Retaining Wall

7/18/2019 Retaining Wall

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Project: XXXXXXXXXXXXXXXX Date 6-Jul Page

Client: XXXXXXXXXXXXXXXXXX

Designed RJ Checked JA

Rev No. A Approved

Rev Date -

RETAINING WALL DESIGN

Angle of internal friction, f = 30

Coefficient of active earth pressre,

= 0.33

srcharge !"# = $

= %&

'otal (eight of soil pressre acting = 3.%) *

! +otto* of raft Raft thk-$#=3.30.%)

ateral pressre de to = 0.33 / $

rcharge = 0.11

ateral pressre de to soil = 0.33 / %& / 3.%)

= %&.2%

ateral pressre at top = 0.11

ateral pressre at otto* = %4.32

5o*ent de to soil = 0.33 / %& / 3.%)63 - 1

= 30.94 kN* per *eter rn

5o*ent de to srcharge = 0.33 / $ / 3.%)6$ - $

= 3.3 kN* per *eter rn

kN-*$

oil densit7 !f# kN-*3

8% = 9a q

kN-*$ per *eter rn

8$ = 9a . γ . h%

kN-*$ per *eter rn

8% kN-*$ per *eter rn

8% 8

$ kN-*$ per *eter rn

5%= 9a γ h

%3-1

5$= 9a " h

%$-$

8%

3.0

0.3

8$

K a

1 sin φ( )−

1 sin φ( )+:=






Rev No. A Approved

Rev Date -

MAIN REINFORCEMENT (VERTICAL) De!"# $%& M'!u %e#*

Characteristic strength of concrete = 30

Characteristic strength of steel = 460

;actored ending *o*ent = 4+.90 kN*

<idth of all = %000 **

'hickness of all D = ,00 **

Clear cover c = 0 **

Dia*eter of *ain reinforce*ent = ,0 **

Dia*eter of secondar7 reinforce*ent = , **

>ffective depth d = Dcd*ds-$

= %$? **

= 0.%0?

@ = d / 0.) 8R' !0.$) 9 - 0.4#B = %02.?4 **

0.4) / d = %%2.& **

ince 0.4)/d,is greater than @, vale of @ is = %02.?4

= %0$0

5in reinf. each face per tale 3.$) + &%%0% = 0.$ = ?00

5ain reinforce*ent ,0 / ,00 ** c-c

>/tra reinforce*ent 0 / 0 ** c-c

Area of reinforce*ent provided = %)20

e#1e O2.

(ori@ontal reinforce*ent , / ,00 ** c-c

Area of reinforce*ent provided = )1)

Reinforcement Summary:

Provide vertical reinforcement T20 @ 200 mm c/c.

Provide horizontal reinforcement T12 @ 200 mm c/c.

f c N-**$

f 7 N-**$

%.? / 5% = 5

d*

ds

9 = 5 - ! / d$ / f

c #

Reinforce*ent re"ired Ast = 5 - ! 0.4) / f

7 / @ # **$

**$

**$

**$






Rev No. A Approved

Rev Date -



Project: ?00-%3$-$$ k +'A'EFN EN AADEGA' EAND Date 1Hl Page

Client: 'RANCF Design P9 Checked 9N

E>5>N Rev No. + Approved PH5

DER DESIGN trctre: %3$ k IE +EDENI Rev Date

C&'15 W!*7 C7e15 F%& W'll

C7e15 $%& C&'15 W!*78 (Se&!1e l%') 5ain teel M: D!&e1*!%# (- e)

