Note 10 No

LEVEL TRANSMITER (N1B) 200 150 247,11 285 -43,4 Note 10 No

OUTLET (N2) 200 150 247,11 285 -20 Nozzle Note 11 No

Pad Note 7 No

RELIEF GAS (N3) 200 150 247,11 285 -20 Nozzle Note 11 No

Pad Note 7 No

CONDENSATE OUTLET (N4) 200 150 298,06 390,35 -33,8 Nozzle Note 8 No

Pad Note 9 No

HIGH LEVEL SWITCH (N5B) 200 150 247,11 285 -43,4 Note 10 No

LOW LEVEL SWITCH (N6A) 200 150 247,11 285 -43,4 Note 10 No

LEVEL GAUGE (N7A) 200 150 247,11 285 -43,4 Note 10 No

LEVEL GAUGE (N7B) 200 150 247,11 285 -43,4 Note 10 No

SPARE (N8A) 200 150 247,11 285 -43,4 Note 10 No

SPARE (N8B) 200 150 247,11 285 -43,4 Note 10 No

PRESSURE INDICATOR (N9) 200 150 247,11 330,03 -155 Note 5 No

Chamber design MDMT is -20 °FChamber rated MDMT is -20 °F @ 218,36 psi

Chamber MAWP hot & corroded is 218,36 psi @ 150 °F

Chamber MAP cold & new is 266,8 psi @ 70 °F

This pressure chamber is not designed for external pressure.

5/192

Notes for MDMT Rating:

Note # Exemption Details

1. Straight Flange governs MDMT

2. Material impact test exemption temperature from Fig UCS-66 Curve B = -7 °FFig UCS-66.1 MDMT reduction = 17,8 °F, (coincident ratio = 0,8215) UCS-66 governing thickness = 0,5 in

3.Material impact test exemption temperature from Fig UCS-66 Curve D = -55 °FFig UCS-66.1 MDMT reduction = 11,7 °F, (coincident ratio = 0,8829)Rated MDMT of -66,7°F is limited to -55°F by UCS-66(b)(2)

UCS-66 governing thickness = 0,5 in

4. Straight Flange governs MDMT

5. Nozzle is impact test exempt to -155 °F per UCS-66(b)(3) (coincident ratio = 0,0332).

6.Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -9,65 °FFig UCS-66.1 MDMT reduction = 119,2 °F, (coincident ratio = 0,3686)Rated MDMT of -128,85°F is limited to -55°F by UCS-66(b)(2)

UCS-66 governing thickness = 0,4724 in.

7. Pad is impact test exempt per UG-20(f) UCS-66 governing thickness = 0,5 in.

8. Nozzle is impact test exempt per UCS-66(d) (NPS 4 or smaller pipe).

9. Pad impact test exemption temperature from Fig UCS-66 Curve B = -7 °FFig UCS-66.1 MDMT reduction = 26,8 °F, (coincident ratio = 0,7323) UCS-66 governing thickness = 0,5 in.

10. Flange rating governs: UCS-66(b)(1)(b)

11. Nozzle is impact test exempt to -155 °F per UCS-66(b)(3) (coincident ratio = 0,1593).

Design notes are available on the Settings Summary page.

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Revision History

No. Date Operator Notes

0 12/ 8/2011 Administrador New vessel created with Vessel Wizard, ASME Section VIII Division 1 [COMPRESS Build 7140]

7/192

Settings Summary

COMPRESS 2012 Build 7200

Units: U.S. Customary

Datum Line Location: 0,00" from bottom seam

Design

ASME Section VIII Division 1, 2010 Edition

Design or Rating: Get Thickness from PressureMinimum thickness: 0,0625" per UG-16(b)Design for cold shut down only: NoDesign for lethal service (full radiography required): No

Design nozzles for: Design P, find nozzle MAWP andMAP

Corrosion weight loss: 100% of theoretical lossUG-23 Stress Increase: 1,20Skirt/legs stress increase: 1,0Minimum nozzle projection: 1"Juncture calculations for α > 30 only: YesPreheat P-No 1 Materials > 1,25&#34 and <= 1,50" thick: NoUG-37(a) shell tr calculation considers longitudinal stress: NoButt welds are tapered per Figure UCS-66.3(a).

Hydro/Pneumatic Test

Shop Hydrotest Pressure: 1,3 times vessel MAPTest liquid specific gravity: 1,00Maximum stress during test: 90% of yield

Required Marking - UG-116

UG-116(e) Radiography: RT1UG-116(f) Postweld heat treatment: None

Code Cases\Interpretations

Use Code Case 2547: NoApply interpretation VIII-1-83-66: YesApply interpretation VIII-1-86-175: YesApply interpretation VIII-1-83-115: YesApply interpretation VIII-1-01-37: YesNo UCS-66.1 MDMT reduction: NoNo UCS-68(c) MDMT reduction: NoDisallow UG-20(f) exemptions: No

UG-22 Loadings

UG-22(a) Internal or External Design Pressure : YesUG-22(b) Weight of the vessel and normal contents under operating or test conditions: YesUG-22(c) Superimposed static reactions from weight of attached equipment (external loads): NoUG-22(d)(2) Vessel supports such as lugs, rings, skirts, saddles and legs: YesUG-22(f) Wind reactions: YesUG-22(f) Seismic reactions: YesUG-22(j) Test pressure and coincident static head acting during the test: NoNote: UG-22(b),(c) and (f) loads only considered when supports are present.

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Thickness Summary

ComponentIdentifier

Material Diameter(in)

Length(in)

Nominal t(in)

Design t(in)

Total Corrosion(in)

JointE

Load

Top Head SA-516 70 60 ID 15,528 0,528* 0,4249 0,125 1,00 Internal

Straight Flange on Top Head SA-516 70 60 ID 2 0,528 0,4281 0,125 1,00 Internal

Cylinder #1 SA-516 70 60 ID 24 0,5 0,4281 0,125 1,00 Internal

Cylinder #2 SA-516 70 60 ID 96 0,5 0,4281 0,125 1,00 Internal

Straight Flange on Bottom Head SA-516 70 60 ID 2 0,528 0,4281 0,125 1,00 Internal

Bottom Head SA-516 70 60 ID 15,528 0,528* 0,4249 0,125 1,00 Internal

Support Skirt SA-36 60,875 ID 41,75 0,5906 0,0054 0 0,55 Seismic

Nominal t: Vessel wall nominal thickness

Design t: Required vessel thickness due to governing loading + corrosion

Joint E: Longitudinal seam joint efficiency

* Head minimum thickness after forming

Load

internal: Circumferential stress due to internal pressure governs

external: External pressure governs

Wind: Combined longitudinal stress of pressure + weight + wind governs

Seismic: Combined longitudinal stress of pressure + weight + seismic governs

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Weight Summary

ComponentWeight ( lb) Contributed by Vessel Elements

Surface Areaft2Metal

New*Metal

Corroded* Insulation InsulationSupports Lining Piping

+ LiquidOperating

Liquid Test Liquid

New Corroded New Corroded

Top Head 690,2 529,4 0 0 0 0 0 0 1.224,7 1.243,5 34

Cylinder #1 634,3 476,8 0 0 0 0 0 0 2.463,2 2.483,7 31

Cylinder #2 2.512,8 1.888,6 0 0 0 0 0 0 9.948,8 10.033,8 124

Bottom Head 685,4 525,7 0 0 0 0 0 0 1.230,6 1.249,4 34

Support Skirt 1.347,5 1.347,5 0 0 0 0 0 0 0 0 113

Base Ring 351 351 0 0 0 0 0 0 0 0 34

TOTAL: 6.221,3 5.119 0 0 0 0 0 0 14.867,4 15.010,4 370

* Shells with attached nozzles have weight reduced by material cut out for opening.

ComponentWeight ( lb) Contributed by Attachments

Surface Areaft2Body Flanges Nozzles &

Flanges PackedBeds

Ladders &Platforms

Trays TraySupports

Rings &Clips

VerticalLoads

New Corroded New Corroded

Top Head 0 0 0 0 0 0 0 0 6,9 0 1

Cylinder #1 0 0 87,8 87,3 0 0 0 0 0 0 5

Cylinder #2 0 0 970,9 937,5 0 0 0 0 0 0 21

Bottom Head 0 0 30,2 26,8 0 0 0 0 0 0 1

Support Skirt 0 0 22,6 22,6 0 0 0 0 0 0 0

TOTAL: 0 0 1.111,4 1.074,2 0 0 0 0 6,9 0 28

Vessel operating weight, Corroded: 6.200 lbVessel operating weight, New: 7.340 lbVessel empty weight, Corroded: 6.200 lbVessel empty weight, New: 7.340 lbVessel test weight, New: 22.207 lbVessel test weight, Corroded: 21.210 lbVessel surface area: 398 ft2

Vessel center of gravity location - from datum - lift condition

Vessel Lift Weight, New: 7.340 lbCenter of Gravity: 34,9714"

Vessel Capacity

Vessel Capacity** (New): 1.763 US galVessel Capacity** (Corroded): 1.779 US gal**The vessel capacity does not include volume of nozzle, piping or other attachments.

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Long Seam Summary

Shell Long SeamAngles

Component Seam 1

Cylinder #1 180°

Cylinder #2 90°

Support Skirt 0°

Shell Plate Lengths

Component StartingAngle Plate 1

Cylinder #1 180° 190,0664"

Cylinder #2 90° 190,0664"

Support Skirt 0° 193,0999"

*North is located at 0°*Plate Lengths use the circumfrence of the vessel based on the mid diameter of the components

Shell Rollout

11/192

Hydrostatic Test

Shop test pressure determination for Chamber bounded by Bottom Head and Top Head based on MAP per UG-99(c)

Shop hydrostatic test gauge pressure is 344,957 psi at 70 °F

The shop test is performed with the vessel in the horizontal position.

Identifier MAPpsi

Testpressure

psi

Test liquidstatic head

psi

UG-99(c)pressure

factorTop Head 348,322 347,502 2,545 1,30

Straight Flange on Top Head 348,322 347,502 2,545 1,30

Cylinder #1 330,033 347,502 2,545 1,30

Cylinder #2 330,033 347,502 2,545 1,30

Straight Flange on Bottom Head 348,322 347,502 2,545 1,30

Bottom Head 348,322 347,502 2,545 1,30

CONDENSATE OUTLET (N4) 390,35 346,852 1,896 1,30

HIGH LEVEL SWITCH (N5B) 285 347,182 2,225 1,30

LEVEL GAUGE (N7A) 285 345,901 0,944 1,30

LEVEL GAUGE (N7B) 285 345,901 0,944 1,30

LEVEL TRANSMITER (N1A) 285 347,881 2,924 1,30

LEVEL TRANSMITER (N1B) 285 347,881 2,924 1,30

LOW LEVEL SWITCH (N6A) 285 347,703 2,747 1,30

MANHOLE (N14) (1) 266,796 346,835 1,878 1,30

OUT DRAIN (N16) 390,35 346,491 1,535 1,30

OUTLET (N2) 285 345,318 0,361 1,30

PRESSURE INDICATOR (N9) 330,031 347,007 2,051 1,30

PRESSURE TRANSMITER (N10) 330,031 346,639 1,683 1,30

RELIEF GAS (N3) 285 345,718 0,761 1,30

SPARE (N8A) 285 345,484 0,527 1,30

SPARE (N8B) 285 345,484 0,527 1,30

TEMPERATURE INDICATOR (N11) 330,031 346,251 1,294 1,30

TEMPERATURE TRANSMITER (N12) 330,031 345,889 0,932 1,30

Notes:(1) MANHOLE (N14) is the component that determines the test pressure.(2) The zero degree angular position is assumed to be up, and the test liquid height is assumed to the top-most flange.

The field test condition has not been investigated for the Chamber bounded by Bottom Head and Top Head.

The test temperature of 70 °F is warmer than the minimum recommended temperature of 30 °F so the brittle fracture provision ofUG-99(h) has been met.NOTE: Figure UCS 66.2 general note (6) has been applied.

12/192

Seismic Code

Method of seismic analysis: ASCE 7-05 groundsupported

Site Class CImportance Factor: I = 1,0000Spectral Response Acceleration at short period (% g) Ss = 75,00%Spectral Response Acceleration at period of 1 sec (% g) S1 = 75,00%Response Modification Coeficient from Table 15.4-2 R = 3,0000Acceleration based site co-efficient: Fa = 1,1000Velocity based site co-efficient: Fv = 1,3000Long-period transition period: TL = 12,0000Redundancy factor: ρ = 1,0000User Defined Vertical Accelerations Considered: No

12.4.2.3 Basic Load Combinations for Allowable Stress DesignThe following load combinations are considered in accordance with ASCE section 2.4.1:

5. D + P + Ps + 0.7E = (1.0 + 0.14SDS)D + P + Ps + 0.7ρQE8. 0.6D + P + Ps + 0.7E = (0.6 - 0.14SDS)D + P + Ps + 0.7ρQEWhereD = Dead loadP = Internal or external pressure loadPs = Static head loadE = Seismic load = Eh +/- Ev = ρQE +/- 0.2SDSD

Vessel Characteristics

Vessel height: 15,2069 ftVessel Weight:

Operating, Corroded: 6.200 lbEmpty, Corroded: 6.200 lb

Period of Vibration Calculation

Fundamental Period, T:Operating, Corroded: 0,013 sec (f = 74,9 Hz)

Empty, Corroded: 0,013 sec (f = 75,2 Hz)

The fundamental period of vibration T (above) is calculated using the Rayleigh method of approximation:

T = 2 * PI * Sqr( {Sum(Wi * yi2 )} / {g * Sum(Wi * yi )} ), where

Wi is the weight of the ith lumped mass, andyi is its deflection when the system is treated as a cantilever beam.

Seismic Shear Reports:

Operating, CorrodedEmpty, CorrodedBase Shear Calculations

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Seismic Shear Report: Operating, Corroded

Component Elevation of bottomabove base (in)

Elastic modulus E(106 psi)

Inertia I(ft4)

Seismic shear atBottom (lbf)

Bending Moment atBottom (lbf-ft)

Top Head 164,9548 29,0 * 140 104

Cylinder #1 140,9548 29,0 1,5825 270 789

Cylinder #2 44,9548 29,0 1,5825 632 7.067

Bottom Head (top) 41,75 29,0 * 639 7.237

Support Skirt 0 29,3 2,598 716 9.630

*Moment of Inertia I varies over the length of the componentSeismic Shear Report: Empty, Corroded

Component Elevation of bottomabove base (in)

Elastic modulus E(106 psi)

Inertia I(ft4)

Seismic shear atBottom (lbf)

Bending Moment atBottom (lbf-ft)

Top Head 164,9548 29,4 * 140 104

Cylinder #1 140,9548 29,4 1,5825 270 789

Cylinder #2 44,9548 29,4 1,5825 632 7.067

Bottom Head (top) 41,75 29,4 * 639 7.237

Support Skirt 0 29,4 2,598 716 9.630

*Moment of Inertia I varies over the length of the component

11.4.3: Maximum considered earthquake spectral response acceleration

The maximum considered earthquake spectral response acceleration at short period, SMSSMS = Fa * Ss = 1,1000 * 75,00 / 100 = 0,8250

11.4.4: Design spectral response acceleration parameters

Design earthquake spectral response acceleration at short period, SDSSDS = 2 / 3 * SMS = 2 / 3 * 0,8250 = 0,5500

12.4.2.3: Seismic Load Combinations: Vertical Term

Factor is applied to dead load.

Compressive Side: = 1.0 + 0.14 * SDS= 1.0 + 0.14 * 0,5500= 1,0770

Tensile Side: = 0.6 - 0.14 * SDS= 0.6 - 0.14 * 0,5500= 0,5230

Base Shear Calculations

Operating, CorrodedEmpty, Corroded

Base Shear Calculations: Operating, Corroded

Paragraph 15.4.2: T < 0,06,so:

V = 0,30 * SDS * W * I= 0,30 * 0,5500 * 6.200,0884 * 1,0000= 1.023,01 lb

12.4.2.1 Seismic Load Combinations: Horizontal Seismic Load Effect, EhQE = VEh = 0.7 * ρ * QE (Only 70% of seismic load considered as per Section 2.4.1)

= 0,70 * 1,0000 * 1.023,01= 716,11 lb

Base Shear Calculations: Empty, Corroded

Paragraph 15.4.2: T

14/192

< 0,06,so:

V = 0,30 * SDS * W * I= 0,30 * 0,5500 * 6.200,0884 * 1,0000= 1.023,01 lb

12.4.2.1 Seismic Load Combinations: Horizontal Seismic Load Effect, EhQE = VEh = 0.7 * ρ * QE (Only 70% of seismic load considered as per Section 2.4.1)

= 0,70 * 1,0000 * 1.023,01= 716,11 lb

15/192

Wind Code

Building Code: ASCE 7-05Elevation of base above grade: 0,0000 ftIncrease effective outer diameter by: 0,0000 ft Wind Force Coefficient Cf: 0,7000 Basic Wind Speed:, V: 85,0000 mph Importance Factor:, I: 1,0000Exposure category: BWind Directionality Factor, Kd: 0,9500Top Deflection Limit: 6 in. per 100 ft.Topographic Factor, Kzt: 1,0000Enforce min. loading of 10 psf: No

Vessel Characteristics

Vessel height, h: 15,2069 ftVessel Minimum Diameter, b

Operating, Corroded: 5,0833 ftEmpty, Corroded: 5,0833 ft

Fundamental Frequency, n1Operating, Corroded: 74,9122 Hz

Empty, Corroded: 75,2256 Hz Damping coefficient, β

Operating, Corroded: 0,0200Empty, Corroded: 0,0200

Vortex Shedding CalculationsTable Lookup Values

2.4.1 Basic Load Combinations for Allowable Stress DesignThe following load combinations are considered in accordance with ASCE section 2.4.1:

5. D + P + Ps + W7. 0.6D + P + Ps + WWhereD = Dead loadP = Internal or external pressure loadPs = Static head loadW = Wind load

Wind Deflection Reports:

Operating, CorrodedEmpty, CorrodedWind Pressure Calculations

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Wind Deflection Report: Operating, Corroded

ComponentElevation of

bottom abovebase (in)

Effective OD(ft)

Elastic modulusE (106 psi)

InertiaI (ft4)

Platformwind shear atBottom (lbf)

Total windshear at

Bottom (lbf)

bendingmoment at

Bottom (lbf-ft)Deflectionat top (in)

Top Head 164,9548 5,09 29,0 * 0 38 24 0,0006

Cylinder #1 140,9548 5,08 29,0 1,582 0 102 430 0,0005

Cylinder #2 44,9548 5,08 29,0 1,582 0 360 4.941 0,0004

Bottom Head (top) 41,75 5,09 29,0 * 0 368 5.038 0

Support Skirt 0 5,17 29,3 2,598 0 482 6.516 0

*Moment of Inertia I varies over the length of the componentWind Deflection Report: Empty, Corroded

ComponentElevation of

bottom abovebase (in)

Effective OD(ft)

Elastic modulusE (106 psi)

InertiaI (ft4)

Platformwind shear atBottom (lbf)

Total windshear at

Bottom (lbf)

bendingmoment at

Bottom (lbf-ft)Deflectionat top (in)

Top Head 164,9548 5,09 29,4 * 0 38 24 0,0006

Cylinder #1 140,9548 5,08 29,4 1,582 0 102 430 0,0005

Cylinder #2 44,9548 5,08 29,4 1,582 0 360 4.941 0,0004

Bottom Head (top) 41,75 5,09 29,4 * 0 368 5.038 0

Support Skirt 0 5,17 29,4 2,598 0 482 6.516 0

*Moment of Inertia I varies over the length of the component

Wind Pressure (WP) Calculations

Gust Factor (G¯) Calculations

Kz = 2,01 * (Z/Zg)2/α

= 2,01 * (Z/1.200,0000)0,2857

qz = 0,00256 * Kz * Kzt * Kd * V2 * I= 0,00256 * Kz * 1,0000 * 0,9500 * 85,00002 * 1,0000= 17,5712 * Kz

WP = qz * G * Cf= qz * G * 0,7000

Design Wind Pressures

Height Z(') Kz qz

(psf)WP: Operating

(psf)WP: Empty

(psf)WP: Hydrotest New

(psf)WP: Hydrotest Corroded

(psf)WP:

Vacuum(psf)

15,0 0,5747 10,10 6,32 6,32 N.A. N.A. N.A.

20,0 0,6240 10,96 6,86 6,86 N.A. N.A. N.A.Design Wind Force determined from: F = Pressure * Af , where Af is the projected area.

