WELCOME

AREA OF REGULAR HEXAGON

RENJU.V.UB.ED

MATHEMATICS

AREA OF REGULAR HEXAGON

B C

A D

F E

JOIN AD,CF,BE

B C

A D

F E

O

DIAGONALS DIVIDES REGULAR HEXAGON INTO 6 EQUILATERAL TRIANGLES

B C B C

A O D A D F F E E

AREA OF AN ONE EQUILATERAL TRIANGLE = s (s-a) (s-b) (s-c) , s =

a+b+c

2 = 3a 3a - a 3a – a 3a – a 2 2 2 2

= 3a a a a 2 2 2 2 = 3 a 16

= 3a 2 4

AREA OF REGULAR HEXAGON = 6 (AREA OF EQUILATERAL TRIANGLE)

= 6 3 a 2 4 = 3 3 a 2 2