ocation: ertical reinforce*ent ocation : Ou*e& F'1e Re!#$%&1ee#*

'hickness of all !h# = 300 ** !pto 0.1* height#

Cover to reinforce*ent = + **


Characteristic strength of steel = 4,0

5odls of elasticit7 of concrete = ,000

5odls of elasticit7 of steel = ,00000

Dia of ar sed = 6 **

pacing of ars provided = , **

Dia of ar sed !>/tra reinforce*ent# = 0 **

pacing of ars provided !>/tra reinforce*ent# = 0 **

ervice 5o*ent = 43.4 kN*

Per*issile crack idth = 0., **

!;or Plate No: 1 oad Condition: %$ #

>ffective Depth!d# = 300 2) %1-$ = $%2 **

Depth of netral a/is J / J = &?.33 **

= %1.12

!As per Cl. $.).$ of + &%%0:Part%:%442#

Area of reinforce*ent = %10& **K

Considering %* idth of all,

Percentage of +otto* reiforce*ent = %10& - !%000 / $%2#

= 0.2? L

5o*ent of resistance of the section =

?3?)0000 = %10& / ! $%2 &?.33 - 3 # / fs

?3?)0000 = 30312).2%$$

= 43.0; N-**K

A <e& S - ;00+ 9;9

5aincontractor:

f cu N-**$

f y N-**$

E c N-**$

E s N-**$

5odlar ratio ae >s - >c

As / f

s / ! d /-3 #

/ f s

(ence stress in steel , f s

Reinf. vl εs

ε%

/

d / h /







5aincontractor:

= 0.& / ?$0 - $00000

= 0.00$

train in steel = %?3.0& - $00000

= 0.000+ M 0.00,

(ence SAFE

=

= ! %?3.0& - %2 #/ &?.33 - ! $%2 &?.33 #

= ).?1

= 0.?) / 3)

= %).2) N-**K

.46 M .+

(ence SAFE

=

= %?3.0& / ! 300&?.33 #

$00000 / ! $%2&?.33 #

= 0.00%%13

tiffening effect of Concrete = t / ! h / #K

3 / >s / As / ! d / #

= %000 / ! 300&?.33 # 6 $

100000 / %10& / ! $%2&?.33 #

= 0.000313)

=

= 0.00%%13 0.000313)

= 0.000244 1 $ .

)

C7e15 $%& 1&'15=!*7

Crack idth J < J =

1 $ .

)

= &3 K 13 K %1 - $

= 4).40 ** &3

'hereforce J < J = 3 / 0.000&0 / 4).400

% $ / ! 4).40 2) # - ! 300 &?.33 #

= 0.%43 ** M 0.$ **

train in steel and tress in concrete shold not e/ceed 0.&f 7->s and 0.?)f c respectivel70.& / f

7->s

= f s - >

s

tress in concrete, f c

! f s - * # / - !d / #

0.?) / f c

Average elastic tensile strain in the Concrete,e%

f s

/ ! h / #

>s / ! d / #

e%

e$

e$

e*

e%

e$

3 / e* / a

cr

% $ / !acr C

*in# - !h /#

acr







5aincontractor:

e#1e S'$e

CEC2 FOR TEM>ERAT?RE CRAC2

(7dration peak and a*ient te*peratre '% = ,

ariation in te*peratre '$ =

f ratio = 0.6+

>/ternal restraint factor R = 0.

'her*al e/pansion coef. for concrete alpha = 0.0000

'e*peratre Oone depth co*pression steel = 0 **

'e*peratre Oone depth tension steel = 0 **

5ini** reinforce*ent to control crack = 0.003) = %0)0

= )$)

Te<e&'*u&e 1&'15!#" - C%<&e!%# &e!#$%&1ee#*

Co*pression steel provided = , , ** c-c

0 0 ** c-c

= 40) Q )$)

teel proportion = 0.00103$ O5

Proale *a/. crack spacing s*a/ = fratio / diat - !$ / p#

= 111.) **

>sti*ated *a/i** crack idth = s*a/ / R / alpha / !'%'$#

= 0.%333 ** M 0.$ **

e#1e S'$e

Te<e&'*u&e 1&'15!#" - Te#!%# &e!#$%&1ee#*

'ension steel provided = %1 %$) ** c-c

0 0 ** c-c

= %10& Q )$)

teel proportion = 0.0%02$3 O5


o

o

f ct-f

**$

**$ per face

**$ **$

**$ **$







5aincontractor:

= ?44.& **


= 0.%000 ** M 0.$ **

e#1e S'$e







C&'15 W!*7 C7e15 F%& W'll

C7e15 $%& C&'15 W!*78 (Se&!1e l%') 5ain teel M: D!&e1*!%# (- e)

ocation: ertical reinforce*ent ocation : Ou*e& F'1e Re!#$%&1ee#*

'hickness of all !h# = 300 ** !Aove 0.1* height#

Cover to reinforce*ent = + **





Dia of ar sed = , **




ervice 5o*ent = +.4; kN*


!;or Plate No: $1 oad Condition: %$ #

>ffective Depth!d# = 300 2) %$-$ = $%4 **

Depth of netral a/is J / J = 12.)2 **

= %1.12

!As per Cl. $.).$ of + &%%0:Part%:%442#

Area of reinforce*ent = 40? **K


Percentage of +otto* reiforce*ent = 40? - !%000 / $%4#

= 0.?% L


2?&0000 = 40? / ! $%4 12.)2 - 3 # / fs

2?&0000 = %22122.431%

= 4,.0 N-**K

A <e& S - ;00+ 9;9

5aincontractor:

f cu N-**$

f y N-**$

E c N-**$

E s N-**$


As / f

s / ! d /-3 #

/ f s


Reinf. vl εs

ε%

/

d / h /







5aincontractor:

= 0.& / ?$0 - $00000

= 0.00$

train in steel = ?$.% - $00000

= 0.000, M 0.00,

(ence SAFE

=

= ! ?$.%0 - %2 #/ 12.)2 - ! $%4 12.)2 #

= %.%3

= 0.?) / 3)

= %).2) N-**K

.3 M .+

(ence SAFE

=

= ?$.%0 / ! 30012.)2 #

$00000 / ! $%412.)2 #

= 0.0003$3


3 / >s / As / ! d / #

= %000 / ! 30012.)2 # 6 $

100000 / 40? / ! $%412.)2 #

= 0.0001)2)

=

= 0.0003$3 0.0001)2)

= 0.00033? 1 $ .

)

N% #ee *% 17e15 *7e 1&'15 =!*7

Crack idth J < J =

1 $ .

)

= &% K 13 K %$ - $

= 41.3% ** &%

'hereforce J < J = 3 / 0.00033 / 41.3%0

% $ / ! 41.3% 2) # - ! 300 12.)2 #

= 0.0&$ ** M 0.$ **


7->s

= f s - >

s


! f s - * # / - !d / #

0.?) / f c


f s

/ ! h / #

>s / ! d / #

e%

e$

e$

e*

e%

e$

3 / e* / a

cr

% $ / !acr C

*in# - !h /#

acr







5aincontractor:

e#1e S'$e




f ratio = 0.6+






= )$)

Te<e&'*u&e 1&'15!#" - C%<&e!%# &e!#$%&1ee#*

Co*pression steel provided = , , ** c-c

0 0 ** c-c

= 40) Q )$)



= 111.) **


= 0.%333 ** M 0.$ **

e#1e S'$e

Te<e&'*u&e 1&'15!#" - Te#!%# &e!#$%&1ee#*

'ension steel provided = %$ %$) ** c-c

0 0 ** c-c

= 40) Q )$)



o

o

f ct-f

**$

**$ per face

**$ **$

**$ **$







5aincontractor:

= 111.) **


= 0.%333 ** M 0.$ **

e#1e S'$e







C&'15 W!*7 C7e15 F%& W'll

C7e15 $%& C&'15 W!*78 (Se&!1e l%') econdar7 teel M D!&e1*!%# (- e)

ocation: (ori@ontal reinforce*ent ocation : Ou*e& F'1e Re!#$%&1ee#*

'hickness of all !h# = 300 **

Cover to reinforce*ent = 9 **





Dia of ar sed = 0 **




ervice 5o*ent = .6; kN*


!;or Plate No: 41 oad Condition: %$ #

>ffective Depth!d# = 300 4% %0-$ = $0? **

Depth of netral a/is J / J = )).2$ **

= %1.12

!As per Cl. $.).$ of + &%%0:Part%:%442#

Area of reinforce*ent = 1$& **K


Percentage of +otto* reiforce*ent = 1$& - !%000 / $0?#

= 0.3% L


%)1&0000 = 1$& / ! $0? )).2$ - 3 # / fs

%)1&0000 = %%1??&.%04?