Vortex Shedding Calculations

Vortex shedding calculations are based on NBC 1995 building code, Structural Commentaries (Part 4).

Average diameter of vessel (upper third): D = 4,7191 ftAspect ratio: Ar = 3,2224

Weight per foot of vessel, Operating, Corroded, (upper third): M = 294,1100lb/ft

Strouhal number, Operating, Corroded: S = 0,2000

Weight per foot of vessel, Empty, Corroded, (upper third): M = 294,1100lb/ft

Strouhal number, Empty, Corroded: S = 0,2000

Weight per foot of vessel, Vacuum, Corroded, (upper third): M = 294,1100lb/ft

Strouhal number, Vacuum, Corroded: S = 0,2000

Critical wind speed at top of vessel, Vh = (n*D/S)*(3600/5280) mph

Operating, Corroded: Vh = (74,9122*4,7191/0,2000)*(3600/5280) = 1.205,1713 mph (1939,5351 km/h)Empty, Corroded: Vh = (75,2256*4,7191/0,2000)*(3600/5280) = 1.210,2139 mph (1947,6504 km/h)

17/192

Vacuum, Corroded: Vh = (74,4714*4,7191/0,2000)*(3600/5280) = 1.198,0801 mph (1928,1229 km/h)Reference wind speed corresponding to critical wind speed, VRef

Operating, Corroded: VRef = 1.346,2211 mph (2166,5327 km/h)Empty, Corroded: VRef = 1.351,8538 mph (2175,5978 km/h)Vacuum, Corroded: VRef = 1.338,2999 mph (2153,7849 km/h)Corresponding reference wind speed, VRef

Operating, Corroded: VRef = 85,0000 mph (136,7942 km/h)Empty, Corroded: VRef = 85,0000 mph (136,7942 km/h)Vacuum, Corroded: VRef = 85,0000 mph (136,7942 km/h)

Speed for operating, corroded condition which produces vortex shedding is greater than reference speed. No further vortexshedding computations were done for this condition.Speed for empty, corroded condition which produces vortex shedding is greater than reference speed. No further vortex sheddingcomputations were done for this condition.Speed for vacuum, corroded condition which produces vortex shedding is greater than reference speed. No further vortex sheddingcomputations were done for this condition.

Gust Factor Calculations

Operating, CorrodedEmpty, Corroded

Gust Factor Calculations: Operating, Corroded

Vessel is considered a rigid structure as n1 = 74,9122 Hz ≥ 1 Hz.

z¯ = max ( 0,60 * h , zmin )= max ( 0,60 * 15,2069 , 30,0000 )= 30,0000

Iz¯ = c * (33 / z¯)1/6

= 0,3000 * (33 / 30,0000)1/6

= 0,3048Lz¯ = l * (z¯ / 33)ep

= 320,0000 * (30,0000 / 33)0,3333

= 309,9934Q = Sqr(1 / (1 + 0,63 * ((b + h) / Lz¯)0,63))

= Sqr(1 / (1 + 0,63 * ((5,0833 + 15,2069) / 309,9934)0,63))= 0,9478

G = 0.925 * (1 + 1.7 * gQ * Iz¯ * Q) / (1 + 1.7 * gv * Iz¯)= 0.925 * (1 + 1.7 * 3,40* 0,3048 * 0,9478) / (1 + 1.7 * 3,40 * 0,3048)= 0,8942

Gust Factor Calculations: Empty, Corroded

Vessel is considered a rigid structure as n1 = 75,2256 Hz ≥ 1 Hz.

z¯ = max ( 0,60 * h , zmin )= max ( 0,60 * 15,2069 , 30,0000 )= 30,0000

Iz¯ = c * (33 / z¯)1/6

= 0,3000 * (33 / 30,0000)1/6

= 0,3048Lz¯ = l * (z¯ / 33)ep

= 320,0000 * (30,0000 / 33)0,3333

= 309,9934Q = Sqr(1 / (1 + 0,63 * ((b + h) / Lz¯)0,63))

= Sqr(1 / (1 + 0,63 * ((5,0833 + 15,2069) / 309,9934)0,63))= 0,9478

G = 0.925 * (1 + 1.7 * gQ * Iz¯ * Q) / (1 + 1.7 * gv * Iz¯)= 0.925 * (1 + 1.7 * 3,40* 0,3048 * 0,9478) / (1 + 1.7 * 3,40 * 0,3048)= 0,8942

18/192

Table Lookup Values

α = 7,0000, zg = 1.200,0000 ft [Table 6-2, page 78]c = 0,3000, l = 320,0000, ep = 0,3333 [Table 6-2, page 78]a¯ = 0,2500, b¯ = 0,4500 [Table 6-2, page 78]zmin = 30,0000 ft [Table 6-2, page 78]gQ = 3,40 [6.5.8.1 page 26]gv = 3,40 [6.5.8.1 page 26]

19/192

Top Head

ASME Section VIII, Division 1, 2010 Edition

Component: Ellipsoidal HeadMaterial Specification: SA-516 70 (II-D p.18, ln. 19)Straight Flange governs MDMT

Internal design pressure: P = 200 psi @ 150 °F

Static liquid head:

Ps= 0 psi (SG=1, Hs=0" Operating head)Pth= 2,54 psi (SG=1, Hs=70,5" Horizontal test head)

Corrosion allowance: Inner C = 0,125" Outer C = 0"

Design MDMT = -20°F No impact test performedRated MDMT = -24,8°F Material is not normalized

Material is not produced to fine grain practicePWHT is not performedDo not Optimize MDMT / Find MAWP

Radiography: Category A joints - Seamless No RT Head to shell seam - Full UW-11(a) Type 1

Estimated weight*: new = 690,2 lb corr = 529,4 lbCapacity*: new = 146,9 US gal corr = 149,1 US gal* includes straight flange

Inner diameter = 60"Minimum head thickness = 0,528"Head ratio D/2h = 2 (new)Head ratio D/2h = 1,9917 (corroded)Straight flange length Lsf = 2"Nominal straight flange thickness tsf = 0,528"Results Summary

The governing condition is internal pressure.Minimum thickness per UG-16 = 0,0625" + 0,125" = 0,1875"Design thickness due to internal pressure (t) = 0,4249"Maximum allowable working pressure (MAWP) = 268,67 psiMaximum allowable pressure (MAP) = 351,38 psi

K (Corroded)

K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (60,25 / (2*15,125))2]=0,994502

K (New)

K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (60 / (2*15))2]=1

Design thickness for internal pressure, (Corroded at 150 °F) Appendix 1-4(c)

t = P*D*K / (2*S*E - 0,2*P) + Corrosion= 200*60,25*0,994502 / (2*20.000*1 - 0,2*200) + 0,125= 0,4249"

The head internal pressure design thickness is 0,4249".

Maximum allowable working pressure, (Corroded at 150 °F) Appendix 1-4(c)

P = 2*S*E*t / (K*D + 0,2*t) - Ps= 2*20.000*1*0,403 / (0,994502*60,25 +0,2*0,403) - 0= 268,67 psi

The maximum allowable working pressure (MAWP) is 268,67 psi.

Maximum allowable pressure, (New at 70 °F) Appendix 1-4(c)

P = 2*S*E*t / (K*D + 0,2*t) - Ps= 2*20.000*1*0,528 / (1*60 +0,2*0,528) - 0= 351,38 psi

20/192

The maximum allowable pressure (MAP) is 351,38 psi.

% Extreme fiber elongation - UCS-79(d)

EFE = (75*t / Rf)*(1 - Rf / Ro)= (75*0,528 / 10,464)*(1 - 10,464 / ∞)= 3,7844%

The extreme fiber elongation does not exceed 5%.

21/192

Straight Flange on Top Head


Component: Straight FlangeMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve B = -7 °FFig UCS-66.1 MDMT reduction = 17,8 °F, (coincident ratio = 0,8215)UCS-66 governing thickness = 0,5 in


Static liquid head:

Pth = 2,54 psi (SG = 1, Hs = 70,5", Horizontaltest head)

Corrosion allowance Inner C = 0,125" Outer C = 0"

Design MDMT = -20 °F No impact test performedRated MDMT = -24,8 °F Material is not normalized

Material is not produced to Fine Grain PracticePWHT is not performed

Radiography: Longitudinal joint - Seamless No RTCircumferential joint - Full UW-11(a) Type 1

Estimated weight New = 56,8 lb corr = 43,5 lbCapacity New = 24,48 US gal corr = 24,68 US gal

ID = 60"LengthLc

= 2"t = 0,528"

Design thickness, (at 150 °F) UG-27(c)(1)

t = P*R / (S*E - 0,60*P) + Corrosion= 200*30,125 / (20.000*1,00 - 0,60*200) + 0,125= 0,4281"

Maximum allowable working pressure, (at 150 °F) UG-27(c)(1)

P = S*E*t / (R + 0,60*t) - Ps= 20.000*1,00*0,403 / (30,125 + 0,60*0,403) - 0= 265,42 psi

Maximum allowable pressure, (at 70 °F) UG-27(c)(1)

P = S*E*t / (R + 0,60*t)= 20.000*1,00*0,528 / (30 + 0,60*0,528)= 348,32 psi


EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0,528 / 30,264)*(1 - 30,264 / ∞)= 0,8723%


Design thickness = 0,4281"

The governing condition is due to internal pressure.

The cylinder thickness of 0,528" is adequate.

22/192

Thickness Required Due to Pressure + External Loads

Condition Pressure P (psi)

Allowable StressBefore UG-23

Stress Increase (psi)

Temperature ( °F) Corrosion C(in) Load Req'd Thk Due to

Tension (in)

Req'd Thk Dueto

Compression(in)

St Sc

Operating, Hot & Corroded 200 20.000 14.196 150 0,125 Wind 0,1252 0,1252

Seismic 0,1253 0,1252

Operating, Hot & New 200 20.000 15.223 150 0 Wind 0,1247 0,1246

Seismic 0,1247 0,1246

Hot Shut Down, Corroded 0 20.000 14.196 150 0,125 Wind 0,0001 0,0002

Seismic 0,0001 0,0002

Hot Shut Down, New 0 20.000 15.223 150 0 Wind 0,0001 0,0002

Seismic 0,0001 0,0002

Empty, Corroded 0 20.000 14.196 70 0,125 Wind 0,0001 0,0002

Seismic 0,0001 0,0002

Empty, New 0 20.000 15.223 70 0 Wind 0,0001 0,0002

Seismic 0,0001 0,0002

Hot Shut Down, Corroded, Weight &Eccentric Moments Only 0 20.000 14.196 150 0,125 Weight 0,0002 0,0002

Allowable Compressive Stress, Hot and Corroded- ScHC, (table CS-2)A = 0,125 / (Ro / t)

= 0,125 / (30,528 / 0,403)= 0,001650

B = 14.196 psi

S = 20.000 / 1,00 = 20.000 psi

ScHC = min(B, S) = 14.196 psi

Allowable Compressive Stress, Hot and New- ScHN, (table CS-2)A = 0,125 / (Ro / t)

= 0,125 / (30,528 / 0,528)= 0,002162

B = 15.223 psi

S = 20.000 / 1,00 = 20.000 psi

ScHN = min(B, S) = 15.223 psi

Allowable Compressive Stress, Cold and New- ScCN, (table CS-2)A = 0,125 / (Ro / t)

= 0,125 / (30,528 / 0,528)= 0,002162

B = 15.223 psi

S = 20.000 / 1,00 = 20.000 psi

ScCN = min(B, S) = 15.223 psi

Allowable Compressive Stress, Cold and Corroded- ScCC, (table CS-2)A = 0,125 / (Ro / t)

= 0,125 / (30,528 / 0,403)= 0,001650

B = 14.196 psi

S = 20.000 / 1,00 = 20.000 psi

ScCC = min(B, S) = 14.196 psi

Allowable Compressive Stress, Vacuum and Corroded- ScVC, (table CS-2)A = 0,125 / (Ro / t)

= 0,125 / (30,528 / 0,403)= 0,001650

B = 14.196 psi

23/192

S = 20.000 / 1,00 = 20.000 psi

ScVC = min(B, S) = 14.196 psi

Operating, Hot & Corroded, Wind, Bottom Seam

tp = P*R / (2*St*Ks*Ec + 0,40*|P|) (Pressure)= 200*30,125 / (2*20.000*1,20*1,00 + 0,40*|200|)= 0,1253"

tm = M / (π*Rm2*St*Ks*Ec) (bending)

= 289 / (π*30,32652*20.000*1,20*1,00)= 0"

tw = 0,6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,60*536,3 / (2*π*30,3265*20.000*1,20*1,00)= 0,0001"

tt = tp + tm - tw(total required,tensile)

= 0,1253 + 0 - (0,0001)= 0,1252"

twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 536,3 / (2*π*30,3265*20.000*1,20*1,00)= 0,0001"

tc = |tmc + twc - tpc|(total, nettensile)

= |0 + (0,0001) - (0,1253)|= 0,1252"

Maximum allowable working pressure, Longitudinal Stress

P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,403 - 0 + (0,0001)) / (30,125 - 0,40*(0,403 - 0 + (0,0001)))= 645,69 psi

Operating, Hot & New, Wind, Bottom Seam

tp = P*R / (2*St*Ks*Ec + 0,40*|P|) (Pressure)= 200*30 / (2*20.000*1,20*1,00 + 0,40*|200|)= 0,1248"


= 289 / (π*30,2642*20.000*1,20*1,00)= 0"

tw = 0,6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,60*697,1 / (2*π*30,264*20.000*1,20*1,00)= 0,0001"

tt = tp + tm - tw (total required, tensile)= 0,1248 + 0 - (0,0001)= 0,1247"

twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 697,1 / (2*π*30,264*20.000*1,20*1,00)= 0,0002"

tc = |tmc + twc - tpc| (total, net tensile)= |0 + (0,0002) - (0,1248)|= 0,1246"


P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,528 - 0 + (0,0001)) / (30 - 0,40*(0,528 - 0 + (0,0001)))= 850,93 psi

24/192

Hot Shut Down, Corroded, Wind, Bottom Seam

tp = 0" (Pressure)tm = M / (π*Rm

2*Sc*Ks) (bending)= 289 / (π*30,32652*14.196,49*1,20)= 0"

tw = 0,6*W / (2*π*Rm*Sc*Ks) (Weight)= 0,60*536,3 / (2*π*30,3265*14.196,49*1,20)= 0,0001"

tt = |tp + tm - tw| (total, net compressive)= |0 + 0 - (0,0001)|= 0,0001"

twc = W / (2*π*Rm*Sc*Ks) (Weight)= 536,3 / (2*π*30,3265*14.196,49*1,20)= 0,0002"

tc = tmc + twc - tpc (total required, compressive)= 0 + (0,0002) - (0)= 0,0002"

Hot Shut Down, New, Wind, Bottom Seam


2*Sc*Ks) (bending)= 289 / (π*30,2642*15.223,33*1,20)= 0"





Empty, Corroded, Wind, Bottom Seam


2*Sc*Ks) (bending)= 289 / (π*30,32652*14.196,49*1,20)= 0"





25/192

Empty, New, Wind, Bottom Seam


2*Sc*Ks) (bending)= 289 / (π*30,2642*15.223,33*1,20)= 0"





Hot Shut Down, Corroded, Weight & Eccentric Moments Only, Bottom Seam


2*Sc*Ks) (bending)= 0 / (π*30,32652*14.196,49*1,00)= 0"

tw = W / (2*π*Rm*Sc*Ks) (Weight)= 536,3 / (2*π*30,3265*14.196,49*1,00)= 0,0002"



Operating, Hot & Corroded, Seismic, Bottom Seam



= 1.246 / (π*30,32652*20.000*1,20*1,00)= 0"

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,52*536,3 / (2*π*30,3265*20.000*1,20*1,00)= 0,0001"


= 0,1253 + 0 - (0,0001)= 0,1253"

twc = (1 + 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1,08*536,3 / (2*π*30,3265*20.000*1,20*1,00)= 0,0001"


= |0 + (0,0001) - (0,1253)|= 0,1252"

26/192


P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,403 - 0 + (0,0001)) / (30,125 - 0,40*(0,403 - 0 + (0,0001)))= 645,65 psi

Operating, Hot & New, Seismic, Bottom Seam



= 1.530 / (π*30,2642*20.000*1,20*1,00)= 0"

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,52*697,1 / (2*π*30,264*20.000*1,20*1,00)= 0,0001"

tt = tp + tm - tw (total required, tensile)= 0,1248 + 0 - (0,0001)= 0,1247"

twc = (1 + 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1,08*697,1 / (2*π*30,264*20.000*1,20*1,00)= 0,0002"

tc = |tmc + twc - tpc| (total, net tensile)= |0 + (0,0002) - (0,1248)|= 0,1246"


P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,528 - 0 + (0,0001)) / (30 - 0,40*(0,528 - 0 + (0,0001)))= 850,88 psi

Hot Shut Down, Corroded, Seismic, Bottom Seam


2*Sc*Ks) (bending)= 1.246 / (π*30,32652*14.196,49*1,20)= 0"

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0,52*536,3 / (2*π*30,3265*14.196,49*1,20)= 0,0001"


twc = (1 + 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1,08*536,3 / (2*π*30,3265*14.196,49*1,20)= 0,0002"


Hot Shut Down, New, Seismic, Bottom Seam


2*Sc*Ks) (bending)= 1.530 / (π*30,2642*15.223,33*1,20)= 0"


27/192




Empty, Corroded, Seismic, Bottom Seam


2*Sc*Ks) (bending)= 1.246 / (π*30,32652*14.196,49*1,20)= 0"





Empty, New, Seismic, Bottom Seam


2*Sc*Ks) (bending)= 1.530 / (π*30,2642*15.223,33*1,20)= 0"





28/192

Cylinder #1


Component: CylinderMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve D = -55 °FFig UCS-66.1 MDMT reduction = 11,7 °F, (coincident ratio = 0,8829)Rated MDMT of -66,7°F is limited to -55°F by UCS-66(b)(2)UCS-66 governing thickness = 0,5 in


Static liquid head:



Design MDMT = -20 °F No impact test performedRated MDMT = -55 °F Material is normalized


Radiography: Longitudinal joint - Full UW-11(a) Type 1Top circumferential joint - Full UW-11(a) Type 1Bottom circumferential joint - Full UW-11(a) Type 1


ID = 60"LengthLc

= 24"t = 0,5"




P = S*E*t / (R + 0,60*t) - Ps= 20.000*1,00*0,375 / (30,125 + 0,60*0,375) - 0= 247,12 psi


P = S*E*t / (R + 0,60*t)= 20.000*1,00*0,5 / (30 + 0,60*0,5)= 330,03 psi


EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0,5 / 30,25)*(1 - 30,25 / ∞)= 0,8264%





29/192






Tension (in)

Req'd Thk Dueto

Compression(in)

St Sc


Seismic 0,1253 0,1249


Seismic 0,1248 0,1243


Seismic 0 0,0006


Seismic 0 0,0007


Seismic 0 0,0006

Empty, New 0 20.000 15.069 70 0 Wind 0,0001 0,0005

Seismic 0 0,0007



= 0,125 / (30,5 / 0,375)= 0,001537

B = 13.910 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,5)= 0,002049

B = 15.069 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,5)= 0,002049

B = 15.069 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,375)= 0,001537

B = 13.910 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,375)= 0,001537

B = 13.910 psi

30/192

S = 20.000 / 1,00 = 20.000 psi





= 5.164 / (π*30,31252*20.000*1,20*1,00)= 0,0001"

tw = 0,6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,60*1.100,3 / (2*π*30,3125*20.000*1,20*1,00)= 0,0001"


= 0,1253 + 0,0001 - (0,0001)= 0,1252"

twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 1.100,3 / (2*π*30,3125*20.000*1,20*1,00)= 0,0002"


= |0,0001 + (0,0002) - (0,1253)|= 0,125"


P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,375 - 0,0001 + (0,0001)) / (30,125 - 0,40*(0,375 - 0,0001 + (0,0001)))= 600,61 psi




= 5.177 / (π*30,252*20.000*1,20*1,00)= 0,0001"


tt = tp + tm - tw (total required, tensile)= 0,1248 + 0,0001 - (0,0002)= 0,1247"


tc = |tmc + twc - tpc| (total, net tensile)= |0,0001 + (0,0003) - (0,1248)|= 0,1244"


P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,5 - 0,0001 + (0,0002)) / (30 - 0,40*(0,5 - 0,0001 + (0,0002)))= 805,55 psi

