REU 2004

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REU 2004 REU 2004 Population Models Day 2 Population Models Day 2 Predator Prey Predator Prey

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REU 2004. Population Models Day 2 Predator Prey. REU’04—Day 2. Today we have 2 species; one predator y(t) (e.g. wolf) and one its prey x(t) (e.g. hare). Actual Data. Model. Want a DE to describe this situation. dx/dt= ax-bxy = x(a-by) dy/dt=-cx+dxy = y(-c+dx). 3. - PowerPoint PPT Presentation

Transcript of REU 2004

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REU 2004REU 2004

Population Models Day 2Population Models Day 2Predator PreyPredator Prey

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REU’04—Day 2REU’04—Day 2

• Today we have 2 species; one predator y(t) (e.g. wolf) and one its prey x(t) (e.g. hare)

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Actual DataActual Data

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ModelModel

• Want a DE to describe this situation

• dx/dt= ax-bxy = x(a-by) dy/dt=-cx+dxy = y(-c+dx)

• Could get rid of __________constants3

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Called Lotka-Volterra Equation, Lotka & Volterra independently studied this post WW I.

• Fixed points: (0,0), (c/d,a/b)

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The ANSWER:

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Solution vs timeSolution vs time

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What are you going to do?What are you going to do?

• Try to use analysis to argue that this is indeed the phase portrait.

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OK what now?OK what now?

• 3 species food chain!– x = worms; y= robins; z= eagles

dx/dt = ax-bxydy/dt= -cy+dxy-eyzdz/dt= -fz+gyz

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New toolsNew tools

• Invariant sets & trapping regions!