Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of...
-
Upload
merry-daniel -
Category
Documents
-
view
255 -
download
0
Transcript of Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of...
![Page 1: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/1.jpg)
Questions
From HW.
![Page 2: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/2.jpg)
1.
The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y4-). Calculate the percent Zn in this sample. Moles of EDTA = Moles of Zn
(0.01645 M)(0.02127L) = Moles of Zn
0.0003498915= Moles of Zn
Convert to grams of Zn and compare to original value
0.0003498915 moles x 65.39 gram/mole = 0.022879 gram of Zn
%1007556.0
022879.0% x
g
gZn %0279.3
![Page 3: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/3.jpg)
2. A 50.00-mL aliquot of a solution containing
Iron (II) required 13.73 mL of 0.01200 M EDTA (Y4-) when titrated at pH 2.0. Express the concentration of iron in parts per million.
Moles of EDTA = Moles of Fe2+
(0.01200 M)(0.01373L) = Moles of Fe2+
0.00016476 = Moles of Fe2+
L
moleMFe
0500.0
00016476.0,2
L
mole
1
0032952.0
![Page 4: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/4.jpg)
2. A 50.00-mL aliquot of a solution containing
Iron (II) required 13.73 mL of 0.01200 M EDTA (Y4-) when titrated at pH 2.0. Express the concentration of iron in parts per million.
g
mgx
mole
gx
L
mole
1
1000847.55
1
0032952.0L
mg0.184
![Page 5: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/5.jpg)
13-5.
Calculate the conditional constants for the formation of EDTA complex of Fe2+ at a pH of (a) 6.0, (b) 8.0, (c) 10.0.
K’f = Kf
K’f = x 10-5 (1.995 x 1014)
K’f = x 109
K’f = x 10-3 (1.995 x 1014)
K’f = x 1012
K’f = (1.995 x 1014)
K’f = x 1013
![Page 6: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/6.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant.
At initial Point pSr = -log (0.0100)
At initial Point pSr = 2.000
Find equivalence Volume
Moles Sr2+ = Moles EDTA
(0.05000 L)x(0.01000M Sr2+) = 0.02000 M x Ve
25.0 mL = Ve
![Page 7: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/7.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Excess will determine pSr
Sr2+ + Y4- -> SrY2-
Before ? After
0.0005000 moles 0.0002000 moles None
0.0003000 moles None 0.0002000 moles
LL
molespSr
01000.005000.0
0003000.0log 3010.2
![Page 8: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/8.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Excess will determine pSr
Sr2+ + Y4- -> SrY2-
Before ? After
0.0005000 moles 0.0004800 moles None
0.0000200 moles None 0.0004800 moles
LL
molespSr
02400.005000.0
00002000.0log 568.3
![Page 9: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/9.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Excess will determine pSr
Sr2+ + Y4- -> SrY2-
Before ? After
0.0005000 moles 0.0004980 moles None
0.00000200 moles None 0.0004980 moles
LL
molespSr
02490.005000.0
000002000.0log 5735.4
![Page 10: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/10.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Equivalence
- EQUILIBRIUM OF SrY2- is source of Sr2+
Sr2+ + Y4- -> SrY2-
Before After
0.0005000 moles 0.0005000 moles None
None None 0.0005000 moles
![Page 11: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/11.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Equivalence
- EQUILIBRIUM OF SrY2- is source of Sr2+
Sr2+ + Y4- SrY2-
I C
E
None None 0.0005000 moles/ 0.075 L
+x +x -x
+x +x 0.00666 –x
K’ = 4.25 x 108
]][[
][34
2
SrY
SrY
]][[
]0066.0[
xx
x
61094.3 xpSr = 5.40
![Page 12: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/12.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Post equivalence
- EQUILIBRIUM OF SrY2- is source of Sr2+
Sr2+ + Y4- SrY2-
I C
E
None 0.000002/0.0751 L0.0005000 moles/ 0.0751 L
+x +x -x
+x 2.666x10-5 +x 0.006657 –x
K’ = 4.25 x 108
]][[
][34
2
SrY
SrY 710205.5 xpSr = 6.2835]10666.2][[
]006657.0[5 xx
x
![Page 13: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/13.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Post equivalence
- EQUILIBRIUM OF SrY2- is source of Sr2+
Sr2+ + Y4- SrY2-
I C
E
None 0.00002/0.076 L 0.0005000 moles/ 0.076 L
+x +x -x
+x 2.63x10-4
+x
0.006578 –x
K’ = 4.25 x 108
]][[
][34
2
SrY
SrY 810885.5 xpSr = 7.230]1063.2][[
]006578.0[4 xx
x
![Page 14: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/14.jpg)
4. Derive a titration curve for 50.00 mL of 0.01000 M Sr2+ with
0.02000 M EDTA in a solution buffered to pH 11.0. Calculate pSr values after the addition of 0.00, 10.00, 24.00, 24.90, 25.00, 25.10, 26.00, 30.00 mL of titrant. Post equivalence
- EQUILIBRIUM OF SrY2- is source of Sr2+
Sr2+ + Y4- SrY2-
I C
E
None 0.0001000/0.080 L0.0005000 moles/ 0.080 L
+x +x -x
+x 0.00125
+x
0.00625 –x
K’ = 4.25 x 108
]][[
][34
2
SrY
SrY 810176.1 xxpSr = 7.929]00125.0][[
]00625.0[
xx
x
![Page 15: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/15.jpg)
0
1
2
3
4
5
6
7
8
9
0 10 20 30 40
Volume Titrant
pS
r
![Page 16: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/16.jpg)
Section 23-3 A Plumber’s View of A Plumber’s View of ChromatographyChromatography
The chromatogram“Retention time”
“Relative retention time”“Relative Retention”
“Capacity Factor”
![Page 17: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/17.jpg)
A chromatogramRetention time (tr) – the time required for a substance to pass
from one end of the column to the other.Adjusted Retention time – is the retention time corrected for dead
volume “the difference between tr and a non-retained solute”
![Page 18: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/18.jpg)
A chromatogramAdjusted Retention time (t’
r) - is the retention time corrected for dead volume “the difference between tr and a non-retained
solute”
![Page 19: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/19.jpg)
A chromatogramRelative Retention () -the ratio of adjusted retention times for
any two components. The greater the relative retention the greater the separation. Used to help identify peaks when flow
rate changes.
