Question:Consider the expressions: (a)F = XY + XY' (b)B = XYZ + XYZ' + X'Y'Z + X'Y'Z' (c)D =...
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Transcript of Question:Consider the expressions: (a)F = XY + XY' (b)B = XYZ + XYZ' + X'Y'Z + X'Y'Z' (c)D =...
Question: Consider the expressions:(a) F = XY + XY'(b) B = XYZ + XYZ' + X'Y'Z + X'Y'Z'(c) D = W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'
Example
For each of these expressions,1 i. Build the truth table
ii. Implement the logic circuit
2 i. Simplify the expression using theorems of Boolean Algebraii. Build the truth table (of the simplified expression)iii. Implement the logic circuit
3 Simplify the expression using Karnaugh map
Question: (a) F = XY + XY'
1 ii. Implement the logic circuit
1 i. Build the truth table
X Y F0 0 00 1 01 0 11 1 1
X
Y
Y'
XY
XY'
F = XY + XY'
Question: (a) F = XY + XY'
2 ii. Build the truth table (of the simplified expression)
2 i. Simplify the expression using theorems of Boolean Algebra
F = XY + XY'= X(Y + Y')= X . 1= X
X Y F0 x 01 x 1
2 iii. Implement the logic circuit
X F = X
Question: (a) F = XY + XY'
3 Simplify the expression using Karnaugh map
0X
Y
0
11
0 1
0
1
F = X
Question: (b) B = XYZ + XYZ' + X'Y'Z + X'Y'Z'
1 i. Build the truth table
X Y Z B0 0 0 10 0 1 10 1 0 00 1 1 01 0 0 01 0 1 01 1 0 11 1 1 1
Question: (b) B = XYZ + XYZ' + X'Y'Z + X'Y'Z'
1 ii. Implement the logic circuit
X Y Z
X' Y' Z'
B = XYZ + XYZ' + X'Y'Z + X'Y'Z'
XYZ
XYZ'
X'Y'Z
X'Y'Z'
Question: (b) B = XYZ + XYZ' + X'Y'Z + X'Y'Z'
2 ii. Build the truth table (of the simplified expression)
2 i. Simplify the expression using theorems of Boolean Algebra
B= XYZ + XYZ' + X'Y'Z + X'Y'Z'= XY(Z + Z') + X'Y'(Z + Z')= XY + X'Y'
X Y Z B0 0 x 10 1 x 01 0 x 01 1 x 1
2 iii. Implement the logic circuit
Question: (b) B = XYZ + XYZ' + X'Y'Z + X'Y'Z'
X
Y
Y'
XY
X'Y'
B = XY + X'Y'
X'
3 Simplify the expression using Karnaugh map
B = X'Y' + XY
1X
YZ
1
00
00 01
0
1
0 0
11
11 10
Question: (c)D = W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'
1 i. Build the truth table
W X Y Z B0 0 0 0 10 0 0 1 00 0 1 0 10 0 1 1 00 1 0 0 10 1 0 1 00 1 1 0 10 1 1 1 01 0 0 0 01 0 0 1 01 0 1 0 01 0 1 1 01 1 0 0 01 1 0 1 01 1 1 0 01 1 1 1 0
Question: (c)D = W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'
1 ii. Implement the logic circuit
X Y Z
X' Y' Z'
D = W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'
W'XYZ'
W
W'
W'XY'Z'
W'X'YZ'
W'X'Y'Z'
Question: (c)D = W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'
2 ii. Build the truth table (of the simplified expression)
2 i. Simplify the expression using theorems of Boolean Algebra
D= W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'= W'Z'(X'Y' + X'Y + XY' + XY)= W'Z'((X'(Y' + Y) + X(Y' + Y))= W'Z'(X' + X)= W'Z'
W X Y Z D0 x x 0 10 x x 1 01 x x 0 01 x x 1 0
2 iii. Implement the logic circuit
Question: (c)D = W'X'Y'Z' + W'X'YZ' + W'XY'Z' + W'XYZ'
3 Simplify the expression using Karnaugh map
D = W'Z'
W
Z
D = W'Z'
1WX
YZ
0
01
00 01
00
01
0 1
10
11 10
0 0
00
11
10
0 0
00