= 34.6 N-**K

A <e& S - ;00+ 9;9

5aincontractor:

f cu N-**$

f y N-**$

E c N-**$

E s N-**$


As / f

s / ! d /-3 #

/ f s


Reinf. vl εs

ε%

/

d / h /







5aincontractor:

= 0.& / ?$0 - $00000

= 0.00$

train in steel = %3?.1) - $00000

= 0.000+ M 0.00,

(ence SAFE

=

= ! %3?.1) - %2 #/ )).2$ - ! $0? )).2$ #

= 3.0?

= 0.?) / 3)

= %).2) N-**K

3.04 M .+

(ence SAFE

=

= %3?.1) / ! 300)).2$ #

$00000 / ! $0?)).2$ #

= 0.00%%04


3 / >s / As / ! d / #

= %000 / ! 300)).2$ # 6 $

%000 / ! 300)).2$ # 6 $

= 0.00%01&0

=

= 0.00%%04 0.00%01&0

= 0.0000?% 1 $ .

)

C7e15 $%& 1&'15=!*7

Crack idth J < J =

1 $ .

)

= 41 K 13 K %0 - $

= %04.)) ** 41

'hereforce J < J = 3 / 0.0000? / %04.))$

% $ / ! %04.)) 4% # - ! 300 )).2$ #

= 0.0%$ ** M 0.$ **


7->s

= f s - >

s


! f s - * # / - !d / #

0.?) / f c


f s

/ ! h / #

>s / ! d / #

e%

e$

e$

e*

e%

e$

3 / e* / a

cr

% $ / !acr C

*in# - !h /#

acr







5aincontractor:

e#1e S'$e




f ratio = 0.6+






= )$)

Te<e&'*u&e 1&'15!#" - C%<&e!%# &e!#$%&1ee#*

Co*pression steel provided = 0 , ** c-c

0 0 ** c-c

= 1$& Q )$)

teel proportion = 0.00?%&4 O5


= 244.& **


= 0.%100 ** M 0.$ **

e#1e S'$e

Te<e&'*u&e 1&'15!#" - Te#!%# &e!#$%&1ee#*

'ension steel provided = %0 %$) ** c-c

0 0 ** c-c

= 1$& Q )$)

teel proportion = 0.00?%&4 O5


o

o

f ct-f

**$

**$ per face

**$ **$

**$ **$







5aincontractor:

= 244.& **


= 0.%100 ** M 0.$ **

e#1e S'$e



Project: %3$-%% k +'A'EFN A' +AR(A F'( Date 1Hl Page

Client: D><A Design P9 Checked

+A(<AN >NIEN>>RENI CF5PANG Rev No. + Approved


SEAR CEC2 FOR WALL Main steel

( For SQY Value Refer attached STAAD output sheets )

Max shear stress from STAAD Output, V = 0.07

late !o" 2337 #oad case" 21

Th$c%!ess of Raft D = 250 mm

&lear co'er = 75 mm

D$ameter of ma$! re$!forceme!t = 12 mm

Spac$! of ma$! re$!forceme!t = 200 mm cc

D$ameter of seco!dar* re$!forceme!t = 12 mm

Spac$! of seco!dar* re$!forceme!t = 200 mm cc

+ffect$'e depth d = -. mm

= 35

=

/ of steel pro'$ded = 0122 /

Des$! shear stre!th = 013.x(0122)42 x(500-.)45x167 x (276of co!crete = 01-

As 0.070 < 0.61 SAFE

5aincontractor:

8mm6

9rade of co!crete , f cu 8mm6

8mm6

8mm6 8mm6



9N

PH5

)42

Retaining Wall

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