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Transcript of Riazuddin-QuantMech_chap03
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Chapter 3
Basic Postulates of Quantum
Mechanics
3.1 Basic Postulates of Quantum Mechanics
We have introduced two concepts: (i) the state of a particle or a quan-
tum mechanical system is described by a wave function or state function
(r, t) which satisfies Schrodinger equation; (ii) the dynamical variables
like momentum p and energy E are operators.
Now important properties of a physical system are quantities like p, E
which can be measured or observed; such quantities are called observables.
There must be a means of predicting the values of observables from thestate function and the procedure for doing this is given by following set of
postulates:
(1) To every observable there corresponds an operator A.(2) The possible result of a measurement of an observable is one of the
eigenvalues an of A given by the equation
Aun = anun (3.1)
where A is an operator and an is eigenvalue corresponding to eigen-function un.
(3) A measurement of A on a system in an eigenstate certainly leadsto the result an, the eigenvalue.
(4) The average value of a large number of measurements of an ob-
servable on a system described by an arbitrary state is given
by
A a a = Adr (3.2)provided that
dr = 1, and there exist suitable boundary conditions.
Thus for example, the average value of momentum in x-direction for a state
33
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34 Quantum Mechanics
(x, t) is given by
p = (x) i
x(x)dx. (3.3)Applying to the special case of A = x, we get the average value of position
x =
(x)x(x)dx
=
xdx =
x|(x)|2dx. (3.4)
This is consistent with our interpretation of (x), that |(x)|2 determinesthe probability density P(x) of the particle in space, since
|(x)
|2 appears
as the weighing factor appropriate to x in the calculation of the average
position.
It is convenient to introduce a compact notation for the matrix element
(|A) or |A| to mean Adr. Furthermore, the integration maynot always be over space and it may be necessary to imply integration over
other continuous or discontinuous variables.
3.2 Formal Properties of Quantum Mechanical Operators
The quantum mechanical operators (observables) possess certain properties
which are important and we discuss some of them briefly.
(a) They are linear, i.e. if (Cn are numbers)
=n
Cnn (3.5)
then we have A = n
Cn An (3.6)(b) They obey the laws of association and distribution. Thus if A, B
and C are three operators, we haveA( B C) = ( AB)C , (3.7)
A(
B +
C) =
A
B +
A
C . (3.8)
(c) An observable corresponds to a hermitian operator. We define thehermitian conjugate or adjoint A of an operator A by the equation
(|A) = (|A) = ( A|) (3.9)
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Basic Postulates of Quantum Mechanics 35
i.e.
Adr =
(
A)dr .
An operator is said to hermitian if A = A, i.e.(|A) = (|A) = ( A|) . (3.10)
Theorems:
(i) The eigenvalues of a hermitian operator are real.
(ii) The eigenfunctions of a hermitian operator corresponding to dif-
ferent eigenvalues are orthogonal:
We have eigenvalue equation Aun = anun (3.11)and then
um|Aun = anum|un = anun|um. (3.12)But from Eq (3.9):
um
|Aun
=
um
|Aun = un|Aum= amun|um. (3.13)Hence from Eqs (3.12) and (3.13):
(am an)un|um = 0.Therefore if
i) m = n, an = an, since un|un = 0 (3.14)
ii) m= n,
un
|um
= unumdr = 0. (3.15)
If the eigenfunctions are normalized,
un|un =
unundr = 1. (3.16)
Hence Eqs (3.15) and (3.16) can be written in a compact form :
un|um =
unumdr = mn (3.17)
where mn = 0 m = n ,mn = 1 m = n.
(3.18)
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36 Quantum Mechanics
mn is called the Kronecker delta. The eigenfunctions are then said to be
orthonormal.
(d) The eigenfunctions un of a hermitian operator (observable) form a
complete orthonormal set so that any arbitrary state function can be
expanded in terms of them, i.e.
=n
Cnun . (3.19)
This is what we mean by a complete set. The Eq. (3.19) is called to the
superposition principle, a basic ingredient of quantum mechanics.
Now in analogy with vector analysis where we express a vector in terms
of basis vectors i,j, k, the uns are called basis vectors and Cn the corre-sponding coordinates. It follows thatumdr = (um|)
=n
Cn(um|un)
=n
Cnmn
= Cm , (3.20)where Cm is related to the probability of finding the system described by
state in an eigenstate um. Thus
|Cm|2 = |
umdr|2 (3.21)
gives the probability of operator
A having the eigenvalue am, when the
system is described by a state . To see this we note that the average value
of the operator A in state is givena =
Adr
=m
n
CmCn
um Aundr
=m
n
CmCnan
umundr
= m n CmCnanmn=m
|Cm|2am , (3.22)
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Basic Postulates of Quantum Mechanics 37
The weighing factor |Cm|2 above gives the probability of finding the Eigen-value am.
