Purification

Vessel 2 KOH

A = Stearin

B = Potassium Hydroxide (KOH)

C = Glycerol B = 2481.9327 mol

D = Potassium Stearate

S5 = 3746.6533 mol S6 = 1264.7206 mol

A = 107.6853 A = 107.6277 mol

B = 2481.9327 C = 92.3246 mol

C = 92.1723 D = 1064.7683 mol

D = 1064.8630

Mole fraction of each component:

A = 0.02874

B = 0.6624

C = 0.0246

D = 0.2842

Assumptions: 100 % of KOH is separated from the mixture based on its boiling point.

Overall mass balance:

S5 = S6 + B

3746.6533 = S6 + 2481.9327

S6 = 1264.7206 mol

Balance of A3746.6533 (0.02874) = 1264.7206 (A) + 2481.9327 (0)A = 0.0851

Balance of B3746.6533 (0.6624) = 1264.7206 (0) + 2481.9327 (1)B = 0

Balance of C3746.6533 (0.0246) = 1264.7206 (C) + 2481.9327 (0)C = 0.0730

Balance of D3746.6533 (0.2842) = 1264.7206 (D) + 2481.9327 (0)D = 0.8419

Vessel 3 Potassium stearate

D = 1064.7683 mol

S7 = 1264.7206 mol S8 = 199.9523 mol

A = 0.0851 A = 107.6343 mol

C = 0.0730 C = 92.3180 mol

D = 0.8419

Overall mass balance:

Assumptions: 100 % of Potassium Stearate is separated from the mixture based on its boiling point

S7 = S8 + D

1264.7206 = S8 + 1264.7206(0.8419)

S8 = 199.9523 mol

Balance of A1264.7206 (0.0851) = 199.9523 (A) + 1064.7683(0)A = 0.5383

Balance of C1264.7206 (0.0730) = 199.9523 C) + 1064.7683 (0)C = 0.4617

Balance of D1264.7206 (0.2842) = 199.9523 (0) + 1064.7683(1)D = 0

Vessel 4 Stearin

A = 107.6343

S9 = 199.9523 mol S10 = 92.3180 mol

A = 0.5383 C = 1.0000

C = 0.4617

Assumptions: 100 % of Stearin is separated from the mixture based on its boiling point

S9 = S10 + A

199.9523 = S10 + 107.6343

S10 = 92.3180 mol

Balance of A199.9523 (0.5383) = 92.3180 (0) + 107.6343 (1)A = 0.000

Balance of C199.9523 (0. 4617) = 92.3180 C) + 107.6343 (0)C = 1.000