Prof. Matt Jarvis [email protected] Hilary Term 2015

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Waves & Normal Modes Prof. Matt Jarvis [email protected] Hilary Term 2015

Transcript of Prof. Matt Jarvis [email protected] Hilary Term 2015

Page 1: Prof. Matt Jarvis matt.jarvis@astro.ox.ac.uk Hilary Term 2015

Waves & Normal Modes

Prof. Matt Jarvis [email protected]

Hilary Term 2015

Page 2: Prof. Matt Jarvis matt.jarvis@astro.ox.ac.uk Hilary Term 2015

Spring-mass systems

Now consider a horizontal system in the form of masses on springs •  Again solve via decoupling and matrix

methods •  Obtain the energy within the system •  Find specific solutions

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Solutions of horizontal spring-mass system Equations of motion:

Solve by decoupling method (add 1 and 2 and subtract 2 from 1). As before, we can write down the normal coordinates, call them q1 and q2

which means…

Substituting gives:

(1)

(2)

Gives normal frequencies of:

Centre of Mass Relative

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Total Energy:

Energy of horizontal spring-mass system Kinetic Energy Potential Energy

Sum of energies in each normal mode

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Specific Solutions for horizontal spring-mass system

General solution is the sum of the two normal modes

Initial conditions:

These give:

Both normal modes excited. The `beats’ solution. Completely analogous to the coupled pendulum

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Decoupling method only works for limited cases with a sufficient amount of symmetry. You cannot solve this with decoupling, so have to go to matrix method and have a guess!

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Coupled Oscillators with a driving force

•  So the last physical system we are going to look at in this first part of the course is the forced coupled pendula, along with a damping factor 1. Finding the Complementary Function 2. Finding the particular integral

•  Then do the same for a horizontal spring-

mass system

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There is no physical difference between +/- variants. Just use + from now on.

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