1
2
'
'
r
r
t
t 1 '' 21 sottwhere rr
![Page 20: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/20.jpg)
A chromatogramCapacity Factor (k’) -”The longer a component is retained by the column, the greater its capacity factor. To monitor performance of a column – one should monitor the capacity factor, the number
of plates, and peak asymmetry”.
m
mr
t
ttk
'
![Page 21: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/21.jpg)
An Example
A mixture of benzene, toulene, and methane was injected into a gas chromatograph. Methane gave a sharp peak in 42 sec, benzene was @ 251 sec and toulene eluted at 333 sec. Find the adjusted retention time (for each solute), the capacity factor (for each solute) and the relative retention.Adjusted retention time (t’r) = total time – tr (non retained
component)
t’r(benzene) = 251 sec – 42 sec = 209 s
t’r (toulene) = 333-42 sec = 291 s
![Page 22: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/22.jpg)
An Example
A mixture of benzene, toulene, and methane was injected into a gas chromatograph. Methane gave a sharp peak in 42 sec, benzene was @ 251 sec and toulene eluted at 333 sec. Find the adjusted retention time (for each solute), the capacity factor (for each solute) and the relative retention.Capacity Factor (k’) -”The longer a component is retained by the column,
the greater its capacity factor. To monitor performance of a column – one should monitor the capacity factor, the number of plates, and peak
asymmetry”.
m
mr
t
ttk
'
42
42251'
m
mrbenzene t
ttk = 5.0
![Page 23: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/23.jpg)
An Example
A mixture of benzene, toulene, and methane was injected into a gas chromatograph. Methane gave a sharp peak in 42 sec, benzene was @ 251 sec and toulene eluted at 333 sec. Find the adjusted retention time (for each solute), the capacity factor (for each solute) and the relative retention.Capacity Factor (k’) -”The longer a component is retained by the column,
the greater its capacity factor. To monitor performance of a column – one should monitor the capacity factor, the number of plates, and peak
asymmetry”.
m
mr
t
ttk
'
42
42333'
m
mrtoulene t
ttk = 6.9
![Page 24: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/24.jpg)
An Example
A mixture of benzene, toulene, and methane was injected into a gas chromatograph. Methane gave a sharp peak in 42 sec, benzene was @ 251 sec and toulene eluted at 333 sec. Find the adjusted retention time (for each solute), the capacity factor (for each solute) and the relative retention.Relative Retention (a) -the ratio of adjusted retention times for any two
components. The greater the relative retention the greater the separation. Used to help identify peaks when flow rate changes.
1
2
'
'
r
r
t
t sec39.1
sec209
sec291
'
'
benzene
toulene
t
t
![Page 25: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/25.jpg)
Efficiency of Separation
“Two factors”1) How far apart they are ()
2) Width of peaks
![Page 26: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/26.jpg)
ResolutionResolution
![Page 27: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/27.jpg)
Resolution
avw 2/1
r
av
r t589.0
w
tResolution
![Page 28: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/28.jpg)
![Page 29: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/29.jpg)
Example – measuring resolution
A peak with a retention time of 407 s has a width at the base of 13 s. A neighboring peak is eluted at 424 sec with a width of 16 sec. Are these two peaks well resolved?
av
r
w
tResolution
7
21
1.116)(13
407424Resolution
![Page 30: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/30.jpg)
Data Analysis
![Page 31: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/31.jpg)
![Page 32: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/32.jpg)
The Inlet
![Page 33: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/33.jpg)
![Page 34: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/34.jpg)
![Page 35: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/35.jpg)
![Page 36: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/36.jpg)
![Page 37: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/37.jpg)
Why are bands broad?
Diffusion and flow related effects
![Page 38: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/38.jpg)
Of particular concern in Gas Chromatography.Of particular concern in Gas Chromatography.Why?Why?
![Page 39: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/39.jpg)
Diffusion is fasterDiffusion is faster
![Page 40: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/40.jpg)
![Page 41: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/41.jpg)
Gases from the headspace of a beer can!!
![Page 42: Questions From HW.. 1. The Zn in a 0.7556-g sample of foot powder was titrated with 21.27 mL of 0.01645 M EDTA (Y 4- ). Calculate the percent Zn in this.](https://reader035.fdocuments.us/reader035/viewer/2022062221/56649e345503460f94b23327/html5/thumbnails/42.jpg)
Packed column ... Compare peak widths with your sample