(e) The operators do not necessarily obey a commutative law, i.e. two
operators A and B need not give AB = B A. If AB equals B A, the operatorsare said to commute, i.e.
[ A, B] = AB B A = 0 (3.23)[ A, B] is called the commutator of two operators.
(f) If two observables commute, then it is possible to find a set of func-
tions which are simultaneously eigenfunctions of
A and
B. If they do not
commute, i.e. [
A,
B] = 0, this cannot be done except for a state which
has [ A, B] = 0.We now show that if un is a simultaneous eigenfunction of A and B
corresponding to eigenvalues an and bn, then
[ A, B]un = 0 . (3.24)Now Aun = anun , (3.25a)
Bun = bnun . (3.25b)
Further ABun = Abnun= bn Aun= bnanun , (3.26a)
B
Aun =
Banun
= an Bun= anbnun . (3.26b)Therefore
( AB B A)un = (bnan anbn)un = 0 ,i.e.
[
A,
B]un = 0 . (3.27)
The implication of this result is as follows:
Since un form a complete set so that an arbitrary function can beexpanded in terms of them, it follows that
[ A, B] = 0 .
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38 Quantum Mechanics
Since is arbitrary, [ A, B] = 0. Thus if a set of simultaneous eigenfunctionsof two observables
A and
B exist, then
A and
B commute.
If [ A, B] = 0 and [ A, C] = 0 but [ B, C] = 0, then it is not possible to findfunctions which are simultaneously eigenfunctions of A, B and C. It is onlypossible to find eigenfunctions for A and B or for A and C. Correspondingto this, we can only make simultaneous measurements of the observables
corresponding to the pair of operators A and B or to the pair A and C, itis not possible to measure B, C together.3.3 Continuous Spectrum and Dirac Delta Functions
(a) Continuous Spectrum
So far we have considered the case when the eigenvalues of an operatorA are discrete. In case eigenvalues of an operator take on continuous values,the sum in the completeness relation (3.19) takes the form of an integral
(x) =
C(a)ua(x)da , (3.28)
where the label a corresponds to continuous set of eigenvalues and replaces
the discrete label n in Eq. (3.19). For simplicity we first consider to be afunction of a single variable x only; the generalisation to three dimensions
is straightforward.
Now using (3.28)ua(x)(x)dx (ua |)
=
daC(a)(ua |ua) , (3.29)
where a lies in the domain of integration of a. Now the orthogonalitycondition (3.18) becomes
ua(x)ua(x)dx (ua |ua)= 0 when a = a . (3.30)
For a = a, it does not have to vanish. In fact it must be infinitely largeat a = a because if it is finite at a = a, then the integral on right-handside of Eq. (3.29) vanishes but (x) does not vanish in general. But this
infinity must be such thatua(x)(x)dx = C(a
)
da(ua |ua) , (3.31)
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Basic Postulates of Quantum Mechanics 39
so that in analogy with Eq. (3.20), we have
C(a) = ua(x)(x)dx (3.32)
with da(ua |ua) = 1 . (3.33)
Thus (ua |ua) has the peculiar property: it is zero everywhere except ata = a [see Fig. 3.1] and at a = a it is infinitely large such that its integralis 1.
(aa)
ag1
g2
a
Fig. 3.1 The Dirac delta function.
Such a function is called Dirac -function and is written as
(a a) = 0 for a = a= for a = a (3.34a)
such that da(a a) = 1 . (3.34b)
Thus we write
(ua |ua) = ua(x)ua(x)dx= (a a) , (3.35)
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40 Quantum Mechanics
corresponding to orthonormality relation (3.17) for discrete set. Substitut-
ing Eq. (3.38) into Eq. (3.29), we have
ua(x)(x)dx = daC(a)(a a) .Comparing it with Eq. (3.35), we have
daC(a)(a a) = C(a) . (3.36)
This is the fundamental property of the -function which we require.
The generalisation to three dimensions is obvious
x
r, a
a, a
a .
Thus Eqs. (3.28), (3.32), (3.34), (3.35) and (3.36) respectively become
(r) =
C(a)ua(r)da (3.37)
C(a) =
ua
(r)(r)dr (3.38)
(a a) = 0 for a = a ,= for a = a.
(3.39a)
da(a a) = 1 , (3.39b)
(ua |ua) = (a a) , (3.40)C(a)(a a)da = C(a) . (3.41)
Here(a a) = (ax ax)(ay ay)(az az) . (3.42)
(b) Closure Relations We have
(r) =n
Cnun(r) (for discrete set) (3.43a)
=
C(a)ua(r)da (for continuous set) . (3.43b)
ThenCn =
un(r
)(r)dr , (3.44a)
C(a) =
ua
(r)(r)dr . (3.44b)
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Basic Postulates of Quantum Mechanics 41
Substituting in Eq. (3.43a), we have for discrete set
(r) = n un(r)(r)drun(r)=
n
un(r)un(r
)
(r)dr .