31/192



2*Sc*Ks) (bending)= 5.164 / (π*30,31252*13.910,45*1,20)= 0,0001"

tw = 0,6*W / (2*π*Rm*Sc*Ks) (Weight)= 0,60*1.100,3 / (2*π*30,3125*13.910,45*1,20)= 0,0002"

tt = |tp + tm - tw| (total, net compressive)= |0 + 0,0001 - (0,0002)|= 0,0001"

twc = W / (2*π*Rm*Sc*Ks) (Weight)= 1.100,3 / (2*π*30,3125*13.910,45*1,20)= 0,0003"

tc = tmc + twc - tpc (total required, compressive)= 0,0001 + (0,0003) - (0)= 0,0005"



2*Sc*Ks) (bending)= 5.177 / (π*30,252*15.069,32*1,20)= 0,0001"







2*Sc*Ks) (bending)= 5.164 / (π*30,31252*13.910,45*1,20)= 0,0001"





32/192



2*Sc*Ks) (bending)= 5.177 / (π*30,252*15.069,32*1,20)= 0,0001"







2*Sc*Ks) (bending)= 3.186 / (π*30,31252*13.910,45*1,00)= 0,0001"

tw = W / (2*π*Rm*Sc*Ks) (Weight)= 1.100,3 / (2*π*30,3125*13.910,45*1,00)= 0,0004"






= 9.473 / (π*30,31252*20.000*1,20*1,00)= 0,0001"

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,52*1.100,3 / (2*π*30,3125*20.000*1,20*1,00)= 0,0001"


= 0,1253 + 0,0001 - (0,0001)= 0,1253"

twc = (1 + 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1,08*1.100,3 / (2*π*30,3125*20.000*1,20*1,00)= 0,0003"


= |0,0001 + (0,0003) - (0,1253)|= 0,1249"

33/192






= 10.858 / (π*30,252*20.000*1,20*1,00)= 0,0002"









2*St*Ks*Ec) (bending)= 9.473 / (π*30,31252*20.000*1,20*1,00)= 0,0001"


tt = tp + tm - tw (total required, tensile)= 0 + 0,0001 - (0,0001)= 0"

tmc = M / (π*Rm2*Sc*Ks) (bending)

= 9.473 / (π*30,31252*13.910,45*1,20)= 0,0002"

twc = (1 + 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1,08*1.100,3 / (2*π*30,3125*13.910,45*1,20)= 0,0004"




2*Sc*Ks) (bending)= 10.858 / (π*30,252*15.069,32*1,20)= 0,0002"

34/192

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0,52*1.419,3 / (2*π*30,25*15.069,32*1,20)= 0,0002"

tt = |tp + tm - tw| (total, net compressive)= |0 + 0,0002 - (0,0002)|= 0"





2*St*Ks*Ec) (bending)= 9.473 / (π*30,31252*20.000*1,20*1,00)= 0,0001"


tt = tp + tm - tw (total required, tensile)= 0 + 0,0001 - (0,0001)= 0"


= 9.473 / (π*30,31252*13.910,45*1,20)= 0,0002"





2*Sc*Ks) (bending)= 10.858 / (π*30,252*15.069,32*1,20)= 0,0002"

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 0,52*1.419,3 / (2*π*30,25*15.069,32*1,20)= 0,0002"

tt = |tp + tm - tw| (total, net compressive)= |0 + 0,0002 - (0,0002)|= 0"



35/192

Cylinder #2


Component: CylinderMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve D = -55 °FFig UCS-66.1 MDMT reduction = 11,7 °F, (coincident ratio = 0,8829)Rated MDMT of -66,7°F is limited to -55°F by UCS-66(b)(2)UCS-66 governing thickness = 0,5 in


Static liquid head:



Design MDMT = -20 °F No impact test performedRated MDMT = -55 °F Material is normalized


Radiography: Longitudinal joint - Full UW-11(a) Type 1Top circumferential joint - Full UW-11(a) Type 1Bottom circumferential joint - Full UW-11(a) Type 1

Estimated weight New = 2.512,8 lb corr = 1.888,6 lbCapacity New = 1.175,04 US gal corr = 1.184,85 US gal

ID = 60"LengthLc

= 96"t = 0,5"




P = S*E*t / (R + 0,60*t) - Ps= 20.000*1,00*0,375 / (30,125 + 0,60*0,375) - 0= 247,12 psi


P = S*E*t / (R + 0,60*t)= 20.000*1,00*0,5 / (30 + 0,60*0,5)= 330,03 psi


EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0,5 / 30,25)*(1 - 30,25 / ∞)= 0,8264%





36/192






Tension (in)

Req'd Thk Dueto

Compression(in)

St Sc


Seismic 0,1261 0,1232


Seismic 0,1256 0,1222


Seismic 0,0008 0,0031


Seismic 0,0008 0,0034


Seismic 0,0008 0,0031

Empty, New 0 20.000 15.069 70 0 Wind 0,0002 0,0026

Seismic 0,0008 0,0034



= 0,125 / (30,5 / 0,375)= 0,001537

B = 13.910 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,5)= 0,002049

B = 15.069 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,5)= 0,002049

B = 15.069 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,375)= 0,001537

B = 13.910 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,5 / 0,375)= 0,001537

B = 13.910 psi

37/192

S = 20.000 / 1,00 = 20.000 psi





= 59.296 / (π*30,31252*20.000*1,20*1,00)= 0,0009"



= 0,1253 + 0,0009 - (0,0005)= 0,1257"



= |0,0009 + (0,0009) - (0,1253)|= 0,1236"






= 60.628 / (π*30,252*20.000*1,20*1,00)= 0,0009"

tw = 0,6*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,60*4.903 / (2*π*30,25*20.000*1,20*1,00)= 0,0006"


twc = W / (2*π*Rm*St*Ks*Ec) (Weight)= 4.903 / (2*π*30,25*20.000*1,20*1,00)= 0,0011"




38/192



2*St*Ks*Ec) (bending)= 59.296 / (π*30,31252*20.000*1,20*1,00)= 0,0009"


tt = tp + tm - tw (total required, tensile)= 0 + 0,0009 - (0,0005)= 0,0003"


= 59.296 / (π*30,31252*13.910,45*1,20)= 0,0012"





2*St*Ks*Ec) (bending)= 60.628 / (π*30,252*20.000*1,20*1,00)= 0,0009"




= 60.628 / (π*30,252*15.069,32*1,20)= 0,0012"

twc = W / (2*π*Rm*Sc*Ks) (Weight)= 4.903 / (2*π*30,25*15.069,32*1,20)= 0,0014"




2*St*Ks*Ec) (bending)= 59.296 / (π*30,31252*20.000*1,20*1,00)= 0,0009"




= 59.296 / (π*30,31252*13.910,45*1,20)= 0,0012"

39/192





2*St*Ks*Ec) (bending)= 60.628 / (π*30,252*20.000*1,20*1,00)= 0,0009"




= 60.628 / (π*30,252*15.069,32*1,20)= 0,0012"

twc = W / (2*π*Rm*Sc*Ks) (Weight)= 4.903 / (2*π*30,25*15.069,32*1,20)= 0,0014"




2*Sc*Ks) (bending)= 35.140 / (π*30,31252*13.910,45*1,00)= 0,0009"







= 84.802 / (π*30,31252*20.000*1,20*1,00)= 0,0012"



= 0,1253 + 0,0012 - (0,0004)

40/192

= 0,1261"



= |0,0012 + (0,0009) - (0,1253)|= 0,1232"






= 96.965 / (π*30,252*20.000*1,20*1,00)= 0,0014"

tw = (0,6 - 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 0,52*4.903 / (2*π*30,25*20.000*1,20*1,00)= 0,0006"


twc = (1 + 0,14*SDS)*W / (2*π*Rm*St*Ks*Ec) (Weight)= 1,08*4.903 / (2*π*30,25*20.000*1,20*1,00)= 0,0012"



P = 2*St*Ks*Ec*(t - tm + tw) / (R - 0,40*(t - tm + tw))= 2*20.000*1,20*1,00*(0,5 - 0,0014 + (0,0006)) / (30 - 0,40*(0,5 - 0,0014 + (0,0006)))= 804 psi



2*St*Ks*Ec) (bending)= 84.802 / (π*30,31252*20.000*1,20*1,00)= 0,0012"




= 84.802 / (π*30,31252*13.910,45*1,20)= 0,0018"


41/192




2*St*Ks*Ec) (bending)= 96.965 / (π*30,252*20.000*1,20*1,00)= 0,0014"




= 96.965 / (π*30,252*15.069,32*1,20)= 0,0019"

twc = (1 + 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1,08*4.903 / (2*π*30,25*15.069,32*1,20)= 0,0015"




2*St*Ks*Ec) (bending)= 84.802 / (π*30,31252*20.000*1,20*1,00)= 0,0012"




= 84.802 / (π*30,31252*13.910,45*1,20)= 0,0018"





2*St*Ks*Ec) (bending)= 96.965 / (π*30,252*20.000*1,20*1,00)= 0,0014"


tt = tp + tm - tw (total required, tensile)= 0 + 0,0014 - (0,0006)

42/192

= 0,0008"


= 96.965 / (π*30,252*15.069,32*1,20)= 0,0019"

twc = (1 + 0,14*SDS)*W / (2*π*Rm*Sc*Ks) (Weight)= 1,08*4.903 / (2*π*30,25*15.069,32*1,20)= 0,0015"


43/192

Straight Flange on Bottom Head


Component: Straight FlangeMaterial specification: SA-516 70 (II-D p. 18, ln. 19)Material impact test exemption temperature from Fig UCS-66 Curve B = -7 °FFig UCS-66.1 MDMT reduction = 17,8 °F, (coincident ratio = 0,8215)UCS-66 governing thickness = 0,5 in


Static liquid head:



Design MDMT = -20 °F No impact test performedRated MDMT = -24,8 °F Material is not normalized


Radiography: Longitudinal joint - Seamless No RTCircumferential joint - Full UW-11(a) Type 1


ID = 60"LengthLc

= 2"t = 0,528"




P = S*E*t / (R + 0,60*t) - Ps= 20.000*1,00*0,403 / (30,125 + 0,60*0,403) - 0= 265,42 psi


P = S*E*t / (R + 0,60*t)= 20.000*1,00*0,528 / (30 + 0,60*0,528)= 348,32 psi


EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0,528 / 30,264)*(1 - 30,264 / ∞)= 0,8723%





44/192






Tension (in)

Req'd Thk Dueto

Compression(in)

St Sc


Seismic 0,1261 0,1231


Seismic 0,1257 0,1222


Seismic 0,0008 0,0031


Seismic 0,0009 0,0034


Seismic 0,0008 0,0031

Empty, New 0 20.000 15.223 70 0 Wind 0,0002 0,0026

Seismic 0,0009 0,0034



= 0,125 / (30,528 / 0,403)= 0,001650

B = 14.196 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,528 / 0,528)= 0,002162

B = 15.223 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,528 / 0,528)= 0,002162

B = 15.223 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,528 / 0,403)= 0,001650

B = 14.196 psi

S = 20.000 / 1,00 = 20.000 psi



= 0,125 / (30,528 / 0,403)= 0,001650

B = 14.196 psi

45/192

S = 20.000 / 1,00 = 20.000 psi





= 60.037 / (π*30,32652*20.000*1,20*1,00)= 0,0009"



= 0,1253 + 0,0009 - (0,0005)= 0,1257"



= |0,0009 + (0,0009) - (0,1253)|= 0,1236"






= 61.369 / (π*30,2642*20.000*1,20*1,00)= 0,0009"







46/192



2*St*Ks*Ec) (bending)= 60.037 / (π*30,32652*20.000*1,20*1,00)= 0,0009"




= 60.037 / (π*30,32652*14.196,49*1,20)= 0,0012"





2*St*Ks*Ec) (bending)= 61.369 / (π*30,2642*20.000*1,20*1,00)= 0,0009"




= 61.369 / (π*30,2642*15.223,33*1,20)= 0,0012"





2*St*Ks*Ec) (bending)= 60.037 / (π*30,32652*20.000*1,20*1,00)= 0,0009"




= 60.037 / (π*30,32652*14.196,49*1,20)= 0,0012"

47/192





2*St*Ks*Ec) (bending)= 61.369 / (π*30,2642*20.000*1,20*1,00)= 0,0009"




= 61.369 / (π*30,2642*15.223,33*1,20)= 0,0012"





2*Sc*Ks) (bending)= 35.140 / (π*30,32652*14.196,49*1,00)= 0,0009"







= 86.099 / (π*30,32652*20.000*1,20*1,00)= 0,0012"



= 0,1253 + 0,0012 - (0,0005)

48/192

= 0,1261"



= |0,0012 + (0,0009) - (0,1253)|= 0,1231"






= 98.518 / (π*30,2642*20.000*1,20*1,00)= 0,0014"









2*St*Ks*Ec) (bending)= 86.099 / (π*30,32652*20.000*1,20*1,00)= 0,0012"




= 86.099 / (π*30,32652*14.196,49*1,20)= 0,0017"


49/192




2*St*Ks*Ec) (bending)= 98.518 / (π*30,2642*20.000*1,20*1,00)= 0,0014"




= 98.518 / (π*30,2642*15.223,33*1,20)= 0,0019"





2*St*Ks*Ec) (bending)= 86.099 / (π*30,32652*20.000*1,20*1,00)= 0,0012"




= 86.099 / (π*30,32652*14.196,49*1,20)= 0,0017"





2*St*Ks*Ec) (bending)= 98.518 / (π*30,2642*20.000*1,20*1,00)= 0,0014"


tt = tp + tm - tw (total required, tensile)= 0 + 0,0014 - (0,0006)

50/192

= 0,0009"


= 98.518 / (π*30,2642*15.223,33*1,20)= 0,0019"



51/192

Bottom Head


Component: Ellipsoidal HeadMaterial Specification: SA-516 70 (II-D p.18, ln. 19)Straight Flange governs MDMT


Static liquid head:

Ps= 0 psi (SG=1, Hs=0" Operating head)Pth= 2,54 psi (SG=1, Hs=70,5" Horizontal test head)

Corrosion allowance: Inner C = 0,125" Outer C = 0"

Design MDMT = -20°F No impact test performedRated MDMT = -24,8°F Material is not normalized

Material is not produced to fine grain practicePWHT is not performedDo not Optimize MDMT / Find MAWP

Radiography: Category A joints - Seamless No RT Head to shell seam - Full UW-11(a) Type 1

Estimated weight*: new = 685,4 lb corr = 525,7 lbCapacity*: new = 146,9 US gal corr = 149,1 US gal* includes straight flange

Inner diameter = 60"Minimum head thickness = 0,528"Head ratio D/2h = 2 (new)Head ratio D/2h = 1,9917 (corroded)Straight flange length Lsf = 2"Nominal straight flange thickness tsf = 0,528"Results Summary

The governing condition is internal pressure.Minimum thickness per UG-16 = 0,0625" + 0,125" = 0,1875"Design thickness due to internal pressure (t) = 0,4249"Maximum allowable working pressure (MAWP) = 268,67 psiMaximum allowable pressure (MAP) = 351,38 psi

K (Corroded)

K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (60,25 / (2*15,125))2]=0,994502

K (New)

K=(1/6)*[2 + (D / (2*h))2]=(1/6)*[2 + (60 / (2*15))2]=1

Design thickness for internal pressure, (Corroded at 150 °F) Appendix 1-4(c)

t = P*D*K / (2*S*E - 0,2*P) + Corrosion= 200*60,25*0,994502 / (2*20.000*1 - 0,2*200) + 0,125= 0,4249"

The head internal pressure design thickness is 0,4249".

Maximum allowable working pressure, (Corroded at 150 °F) Appendix 1-4(c)

P = 2*S*E*t / (K*D + 0,2*t) - Ps= 2*20.000*1*0,403 / (0,994502*60,25 +0,2*0,403) - 0= 268,67 psi

The maximum allowable working pressure (MAWP) is 268,67 psi.

Maximum allowable pressure, (New at 70 °F) Appendix 1-4(c)

P = 2*S*E*t / (K*D + 0,2*t) - Ps= 2*20.000*1*0,528 / (1*60 +0,2*0,528) - 0= 351,38 psi

52/192

The maximum allowable pressure (MAP) is 351,38 psi.


EFE = (75*t / Rf)*(1 - Rf / Ro)= (75*0,528 / 10,464)*(1 - 10,464 / ∞)= 3,7844%


53/192

LEVEL TRANSMITER (N1A)


tw(lower) = 0,5 inLeg41 = 0,1875 in

Note: round inside edges per UG-76(c)

Located on: Cylinder #2Liquid static head included: 0 psiNozzle material specification: SA-106 B Smls pipe (II-D p. 10, ln. 40)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 2 Sch 40 (Std)Flange description: NPS 2 Class 150 WN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Flange rated MDMT: -43,4°F(UCS-66(b)(1)(b))Liquid static head on flange: 0 psiASME B16.5-2003 flange rating MAWP: 272,5 psi @ 150°FASME B16.5-2003 flange rating MAP: 285 psi @ 70°FASME B16.5-2003 flange hydro test: 450 psi @ 70°FPWHT performed: NoCircumferential joint radiography: Full UW-11(a) Type 1Nozzle orientation: 180°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 48 inEnd of nozzle to shell center: 40,5 inNozzle inside diameter, new: 2,067 inNozzle nominal wall thickness: 0,154 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 7,5 inProjection available outside vessel to flange face, Lf: 10 in

54/192

Reinforcement Calculations for Internal Pressure

The vessel wall thickness governs the MAWP of this nozzle.

UG-37 Area Calculation Summary(in2)

For P = 247,11 psi @ 150 °F

UG-45 NozzleWall

ThicknessSummary (in)The nozzle passes

UG-45

Arequired

Aavailable A1 A2 A3 A5

Awelds treq tmin

This nozzle is exempt from areacalculations per UG-36(c)(3)(a) 0,1348 0,1348

UG-41 Weld Failure Path Analysis Summary

The nozzle is exempt from weld strength calculationsper UW-15(b)(2)

UW-16 Weld Sizing Summary

Weld description Required weldthroat size (in)

Actual weldthroat size (in) Status

Nozzle to shell fillet (Leg41) 0,1078 0,1312 weld size is adequate

Calculations for internal pressure 247,11 psi @ 150 °F

Fig UCS-66.2 general note (1) applies.

Nozzle is impact test exempt per UCS-66(d) (NPS 4 or smaller pipe).

Nozzle UCS-66 governing thk: 0,1348 inNozzle rated MDMT: -155 °FParallel Limit of reinforcement per UG-40

LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(2,067, 1,0335 + (0,154 - 0) + (0,5 - 0,125))= 2,067 in

Outer Normal Limit of reinforcement per UG-40

LH = MIN(2,5*(t - C), 2,5*(tn - Cn) + te)= MIN(2,5*(0,5 - 0,125), 2,5*(0,154 - 0) + 0)= 0,385 in

Nozzle required thickness per UG-27(c)(1)

trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in

Required thickness tr from UG-37(a)

tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in

This opening does not require reinforcement per UG-36(c)(3)(a)

UW-16(c) Weld Check

Fillet weld: tmin = lesser of 0,75 or tn or t = 0,154 intc(min) = lesser of 0,25 or 0,7*tmin = 0,1078 intc(actual) = 0,7*Leg = 0.7*0,1875 = 0,1313 in

The fillet weld size is satisfactory.

Weld strength calculations are not required for this detail which conforms to Fig. UW-16.1, sketch (c-e).

55/192

UG-45 Nozzle Neck Thickness Check

ta UG-27 = P*R / (S*E - 0,6*P) + Corrosion= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132) + 0= 0,0151 in

ta = max[ ta UG-27 , ta UG-22 ]= max[ 0,0151 , 0 ]= 0,0151 in

tb1 = P*R / (S*E - 0,6*P) + Corrosion= 247,1132*30,125 / (20.000*1 - 0,6*247,1132) + 0,125= 0,5 in

tb1 = max[ tb1 , tb UG16 ]= max[ 0,5 , 0,0625 ]= 0,5 in

tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in

tUG-45 = max[ ta , tb ]= max[ 0,0151 , 0,1348 ]= 0,1348 in

56/192

Available nozzle wall thickness new, tn = 0,875*0,154 = 0,1348 in

The nozzle neck thickness is adequate.

Reinforcement Calculations for MAP

The attached ASME B16.5 flange limits the nozzle MAP.


