Question Bank - Unit IV
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Transcript of Question Bank - Unit IV
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AE 2203 SOLID MECHANICS
UNIT IV Torsion
TB 1
TB 2REF 1
Nash William Strength of Materials, TMH, 1998
Timoshenko.S. and Young D.H. Elements of strength materials Vol. I and Vol. II.,Strength of Materials R.K.Rajput
Qs. No. Questions
Univ.QsTextbook
No.
Ans -
Page
Nos.
Mark
TLP No.1 Torsion of Circular Shafts
1. Define Torsion. May 10 Ref 1 725 22. What are the possible types of loads which can act in shafts? - Ref 1 724 23. Give torsion equation. - Ref 1 726 24. What is the formula for power transmitted by a shaft? May 09 Ref 1 728 25. A solid circular shaft transmits 75kW power at 200rpm. Calculate
the diameter of shaft , if the twist in shaft is not to exceed 1degree in
2metres length of shaft, and shear stress is limited to 50 MN/m2
.Take C=100GN/ m
2.
- Ref 1 732
16
6. In a Tensile test a piece of 25mm diameter, 200mm gauge length,stretched 0.0975mm under a pull of 50kN. In a torsion test, the same
rod twisted 0.025radian over a length of 200mm when a torque of
0.4kNm was applied. Evaluate Poissons ratio and three elastic moduli
for the material.
May 10 Ref 1 729
16
7. A hollow shaft of external diameter 120mm transmits 300kW power at200rpm. Determine the maximum internal diameter if the maximum
shear stress in the shaft is not to exceed 60N/mm2.
- Ref 1 735
16
8. A hollow circular shaft 20mm thick transmits 294kW at 200rpm.Determine the diameter of the shaft if shear strain due to torsion is notto exceed 8.6x10-4.
Take C=8oGN/m2.
- Ref 1 735
16
TLP No.2 Shear Stresses and twist in Solid and hollow circular shafts Ref 1
9. Prove that hollow shaft is stronger than solid shaft by comparing thesolid and hollow shaft by strength.
- Ref 1 7378
10. Prove that hollow shaft is less than the weight of solid shaft bycomparing the solid and hollow shaft by weight.
May 09 Ref 1 7388
11. A solid cylindrical shaft is to transmit 300kW at 100rpm.(i) If the shear stress is not to exceed 80MN/m2, find its
diameter.
(ii) What percentage saving in weight would be obtained inthis shaft is replaced by a hollow one whose internal
diameter equals 0.6 of the external diameter, the length,
the material and maximum shear stress being the same?
May 10 Ref 1 740
16
12. A hollow shaft having an inside diameter 60% of its outer diameter is toreplace a solid shaft transmitting the same power at the same speed.
Calculate the percentage saving in material, if the material to be used is
also the same.
- Ref 1 741
16
13. A hollow steel shaft is made to replace a solid wrought iron shaft of thesame external diameter, the material being 35percent stronger than
iron. Find what fraction of outside diameter the internal diameter
maybe. Also neglect coupling, find percentage saving in weight by
substitution, assuming that steel is 2 percent heavier than wroughtiron.
- Ref 1 742
16
TLP No.3 Closely coiled helical springs Ref 1
14. What are the types of springs? - Ref 1 813 215. Define closely coiled helical springs. - Ref 1 814 216. Give deflection formula for springs. - Ref 1 81517. A closely coiled helical spring of round steel wire 10mm in diameter
having 10 complete turns with a mean diameter of 120mm,
subjected to an axial load of 200N. Determine the deflection of
spring, Maximum shear stress in the wire and stiffness of spring.
Take C=80Gpa.
- Ref 1 819
18. A closely coiled helical spring is to have a stiffness of 900N/m incompression, with a maximum load of 45N and a maximum shear stressof 120N/mm2. The solid length of spring is 45mm. find
Ref 1 81816
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AE 2203 SOLID MECHANICS
UNIT IV Torsion
(i) Wire diameter(ii) Mean radius of coil(iii) Number of coilsTake C= 0.4x105N/mm2.
19. For a close coiled helical spring subjected to an axial load of 300Nhaving 12 coils of wire diameter 16mm, and made with coil diameter 0f
250mm, find
(i) Axial deflection(ii) Strain energy stored(iii) Maximum torsional shear stress in the wire(iv) Maximum shear stress using wahls correction factor.Take : C=80GN/m2.
- Ref 1 820
16
Prepared by: INAMUL HASAN M.
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