Relations and Functions
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Transcript of Relations and Functions
Relations and Functions Linear Equations
Vocabulary:RelationDomainRange
FunctionFunction Notation
Evaluating Functions Slope-intercept Form Point-slope form:
Standard Form.No fractions!No decimals!
Slope
Transformation of f(x) Translation: Vertical (k > 0) Translation: Horizontal (h > 0)
Stretch or compression:
Vertical by a factor of a
Reflection
𝑓 (𝑥 )+𝑘Up k units
Down k units 𝑓 (𝑥 ) −𝑘𝑓 (𝑥−h )Right h units
Left h units 𝑓 (𝑥+h )
𝑎>1Stretch:Compression:
𝑎⋅ 𝑓 (𝑥 ) − 𝑓 (𝑥 )Across x-axis
Across y-axis 𝑓 (−𝑥 )0<𝑎<1
Absolute Value Function f(x) = |x|
0 when ,
0 when ,)(
xxx
xxxxf
-6 -4 -2 2 4 6-6
-4
-2
2
4
6
x
y
VertexAxis of symmetry
x = 0
Graphing1. Graph the vertex2. Graph right branch3. Use symmetry to graph left branch
Vertex: (h, k)Slope of right branch: ±a
khxay
Equation from graph1. Identify the vertex2. Find the slope of the right branch
Pg. 127 #1-20, 23-26, 31-37
Functions, Equations and GraphsFunctions Linear Equations Transformations Absolute Values
More Linear Equations
10 10 10 10 10
20 20 20 20 20
30 30 30 30 30
40 40 40 40 40
50 50 50 50 50
x
y
Is the relation a function?
Answer
A. {(1, 2); (2,3); (1,4); (3,5)}
B. {(1, 5); (2,5); (3,5)}
C.
x
y
Is the relation a function?
A. {(1, 2); (2,3); (1,4); (3,5)}
B. {(1, 5); (2,5); (3,5)}
C.
No
Yes
Yes
What is the domain and range?
A. {(1, 2); (2,3); (1,4); (3,5)}
B. {(1, 5); (2,5); (3,5)}
Domain:{1, 2, 3}Range: {2, 3, 4, 5}
Domain:{1, 2, 3}Range: {5}
Find the value of
𝑓 (𝑥 )=7− 4 𝑥 𝑔 (𝑥 )=|4 −7 𝑥|+2
𝑓 (−3 )=7 − 4 (−3)𝑓 (−3 )=19
𝑔 (2 )=|4 − 7(2)|+2
𝑔 (2 )=12
𝑓 (−3 )+𝑔 (2 )=19+12¿31
Find the value of
𝑓 (𝑥 )=7− 4 𝑥 𝑔 (𝑥 )=|4 −7 𝑥|+2
𝑓 (5 )=7 − 4(5)𝑓 (5 )=−13
𝑔 (− 6 )=|4 −7 (− 6)|+2
𝑔 (− 6 )=48
𝑓 (5 ) −𝑔 (− 6 )=−13 − 48¿− 61
Write and equation in slope-intercept form:
and y-intercept and
𝑦=−75𝑥+5
𝑦− 3=−12(𝑥+4)
𝑦− 3=−12𝑥−2
𝑦=−12𝑥+1
Write an equation in point-slope form: and and
𝑦− 3=−25(𝑥−5)
𝑦+4=8(𝑥− 2)
𝑦− 4=8(𝑥− 3)
𝑚=4 −(− 4)
3 − 2=8
1=8
Write an equation in standard form and and
𝑦−1=−34(𝑥− 8)
4 𝑦− 4=− 3(𝑥− 8)4 𝑦− 4=− 3𝑥+24
3 𝑥+4 𝑦=28
𝑦−7=14(𝑥− 1)
4 𝑦− 28=(𝑥−1)4 𝑦− 28=𝑥− 1
−𝑥+4 𝑦=27
𝑚=6− 7
− 3−1=
− 1− 4
=14
-5 5
-5
5
x
y
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
Answer
𝑓 (𝑥−3 )+2Function notation:
Description:
𝒇 (𝒙 )
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
𝑓 (𝑥−3 )+2Function notation:
Description:
-5 5
-5
5
x
y
Right 3Up 2
Function notation:
-5 5
-5
5
x
y
Answer
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
Description:
𝒇 (𝒙 )Stretch by 2Down 2
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
Function notation:
Description:
-5 5
-5
5
x
y2
Stretch by 2Down 2
-5 5
-5
5
x
y
Answer
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
Function notation:
Description:
𝒇 (𝒙 )12𝑓 (𝑥+2 ) −3
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
Function notation:
Description:
12𝑓 (𝑥+2 ) −3
-5 5
-5
5
x
y
Compress by ½ Left 2Down 3
-5 5
-5
5
x
y
Answer
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
Function notation:
Description:
𝒇 (𝒙 )Reflect across x-axisStretch by 2Right 1Up 4
Describe the transformation or write the transformation in function, then sketch a graph of the transformation.
−2 𝑓 (𝑥−1 )+4Function notation:
Description: Reflect across x-axisStretch by 2Right 1Up 4
-5 5
-5
5
x
y
Describe transformations of f(x) that produces g(x).
𝑓 (𝑥 )=2𝑥2 𝑔 (𝑥 )=− (𝑥−3 )2+4
−𝟏𝟐𝑓 (𝑥−𝟑 )+𝟒=−
𝟏𝟐
∙ 2 (𝑥−𝟑 )2+𝟒
−𝟏𝟐𝑓 (𝑥−𝟑 )+𝟒=− (𝑥−3 )2+4=𝑔 (𝑥)
Reflect across x-axis; compress by ½; right 3; up 4
Write an equation of line in standard form that is parallel to the given line and goes through the
given point.
Answer
Point:5 𝑥−2 𝑦=− 4
Write an equation of line in standard form that is parallel to the given line and goes through the
given point.
Point:5 𝑥−2 𝑦=− 4
−2 𝑦=− 5𝑥−4
𝑦=52𝑥+2
𝑦+4=52(𝑥− 1)
2 𝑦+8=5(𝑥− 1)2 𝑦+8=5𝑥−5
−5 𝑥+2 𝑦=−13
Answer
Write an equation of line in standard form that is perpendicular to the given line and goes through
the given point.Point:5 𝑥−2 𝑦=− 4
Write an equation of line in standard form that is perpendicular to the given line and goes through
the given point.Point:5 𝑥−2 𝑦=− 4
−2 𝑦=− 5𝑥−4
𝑦=52𝑥+2
𝑦+4=−25(𝑥−1)
5 𝑦+20=−2(𝑥− 1)5 𝑦+20=−2 𝑥+2
2 𝑥+5 𝑦=− 18