Thus it follows that n
un(r)un(r
) = (r r) . (3.45a)
The corresponding relation for continuous set is
ua(r)u
a
(r)da = (r r) . (3.45b)
These are known as Closure Relations. These are equivalent to complete-
ness relations, since one can write (e.g. discrete set)
(r) =
(r)(r r)dr
= (r)n
un(r)un(r)dr
=n
un(r
)(r)dr
un(r)
=n
Cnun(r) . (3.46)
(c) A Simple Representation of -function Consider the function
eia(xx)da .Now eia(xx
) is an oscillating function and the above integral is not defined.
It is a question of agreeing to give a value to this integral. The prescription
is
eia(xx)da = lim
0
0
eia(xx)+ada +
0
eia(xx)ada
= lim0 1i(x x) + 1i(x x) = lim
0
22 + (x x)2
.
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42 Quantum Mechanics
If x = x, (x x)2 is a fixed number, no matter how small it may be. Nowwhen 0, 2 can be neglected in comparison with (x x)2 so that thelimit = 0. If x = x
lim0
22 + (x x)2
= lim
02
= .
The behaviour is that of a -function, but we have to verify that its integral
is 1. Thus we calculate
eia(xx)da
dx = lim
0
2
2 + (x x)2 dx
= lim0
2
2
+ 2
d, = (x
x)
= lim0
2tan1
= 2 lim0
2
2
= 2 .
Thus
1
2
eia(xx)da = (x x) . (3.47a)
Its generalisation to three dimension is
1
(2)3
eia(rr
)da = (r r) . (3.47b)
(d) Properties of -function
f(x)(x b) = f(b)(x b) ,x(x) = 0 ,
(x) = (x) ,(bx) =
1
|b|(x) ,
(x2 b2) = 12b
(x b) + (x + b) , b > 0
(a x)dx(x b) = (a b) .
These equations have meaning only in the sense of integration; for example,
the first one means f(x)(x b)dx = f(b) .
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Basic Postulates of Quantum Mechanics 43
(bx) = 1|b|(x) means
(bx)dx =1
| b |.
(e) Fourier Transform
The completeness relation, in terms of eigenfunctions 12
eiax becomes
f(x) =12
C(a)eiaxda , (3.48)
1
2
f(x)eia
xdx =1
(2)
daC(a)
eix(aa
)dx
=
daC(a)(a a)
= C(a) .
Therefore
C(a) =12
f(x)eiaxdx . (3.49)
C(a) and f(x) are called the Fourier transforms of each other.The generalisation to three dimensions is
f(r) =1
(2)3/2
C(a)eiarda , (3.50a)
C(a) =1
(2)3/2
f(r)eiardr . (3.50b)
(f) Momentum Eigenfunctions (An Example of Continuous
Spectrum of Eigenvalues
The momentum operator in Schrodinger representation isp = i x
.
Eigenvalue equation is
pup(x) = pup(x) ,i
xup(x) = pup(x) . (3.51)
A solution of this equation is
up(x) = B exp i
px
. (3.52)
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44 Quantum Mechanics
Here eigenvalue p is a continuous variable and takes on any value. Above
we have taken the momentum in x direction. For three dimensions
p = iand
pup(r) = pup(r) ,up(r) = B exp
i
p r
. (3.53)
Now
(up |up) = up(r)up(r)dr= |B|2
e(i/)(pp
)rdr
= |B|23(2)3(p p) .
Thus if we select
B =
1
(2)3/2 ,
then
(up |up) = (p p) . (3.54)
Thus normalised momentum eigenfunctions are
up(r) =1
(2)3/2
e(i/)pr . (3.55)
Since these eigenfunctions form a complete set we can write
(r) =1
(2)3/2
C(p)e(i/)prdp , (3.56a)
where
C(p) =1
(2
)3/2 e
(i/)pr(r)dr (3.56b)
(r) and C(p) are the Fourier transform of each other.
Now average value of the momentum operator is given by
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Basic Postulates of Quantum Mechanics 45
p = p =
(r)
p(r)dr
=
1
(2)3
dpdpC(p)C(p)e(i/)p
r
(i)e(i/)prdr=
1
(2)3
dpdpC(p)C(p)
pe(i/)(pp)rdr=
dpdpC(p)C(p)p(p p)
= |C(p)|2pdp . (3.57)Thus |C(p)|2 is the probability of momentum operator p having eigen-
value p when the system is in state (r). In other words, in a measurement
of the momentum of a particle, the probability of finding the result p is
|C(p)|2. Thus C(p) may be regarded as the wave function, in momen-tum space just as (r) is the wave function in r space. C(p) is sometimes
written as (p).