For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin








Calculations for internal pressure 285 psi @ 70 °F

Parallel Limit of reinforcement per UG-40

LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(2,067, 1,0335 + (0,154 - 0) + (0,5 - 0))= 2,067 in


LH = MIN(2,5*(t - C), 2,5*(tn - Cn) + te)= MIN(2,5*(0,5 - 0), 2,5*(0,154 - 0) + 0)= 0,385 in


trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




57/192


ta UG-27 = P*R / (S*E - 0,6*P) + Corrosion= 285*1,0335 / (17.100*1 - 0,6*285) + 0= 0,0174 in


tb1 = P*R / (S*E - 0,6*P) + Corrosion= 285*30 / (20.000*1 - 0,6*285) + 0= 0,4312 in


tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




58/192

LEVEL TRANSMITER (N1B)





59/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




60/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


61/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




62/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




63/192

OUTLET (N2)


tw(lower) = 0,5 inLeg41 = 0,3125 intw(upper) = 0,5 inLeg42 = 0,375 inDp = 10,625 inte = 0,5 in


Located on: Cylinder #1Liquid static head included: 0 psiNozzle material specification: SA-106 B Smls pipe (II-D p. 10, ln. 40)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 6 Sch 40 (Std)Pad material specification: SA-516 70 (II-D p. 18, ln. 19)Pad diameter: 10,625 inFlange description: NPS 6 Class 150 WN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Flange rated MDMT: -43,4°F(UCS-66(b)(1)(b))Liquid static head on flange: 0 psiASME B16.5-2003 flange rating MAWP: 272,5 psi @ 150°FASME B16.5-2003 flange rating MAP: 285 psi @ 70°FASME B16.5-2003 flange hydro test: 450 psi @ 70°FPWHT performed: NoCircumferential joint radiography: Full UW-11(a) Type 1Nozzle orientation: 0°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 110 inEnd of nozzle to shell center: 40,5 inNozzle inside diameter, new: 6,065 inNozzle nominal wall thickness: 0,28 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 6,5 inProjection available outside vessel to flange face, Lf: 10 inPad is split: No

64/192



UG-37 Area Calculation Summary (in2)For P = 247,11 psi @ 150 °F

The opening is adequately reinforced

UG-45Nozzle WallThicknessSummary

(in)The nozzle

passes UG-45

Arequired


Awelds treq tmin

2,3048 2,6022 0,0001 0,378 -- 2 0,2241 0,245 0,245

UG-41 Weld Failure Path Analysis Summary (lbf)All failure paths are stronger than the applicable weld loads

Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

46.093,37 52.042 94.739,09 12.821 162.013,35 55.633 119.090,91


Weld description Required weldsize (in)

Actual weldsize (in) Status

Nozzle to pad fillet (Leg41) 0,196 0,2188 weld size isadequate

Pad to shell fillet (Leg42) 0,1875 0,2625 weld size isadequate

Nozzle to pad groove (Upper) 0,196 0,5 weld size isadequate



Nozzle is impact test exempt to -155 °F per UCS-66(b)(3) (coincident ratio = 0,1593).

Pad is impact test exempt per UG-20(f).

Nozzle UCS-66 governing thk: 0,245 inNozzle rated MDMT: -155 °FPad UCS-66 governing thickness: 0,5 inPad rated MDMT: -20 °FParallel Limit of reinforcement per UG-40



LH = MIN(2,5*(t - C), 2,5*(tn - Cn) + te)= MIN(2,5*(0,5 - 0,125), 2,5*(0,28 - 0) + 0,5)= 0,9375 in


trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*3,0325 / (17.100*1 - 0,6*247,1132)= 0,0442 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in

65/192

Area required per UG-37(c)

Allowable stresses: Sn = 17.100, Sv = 20.000, Sp = 20.000 psi

fr1 = lesser of 1 or Sn / Sv = 0,855


fr3 = lesser of fr2 or Sp / Sv = 0,855

fr4 = lesser of 1 or Sp / Sv = 1

A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 6,065*0,375*1 + 2*0,28*0,375*1*(1 - 0,855)= 2,3048 in2

Area available from FIG. UG-37.1

A1 = larger of the following= 0,0001 in2

= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 6,065*(1*0,375 - 1*0,375) - 2*0,28*(1*0,375 - 1*0,375)*(1 - 0,855)= 0,0001 in2

= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 2*(0,375 + 0,28)*(1*0,375 - 1*0,375) - 2*0,28*(1*0,375 - 1*0,375)*(1 - 0,855)= 0 in2

A2 = smaller of the following= 0,378 in2

= 5*(tn - trn)*fr2*t= 5*(0,28 - 0,0442)*0,855*0,375= 0,378 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,28 - 0,0442)*(2,5*0,28 + 0,5)*0,855= 0,4839 in2

A41 = Leg2*fr3= 0,31252*0,855= 0,0835 in2

A42 = Leg2*fr4= 0,3752*1= 0,1406 in2

A5 = (Dp - d - 2*tn)*te*fr4= (10,625 - 6,065 - 2*0,28)*0,5*1= 2 in2

Area = A1 + A2 + A41 + A42 + A5= 0,0001 + 0,378 + 0,0835 + 0,1406 + 2= 2,6022 in2

As Area >= A the reinforcement is adequate.

UW-16(c)(2) Weld Check

Inner fillet: tmin = lesser of 0,75 or tn or te = 0,28 intc(min) = lesser of 0,25 or 0,7*tmin = 0,196 intc(actual) = 0,7*Leg = 0.7*0,3125 = 0,2188 in

66/192

Outer fillet: tmin = lesser of 0,75 or te or t = 0,375 intw(min) = 0,5*tmin = 0,1875 intw(actual) = 0,7*Leg = 0.7*0,375 = 0,2625 in






tb = min[ tb3 , tb1 ]= min[ 0,245 , 0,5 ]= 0,245 in




Allowable stresses in joints UG-45 and UW-15(c)

Groove weld in tension: 0,74*20.000 = 14.800 psiNozzle wall in shear: 0,7*17.100 = 11.970 psiInner fillet weld in shear: 0,49*17.100 = 8.379 psiOuter fillet weld in shear: 0,49*20.000 = 9.800 psiUpper groove weld in tension: 0,74*20.000 = 14.800 psiStrength of welded joints:

(1) Inner fillet weld in shear(π / 2)*Nozzle OD*Leg*Si = (π / 2)*6,625*0,3125*8.379 = 27.248,84 lbf

(2) Outer fillet weld in shear(π / 2)*Pad OD*Leg*So = (π / 2)*10,625*0,375*9.800 = 61.334,69 lbf

(3) Nozzle wall in shear(π / 2)*Mean nozzle dia*tn*Sn = (π / 2)*6,345*0,28*11.970 = 33.404,4 lbf

(4) Groove weld in tension(π / 2)*Nozzle OD*tw*Sg = (π / 2)*6,625*0,375*14.800 = 57.756,22 lbf

(6) Upper groove weld in tension(π / 2)*Nozzle OD*tw*Sg = (π / 2)*6,625*0,5*14.800 = 77.008,29 lbf

Loading on welds per UG-41(b)(1)

W = (A - A1 + 2*tn*fr1*(E1*t - F*tr))*Sv= (2,3048 - 0,0001 + 2*0,28*0,855*(1*0,375 - 1*0,375))*20.000= 46.093,37 lbf

W1-1 = (A2 + A5 + A41 + A42)*Sv

67/192

= (0,378 + 2 + 0,0835 + 0,1406)*20.000= 52.042 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,378 + 0 + 0,0835 + 0 + 2*0,28*0,375*0,855)*20.000= 12.821 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,378 + 0 + 2 + 0,0835 + 0,1406 + 0 + 2*0,28*0,375*0,855)*20.000= 55.633 lbf

68/192

Load for path 1-1 lesser of W or W1-1 = 46.093,37 lbfPath 1-1 through (2) & (3) = 61.334,69 + 33.404,4 = 94.739,09 lbfPath 1-1 is stronger than W so it is acceptable per UG-41(b)(2).

Load for path 2-2 lesser of W or W2-2 = 12.821 lbfPath 2-2 through (1), (4), (6) = 27.248,84 + 57.756,22 + 77.008,29 = 162.013,35 lbfPath 2-2 is stronger than W2-2 so it is acceptable per UG-41(b)(1).

Load for path 3-3 lesser of W or W3-3 = 46.093,37 lbfPath 3-3 through (2), (4) = 61.334,69 + 57.756,22 = 119.090,91 lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).



UG-37 Area Calculation Summary (in2)For P = 285 psi @ 70 °F



(in)The nozzle

passes UG-45

Arequired


Awelds treq tmin

2,6502 3,1055 0,4117 0,4697 -- 2 0,2241 0,245 0,245


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

45.428,52 53.876 94.739,09 15.852 181.265,42 58.664 138.342,98











LH = MIN(2,5*(t - C), 2,5*(tn - Cn) + te)= MIN(2,5*(0,5 - 0), 2,5*(0,28 - 0) + 0,5)= 1,2 in


trn = P*Rn / (Sn*E - 0,6*P)= 285*3,0325 / (17.100*1 - 0,6*285)= 0,0511 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in

69/192







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 6,065*0,4312*1 + 2*0,28*0,4312*1*(1 - 0,855)= 2,6502 in2




= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 2*(0,5 + 0,28)*(1*0,5 - 1*0,4312) - 2*0,28*(1*0,5 - 1*0,4312)*(1 - 0,855)= 0,1018 in2


= 5*(tn - trn)*fr2*t= 5*(0,28 - 0,0511)*0,855*0,5= 0,4893 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,28 - 0,0511)*(2,5*0,28 + 0,5)*0,855= 0,4697 in2

A41 = Leg2*fr3= 0,31252*0,855= 0,0835 in2

A42 = Leg2*fr4= 0,3752*1= 0,1406 in2

A5 = (Dp - d - 2*tn)*te*fr4= (10,625 - 6,065 - 2*0,28)*0,5*1= 2 in2

Area = A1 + A2 + A41 + A42 + A5= 0,4117 + 0,4697 + 0,0835 + 0,1406 + 2= 3,1055 in2




70/192







tb = min[ tb3 , tb1 ]= min[ 0,245 , 0,4312 ]= 0,245 in













W1-1 = (A2 + A5 + A41 + A42)*Sv

71/192

= (0,4697 + 2 + 0,0835 + 0,1406)*20.000= 53.876 lbf






72/192

RELIEF GAS (N3)




Located on: Cylinder #1Liquid static head included: 0 psiNozzle material specification: SA-106 B Smls pipe (II-D p. 10, ln. 40)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 6 Sch 40 (Std)Pad material specification: SA-516 70 (II-D p. 18, ln. 19)Pad diameter: 10,625 inFlange description: NPS 6 Class 150 WN A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Flange rated MDMT: -43,4°F(UCS-66(b)(1)(b))Liquid static head on flange: 0 psiASME B16.5-2003 flange rating MAWP: 272,5 psi @ 150°FASME B16.5-2003 flange rating MAP: 285 psi @ 70°FASME B16.5-2003 flange hydro test: 450 psi @ 70°FPWHT performed: NoCircumferential joint radiography: Full UW-11(a) Type 1Nozzle orientation: 315°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 115 inEnd of nozzle to shell center: 40,5 inNozzle inside diameter, new: 6,065 inNozzle nominal wall thickness: 0,28 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 6,5 inProjection available outside vessel to flange face, Lf: 10 inPad is split: No

73/192






(in)The nozzle

passes UG-45

Arequired


Awelds treq tmin

2,3048 2,6022 0,0001 0,378 -- 2 0,2241 0,245 0,245


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

46.093,37 52.042 94.739,09 12.821 162.013,34 55.633 119.090,9
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*3,0325 / (17.100*1 - 0,6*247,1132)= 0,0442 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in

74/192







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 6,065*0,375*1 + 2*0,28*0,375*1*(1 - 0,855)= 2,3048 in2






= 5*(tn - trn)*fr2*t= 5*(0,28 - 0,0442)*0,855*0,375= 0,378 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,28 - 0,0442)*(2,5*0,28 + 0,5)*0,855= 0,4839 in2

A41 = Leg2*fr3= 0,31252*0,855= 0,0835 in2

A42 = Leg2*fr4= 0,3752*1= 0,1406 in2

A5 = (Dp - d - 2*tn)*te*fr4= (10,625 - 6,065 - 2*0,28)*0,5*1= 2 in2

Area = A1 + A2 + A41 + A42 + A5= 0,0001 + 0,378 + 0,0835 + 0,1406 + 2= 2,6022 in2




75/192







tb = min[ tb3 , tb1 ]= min[ 0,245 , 0,5 ]= 0,245 in













W1-1 = (A2 + A5 + A41 + A42)*Sv

76/192

= (0,378 + 2 + 0,0835 + 0,1406)*20.000= 52.042 lbf



77/192






UG-37 Area Calculation Summary (in2)For P = 285 psi @ 70 °F



(in)The nozzle

passes UG-45

Arequired


Awelds treq tmin

2,6502 3,1055 0,4117 0,4697 -- 2 0,2241 0,245 0,245


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

45.428,52 53.876 94.739,09 15.852 181.265,42 58.664 138.342,98













trn = P*Rn / (Sn*E - 0,6*P)= 285*3,0325 / (17.100*1 - 0,6*285)= 0,0511 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in

78/192







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 6,065*0,4312*1 + 2*0,28*0,4312*1*(1 - 0,855)= 2,6502 in2




= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 2*(0,5 + 0,28)*(1*0,5 - 1*0,4312) - 2*0,28*(1*0,5 - 1*0,4312)*(1 - 0,855)= 0,1018 in2


= 5*(tn - trn)*fr2*t= 5*(0,28 - 0,0511)*0,855*0,5= 0,4893 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,28 - 0,0511)*(2,5*0,28 + 0,5)*0,855= 0,4697 in2

A41 = Leg2*fr3= 0,31252*0,855= 0,0835 in2

A42 = Leg2*fr4= 0,3752*1= 0,1406 in2

A5 = (Dp - d - 2*tn)*te*fr4= (10,625 - 6,065 - 2*0,28)*0,5*1= 2 in2

Area = A1 + A2 + A41 + A42 + A5= 0,4117 + 0,4697 + 0,0835 + 0,1406 + 2= 3,1055 in2




79/192







tb = min[ tb3 , tb1 ]= min[ 0,245 , 0,4312 ]= 0,245 in













W1-1 = (A2 + A5 + A41 + A42)*Sv

80/192

= (0,4697 + 2 + 0,0835 + 0,1406)*20.000= 53.876 lbf






81/192

CONDENSATE OUTLET (N4)


tw(lower) = 0,528 inLeg41 = 0,25 intw(upper) = 0,5 inLeg42 = 0,375 inLeg43 = 0,25 inhnew = 6,5 inDp = 8,5676 inte = 0,5 in


Located on: Bottom HeadLiquid static head included: 0 psiNozzle material specification: SA-106 B Smls pipe (II-D p. 10, ln. 40)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 4 Sch 40 (Std)Pad material specification: SA-516 70 (II-D p. 18, ln. 19)Pad diameter: 8,5676 inNozzle orientation: 180°Calculated as hillside: YesLocal vessel minimum thickness: 0,528 inEnd of nozzle to datum line: -23,4302 inNozzle inside diameter, new: 4,026 inNozzle nominal wall thickness: 0,237 inNozzle corrosion allowance: 0 inOpening chord length: 4,0885 inProjection available outside vessel, Lpr: 6,4109 inInternal projection, hnew: 6,5 inDistance to head center, R: 10 inPad is split: No

82/192





UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin

1,6753 2,2632 -- 0,3471 0,0536 1,8047 0,0578 0,2074 0,2074


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

33.506,52 44.104 68.454,66 12.436,99 113.504,84 48.530,99 95.848,39










Pad impact test exemption temperature from Fig UCS-66 Curve B = -7 °FFig UCS-66.1 MDMT reduction = 26,8 °F, (coincident ratio = 0,7323).

Nozzle UCS-66 governing thk: 0,2074 inNozzle rated MDMT: -155 °FPad UCS-66 governing thickness: 0,5 inPad rated MDMT: -33,8 °FParallel Limit of reinforcement per UG-40




Inner Normal Limit of reinforcement per UG-40

LI = MIN(2,5*(t - C), 2,5*(ti - Cn - C))= MIN(2,5*(0,528 - 0,125), 2,5*(0,237 - 0 - 0,125))= 0,28 in


trn = P*Rn / (Sn*E - 0,6*P)= 298,0583*2,013 / (17.100*1 - 0,6*298,0583)= 0,0355 in

83/192

Required thickness tr from UG-37(a)(c)

tr = P*K1*D / (2*S*E - 0,2*P)= 298,0583*0,8963*60,25 / (2*20.000*1 - 0,2*298,0583)= 0,403 in







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 4,0885*0,403*1 + 2*0,237*0,403*1*(1 - 0,855)= 1,6753 in2


A1 = larger of the following= 0 in2

= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 4,0885*(1*0,403 - 1*0,403) - 2*0,237*(1*0,403 - 1*0,403)*(1 - 0,855)= 0 in2



= 5*(tn - trn)*fr2*t= 5*(0,237 - 0,0355)*0,855*0,403= 0,3471 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,237 - 0,0355)*(2,5*0,237 + 0,5)*0,855= 0,3764 in2


= 5*t*ti*fr2= 5*0,403*0,112*0,855= 0,193 in2

= 5*ti*ti*fr2= 5*0,112*0,112*0,855= 0,0536 in2

= 2*h*ti*fr2= 2*6,375*0,112*0,855= 1,2209 in2

A41 = Leg2*fr3= 0,252*0,855= 0,0534 in2

A42 = Leg2*fr4

84/192

= 02*1= 0 in2

(Part of the weld is outside of the limits)

A43 = Leg2*fr2= 0,07142*0,855= 0,0044 in2

A5 = (Dp - d - 2*tn)*te*fr4= (8,177 - 4,5676)*0,5*1= 1,8047 in2

Area = A1 + A2 + A3 + A41 + A42 + A43 + A5= 0 + 0,3471 + 0,0536 + 0,0534 + 0 + 0,0044 + 1,8047= 2,2632 in2






Interpretation VIII-1-83-66 has been applied.



tb1 = 0,5721 in


tb = min[ tb3 , tb1 ]= min[ 0,2074 , 0,5721 ]= 0,2074 in





Groove weld in tension: 0,74*20.000 = 14.800 psiNozzle wall in shear: 0,7*17.100 = 11.970 psi

85/192

Inner fillet weld in shear: 0,49*17.100 = 8.379 psiOuter fillet weld in shear: 0,49*20.000 = 9.800 psiUpper groove weld in tension: 0,74*20.000 = 14.800 psiLower fillet weld in shear: 0,49*17.100 = 8.379 psiStrength of welded joints:





(5) Lower fillet weld in shear(π / 2)*Nozzle OD*Leg*Sl = (π / 2)*4,5*0,0714*8.379 = 4.230,55 lbf



W = (A - A1 + 2*tn*fr1*(E1*t - F*tr))*Sv= (1,6753 - 0 + 2*0,237*0,855*(1*0,403 - 1*0,403))*20.000= 33.506,52 lbf

W1-1 = (A2 + A5 + A41 + A42)*Sv= (0,3471 + 1,8047 + 0,0534 + 0)*20.000= 44.104 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,3471 + 0,0536 + 0,0534 + 0,0044 + 2*0,237*0,403*0,855)*20.000= 12.436,99 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,3471 + 0,0536 + 1,8047 + 0,0534 + 0 + 0,0044 + 2*0,237*0,403*0,855)*20.000= 48.530,99 lbf

86/192


Load for path 2-2 lesser of W or W2-2 = 12.436,99 lbfPath 2-2 through (1), (4), (5), (6) = 14.806,92 + 42.159,86 + 4.230,55 + 52.307,52 = 113.504,84 lbfPath 2-2 is stronger than W2-2 so it is acceptable per UG-41(b)(1).

Load for path 3-3 lesser of W or W3-3 = 33.506,52 lbfPath 3-3 through (2), (4), (5) = 49.457,98 + 42.159,86 + 4.230,55 = 95.848,39 lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).


The vessel wall thickness governs the MAP of this nozzle.



UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin

2,1951 2,5074 -- 0,3557 0,2401 1,8048 0,1068 0,2074 0,2074


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

43.901,4 44.278 68.454,66 18.332,1 137.158,09 54.428,1 119.501,64












Inner Normal Limit of reinforcement per UG-40

LI = MIN(2,5*(t - C), 2,5*(ti - Cn - C))= MIN(2,5*(0,528 - 0), 2,5*(0,237 - 0 - 0))= 0,5925 in


trn = P*Rn / (Sn*E - 0,6*P)= 390,3502*2,013 / (17.100*1 - 0,6*390,3502)= 0,0466 in

87/192


tr = P*K1*D / (2*S*E - 0,2*P)= 390,3502*0,9*60 / (2*20.000*1 - 0,2*390,3502)= 0,528 in







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 4,0886*0,528*1 + 2*0,237*0,528*1*(1 - 0,855)= 2,1951 in2






= 5*(tn - trn)*fr2*t= 5*(0,237 - 0,0466)*0,855*0,528= 0,4298 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,237 - 0,0466)*(2,5*0,237 + 0,5)*0,855= 0,3557 in2


= 5*t*ti*fr2= 5*0,528*0,237*0,855= 0,535 in2

= 5*ti*ti*fr2= 5*0,237*0,237*0,855= 0,2401 in2

= 2*h*ti*fr2= 2*6,5*0,237*0,855= 2,6343 in2

A41 = Leg2*fr3= 0,252*0,855= 0,0534 in2

A42 = Leg2*fr4

88/192

= 02*1= 0 in2


A43 = Leg2*fr2= 0,252*0,855= 0,0534 in2

A5 = (Dp - d - 2*tn)*te*fr4= (8,1772 - 4,5676)*0,5*1= 1,8048 in2

Area = A1 + A2 + A3 + A41 + A42 + A43 + A5= 0 + 0,3557 + 0,2401 + 0,0534 + 0 + 0,0534 + 1,8048= 2,5074 in2









tb1 = 0,5867 in


tb = min[ tb3 , tb1 ]= min[ 0,2074 , 0,5867 ]= 0,2074 in





Groove weld in tension: 0,74*20.000 = 14.800 psiNozzle wall in shear: 0,7*17.100 = 11.970 psi

89/192

Inner fillet weld in shear: 0,49*17.100 = 8.379 psiOuter fillet weld in shear: 0,49*20.000 = 9.800 psiUpper groove weld in tension: 0,74*20.000 = 14.800 psiLower fillet weld in shear: 0,49*17.100 = 8.379 psiStrength of welded joints:





(5) Lower fillet weld in shear(π / 2)*Nozzle OD*Leg*Sl = (π / 2)*4,5*0,25*8.379 = 14.806,92 lbf




W1-1 = (A2 + A5 + A41 + A42)*Sv= (0,3557 + 1,8048 + 0,0534 + 0)*20.000= 44.278 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,3557 + 0,2401 + 0,0534 + 0,0534 + 2*0,237*0,528*0,855)*20.000= 18.332,1 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,3557 + 0,2401 + 1,8048 + 0,0534 + 0 + 0,0534 + 2*0,237*0,528*0,855)*20.000= 54.428,1 lbf


Load for path 2-2 lesser of W or W2-2 = 18.332,1 lbfPath 2-2 through (1), (4), (5), (6) = 14.806,92 + 55.236,74 + 14.806,92 + 52.307,52 = 137.158,09 lbfPath 2-2 is stronger than W2-2 so it is acceptable per UG-41(b)(1).

Load for path 3-3 lesser of W or W3-3 = 43.901,4 lbfPath 3-3 through (2), (4), (5) = 49.457,98 + 55.236,74 + 14.806,92 = 119.501,64 lbfPath 3-3 is stronger than W so it is acceptable per UG-41(b)(2).

90/192

HIGH LEVEL SWITCH (N5B)





91/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




92/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


93/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




94/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




95/192

LOW LEVEL SWITCH (N6A)





96/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




97/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


98/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




99/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




100/192

LEVEL GAUGE (N7A)





101/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




102/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


103/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




104/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




105/192

LEVEL GAUGE (N7B)





106/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




107/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


108/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




109/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




110/192

SPARE (N8A)





111/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




112/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


113/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




114/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




115/192

SPARE (N8B)





116/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin
















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*1,0335 / (17.100*1 - 0,6*247,1132)= 0,0151 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




117/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,5 ]= 0,1348 in


118/192






For P = 285 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 285*1,0335 / (17.100*1 - 0,6*285)= 0,0174 in


tr = P*R / (S*E - 0,6*P)= 285*30 / (20.000*1 - 0,6*285)= 0,4312 in


UW-16(c) Weld Check




119/192






tb = min[ tb3 , tb1 ]= min[ 0,1348 , 0,4312 ]= 0,1348 in




120/192

PRESSURE INDICATOR (N9)




Located on: Cylinder #1Liquid static head included: 0 psiNozzle material specification: SA-105 (II-D p. 18, ln. 5)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 1 Class 3000 - threadedNozzle orientation: 120°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 110 inEnd of nozzle to shell center: 31,4724 inNozzle inside diameter, new: 1,315 inNozzle nominal wall thickness: 0,2175 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 0,9724 in

121/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*0,6575 / (20.000*1 - 0,6*247,1132)= 0,0082 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




122/192

ASME B16.11 Coupling Wall Thickness Check

Wall thickness req'd per ASME B16.11 2.1.1: tr1 = 0,0108 in (E =1)Wall thickness per UG-16(b): tr3 = 0,0625 in

123/192

Available nozzle wall thickness new, tn = 0,2175 in





For P = 330,03 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 330,031*0,6575 / (20.000*1 - 0,6*330,031)= 0,011 in


tr = P*R / (S*E - 0,6*P)= 330,031*30 / (20.000*1 - 0,6*330,031)= 0,5 in


UW-16(c) Weld Check




124/192





125/192

PRESSURE TRANSMITER (N10)




Located on: Cylinder #1Liquid static head included: 0 psiNozzle material specification: SA-105 (II-D p. 18, ln. 5)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 1 Class 3000 - threadedNozzle orientation: 100°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 110 inEnd of nozzle to shell center: 31,4724 inNozzle inside diameter, new: 1,315 inNozzle nominal wall thickness: 0,2175 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 0,9724 in

126/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*0,6575 / (20.000*1 - 0,6*247,1132)= 0,0082 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




127/192



128/192






For P = 330,03 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 330,031*0,6575 / (20.000*1 - 0,6*330,031)= 0,011 in


tr = P*R / (S*E - 0,6*P)= 330,031*30 / (20.000*1 - 0,6*330,031)= 0,5 in


UW-16(c) Weld Check




129/192





130/192

TEMPERATURE INDICATOR (N11)




Located on: Cylinder #1Liquid static head included: 0 psiNozzle material specification: SA-105 (II-D p. 18, ln. 5)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 1 Class 3000 - threadedNozzle orientation: 80°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 110 inEnd of nozzle to shell center: 31,5 inNozzle inside diameter, new: 1,315 inNozzle nominal wall thickness: 0,2175 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 1 in

131/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*0,6575 / (20.000*1 - 0,6*247,1132)= 0,0082 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




132/192



133/192






For P = 330,03 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 330,031*0,6575 / (20.000*1 - 0,6*330,031)= 0,011 in


tr = P*R / (S*E - 0,6*P)= 330,031*30 / (20.000*1 - 0,6*330,031)= 0,5 in


UW-16(c) Weld Check




134/192





135/192

TEMPERATURE TRANSMITER (N12)




Located on: Cylinder #1Liquid static head included: 0 psiNozzle material specification: SA-105 (II-D p. 18, ln. 5)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 1 Class 3000 - threadedNozzle orientation: 60°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 110 inEnd of nozzle to shell center: 31,5 inNozzle inside diameter, new: 1,315 inNozzle nominal wall thickness: 0,2175 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 1 in

136/192




For P = 247,11 psi @ 150 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin















trn = P*Rn / (Sn*E - 0,6*P)= 247,1132*0,6575 / (20.000*1 - 0,6*247,1132)= 0,0082 in


tr = P*R / (S*E - 0,6*P)= 247,1132*30,125 / (20.000*1 - 0,6*247,1132)= 0,375 in


UW-16(c) Weld Check




137/192



138/192






For P = 330,03 psi @ 70 °F

UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin














trn = P*Rn / (Sn*E - 0,6*P)= 330,031*0,6575 / (20.000*1 - 0,6*330,031)= 0,011 in


tr = P*R / (S*E - 0,6*P)= 330,031*30 / (20.000*1 - 0,6*330,031)= 0,5 in


UW-16(c) Weld Check




139/192





140/192

MANHOLE (N14)


tw(lower) = 0,5 inLeg41 = 0,375 intw(upper) = 0,5 inLeg42 = 0,375 inDp = 36 inte = 0,5 in


Located on: Cylinder #2Liquid static head included: 0 psiNozzle material specification: SA-516 70 (II-D p. 18, ln. 19)Nozzle longitudinal joint efficiency: 1Pad material specification: SA-516 70 (II-D p. 18, ln. 19)Pad diameter: 36 inFlange description: NPS 24 Class 150 SO A105Bolt Material: SA-193 B7 Bolt <= 2 1/2 (II-D p. 334, ln. 32)Flange rated MDMT: -43,4°F(UCS-66(b)(1)(b))Liquid static head on flange: 0 psiASME B16.5-2003 flange rating MAWP: 272,5 psi @ 150°FASME B16.5-2003 flange rating MAP: 285 psi @ 70°FASME B16.5-2003 flange hydro test: 450 psi @ 70°FGasket Description: Flexitallic Solid Metal Core Flexpro Facing; Asbestos : Metal; NickelFlange external fillet weld leg (UW-21): 0,6614 in (0,6614 in min)Flange internal fillet weld leg (UW-21): 0,4286 in (0,4286 in min)PWHT performed: NoNozzle orientation: 270°Local vessel minimum thickness: 0,5 inNozzle center line offset to datum line: 24 inEnd of nozzle to shell center: 40,5 inNozzle inside diameter, new: 23,0552 inNozzle nominal wall thickness: 0,4724 inNozzle corrosion allowance: 0,125 inProjection available outside vessel, Lpr: 9,5276 inProjection available outside vessel to flange face, Lf: 10 inPad is split: No

141/192


Available reinforcement per UG-37 governs the MAWP of this nozzle.



UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin

7,7159 7,716 1,0236 0,4112 -- 6 0,2812 0,2531 0,4724


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

134.456,02 133.848 388.515,71 16.247 626.747,73 139.059 417.046,42








Nozzle impact test exemption temperature from Fig UCS-66 Curve B = -9,65 °FFig UCS-66.1 MDMT reduction = 119,2 °F, (coincident ratio = 0,3686)Rated MDMT of -128,85°F is limited to -55°F by UCS-66(b)(2).



LR = MAX(d, Rn + (tn - Cn) + (t - C))= MAX(23,3052, 11,6526 + (0,4724 - 0,125) + (0,5 - 0,125))= 23,3052 in


LH = MIN(2,5*(t - C), 2,5*(tn - Cn) + te)= MIN(2,5*(0,5 - 0,125), 2,5*(0,4724 - 0,125) + 0,5)= 0,9375 in


trn = P*Rn / (Sn*E - 0,6*P)= 218,3649*11,6526 / (20.000*1 - 0,6*218,3649)= 0,1281 in


tr = P*R / (S*E - 0,6*P)= 218,3649*30,125 / (20.000*1 - 0,6*218,3649)= 0,3311 in

142/192



fr1 = lesser of 1 or Sn / Sv = 1


fr3 = lesser of fr2 or Sp / Sv = 1


A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 23,3052*0,3311*1 + 2*0,3474*0,3311*1*(1 - 1)= 7,7159 in2



= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 23,3052*(1*0,375 - 1*0,3311) - 2*0,3474*(1*0,375 - 1*0,3311)*(1 - 1)= 1,0236 in2

= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 2*(0,375 + 0,3474)*(1*0,375 - 1*0,3311) - 2*0,3474*(1*0,375 - 1*0,3311)*(1 - 1)= 0,0635 in2


= 5*(tn - trn)*fr2*t= 5*(0,3474 - 0,1281)*1*0,375= 0,4112 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,3474 - 0,1281)*(2,5*0,3474 + 0,5)*1= 0,6002 in2

A41 = Leg2*fr3= 0,3752*1= 0,1406 in2

A42 = Leg2*fr4= 0,3752*1= 0,1406 in2

A5 = (Dp - d - 2*tn)*te*fr4= (36 - 23,3052 - 2*0,3474)*0,5*1= 6 in2

Area = A1 + A2 + A41 + A42 + A5= 1,0236 + 0,4112 + 0,1406 + 0,1406 + 6= 7,716 in2




143/192


UG-45 Nozzle Neck Thickness Check (Access Opening)

ta UG-27 = P*R / (S*E - 0,6*P) + Corrosion= 218,3649*11,6526 / (20.000*1 - 0,6*218,3649) + 0,125= 0,2531 in






(1) Inner fillet weld in shear(π / 2)*Nozzle OD*Leg*Si = (π / 2)*24*0,375*9.800 = 138.544,24 lbf

(2) Outer fillet weld in shear(π / 2)*Pad OD*Leg*So = (π / 2)*36*0,375*9.800 = 207.816,35 lbf


(4) Groove weld in tension(π / 2)*Nozzle OD*tw*Sg = (π / 2)*24*0,375*14.800 = 209.230,07 lbf

(6) Upper groove weld in tension(π / 2)*Nozzle OD*tw*Sg = (π / 2)*24*0,5*14.800 = 278.973,43 lbf


W = (A - A1 + 2*tn*fr1*(E1*t - F*tr))*Sv= (7,7159 - 1,0236 + 2*0,3474*1*(1*0,375 - 1*0,3311))*20.000= 134.456,02 lbf

W1-1 = (A2 + A5 + A41 + A42)*Sv= (0,4112 + 6 + 0,1406 + 0,1406)*20.000= 133.848 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,4112 + 0 + 0,1406 + 0 + 2*0,3474*0,375*1)*20.000= 16.247 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,4112 + 0 + 6 + 0,1406 + 0,1406 + 0 + 2*0,3474*0,375*1)*20.000= 139.059 lbf

Load for path 1-1 lesser of W or W1-1 = 133.848 lbfPath 1-1 through (2) & (3) = 207.816,35 + 180.699,36 = 388.515,71 lbfPath 1-1 is stronger than W1-1 so it is acceptable per UG-41(b)(1).

144/192



Check the opening per Appendix 1-7

Area required within 75 percent of the limits of reinforcement= 2 / 3*A = (2 / 3)*7,7159 = 5,1439 in2

Area that is within 75 percent of the limits of reinforcement is:

A1 = larger of 0,0635 or

= (2*limits - d)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= (2*17,4789 - 23,3052)*(1*0,375 - 1*0,3311) - 2*0,3474*(1*0,375 - 1*0,3311)*(1 - 1)= 0,5118 in2

A5 = (Dp - d - 2*tn)*te*fr4= (34,9578 - 23,3052 - 2*0,3474)*0,5*1= 5,4789 in2

Area = A1 + A2 + A3 + A41 + A42 + A43 + A5= 0,5118 + 0,4112 + 0 + 0,1406 + 0 + 0 + 5,4789= 6,5425 in2

The area placement requirements of Appendix 1-7 are satisfied.

The opening is not within the size range defined by 1-7(b)(1)(a) and (b) so it is exempt from the requirements of 1-7(b)(2),(3) and(4).

Rn / R ratio does not exceed 0,7 so a U-2(g) analysis is not required per 1-7(b)(1)(c).


EFE = (50*t / Rf)*(1 - Rf / Ro)= (50*0,4724 / 11,7638)*(1 - 11,7638 / ∞)= 2,0079%

145/192



Available reinforcement per UG-37 governs the MAP of this nozzle.



UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin

9,3009 9,3014 2,2267 0,7935 -- 6 0,2812 0,155 0,4724


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

143.309,55 141.494 452.235,61 28.130 696.491,09 150.942 486.789,78













trn = P*Rn / (Sn*E - 0,6*P)= 266,7959*11,5276 / (20.000*1 - 0,6*266,7959)= 0,155 in


tr = P*R / (S*E - 0,6*P)= 266,7959*30 / (20.000*1 - 0,6*266,7959)= 0,4034 in





fr3 = lesser of fr2 or Sp / Sv = 1


146/192

A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 23,0552*0,4034*1 + 2*0,4724*0,4034*1*(1 - 1)= 9,3009 in2



= d*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 23,0552*(1*0,5 - 1*0,4034) - 2*0,4724*(1*0,5 - 1*0,4034)*(1 - 1)= 2,2267 in2

= 2*(t + tn)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= 2*(0,5 + 0,4724)*(1*0,5 - 1*0,4034) - 2*0,4724*(1*0,5 - 1*0,4034)*(1 - 1)= 0,1878 in2


= 5*(tn - trn)*fr2*t= 5*(0,4724 - 0,155)*1*0,5= 0,7935 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,4724 - 0,155)*(2,5*0,4724 + 0,5)*1= 1,0671 in2

A41 = Leg2*fr3= 0,3752*1= 0,1406 in2

A42 = Leg2*fr4= 0,3752*1= 0,1406 in2

A5 = (Dp - d - 2*tn)*te*fr4= (36 - 23,0552 - 2*0,4724)*0,5*1= 6 in2

Area = A1 + A2 + A41 + A42 + A5= 2,2267 + 0,7935 + 0,1406 + 0,1406 + 6= 9,3014 in2





UG-45 Nozzle Neck Thickness Check (Access Opening)


147/192






(1) Inner fillet weld in shear(π / 2)*Nozzle OD*Leg*Si = (π / 2)*24*0,375*9.800 = 138.544,24 lbf

(2) Outer fillet weld in shear(π / 2)*Pad OD*Leg*So = (π / 2)*36*0,375*9.800 = 207.816,35 lbf


(4) Groove weld in tension(π / 2)*Nozzle OD*tw*Sg = (π / 2)*24*0,5*14.800 = 278.973,43 lbf

(6) Upper groove weld in tension(π / 2)*Nozzle OD*tw*Sg = (π / 2)*24*0,5*14.800 = 278.973,43 lbf


W = (A - A1 + 2*tn*fr1*(E1*t - F*tr))*Sv= (9,3009 - 2,2267 + 2*0,4724*1*(1*0,5 - 1*0,4034))*20.000= 143.309,55 lbf

W1-1 = (A2 + A5 + A41 + A42)*Sv= (0,7935 + 6 + 0,1406 + 0,1406)*20.000= 141.494 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,7935 + 0 + 0,1406 + 0 + 2*0,4724*0,5*1)*20.000= 28.130 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,7935 + 0 + 6 + 0,1406 + 0,1406 + 0 + 2*0,4724*0,5*1)*20.000= 150.942 lbf

Load for path 1-1 lesser of W or W1-1 = 141.494 lbfPath 1-1 through (2) & (3) = 207.816,35 + 244.419,26 = 452.235,61 lbfPath 1-1 is stronger than W1-1 so it is acceptable per UG-41(b)(1).



148/192

Check the opening per Appendix 1-7

Area required within 75 percent of the limits of reinforcement= 2 / 3*A = (2 / 3)*9,3009 = 6,2006 in2

Area that is within 75 percent of the limits of reinforcement is:

A1 = larger of 0,1878 or

= (2*limits - d)*(E1*t - F*tr) - 2*tn*(E1*t - F*tr)*(1 - fr1)= (2*17,2914 - 23,0552)*(1*0,5 - 1*0,4034) - 2*0,4724*(1*0,5 - 1*0,4034)*(1 - 1)= 1,1133 in2

A5 = (Dp - d - 2*tn)*te*fr4= (34,5828 - 23,0552 - 2*0,4724)*0,5*1= 5,2914 in2

Area = A1 + A2 + A3 + A41 + A42 + A43 + A5= 1,1133 + 0,7935 + 0 + 0,1406 + 0 + 0 + 5,2914= 7,3388 in2

The area placement requirements of Appendix 1-7 are satisfied.

The opening is not within the size range defined by 1-7(b)(1)(a) and (b) so it is exempt from the requirements of 1-7(b)(2),(3) and(4).

Rn / R ratio does not exceed 0,7 so a U-2(g) analysis is not required per 1-7(b)(1)(c).

