Psychrometric Charts Animated Guide and Examples · 2014-12-02 · Psychrometric Charts Animated...
Transcript of Psychrometric Charts Animated Guide and Examples · 2014-12-02 · Psychrometric Charts Animated...
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Psychrometric ChartsAnimated Guide and Examples
S. Kresta and I. AyranciUniversity of Alberta,
Ch i l d M i l E i iChemical and Materials EngineeringDecember 2012
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Psychrometric Charts for Humid Air Material and Energy Balances
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Psychrometric Charts• Humid air• Humid air• Useful for drying and humidification or
d h idifi i ( i di i i )dehumidification (air conditioning) problems
• Much faster than working through full material and energy balance calculations by hand
• Basis is 1 kg of bone dry airg y
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Navigating the Charts
• Open your text to Figure 8.4-1• Starting at the line “40°C” color the dryStarting at the line 40 C color the dry
bulb temperature red• Continue with the rest of the lines following• Continue with the rest of the lines following
the color legend in the next slide.
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Data at a pointGreen – enthalpy, wet bulb TRed – dry bulb temperatureRed dry bulb temperatureYellow – moisture content , dew point TPurple – relative humidityBlue – specific volumeB h l d i iBrown – enthalpy deviation
greengreen
purpleyellow
red
brown
Psychrometric Charts for Humid Air Material and Energy Balances
bluered
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Data at a pointGreen – enthalpy, wet bulb TRed – dry bulb temperatureRed dry bulb temperatureYellow – moisture content , dew point TPurple – relative humidityBlue – specific volume
h l d i iPathsGreen – adiabatic humidificationRed isothermal humidification/
Brown – enthalpy deviation
Red – isothermal humidification/dehumidification
Yellow – constant water content
Psychrometric Charts for Humid Air Material and Energy Balances
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1a) 23°C
32
Problem 1: Grain Dryer
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1a) 23°Cb) 0.018kg/kg DA
Problem 1: Grain Dryer
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1a) 23°Cb) 0.018kg/kg DAc) 60% RH
Problem 1: Grain Dryer
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1a) 23°Cb) 0.018kg/kg DAc) 60% RHd) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA))d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1)
d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1) (79 5 0 3))kJ/k DA
d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1) (79 5 0 3))kJ/k DA
1 1
1.1)1.1) -(79.5-0.3))kJ/kg DA1.1) -(79.5-0.3))kJ/kg DA=2000 kJ
-1.1
0 3-0.3
Problem 1: Grain Dryer
0.885m3/kg dry air
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1a) 23°Cb) 0.018kg/kg DAc) 60% RHd) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA))d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1)
d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1) (79 5 0 3))kJ/k DA
d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1) (79 5 0 3))kJ/k DA
0.0265
e)Mass of DA*change in absolute humidity=113 kg DA*
1.1)1.1) -(79.5-0.3))kJ/kg DA1.1) -(79.5-0.3))kJ/kg DA=2000 kJ
y g(0.0265-0.018) kg H2O/kg DA=0.96 kg water
Problem 1: Grain Dryer
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1a) 23°Cb) 0.018kg/kg DAc) 60% RHd) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA))d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1)
d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1) (79 5 0 3))kJ/k DA
d) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA)) * ((98-1 1) (79 5 0 3))kJ/k DA
e)Mass of DA*change in absolute humidity=113 kg DA*
1.1)1.1) -(79.5-0.3))kJ/kg DA1.1) -(79.5-0.3))kJ/kg DA=2000 kJ
y g(0.0265-0.018) kg H2O/kg DA=0.96 kg water
f) 29.5°C)
29.5
Problem 1: Grain Dryer
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2a) 0.018kg/kg DA, 0.019kg/kg DA, 0.019 kg/kg DA, 0.021 kg/kg DA b) 43% 100% 22% 28%b) 43%, 100%, 22%, 28%c) Total mass of water removed/(change in absolute humidity)=(50kg H2O/hr)/((0.021-0.019)kg H2O/kg DA) = 25000 kg DA/hr
3 3d) 25000 kg DA/hr*0.94m3/kg DA=23500 m3/hre) Dried material ΔΗ≅0Air ΔΗ=25000 kg DA/hr*((104-1.0)-(85-0.55))kJ/kg DA = 463 750 kJ/hr
Problem 2: Air cleaning for dryer
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1a) 23°Cb) 0.018kg/kg DAc) 60% RHd) Mass of DA*ΔΗ of DA=(100m3/(0.885 m3/kg DA))* ((98 1 1) (79 5 0 3))kJ/k DA((98-1.1)-(79.5-0.3))kJ/kg DA =2000 kJe) Mass of DA*change in absolute humidity=113 kg DA*humidity 113 kg DA(0.0265-0.018) kg H2O/kg DA=0.96 kg waterf) 29.5°C)
Problem 1: Grain Dryer