3.4 Uncertainty Principle and Non-Commutativity of
Observables
In quantum mechanics, two observables A and B do not necessarily com-mute and obey a commutative law, i.e. in general
[
A,
B] = 0 . (3.58)
This statement is essentially equivalent to the uncertainty principle whichexpresses the limitations on our knowledge imposed by mutual disturbances
of observations. Eq. (3.58) implies that it is not possible to find simultane-
ous eigenfunctions of A and B i.e. we cannot have an exact knowledge ofthe result of measurement of A and B simultaneously.
We now show explicitly that Eq. (3.58) leads to the uncertainty prin-
ciple. A and B being observables are hermitian. Let a and b denote theaverage values of large number of measurements of
A and
B respectively.
Define A a = A ,B b = B . (3.59)
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Basic Postulates of Quantum Mechanics 47
where
P = +
2dx ,
Q =
i
2dx .
Since +2
and i2
are hermitian operators and the average value of
a large number of measurements of a hermitian operator is real, therefore
P and Q are real numbers.
Thus Eq. (3.62) gives
(a)2(b)2
P2 + Q2
Q2
= i 2
dx2= iAB B A
2dx
2 , (3.63)since from Eq. (3.59) = AB B A.
In particular if A =
p, B =x, [p, x] = i
(a)2 = (p)2 ,
(a)2 = (x)2 ,
(p)2(x)2 2
4|
dx|2 = 2
4.
The root mean square deviation is often called the uncertainty (standard
deviation), i.e.
p =
(p)2 , x =
(x)2 . (3.64)
Hencepx /2 , (3.65)
where p and x denote the uncertainties in the measured values of p
and x. If
[ A, B] = 0there is no mutual disturbance, and the result of simultaneous measure-
ments of observables A and B can be known exactly.
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48 Quantum Mechanics
Example
Momentum and energy operators for a free particle are given by
A = p i xB = H = p2
2m
2
2m
2
x2(3.66)
so that
p, H
(x) =
i
x
2
2m
2
x2 (x)
= 0
which is true for an arbitrary function (x). Thus
[p, H] = 0 .The energy and momentum of a free particle can be known exactly, simul-
taneously. In other words, it is possible to find a wave function which is a
simultaneous eigenfunction of both momentum and energy.
3.5 Problems
3.1 IfA denotes the average value for a large number of measurementsof an operator A for an arbitrary state function , show that Ais real if A is hermitian.
3.2 The state function for a free particle moving in x-direction is given
by
(x) = N e(x2/22+ip0x/) .
Normalise this wave function. Find the state function (p) in mo-
mentum space.
(i) Show that for the state (x) given above
x = 0 ,p = p0 ,
x2 = 2
2 ,
p2 = p20 +1
2
2
2.
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Basic Postulates of Quantum Mechanics 49
Hence show that
(x)2 = (x x)2
= 2
2
(p)2 = (p p)2=
1
2
2
2
so that
xp =1
2.
(ii) Using the relations
p =
p|(p)|2dp
p2 =
p2|(p)|2dpshow that
p = p0 ,
p2
= p20 +
1
2
2
2 .Useful integral
+
x2nex2
dx =1
n+1
2
(2n)!
22nn!
3.3 Show that for a particle of mass m, moving in a potential V(r),
[H,r] = ipm
,
[
p, H] = [
p, V(
r)] = iV .
Using the above results and the fact that H is hermitian, show that
md
dtr = p ,
d
dtp = V .
(Note that Newtons law is valid for expectation values.)
3.4 Using the result
[H, x] = i p
m,
for a particle of mass m moving in x-direction in a potential V(x),
show that the average value of its momentum in a stationary state
with discrete energy is zero.
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50 Quantum Mechanics
3.5 A particle is in a state
(x) =1
asin
5x
a , |x| a= 0 elsewhere ,show that the probability for the particle to be found with momen-
tum p is given by
100a
2
sin2(pa/)
(p2a2/2 252) .
3.6 A particle of mass m is confined by an infinite square well potential
V(x) = 0,
|x
| a; V(x) =
,
|x
|> a. If the particle is in the state
(x) = x , |x| a ,(x) = 0 , |x| > a ,
find the probability that a measurement of energy will give the
result
En =2
2m
24a2
n2 .
3.7 For a free particle, find a wave funcion which is a simultaneous
eigenfunction of both momentum and energy. This is not so for aparticle moving in a potential since then |p, H| = 0 [cf. Problem3.3].
3.8 a) If a particle is in a state
(x) = 2
2
14
ex2
2
find the probability of finding it in the momentum eigenstate
up(x) = 12e ipx.b) If it is in a state
up(x) =
2
sin nx, 0 x
show that the probability of finding it with momentum p is given
by
|(p)|2 = 12
sin4(p n)2pn2
2 .