Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15...
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Transcript of Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15...
![Page 1: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/1.jpg)
Representing Data for Finding Probabilities
•There are 35 students•20 take math•25 take science•15 take both
•Venn Diagram Contingency table
155 10
5 M ^M
S 15 10 25
^S 5 5 10
20 15 35
![Page 2: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/2.jpg)
Conditional Probability
P(B|A) means the probability B happens, given that A happens•P(Science|Math) = 15/20•P(Math|Science) = 15/25
You can get this from either representation
155 10
5 M ^M
S 15 10 25
^S 5 5 10
20 15 35
![Page 3: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/3.jpg)
Independence
Two events, A and B are independent if P(B|A)=P(B)
Example:
I roll a die and flip a coin. P(H|6)=P(H) because the number on the die does not affect my chance of getting heads. Heads and Getting a Six are independent events.
![Page 4: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/4.jpg)
Independence
Two events, A and B are independent if P(B|A)=P(B)
Example:
I pick a card out of a regular 52 card deck. Then, I pick a second card without replacing the first. Are the events getting a red card and then getting a queen independent?
No, because removing a card from the deck changes my probabilities for the second draw. My denominator is now 51 instead of 52.
![Page 5: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/5.jpg)
Independence
Two events, A and B are independent if P(B|A)=P(B)
Example:
I pick a card out of a regular 52 card deck. Then, I pick a second card after putting the first card back in the deck. Are the events getting a red card and then getting a queen independent?
Yes, because replacing the first card makes it as if I never drew it in the first place. All probabilities remain the same for the second draw
![Page 6: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/6.jpg)
Multiplication Rule
P(A and B) = P(A)*P(B|A)
If A and B are independent, this becomes:
P(A and B) = P(A)*P(B)
![Page 7: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/7.jpg)
Multiplication Rule
Experiment: Flip a Coin and Roll a Die.
H1
H2
H3
H4
H5
H6
T1
T2
T3
T4
T5
T6
H
T
What is the probability of getting a head and then an even number?
P(H and E)=P(H)*P(E)
=
4
1
6
3
2
1
P(H and E) =
4
1
12
3
![Page 8: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/8.jpg)
Multiplication Rule
There are 3 blue marbles and 2 green in a box. What is the probability you draw a blue and then a green?
P(B) = 3/5 P(G|B) = 1/2
X
10
3)(
2
1
5
3)(
)|(*)()(
BandGP
BandGP
BGPBPBandGP
![Page 9: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/9.jpg)
Multiplication Rule
There are 3 blue marbles and 2 green in a box.
B
G
3/5
2/5
B
G
B
G
2/4
2/4
1/4
3/4
3/10
3/10
3/10
1/10
P(B and G) = 3/10
P(G and G) = 1/10
P(G|B) = 2/4=1/2
P(G|G) = 1/4
![Page 10: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/10.jpg)
Multiplication Rule
What is the probability that I draw a queen and then a Ten when drawing without replacement?P(Q) = 4/52P(Ten|Q) = 4/51P(Q and ten) =
What is the probability that I draw a queen and then a Ten when drawing with replacement?P(Q) = 4/52P(Ten|Q) = 4/52P(Q and ten) =
663
4
2652
16
51
4
52
4
169
1
2704
16
52
4
52
4
![Page 11: Representing Data for Finding Probabilities There are 35 students 20 take math 25 take science 15 take both Venn Diagram Contingency table 15 5 10 5 M^M.](https://reader036.fdocuments.us/reader036/viewer/2022082713/5697bfc91a28abf838ca9072/html5/thumbnails/11.jpg)
Multiplication Rule
Here are the results for 240 students taking an entrance exam for placement in upper mathematics at a high school:
80
Passed Female
8040
40Is a student’s passing status independent of gender?
If so,P(passed) =P(passed|female)
P(passed) =160/240 = 2/3
P(passed|female)=80/120=2/3
P(passed)=P(passed|female) Passing is independent of gender for these results