Redox – Part 2

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Redox – Part 2 Redox – Part 2 a. demonstrate an understanding of: iv. how oxidation number is a useful concept in terms of the classification of reactions as redox and as disproportionation b. write ionic half-equations and use them to construct full ionic equations.

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a.demonstrate an understanding of: iv.how oxidation number is a useful concept in terms of the classification of reactions as redox and as disproportionation b.write ionic half-equations and use them to construct full ionic equations. Redox – Part 2. Task: Match up the formulas with their - PowerPoint PPT Presentation

Transcript of Redox – Part 2

Page 1: Redox  – Part 2

Redox – Part 2Redox – Part 2a. demonstrate an understanding of:

iv. how oxidation number is a useful concept in terms of the classification of reactions as redox and as disproportionation

b. write ionic half-equations and use them to construct full ionic equations.

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Task: Match up the formulas with theircorrect names

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Naming CompoundsNaming Compounds

• Some elements can have more than one oxidation number.

• So to avoid confusion when naming the compounds they form, its helpful to use these numbers in their names.

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Naming CompoundsNaming Compounds

??

??

What are the missing

oxidation numbers here for Manganese and Chromium, respectively?

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Task Answer – sometimes, instead of using the systematic name, scientists still use the traditional

names for some substances.

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Redox and Oxidation Redox and Oxidation NumbersNumbers

• An increase in oxidation number means oxidation has occurred.

• While a decrease in oxidation number means reduction has occurred.

• E.g. What would bethe oxidationnumbers foreach of the

species in thisreaction?0 -1-2 0+1 +1

Therefore,

chlorine has been reduced, and

sulphur has been oxidised.

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Redox and Oxidation Redox and Oxidation NumbersNumbers

• Another example is the Thermite Reaction (click here to see it in action!!)

• But what is oxidised and what is reduced?

0 +3-2 -2+3 0

Therefore,

iron has been reduced, and

aluminium has been oxidised.

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DisproportionationDisproportionation

• Is a type of reaction in which a substances both oxidised and reduced in the same reaction. E.g. the breakdown of hydrogen peroxide:

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Disproportionation – another Disproportionation – another exampleexample

• The reaction of copper(I) oxide with dilute sulphuric acid:

• Study the equation carefully – what disproportionates?

• The answer is copper (Cu) which gets oxidised from +1 to +2 and also reduced from +1 to zero, in the same reaction.

• Other examples of such reactions include reactions of chlorine with water, and chlorine with hot sodium hydroxide solution.

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QuestionsQuestions

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AnswersAnswers

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Oxidation StatesOxidation States

• Some elements show a range of oxidation states.

• One colourful example is the reduction of vanadium (V) to vanadium (II) through sucessive oxidation number.

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Vanadium – its different oxidation statesVanadium – its different oxidation states

Ammonium Vanadate (V) (white solid) can be added to dilute HCl to give the orange Dioxovanadium (V) ion:

VO3- + 2H+ VO2

+ + H2O

If granulated zinc is now added it reduces the vanadium over a period of several minutes and gives several colour changes:

Blue [VO(H2O)5]2+ Vanadium (IV)

Green [VCl2(H2O)4] + Vanadium (III)

Violet [V(H2O)6]2+ Vanadium (II)

+5 +5

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Common Oxidising AgentsCommon Oxidising Agents

• What is an oxidising agent?– A species that reacts by oxidising something else and getting

reduced itself.

• So, as we will see, electrons in the half equations are always on the left-hand side of the equation, as oxidising agents gain electrons.

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More Oxidising AgentsMore Oxidising Agents

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More Oxidising AgentsMore Oxidising Agents

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Common Reducing AgentsCommon Reducing Agents

• What is an reducing agent?– A species that reacts by reducing something else and getting

oxidised itself.

• So, this time, electrons in the half equations are always on the right-hand side of the equation, as reducing agents loose electrons.

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More Reducing AgentsMore Reducing Agents

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More Reducing AgentsMore Reducing Agents

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Writing balanced equations from ionic Writing balanced equations from ionic half equations - Worked Example…half equations - Worked Example…

Firstly, write down the

half equations you

need.

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Worked Example…..cont….Worked Example…..cont….

X5

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Worked Example…..cont….Worked Example…..cont….

Notice, that in adding the two equations togetherThe electrons are cancelled out and not

Included in the final equation

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Worked Example 2…Worked Example 2…

Again, start with the half

equations

Have a gobefore you turn tothe next slide for

the answer

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Worked Example 3…Worked Example 3…

Again, start with the half

equations

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Or

?

X

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molecular equation

Ionic to Molecular EquationIonic to Molecular Equation• To turn an ionic equation to a molecular equation, you would

simply add the spectator ions.

• Eg. Reaction of potassium manganate (VII) solution with iron (II) sulphate solution in the presence of dilute sulphuric acid:

Ionic equation – which you work out

Add in spectator ions by using cluesIn question

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QuestionsQuestions

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AnswersAnswers