149/192

OUT DRAIN (N16)




Located on: Bottom HeadLiquid static head included: 0 psiNozzle material specification: SA-106 B Smls pipe (II-D p. 10, ln. 40)Nozzle longitudinal joint efficiency: 1Nozzle description: NPS 4 Sch 40 (Std)Pad material specification: SA-516 70 (II-D p. 18, ln. 19)Pad diameter: 8,5 inNozzle orientation: 0°Calculated as hillside: NoLocal vessel minimum thickness: 0,528 inEnd of nozzle to datum line: -23,4302 inNozzle inside diameter, new: 4,026 inNozzle nominal wall thickness: 0,237 inNozzle corrosion allowance: 0 inProjection available outside vessel, Lpr: 5,9444 inDistance to head center, R: 0 inPad is split: No

150/192





UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin

1,6501 2,1765 -- 0,3471 -- 1,776 0,0534 0,2074 0,2074


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

33.002,79 43.530 68.064,43 11.276,48 109.274,29 46.796,48 91.227,61










Pad impact test exemption temperature from Fig UCS-66 Curve B = -7 °FFig UCS-66.1 MDMT reduction = 26,8 °F, (coincident ratio = 0,7323).

Nozzle UCS-66 governing thk: 0,2074 inNozzle rated MDMT: -155 °FPad UCS-66 governing thickness: 0,5 inPad rated MDMT: -33,8 °FParallel Limit of reinforcement per UG-40





trn = P*Rn / (Sn*E - 0,6*P)= 298,0583*2,013 / (17.100*1 - 0,6*298,0583)= 0,0355 in


tr = P*K1*D / (2*S*E - 0,2*P)= 298,0583*0,8963*60,25 / (2*20.000*1 - 0,2*298,0583)= 0,403 in

151/192







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 4,026*0,403*1 + 2*0,237*0,403*1*(1 - 0,855)= 1,6501 in2






= 5*(tn - trn)*fr2*t= 5*(0,237 - 0,0355)*0,855*0,403= 0,3471 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,237 - 0,0355)*(2,5*0,237 + 0,5)*0,855= 0,3764 in2

A41 = Leg2*fr3= 0,252*0,855= 0,0534 in2

A42 = Leg2*fr4= 02*1= 0 in2


A5 = (Dp - d - 2*tn)*te*fr4= (8,052 - 4,026 - 2*0,237)*0,5*1= 1,776 in2

Area = A1 + A2 + A41 + A42 + A5= 0 + 0,3471 + 0,0534 + 0 + 1,776= 2,1765 in2




152/192






tb1 = 0,5721 in


tb = min[ tb3 , tb1 ]= min[ 0,2074 , 0,5721 ]= 0,2074 in













W1-1 = (A2 + A5 + A41 + A42)*Sv

153/192

= (0,3471 + 1,776 + 0,0534 + 0)*20.000= 43.530 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,3471 + 0 + 0,0534 + 0 + 2*0,237*0,403*0,855)*20.000= 11.276,48 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,3471 + 0 + 1,776 + 0,0534 + 0 + 0 + 2*0,237*0,403*0,855)*20.000= 46.796,48 lbf

154/192


Load for path 2-2 lesser of W or W2-2 = 11.276,48 lbfPath 2-2 through (1), (4), (6) = 14.806,92 + 42.159,86 + 52.307,52 = 109.274,29 lbfPath 2-2 is stronger than W2-2 so it is acceptable per UG-41(b)(1).






UG-45 NozzleWall


UG-45

Arequired


Awelds treq tmin

2,162 2,1851 -- 0,3557 -- 1,776 0,0534 0,2074 0,2074


Weld loadW

Weld loadW1-1

Path 1-1strength

Weld loadW2-2

Path 2-2strength

Weld loadW3-3

Path 3-3strength

43.240,35 43.702 68.064,43 12.461,65 122.351,17 47.981,65 104.304,49













trn = P*Rn / (Sn*E - 0,6*P)= 390,3502*2,013 / (17.100*1 - 0,6*390,3502)= 0,0466 in


tr = P*K1*D / (2*S*E - 0,2*P)= 390,3502*0,9*60 / (2*20.000*1 - 0,2*390,3502)= 0,528 in

155/192







A = d*tr*F + 2*tn*tr*F*(1 - fr1)= 4,026*0,528*1 + 2*0,237*0,528*1*(1 - 0,855)= 2,162 in2






= 5*(tn - trn)*fr2*t= 5*(0,237 - 0,0466)*0,855*0,528= 0,4298 in2

= 2*(tn - trn)*(2,5*tn + te)*fr2= 2*(0,237 - 0,0466)*(2,5*0,237 + 0,5)*0,855= 0,3557 in2

A41 = Leg2*fr3= 0,252*0,855= 0,0534 in2

A42 = Leg2*fr4= 02*1= 0 in2


A5 = (Dp - d - 2*tn)*te*fr4= (8,052 - 4,026 - 2*0,237)*0,5*1= 1,776 in2

Area = A1 + A2 + A41 + A42 + A5= 0 + 0,3557 + 0,0534 + 0 + 1,776= 2,1851 in2




156/192






tb1 = 0,5867 in


tb = min[ tb3 , tb1 ]= min[ 0,2074 , 0,5867 ]= 0,2074 in













W1-1 = (A2 + A5 + A41 + A42)*Sv

157/192

= (0,3557 + 1,776 + 0,0534 + 0)*20.000= 43.702 lbf

W2-2 = (A2 + A3 + A41 + A43 + 2*tn*t*fr1)*Sv= (0,3557 + 0 + 0,0534 + 0 + 2*0,237*0,528*0,855)*20.000= 12.461,65 lbf

W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2*tn*t*fr1)*Sv= (0,3557 + 0 + 1,776 + 0,0534 + 0 + 0 + 2*0,237*0,528*0,855)*20.000= 47.981,65 lbf


Load for path 2-2 lesser of W or W2-2 = 12.461,65 lbfPath 2-2 through (1), (4), (6) = 14.806,92 + 55.236,74 + 52.307,52 = 122.351,17 lbfPath 2-2 is stronger than W2-2 so it is acceptable per UG-41(b)(1).


158/192

Lifting Lug #1

Geometry Inputs

Attached To Top Head

Material A36

Orientation Longitudinal

Distance of Lift Point From Datum 130"

Angular Position 0,00°

Length of Lug, L 5"

Height of Lug, H 5"

Thickness of Lug, t 0,5"

Hole Diameter, d 1,25"

Pin Diameter, Dp 1"

Load Eccentricity, a1 0"

Distance from Load to Shell or Pad, a2 2,7138"

Weld Size, tw 0,25"

Load Angle Normal to Vessel, β 45,0000 °

Load Angle from Vertical, φ -4,2707 °

Intermediate Values

Load Factor 1,5000

Vessel Weight (new, incl. Load Factor), W 11009 lb

Lug Weight (new), Wlug 3 lb

Allowable Stress, Tensile, σt 19980 psi

Allowable Stress, Shear, σs 13320 psi

Allowable Stress, Bearing, σp 29970 psi

Allowable Stress, Bending, σb 22201 psi

Allowable Stress, Weld Shear, τallowable 13320 psi

Allowable Stress set to 1/3 Sy per ASME B30.20 No

Summary Values

Required Lift Pin Diameter, dreqd 0,5122"

Required Lug Thickness, treqd 0,1832"

Lug Stress Ratio, σratio 0,31

Weld Shear Stress Ratio, τratio 0,58

Lug Design Acceptable

159/192

Lift Forces

Fr = force on vessel at lugFr = [W / cos(φ1)]*(1 - x1 / (x1 + x2))

= (11.009,5) / cos(-4,2707)*(1 - 30,3706/ (30,3706 +30,0318))

= 5.489 lbfwhere 'x1' is the distance between this lug and the center of gravity

'x2' is the distance between the second lift lug and the center of gravity

Lug Pin Diameter - Shear stress

dreqd = (2*Fr / (π*σs))0,5

= (2*5.489 / (π*13.320))0,5 = 0,5122"

dreqd / Dp = 0,5122 / 1 = 0,51 Acceptable

σ = Fr / A= Fr / (2*(0,25*π*Dp

2))= 5.489 / (2*(0,25*π*12)) = 3.494 psi

σ / σs = 3.494 / 13.320 = 0,26 Acceptable

Lug Thickness - Tensile stress

treqd = Fr / ((L - d)*σt)= 5.489 / ((5 - 1,25)*19.980) = 0,0733"

treqd / t = 0,0733 / 0,5 = 0,15 Acceptable

σ = Fr / A= Fr / ((L - d)*t)= 5.489 / ((5 - 1,25)*0,5) = 2.928 psi

σ / σt = 2.928 / 19.980 = 0,15 Acceptable

Lug Thickness - Bearing stress

treqd = Fv / (Dp*σp)= 5.489 / (1*29.970) = 0,1832"


σ = Fv / Abearing= Fv / (Dp*(t))= 5.489 / (1*(0,5)) = 10.978 psi

σ / σp = 10.978 / 29.970 = 0,37 Acceptable

Lug Thickness - Shear stress

treqd = [Fv / σs] / (2*Lshear)= (5.489 / 13.320) / (2*1,8016) = 0,1144"


τ = Fv / Ashear= Fv / (2*t*Lshear )= 5.489 / (2*0,5*1,8016) = 3.047 psi

τ / σs = 3.047 / 13.320 = 0,23 Acceptable

160/192

Shear stress length (per Pressure Vessel and Stacks, A. Keith Escoe)

φ = 55*Dp / d= 55*1 / 1,25= 44°

Lshear = (H - a2 - 0.5*d) + 0.5*Dp*(1 - cos(φ))= (5 - 2,7138 - 0.5*1,25) + 0.5*1*(1 - cos(44))= 1,8016"

Lug Plate Stress

Lug stress tensile + bending during lift:σ ratio = [Ften / (Aten*σt)] + [Mbend / (Zbend*σb)] ≤ 1

= [(Fr*cos(α) ) / (t*L*σt)] + [(6*abs(Fr*sin(α)*Hght - Fr*cos(α)*a1) ) / (t*L2*σb)] ≤ 1

= 5.489*cos(45,0) / (0,5*5*19.980) + 6*abs(5.489*sin(45,0)*2,7138 - 5.489*cos(45,0)*0) /(0,5*52*22.201)

= 0,31 Acceptable

Weld Stress

Weld stress, tensile, bending and shear during lift:

Direct shear:

Shear stress at lift angle 45,00°; lift force = 5.489 lbf

Aweld = 2*(0,707)*tw*(L + t)= 2*(0,707)*0,25*(5 + 0,5) = 1,9442 in2

τt = Fr*cos(α) / Aweld= 5.489*cos(45,0) / 1,9442 = 1.996 psi

τs = Fr*sin(α) / Aweld= 5.489*sin(45,0) / 1,9442 = 1.996 psi

τb = M * c / I= 3*(Fr*sin(α)*Hght - Fr*cos(α)*a1) / (0,707*h*L*(3*t + L))= 3*abs(5.489*sin(45,0)*2,7138 - 5.489*cos(45,0)*(0)) / (5,7444)= 5.501 psi

τ ratio = sqr( (τt + τb)2 +τs

2 ) / τallowable ≤ 1

=sqr ( (1.996 +5.501)2 +(1.996)2 ) /13.320

= 0,58 Acceptable

161/192

Lifting Lug #2

Geometry Inputs

Attached To Top Head

Material A36

Orientation Longitudinal

Distance of Lift Point From Datum 130"

Angular Position 180,00°

Length of Lug, L 5"

Height of Lug, H 5"

Thickness of Lug, t 0,5"

Hole Diameter, d 1,25"

Pin Diameter, Dp 0,875"

Load Eccentricity, a1 0"

Distance from Load to Shell or Pad, a2 3"

Weld Size, tw 0,25"

Load Angle Normal to Vessel, β 45,0000 °

Load Angle from Vertical, φ -5,0345 °

Intermediate Values

Load Factor 1,5000

Vessel Weight (new, incl. Load Factor), W 11009 lb

Lug Weight (new), Wlug 3 lb

Allowable Stress, Tensile, σt 19980 psi

Allowable Stress, Shear, σs 13320 psi

Allowable Stress, Bearing, σp 29970 psi

Allowable Stress, Bending, σb 22201 psi

Allowable Stress, Weld Shear, τallowable 13320 psi

Allowable Stress set to 1/3 Sy per ASME B30.20 No

Summary Values

Required Lift Pin Diameter, dreqd 0,5094"

Required Lug Thickness, treqd 0,207"

Lug Stress Ratio, σratio 0,33

Weld Shear Stress Ratio, τratio 0,62

Lug Design Acceptable

162/192

Lift Forces

Fr = force on vessel at lugFr = [W / cos(φ1)]*(1 - x1 / (x1 + x2))

= (11.009,5) / cos(-5,0345)*(1 - 30,7325/ (30,7325 +29,6699))

= 5.429 lbfwhere 'x1' is the distance between this lug and the center of gravity

'x2' is the distance between the second lift lug and the center of gravity

Lug Pin Diameter - Shear stress

dreqd = (2*Fr / (π*σs))0,5

= (2*5.429 / (π*13.320))0,5 = 0,5094"

dreqd / Dp = 0,5094 / 0,875 = 0,58 Acceptable

σ = Fr / A= Fr / (2*(0,25*π*Dp

2))= 5.429 / (2*(0,25*π*0,8752)) = 4.514 psi

σ / σs = 4.514 / 13.320 = 0,34 Acceptable

Lug Thickness - Tensile stress

treqd = Fr / ((L - d)*σt)= 5.429 / ((5 - 1,25)*19.980) = 0,0725"


σ = Fr / A= Fr / ((L - d)*t)= 5.429 / ((5 - 1,25)*0,5) = 2.895 psi

σ / σt = 2.895 / 19.980 = 0,14 Acceptable

Lug Thickness - Bearing stress

treqd = Fv / (Dp*σp)= 5.429 / (0,875*29.970) = 0,207"


σ = Fv / Abearing= Fv / (Dp*(t))= 5.429 / (0,875*(0,5)) = 12.409 psi

σ / σp = 12.409 / 29.970 = 0,41 Acceptable

Lug Thickness - Shear stress

treqd = [Fv / σs] / (2*Lshear)= (5.429 / 13.320) / (2*1,4701) = 0,1386"


τ = Fv / Ashear= Fv / (2*t*Lshear )= 5.429 / (2*0,5*1,4701) = 3.693 psi

τ / σs = 3.693 / 13.320 = 0,28 Acceptable

163/192

Shear stress length (per Pressure Vessel and Stacks, A. Keith Escoe)

φ = 55*Dp / d= 55*0,875 / 1,25= 38,5°

Lshear = (H - a2 - 0.5*d) + 0.5*Dp*(1 - cos(φ))= (5 - 3 - 0.5*1,25) + 0.5*0,875*(1 - cos(38,5))= 1,4701"

Lug Plate Stress

Lug stress tensile + bending during lift:σ ratio = [Ften / (Aten*σt)] + [Mbend / (Zbend*σb)] ≤ 1

= [(Fr*cos(α) ) / (t*L*σt)] + [(6*abs(Fr*sin(α)*Hght - Fr*cos(α)*a1) ) / (t*L2*σb)] ≤ 1

= 5.429*cos(45,0) / (0,5*5*19.980) + 6*abs(5.429*sin(45,0)*3 -5.429*cos(45,0)*0) / (0,5*52*22.201)

= 0,33 Acceptable

Weld Stress

Weld stress, tensile, bending and shear during lift:

Direct shear:

Shear stress at lift angle 45,00°; lift force = 5.429 lbf

Aweld = 2*(0,707)*tw*(L + t)= 2*(0,707)*0,25*(5 + 0,5) = 1,9442 in2

τt = Fr*cos(α) / Aweld= 5.429*cos(45,0) / 1,9442 = 1.974 psi

τs = Fr*sin(α) / Aweld= 5.429*sin(45,0) / 1,9442 = 1.974 psi

τb = M * c / I= 3*(Fr*sin(α)*Hght - Fr*cos(α)*a1) / (0,707*h*L*(3*t + L))= 3*abs(5.429*sin(45,0)*3 - 5.429*cos(45,0)*(0)) / (5,7444)= 6.014 psi

τ ratio = sqr( (τt + τb)2 +τs

2 ) / τallowable ≤ 1

=sqr ( (1.974 +6.014)2 +(1.974)2 ) /13.320

= 0,62 Acceptable

164/192

Support Skirt

Material: SA-36 (II-D p. 10, ln.15)

Design temperature, operating: 100 °FInner diameter at top, new: 60,875 inInner diameter at bottom, new: 60,875 inOverall length (includes base ring thickness): 41,75 inCorrosion allowance inside: 0 inCorrosion allowance outside: 0 inWeld joint efficiency top: 0,55Weld joint efficiency bottom: 0,8Nominal thickness, new: 0,5906 inSkirt is attached to: Bottom HeadSkirt attachment offset: 3,2048 in down from the top

seam

Skirt design thickness, largest of the following + corrosion = 0,0054 in

The governing condition is due to earthquake, compressive stress at the base, operating & new.

The skirt thickness of 0,5906 in is adequate.

LoadingVessel

Condition(Stress)

GoverningSkirt

LocationTemperature

(°F)Allowable

Stress(psi)

CalculatedStress/E

(psi)

Requiredthickness

(in)

Wind operating, corroded (+) top 100 16.600 19,87 0,0007

Wind operating, corroded (-) bottom 100 15.502,67 95,91 0,0037

Wind operating, new (+) bottom 100 16.600 10,76 0,0004

Wind operating, new (-) bottom 100 15.502,67 106,66 0,0041

Wind empty, corroded (+) top 70 16.600 19,87 0,0007

Wind empty, corroded (-) bottom 70 15.502,67 95,91 0,0037

Wind empty, new (+) bottom 70 16.600 10,76 0,0004

Wind empty, new (-) bottom 70 15.502,67 106,66 0,0041

Seismic operating, corroded (+) top 100 16.600 52,46 0,0019

Seismic operating, corroded (-) bottom 100 15.502,67 121,18 0,0046

Seismic operating, new (+) top 100 16.600 55,94 0,002

Seismic operating, new (-) bottom 100 15.502,67 142,24 0,0054

Seismic empty, corroded (+) top 70 16.600 52,46 0,0019

Seismic empty, corroded (-) bottom 70 15.502,67 121,18 0,0046

Seismic empty, new (+) top 70 16.600 55,94 0,002

Seismic empty, new (-) bottom 70 15.502,67 142,24 0,0054

Loading due to wind, operating & corrodedWindward side (tensile)

Required thickness, tensile stress at base:

t = -0,6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0,6*5.849,09 / (π*61,4656*16.600*0,8) + 48*6.516,2 / (π*61,46562*16.600*0,8)= 0,0006 in

Required thickness, tensile stress at the top:

t = -0,6*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)

= -0,6*4.479,07 / (π*61,4656*16.600*0,55) + 48*5.037,5 / (π*61,46562*16.600*0,55)= 0,0007 in

Leeward side (compressive)

Required thickness, compressive stress at base:

t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 5.849,09 / (π*61,4656*15.503*1) + 48*6.516,2 / (π*61,46562*15.503*1)

165/192

= 0,0037 in

Required thickness, compressive stress at the top:

t = Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)

= 4.479,07 / (π*61,4656*15.503*1) + 48*5.037,5 / (π*61,46562*15.503*1)= 0,0028 in

Loading due to wind, operating & newWindward side (tensile)


t = -0,6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0,6*6.988,66 / (π*61,4656*16.600*0,8) + 48*6.627 / (π*61,46562*16.600*0,8)= 0,0004 in



= -0,6*5.618,64 / (π*61,4656*16.600*0,55) + 48*5.148,4 / (π*61,46562*16.600*0,55)= 0,0004 in



t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 6.988,66 / (π*61,4656*15.503*1) + 48*6.627 / (π*61,46562*15.503*1)= 0,0041 in



= 5.618,64 / (π*61,4656*15.503*1) + 48*5.148,4 / (π*61,46562*15.503*1)= 0,0032 in

Loading due to wind, empty & corrodedWindward side (tensile)


t = -0,6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0,6*5.849,09 / (π*61,4656*16.600*0,8) + 48*6.516,2 / (π*61,46562*16.600*0,8)= 0,0006 in



= -0,6*4.479,07 / (π*61,4656*16.600*0,55) + 48*5.037,5 / (π*61,46562*16.600*0,55)= 0,0007 in



t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 5.849,09 / (π*61,4656*15.503*1) + 48*6.516,2 / (π*61,46562*15.503*1)= 0,0037 in

166/192



= 4.479,07 / (π*61,4656*15.503*1) + 48*5.037,5 / (π*61,46562*15.503*1)= 0,0028 in

Loading due to wind, empty & newWindward side (tensile)


t = -0,6*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -0,6*6.988,66 / (π*61,4656*16.600*0,8) + 48*6.627 / (π*61,46562*16.600*0,8)= 0,0004 in



= -0,6*5.618,64 / (π*61,4656*16.600*0,55) + 48*5.148,4 / (π*61,46562*16.600*0,55)= 0,0004 in



t = W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= 6.988,66 / (π*61,4656*15.503*1) + 48*6.627 / (π*61,46562*15.503*1)= 0,0041 in



= 5.618,64 / (π*61,4656*15.503*1) + 48*5.148,4 / (π*61,46562*15.503*1)= 0,0032 in

Loading due to earthquake, operating & corrodedTensile side


t = -(0,6 - 0,14*SDS)*W / (π*D*St*E) + 48*M / (π*D2*St*E)= -(0,6 - 0,14*0,55)*5.849,09 / (π*61,4656*16.600*0,8) + 48*9.630,4 / (π*61,46562*16.600*0,8)= 0,0017 in


t = -(0,6 - 0,14*SDS)*Wt / (π*Dt*St*E) + 48*Mt / (π*Dt2*St*E)

= -(0,6 - 0,14*0,55)*4.479,07 / (π*61,4656*16.600*0,55) + 48*7.213,7 / (π*61,46562*16.600*0,55)= 0,0019 in

Compressive side


t = (1 + 0,14*SDS)*W / (π*D*Sc*Ec) + 48*M / (π*D2*Sc*Ec)= (1 + 0,14*0,55)*5.849,09 / (π*61,4656*15.503*1) + 48*9.630,4 / (π*61,46562*15.503*1)= 0,0046 in


t = (1 + 0,14*SDS)*Wt / (π*Dt*Sc*Ec) + 48*Mt / (π*Dt2*Sc*Ec)

= (1 + 0,14*0,55)*4.479,07 / (π*61,4656*15.503*1) + 48*7.213,7 / (π*61,46562*15.503*1)

167/192

= 0,0035 in

Loading due to earthquake, operating & newTensile side





= -(0,6 - 0,14*0,55)*5.618,64 / (π*61,4656*16.600*0,55) + 48*8.256 / (π*61,46562*16.600*0,55)= 0,002 in

Compressive side





= (1 + 0,14*0,55)*5.618,64 / (π*61,4656*15.503*1) + 48*8.256 / (π*61,46562*15.503*1)= 0,0042 in

Loading due to earthquake, empty & corrodedTensile side





= -(0,6 - 0,14*0,55)*4.479,07 / (π*61,4656*16.600*0,55) + 48*7.213,7 / (π*61,46562*16.600*0,55)= 0,0019 in

Compressive side





= (1 + 0,14*0,55)*4.479,07 / (π*61,4656*15.503*1) + 48*7.213,7 / (π*61,46562*15.503*1)= 0,0035 in

168/192

Loading due to earthquake, empty & newTensile side





= -(0,6 - 0,14*0,55)*5.618,64 / (π*61,4656*16.600*0,55) + 48*8.256 / (π*61,46562*16.600*0,55)= 0,002 in

Compressive side





= (1 + 0,14*0,55)*5.618,64 / (π*61,4656*15.503*1) + 48*8.256 / (π*61,46562*15.503*1)= 0,0042 in

169/192

Base Ring

Base configuration: single base plateFoundation compressive strength: 1.658 psiConcrete ultimate 28-day strength: 3.000 psiAnchor bolt material: Bolt MaterialAnchor bolt allowable stress, Sb: 20.000 psiBolt circle, BC: 64,875 inAnchor bolt corrosion allowance (applied to root radius): 0 inAnchor bolt clearance: 0,375 inBase plate material: Base Ring MaterialBase plate allowable stress, Sp: 20.000 psiBase plate inner diameter, Di: 50,9375 inBase plate outer diameter, Do: 70,9375 inBase plate thickness, tb: 0,5906 inGusset separation, w: 4 inGusset height, h: 5,5 inGusset thickness, tg: 0,5906 inInitial bolt preload: 0 % (0 psi)Number of bolts, N: 8Bolt size and type: 0,75 inch series 8 threadedBolt root area (corroded), Ab: 0,302 in2

Diameter of anchor bolt holes, db: 1,125 in

Load Vesselcondition

Base M(lbf-ft)

W(lb)

Requiredbolt area

(in2)

trBase(in)

Foundationbearingstress(psi)

Wind operating, corroded 6.516,2 6.200,1 0,0069 0,1443 6,29

Wind operating, new 6.627 7.339,7 0,0031 0,1516 6,94

Wind empty, corroded 6.516,2 6.200,1 0,0069 0,1443 6,29

Wind empty, new 6.627 7.339,7 0,0031 0,1516 6,94

Seismic operating, corroded 9.630,4 6.200,1 0,0243 0,2433 17,88

Seismic operating, new 11.134,8 7.339,7 0,0275 0,261 20,57

Seismic empty, corroded 9.630,4 6.200,1 0,0243 0,2433 17,88

Seismic empty, new 11.134,8 7.339,7 0,0275 0,261 20,57

Anchor bolt load (operating, corroded + Wind)

P = -0,6*W / N + 48 * M / (N*BC)= -0,6*6.200,09 / 8 + 48 * 6.516,2 / (8*64,875)= 137,65 lbf

Required area per bolt = P / Sb = 0,0069 in2

The area provided (0,302 in2) by the specified anchor bolt is adequate.

Foundation bearing stress (operating, corroded + Wind)

Ac = pi*(Do2 - Di

2) / 4 - N*pi*db2 / 4

= π*(70,93752 - 50,93752) / 4 - 8*π*1,1252 / 4= 1.906,4559 in2

Ic = π*(Do4 - Di

4) / 64= π*(70,93754 - 50,93754) / 64= 912.545,4 in4

fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0,302*0 / 1.906,4559 + 6.200,09 / 1.906,4559 + 6*6.516,2*70,9375 / 912.545,4= 6 psi

As fc <= 1.658 psi the base plate width is satisfactory.

Base plate required thickness (operating, corroded + Wind)

From Brownell & Young, Table 10.3:, l / b = 0,2448

Mx = 0,0057*6*20,29522 = 14,8 lbf

My = -0,4471*6*4,96882 = -69,4 lbf

170/192

tr = (6*Mmax / Sp)0,5

= (6*69,45 / 20.000)0,5

= 0,1443 in

The base plate thickness is satisfactory.

Base plate bolt load (Jawad & Farr eq. 12.13, operating, corroded + Wind)

Bolt load = Ab*fs =0,302*456 = 137,65 lbf

tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*137,65 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0747 in


Check skirt for gusset reaction (Jawad & Farr eq. 12.14)

Sr = 1,5*F*b / (gussets*π*tsk2*h)

= 1,5*137,65*4,4407 / (2*π*0,59062*5,5)= 76,06 psi

As Sr <= 24.900 psi the skirt thickness is adequate to resist the gusset reaction.

Anchor bolt load (operating, new + Wind)

P = -0,6*W / N + 48 * M / (N*BC)= -0,6*7.339,66 / 8 + 48 * 6.627 / (8*64,875)= 62,43 lbf



Foundation bearing stress (operating, new + Wind)

Ac = pi*(Do2 - Di

2) / 4 - N*pi*db2 / 4

= π*(70,93752 - 50,93752) / 4 - 8*π*1,1252 / 4= 1.906,4559 in2

Ic = π*(Do4 - Di

4) / 64= π*(70,93754 - 50,93754) / 64= 912.545,4 in4

fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0,302*0 / 1.906,4559 + 7.339,66 / 1.906,4559 + 6*6.627*70,9375 / 912.545,4= 7 psi


Base plate required thickness (operating, new + Wind)


Mx = 0,0057*7*20,29522 = 16,4 lbf

My = -0,4471*7*4,96882 = -76,6 lbf

tr = (6*Mmax / Sp)0,5

= (6*76,62 / 20.000)0,5

= 0,1516 in


Base plate bolt load (Jawad & Farr eq. 12.13, operating, new + Wind)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*62,43 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0503 in




171/192

= 1,5*62,43*4,4407 / (2*π*0,59062*5,5)= 34,5 psi


Anchor bolt load (empty, corroded + Wind)

P = -0,6*W / N + 48 * M / (N*BC)= -0,6*6.200,09 / 8 + 48 * 6.516,2 / (8*64,875)= 137,65 lbf



Foundation bearing stress (empty, corroded + Wind)

Ac = pi*(Do2 - Di

2) / 4 - N*pi*db2 / 4

= π*(70,93752 - 50,93752) / 4 - 8*π*1,1252 / 4= 1.906,4559 in2

Ic = π*(Do4 - Di

4) / 64= π*(70,93754 - 50,93754) / 64= 912.545,4 in4

fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0,302*0 / 1.906,4559 + 6.200,09 / 1.906,4559 + 6*6.516,2*70,9375 / 912.545,4= 6 psi


Base plate required thickness (empty, corroded + Wind)


Mx = 0,0057*6*20,29522 = 14,8 lbf

My = -0,4471*6*4,96882 = -69,4 lbf

tr = (6*Mmax / Sp)0,5

= (6*69,45 / 20.000)0,5

= 0,1443 in


Base plate bolt load (Jawad & Farr eq. 12.13, empty, corroded + Wind)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*137,65 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0747 in




= 1,5*137,65*4,4407 / (2*π*0,59062*5,5)= 76,06 psi


Anchor bolt load (empty, new + Wind)

P = -0,6*W / N + 48 * M / (N*BC)= -0,6*7.339,66 / 8 + 48 * 6.627 / (8*64,875)= 62,43 lbf



Foundation bearing stress (empty, new + Wind)

Ac = pi*(Do2 - Di

2) / 4 - N*pi*db2 / 4

= π*(70,93752 - 50,93752) / 4 - 8*π*1,1252 / 4

172/192

= 1.906,4559 in2

Ic = π*(Do4 - Di

4) / 64= π*(70,93754 - 50,93754) / 64= 912.545,4 in4

fc = N*Ab*Preload / Ac + W / Ac + 6*M*Do / Ic= 8*0,302*0 / 1.906,4559 + 7.339,66 / 1.906,4559 + 6*6.627*70,9375 / 912.545,4= 7 psi


Base plate required thickness (empty, new + Wind)


Mx = 0,0057*7*20,29522 = 16,4 lbf

My = -0,4471*7*4,96882 = -76,6 lbf

tr = (6*Mmax / Sp)0,5

= (6*76,62 / 20.000)0,5

= 0,1516 in


Base plate bolt load (Jawad & Farr eq. 12.13, empty, new + Wind)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*62,43 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0503 in




= 1,5*62,43*4,4407 / (2*π*0,59062*5,5)= 34,5 psi


Anchor bolt load (operating, corroded + Seismic)

P = -(0,6 - 0,14*SDS)*W / N + 48 * M / (N*BC)= -(0,6 - 0,14*0,55)*6.200,09 / 8 + 48 * 9.630,4 / (8*64,875)= 485,34 lbf



Support calculations (Jawad & Farr chapter 12, operating, corroded + Seismic)

Base plate width, tc: 10 inAverage base plate diameter, d: 60,9375 inBase plate elastic modulus, Es: 29,0E+06psiBase plate yield stress, Sy: 36.000 psi

Ec = 57.000*Sqr(3.000) = 3.122.019 psi

n = Es/Ec = 29,0E+06 / 3.122.019 = 9,2889

ts = (N*Ab) / (π*d)= (8*0,302) / (π*60,9375)= 0,0126 in

From table 12.4 for k = 0,230792:

K1 = 2,593, K2 = 1,3132L1 = 16,404, L2 = 36,2102, L3 = 11,1697

Total tensile force on bolting

T = (12*M - (0,6 - 0,14*SDS)*W *(L1 + L3)) / (L2 + L3)

173/192

= (12*9.630,4 - (0,6 - 0,14*0,55)*6.200,09 *(16,404 + 11,1697)) / (36,2102 + 11,1697)= 551,97 lbf

Tensile stress in bolts use the larger of fs or bolt preload = 0 psi

fs = T / (ts * (d / 2) * K1)= 551,97 / (0,0126 * (60,9375 / 2) * 2,593)= 554 psi

Total compressive load on foundation

Cc = T + (1 + 0,14*SDS)*W + Bolt Preload= 551,97 + (1 + 0,14*0,55)*6.200,09 + 0= 7.229,46 lbf

Foundation bearing stress

fc = Cc / (((tc - ts) + n*ts)*(d / 2)*K2)= 7.229,46 / (((10 - 0,0126) + 9,2889*0,0126)*(60,9375 / 2)*1,3132)= 18 psi


k = 1 / (1 + fs / (n*fc))= 1 / (1 + 554 / (9,2889*18))= 0,230792

Base plate required thickness (operating, corroded + Seismic)


Mx = 0,0057*18*20,29522 = 42,2 lbf

My = -0,4471*18*4,96882 = -197,4 lbf

tr = (6*Mmax / Sp)0,5

= (6*197,39 / 20.000)0,5

= 0,2433 in


Base plate bolt load (Jawad & Farr eq. 12.13, operating, corroded + Seismic)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*167,19 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0823 in




= 1,5*167,19*4,4407 / (2*π*0,59062*5,5)= 92,39 psi


Anchor bolt load (operating, new + Seismic)

P = -(0,6 - 0,14*SDS)*W / N + 48 * M / (N*BC)= -(0,6 - 0,14*0,55)*7.339,66 / 8 + 48 * 11.134,8 / (8*64,875)= 549,98 lbf



Support calculations (Jawad & Farr chapter 12, operating, new + Seismic)


Ec = 57.000*Sqr(3.000) = 3.122.019 psi

174/192

n = Es/Ec = 29,0E+06 / 3.122.019 = 9,2889

ts = (N*Ab) / (π*d)= (8*0,302) / (π*60,9375)= 0,0126 in

From table 12.4 for k = 0,240618:

K1 = 2,5713, K2 = 1,3426L1 = 15,8001, L2 = 35,7715, L3 = 11,6453


T = (12*M - (0,6 - 0,14*SDS)*W *(L1 + L3)) / (L2 + L3)= (12*11.134,8 - (0,6 - 0,14*0,55)*7.339,66 *(15,8001 + 11,6453)) / (35,7715 + 11,6453)= 596,08 lbf


fs = T / (ts * (d / 2) * K1)= 596,08 / (0,0126 * (60,9375 / 2) * 2,5713)= 603 psi






k = 1 / (1 + fs / (n*fc))= 1 / (1 + 603 / (9,2889*21))= 0,240618

Base plate required thickness (operating, new + Seismic)


Mx = 0,0057*21*20,29522 = 48,5 lbf

My = -0,4471*21*4,96882 = -227 lbf

tr = (6*Mmax / Sp)0,5

= (6*227,02 / 20.000)0,5

= 0,261 in


Base plate bolt load (Jawad & Farr eq. 12.13, operating, new + Seismic)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*182,08 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0859 in




= 1,5*182,08*4,4407 / (2*π*0,59062*5,5)= 100,61 psi


Anchor bolt load (empty, corroded + Seismic)

P = -(0,6 - 0,14*SDS)*W / N + 48 * M / (N*BC)

175/192

= -(0,6 - 0,14*0,55)*6.200,09 / 8 + 48 * 9.630,4 / (8*64,875)= 485,34 lbf



Support calculations (Jawad & Farr chapter 12, empty, corroded + Seismic)


Ec = 57.000*Sqr(3.000) = 3.122.019 psi

n = Es/Ec = 29,0E+06 / 3.122.019 = 9,2889

ts = (N*Ab) / (π*d)= (8*0,302) / (π*60,9375)= 0,0126 in

From table 12.4 for k = 0,230792:

K1 = 2,593, K2 = 1,3132L1 = 16,404, L2 = 36,2102, L3 = 11,1697


T = (12*M - (0,6 - 0,14*SDS)*W *(L1 + L3)) / (L2 + L3)= (12*9.630,4 - (0,6 - 0,14*0,55)*6.200,09 *(16,404 + 11,1697)) / (36,2102 + 11,1697)= 551,97 lbf


fs = T / (ts * (d / 2) * K1)= 551,97 / (0,0126 * (60,9375 / 2) * 2,593)= 554 psi






k = 1 / (1 + fs / (n*fc))= 1 / (1 + 554 / (9,2889*18))= 0,230792

Base plate required thickness (empty, corroded + Seismic)


Mx = 0,0057*18*20,29522 = 42,2 lbf

My = -0,4471*18*4,96882 = -197,4 lbf

tr = (6*Mmax / Sp)0,5

= (6*197,39 / 20.000)0,5

= 0,2433 in


Base plate bolt load (Jawad & Farr eq. 12.13, empty, corroded + Seismic)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*167,19 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

176/192

= 0,0823 in




= 1,5*167,19*4,4407 / (2*π*0,59062*5,5)= 92,39 psi


Anchor bolt load (empty, new + Seismic)

P = -(0,6 - 0,14*SDS)*W / N + 48 * M / (N*BC)= -(0,6 - 0,14*0,55)*7.339,66 / 8 + 48 * 11.134,8 / (8*64,875)= 549,98 lbf



Support calculations (Jawad & Farr chapter 12, empty, new + Seismic)


Ec = 57.000*Sqr(3.000) = 3.122.019 psi

n = Es/Ec = 29,0E+06 / 3.122.019 = 9,2889

ts = (N*Ab) / (π*d)= (8*0,302) / (π*60,9375)= 0,0126 in

From table 12.4 for k = 0,240618:

K1 = 2,5713, K2 = 1,3426L1 = 15,8001, L2 = 35,7715, L3 = 11,6453


T = (12*M - (0,6 - 0,14*SDS)*W *(L1 + L3)) / (L2 + L3)= (12*11.134,8 - (0,6 - 0,14*0,55)*7.339,66 *(15,8001 + 11,6453)) / (35,7715 + 11,6453)= 596,08 lbf


fs = T / (ts * (d / 2) * K1)= 596,08 / (0,0126 * (60,9375 / 2) * 2,5713)= 603 psi






k = 1 / (1 + fs / (n*fc))= 1 / (1 + 603 / (9,2889*21))= 0,240618

Base plate required thickness (empty, new + Seismic)


Mx = 0,0057*21*20,29522 = 48,5 lbf

177/192

My = -0,4471*21*4,96882 = -227 lbf

tr = (6*Mmax / Sp)0,5

= (6*227,02 / 20.000)0,5

= 0,261 in


Base plate bolt load (Jawad & Farr eq. 12.13, empty, new + Seismic)


tr= (3,91*F / (Sy*(2*b / w+w / (2*l)-db*(2 / w+1 / (2*l)))))0,5

= (3,91*182,08 / (36.000*(2*4,4407 / 4+4 / (2*1,4094)-1,125*(2 / 4+1 / (2*1,4094)))))0,5

= 0,0859 in




= 1,5*182,08*4,4407 / (2*π*0,59062*5,5)= 100,61 psi


178/192

Skirt Opening #1 (SO #1)


Component Skirt Opening

Description Skirt Opening #1

Drawing Mark SO #1

Opening forNozzle CONDENSATE OUTLET (N4)

Sleeve Material SA-516 70 (II-D p. 18, ln. 19)

Location and Orientation

Attached to Support Skirt

Orientation radial

Offset, L 15,5246"

Angle, θ 180°

Distance, r 32,75"

Through aCategory B Joint No

Dimensions

Pipe NPS andSchedule Not Pipe

Inside Diameter 11,25"

Nominal WallThickness 0,375"

Skirt Thickness 0,5906"

Leg41 0,25"

ExternalProjection

Available, Lpr1

1,7219"

Corrosion Inner 0"

Outer 0"

179/192

Skirt Opening Reinforcement Summary

RequiredThickness

tr(in)

AT(in2)

Ar(in2) Ratio Status

Operating Hot & CorrodedWind Tensile 0,0005 6,5987 0,0051 1.296,2534 OK

Compressive 0,0033 4,342 0,0376 115,4529 OK

Seismic Tensile 0,0013 6,5913 0,0141 466,9681 OK

Compressive 0,0042 4,3365 0,0473 91,7364 OK

Operating Hot & NewWind Tensile 0,0003 6,6004 0,003 2.204,0702 OK

Compressive 0,0038 4,3394 0,0422 102,7896 OK


Compressive 0,005 4,3317 0,0558 77,6364 OK

Empty Cold & CorrodedWind Tensile 0,0005 6,5987 0,0051 1.296,2534 OK

Compressive 0,0033 4,342 0,0376 115,4529 OK


Compressive 0,0042 4,3365 0,0473 91,7364 OK

Empty Cold & NewWind Tensile 0,0003 6,6004 0,003 2.204,0702 OK

Compressive 0,0038 4,3394 0,0422 102,7896 OK


Compressive 0,005 4,3317 0,0558 77,6364 OKNote: Skirt required thickness of zero on tensile side indicates load is compressive.

Openings Subject to Axial Tension

LR = min[ (Reff*t)0,5, 2*Rn] (4.5.3)

LH1 = t + te + (Rn*tn)0,5 (4.5.8)

LH2 = Lpr1 + t (4.5.9)

LH3 = 8*(t + te) (4.5.11)

LH = min[ LH1, LH2, LH3] (4.5.12)

fr1 = min[ Sn / S , 1 ]

fr2 = min[ Sn / S , 1 ]

A1 = 2*LR*(E1*t - tr)

A2 = 2*(LH - tr)*tn*fr2

A41 = L412*fr2

AT = A1 + A2 + A41

Ar = d*tr + 2*tn*tr*(1 - fr1)

New

LR = min[ (30,4375*0,5906)0,5, 2*5,625] = 4,2399"

LH1 = 0,5906 + 0 + (5,625*0,375)0,5 = 2,043"

LH2 = 1,7219 + 0,5906 = 2,3125"

LH3 = 8*(0,5906 + 0) = 4,7248"

LH = min[ 2,043, 2,3125, 4,7248] = 2,043"

Corroded

LR = min[ (30,4375*0,5906)0,5, 2*5,625] = 4,2399"

180/192

LH1 = 0,5906 + 0 + (5,625*0,375)0,5 = 2,043"

LH2 = 1,7219 + 0,5906 = 2,3125"

LH3 = 8*(0,5906 + 0) = 4,7248"

LH = min[ 2,043, 2,3125, 4,7248] = 2,043"

Operating Hot & Corroded Wind Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0005) = 5,0043 in2

A2 = 2*(2,043 - 0,0005)*0,375*1 = 1,5319 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,0043 + 1,5319 + 0,0625 = 6,5987 in2

Ar = 11,25*0,0005 + 2*0,375*0,0005*(1 - 1) = 0,0051 in2

AT = 6,5987 in2 ≥ Ar = 0,0051 in2

Operating Hot & New Wind Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0003) = 5,0059 in2

A2 = 2*(2,043 - 0,0003)*0,375*1 = 1,532 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,0059 + 1,532 + 0,0625 = 6,6004 in2

Ar = 11,25*0,0003 + 2*0,375*0,0003*(1 - 1) = 0,003 in2

AT = 6,6004 in2 ≥ Ar = 0,003 in2

Empty Cold & Corroded Wind Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0005) = 5,0043 in2

A2 = 2*(2,043 - 0,0005)*0,375*1 = 1,5319 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,0043 + 1,5319 + 0,0625 = 6,5987 in2

Ar = 11,25*0,0005 + 2*0,375*0,0005*(1 - 1) = 0,0051 in2

AT = 6,5987 in2 ≥ Ar = 0,0051 in2

Empty Cold & New Wind Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0003) = 5,0059 in2

A2 = 2*(2,043 - 0,0003)*0,375*1 = 1,532 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,0059 + 1,532 + 0,0625 = 6,6004 in2

Ar = 11,25*0,0003 + 2*0,375*0,0003*(1 - 1) = 0,003 in2

AT = 6,6004 in2 ≥ Ar = 0,003 in2

Operating Hot & Corroded Seismic Tensile

181/192

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0013) = 4,9975 in2

A2 = 2*(2,043 - 0,0013)*0,375*1 = 1,5313 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9975 + 1,5313 + 0,0625 = 6,5913 in2

Ar = 11,25*0,0013 + 2*0,375*0,0013*(1 - 1) = 0,0141 in2

AT = 6,5913 in2 ≥ Ar = 0,0141 in2

Operating Hot & New Seismic Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0014) = 4,9963 in2

A2 = 2*(2,043 - 0,0014)*0,375*1 = 1,5312 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9963 + 1,5312 + 0,0625 = 6,59 in2

Ar = 11,25*0,0014 + 2*0,375*0,0014*(1 - 1) = 0,0157 in2

AT = 6,59 in2 ≥ Ar = 0,0157 in2

Empty Cold & Corroded Seismic Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0013) = 4,9975 in2

A2 = 2*(2,043 - 0,0013)*0,375*1 = 1,5313 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9975 + 1,5313 + 0,0625 = 6,5913 in2

Ar = 11,25*0,0013 + 2*0,375*0,0013*(1 - 1) = 0,0141 in2

AT = 6,5913 in2 ≥ Ar = 0,0141 in2

Empty Cold & New Seismic Tensile

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0014) = 4,9963 in2

A2 = 2*(2,043 - 0,0014)*0,375*1 = 1,5312 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9963 + 1,5312 + 0,0625 = 6,59 in2

Ar = 11,25*0,0014 + 2*0,375*0,0014*(1 - 1) = 0,0157 in2

AT = 6,59 in2 ≥ Ar = 0,0157 in2

182/192

Division 2 4.5.17.3 Openings Subject to Axial Compression

γn = d / {2*(R*t)0,5} (4.5.170)

γn > {(R / t) / 291 + 0,22}2

tn,eff = min[ tn , t]

LR = 0,75*(R*t)0,5

LH = min[0,5*{(d / 2)*tn}0,5 , 2,5*tn , Lpr1 ]

fr1 = min[ Sn / S , 1 ]

fr2 = min[ Sn / S , 1 ]

A1 = 2*LR*(t - tr) - 2*tn,eff*(t - tr)*(1 - fr1)

A2 = 2*LH*tn,eff*fr2

A41 = L412*fr2

AT = A1 + A2 + A41

Ar = d*tr (4.5.169)

New

γn = 11,25 / {2*(30,4375*0,5906)0,5} = 1,3267

γn > {(30,4375 / 0,5906) / 291 + 0,22}2 = 0,1577

Area required factor for compressive side = 1

LR = 0,75*(30,4375*0,5906)0,5 = 3,1799"

LH = min[0,5*{(11,25 / 2)*0,375}0,5 , 2,5*0,375 , 1,7219 ] = 0,7262"

tn,eff = min[ 0,375 , 0,5906] = 0,375"

Corroded

γn = 11,25 / {2*(30,4375*0,5906)0,5} = 1,3267

γn > {(30,4375 / 0,5906) / 291 + 0,22}2 = 0,1577


LR = 0,75*(30,4375*0,5906)0,5 = 3,1799"

LH = min[0,5*{(11,25 / 2)*0,375}0,5 , 2,5*0,375 , 1,7219 ] = 0,7262"

tn,eff = min[ 0,375 , 0,5906] = 0,375"

Operating Hot & Corroded Wind Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0033) - 2*0,375*(0,5906 - 0,0033)*(1 - 1) = 3,7348 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7348 + 0,5446 + 0,0625 = 4,342 in2

Ar = 11,25*0,0033 = 0,0376 in2

AT = 4,342 in2 ≥ Ar = 0,0376 in2

Operating Hot & New Wind Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0038) - 2*0,375*(0,5906 - 0,0038)*(1 - 1) = 3,7322 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

183/192

A41 = 0,252*1 = 0,0625 in2

AT = 3,7322 + 0,5446 + 0,0625 = 4,3394 in2

Ar = 11,25*0,0038 = 0,0422 in2

AT = 4,3394 in2 ≥ Ar = 0,0422 in2

Empty Cold & Corroded Wind Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0033) - 2*0,375*(0,5906 - 0,0033)*(1 - 1) = 3,7348 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7348 + 0,5446 + 0,0625 = 4,342 in2

Ar = 11,25*0,0033 = 0,0376 in2

AT = 4,342 in2 ≥ Ar = 0,0376 in2

Empty Cold & New Wind Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0038) - 2*0,375*(0,5906 - 0,0038)*(1 - 1) = 3,7322 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7322 + 0,5446 + 0,0625 = 4,3394 in2

Ar = 11,25*0,0038 = 0,0422 in2

AT = 4,3394 in2 ≥ Ar = 0,0422 in2

Operating Hot & Corroded Seismic Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0042) - 2*0,375*(0,5906 - 0,0042)*(1 - 1) = 3,7294 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7294 + 0,5446 + 0,0625 = 4,3365 in2

Ar = 11,25*0,0042 = 0,0473 in2

AT = 4,3365 in2 ≥ Ar = 0,0473 in2

Operating Hot & New Seismic Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,005) - 2*0,375*(0,5906 - 0,005)*(1 - 1) = 3,7245 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7245 + 0,5446 + 0,0625 = 4,3317 in2

Ar = 11,25*0,005 = 0,0558 in2

AT = 4,3317 in2 ≥ Ar = 0,0558 in2

Empty Cold & Corroded Seismic Compressive

184/192

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0042) - 2*0,375*(0,5906 - 0,0042)*(1 - 1) = 3,7294 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7294 + 0,5446 + 0,0625 = 4,3365 in2

Ar = 11,25*0,0042 = 0,0473 in2

AT = 4,3365 in2 ≥ Ar = 0,0473 in2

Empty Cold & New Seismic Compressive

fr1 = min[ 20.000 / 16.600 , 1 ] = 1

fr2 = min[ 20.000 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,005) - 2*0,375*(0,5906 - 0,005)*(1 - 1) = 3,7245 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7245 + 0,5446 + 0,0625 = 4,3317 in2

Ar = 11,25*0,005 = 0,0558 in2

AT = 4,3317 in2 ≥ Ar = 0,0558 in2

185/192

Skirt Opening #2 (SO #2)


Component Skirt Opening

Description Skirt Opening #2

Drawing Mark SO #2

Sleeve Material SA-106 B Smls pipe (II-D p. 10, ln. 40)

Location and Orientation

Attached to Support Skirt

Orientation radial

Offset, L 20,875"

Angle, θ 0°

Distance, r 32,75"

Through aCategory B Joint No

Dimensions

Inside Diameter 11,25"

Nominal WallThickness 0,375"

Skirt Thickness 0,5906"

Leg41 0,25"

ExternalProjection

Available, Lpr1

1,7219"

Corrosion Inner 0"

Outer 0"

186/192

Skirt Opening Reinforcement Summary

RequiredThickness

tr(in)

AT(in2)

Ar(in2) Ratio Status

Operating Hot & CorrodedWind Tensile 0,0004 6,5988 0,0049 1.337,1869 OK

Compressive 0,0032 4,3426 0,0364 119,2936 OK


Compressive 0,0041 4,3374 0,0457 94,9864 OK

Operating Hot & NewWind Tensile 0,0003 6,6005 0,0028 2.325,0251 OK

Compressive 0,0036 4,34 0,041 105,8266 OK


Compressive 0,0048 4,3327 0,054 80,2159 OK

Empty Cold & CorrodedWind Tensile 0,0004 6,5988 0,0049 1.337,1869 OK

Compressive 0,0032 4,3426 0,0364 119,2936 OK


Compressive 0,0041 4,3374 0,0457 94,9864 OK

Empty Cold & NewWind Tensile 0,0003 6,6005 0,0028 2.325,0251 OK

Compressive 0,0036 4,34 0,041 105,8266 OK


Compressive 0,0048 4,3327 0,054 80,2159 OKNote: Skirt required thickness of zero on tensile side indicates load is compressive.

Openings Subject to Axial Tension

LR = min[ (Reff*t)0,5, 2*Rn] (4.5.3)

LH1 = t + te + (Rn*tn)0,5 (4.5.8)

LH2 = Lpr1 + t (4.5.9)

LH3 = 8*(t + te) (4.5.11)

LH = min[ LH1, LH2, LH3] (4.5.12)

fr1 = min[ Sn / S , 1 ]

fr2 = min[ Sn / S , 1 ]

A1 = 2*LR*(E1*t - tr)

A2 = 2*(LH - tr)*tn*fr2

A41 = L412*fr2

AT = A1 + A2 + A41

Ar = d*tr + 2*tn*tr*(1 - fr1)

New

LR = min[ (30,4375*0,5906)0,5, 2*5,625] = 4,2399"

LH1 = 0,5906 + 0 + (5,625*0,375)0,5 = 2,043"

LH2 = 1,7219 + 0,5906 = 2,3125"

LH3 = 8*(0,5906 + 0) = 4,7248"

LH = min[ 2,043, 2,3125, 4,7248] = 2,043"

Corroded

LR = min[ (30,4375*0,5906)0,5, 2*5,625] = 4,2399"

187/192

LH1 = 0,5906 + 0 + (5,625*0,375)0,5 = 2,043"

LH2 = 1,7219 + 0,5906 = 2,3125"

LH3 = 8*(0,5906 + 0) = 4,7248"

LH = min[ 2,043, 2,3125, 4,7248] = 2,043"

Operating Hot & Corroded Wind Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0004) = 5,0044 in2

A2 = 2*(2,043 - 0,0004)*0,375*1 = 1,5319 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,0044 + 1,5319 + 0,0625 = 6,5988 in2

Ar = 11,25*0,0004 + 2*0,375*0,0004*(1 - 1) = 0,0049 in2

AT = 6,5988 in2 ≥ Ar = 0,0049 in2

Operating Hot & New Wind Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0003) = 5,006 in2

A2 = 2*(2,043 - 0,0003)*0,375*1 = 1,532 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,006 + 1,532 + 0,0625 = 6,6005 in2

Ar = 11,25*0,0003 + 2*0,375*0,0003*(1 - 1) = 0,0028 in2

AT = 6,6005 in2 ≥ Ar = 0,0028 in2

Empty Cold & Corroded Wind Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0004) = 5,0044 in2

A2 = 2*(2,043 - 0,0004)*0,375*1 = 1,5319 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,0044 + 1,5319 + 0,0625 = 6,5988 in2

Ar = 11,25*0,0004 + 2*0,375*0,0004*(1 - 1) = 0,0049 in2

AT = 6,5988 in2 ≥ Ar = 0,0049 in2

Empty Cold & New Wind Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0003) = 5,006 in2

A2 = 2*(2,043 - 0,0003)*0,375*1 = 1,532 in2

A41 = 0,252*1 = 0,0625 in2

AT = 5,006 + 1,532 + 0,0625 = 6,6005 in2

Ar = 11,25*0,0003 + 2*0,375*0,0003*(1 - 1) = 0,0028 in2

AT = 6,6005 in2 ≥ Ar = 0,0028 in2

Operating Hot & Corroded Seismic Tensile

188/192

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0012) = 4,9979 in2

A2 = 2*(2,043 - 0,0012)*0,375*1 = 1,5313 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9979 + 1,5313 + 0,0625 = 6,5917 in2

Ar = 11,25*0,0012 + 2*0,375*0,0012*(1 - 1) = 0,0136 in2

AT = 6,5917 in2 ≥ Ar = 0,0136 in2

Operating Hot & New Seismic Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0013) = 4,9968 in2

A2 = 2*(2,043 - 0,0013)*0,375*1 = 1,5312 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9968 + 1,5312 + 0,0625 = 6,5906 in2

Ar = 11,25*0,0013 + 2*0,375*0,0013*(1 - 1) = 0,015 in2

AT = 6,5906 in2 ≥ Ar = 0,015 in2

Empty Cold & Corroded Seismic Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0012) = 4,9979 in2

A2 = 2*(2,043 - 0,0012)*0,375*1 = 1,5313 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9979 + 1,5313 + 0,0625 = 6,5917 in2

Ar = 11,25*0,0012 + 2*0,375*0,0012*(1 - 1) = 0,0136 in2

AT = 6,5917 in2 ≥ Ar = 0,0136 in2

Empty Cold & New Seismic Tensile

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*4,2399*(1*0,5906 - 0,0013) = 4,9968 in2

A2 = 2*(2,043 - 0,0013)*0,375*1 = 1,5312 in2

A41 = 0,252*1 = 0,0625 in2

AT = 4,9968 + 1,5312 + 0,0625 = 6,5906 in2

Ar = 11,25*0,0013 + 2*0,375*0,0013*(1 - 1) = 0,015 in2

AT = 6,5906 in2 ≥ Ar = 0,015 in2

189/192

Division 2 4.5.17.3 Openings Subject to Axial Compression

γn = d / {2*(R*t)0,5} (4.5.170)

γn > {(R / t) / 291 + 0,22}2

tn,eff = min[ tn , t]

LR = 0,75*(R*t)0,5

LH = min[0,5*{(d / 2)*tn}0,5 , 2,5*tn , Lpr1 ]

fr1 = min[ Sn / S , 1 ]

fr2 = min[ Sn / S , 1 ]

A1 = 2*LR*(t - tr) - 2*tn,eff*(t - tr)*(1 - fr1)

A2 = 2*LH*tn,eff*fr2

A41 = L412*fr2

AT = A1 + A2 + A41

Ar = d*tr (4.5.169)

New

γn = 11,25 / {2*(30,4375*0,5906)0,5} = 1,3267

γn > {(30,4375 / 0,5906) / 291 + 0,22}2 = 0,1577


LR = 0,75*(30,4375*0,5906)0,5 = 3,1799"

LH = min[0,5*{(11,25 / 2)*0,375}0,5 , 2,5*0,375 , 1,7219 ] = 0,7262"

tn,eff = min[ 0,375 , 0,5906] = 0,375"

Corroded

γn = 11,25 / {2*(30,4375*0,5906)0,5} = 1,3267

γn > {(30,4375 / 0,5906) / 291 + 0,22}2 = 0,1577


LR = 0,75*(30,4375*0,5906)0,5 = 3,1799"

LH = min[0,5*{(11,25 / 2)*0,375}0,5 , 2,5*0,375 , 1,7219 ] = 0,7262"

tn,eff = min[ 0,375 , 0,5906] = 0,375"

Operating Hot & Corroded Wind Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0032) - 2*0,375*(0,5906 - 0,0032)*(1 - 1) = 3,7355 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7355 + 0,5446 + 0,0625 = 4,3426 in2

Ar = 11,25*0,0032 = 0,0364 in2

AT = 4,3426 in2 ≥ Ar = 0,0364 in2

Operating Hot & New Wind Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0036) - 2*0,375*(0,5906 - 0,0036)*(1 - 1) = 3,7329 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

190/192

A41 = 0,252*1 = 0,0625 in2

AT = 3,7329 + 0,5446 + 0,0625 = 4,34 in2

Ar = 11,25*0,0036 = 0,041 in2

AT = 4,34 in2 ≥ Ar = 0,041 in2

Empty Cold & Corroded Wind Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0032) - 2*0,375*(0,5906 - 0,0032)*(1 - 1) = 3,7355 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7355 + 0,5446 + 0,0625 = 4,3426 in2

Ar = 11,25*0,0032 = 0,0364 in2

AT = 4,3426 in2 ≥ Ar = 0,0364 in2

Empty Cold & New Wind Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0036) - 2*0,375*(0,5906 - 0,0036)*(1 - 1) = 3,7329 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7329 + 0,5446 + 0,0625 = 4,34 in2

Ar = 11,25*0,0036 = 0,041 in2

AT = 4,34 in2 ≥ Ar = 0,041 in2

Operating Hot & Corroded Seismic Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0041) - 2*0,375*(0,5906 - 0,0041)*(1 - 1) = 3,7303 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7303 + 0,5446 + 0,0625 = 4,3374 in2

Ar = 11,25*0,0041 = 0,0457 in2

AT = 4,3374 in2 ≥ Ar = 0,0457 in2

Operating Hot & New Seismic Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0048) - 2*0,375*(0,5906 - 0,0048)*(1 - 1) = 3,7256 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7256 + 0,5446 + 0,0625 = 4,3327 in2

Ar = 11,25*0,0048 = 0,054 in2

AT = 4,3327 in2 ≥ Ar = 0,054 in2

Empty Cold & Corroded Seismic Compressive

191/192

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0041) - 2*0,375*(0,5906 - 0,0041)*(1 - 1) = 3,7303 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7303 + 0,5446 + 0,0625 = 4,3374 in2

Ar = 11,25*0,0041 = 0,0457 in2

AT = 4,3374 in2 ≥ Ar = 0,0457 in2

Empty Cold & New Seismic Compressive

fr1 = min[ 17.100 / 16.600 , 1 ] = 1

fr2 = min[ 17.100 / 16.600 , 1 ] = 1

A1 = 2*3,1799*(0,5906 - 0,0048) - 2*0,375*(0,5906 - 0,0048)*(1 - 1) = 3,7256 in2

A2 = 2*0,7262*0,375*1 = 0,5446 in2

A41 = 0,252*1 = 0,0625 in2

AT = 3,7256 + 0,5446 + 0,0625 = 4,3327 in2

Ar = 11,25*0,0048 = 0,054 in2

AT = 4,3327 in2 ≥ Ar = 0,054 in2

192/192

Se Parador Multi Fa Sico 19

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