Primality Testing By Ho, Ching Hei Cheung, Wai Kwok.
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Transcript of Primality Testing By Ho, Ching Hei Cheung, Wai Kwok.
Primality Testing
ByHo, Ching Hei
Cheung, Wai Kwok
Introduction
The primality test provides the probability of whether or not a large number is prime.
Several theorems including Fermat’s theorem provide idea of primality test.
Cryptography schemes such as RSA algorithm heavily based on primality test.
Definitions
A Prime number is an integer that has no integer factors other than 1 and itself. On the other hand, it is called composite number.
A primality testing is a test to determine whether or not a given number is prime, as opposed to actually decomposing the number into its constituent prime factors (which is known as prime factorization) Use multiple points if necessary.
Algorithms
A Naïve Algorithm Pick any integer P that is greater than 2. Try to divide P by all odd integers starting from 3
to square root of P. If P is divisible by any one of these odd integers,
we can conclude that P is composite. The worst case is that we have to go through all
odd number testing cases up to square root of P. Time complexity is O(square root of N)
Algorithms (Cont.) Fermat’s Theorem
Given that P is an integer that we would like to test that it is either a PRIME or not.
And A is another integer that is greater than zero and less than P. From Fermat’s Theorem, if P is a PRIME, it will satisfy this two
equalities: A^(p-1) = 1(mod P) or A^(p-1)mod P = 1 A^P = A(mod P) or A^P mod P = A
For instances, if P = 341, will P be PRIME?
-> from previous equalities, we would be able to obtain that:
2^(341-1)mod 341 = 1, if A = 2
Algorithms (Cont.)
It seems that 341 is a prime number under Fermat’s Theorem. However, if A is now equal to 3:
3^(341-1)mod 341 = 56 !!!!!!!!! That means Fermat’s Theorem is not
true in this case! Time complexity is O(log n)
Algorithms (Cont.) Rabin-Miller’s Probabilistic Primality Algorithm
The Rabin-Miller’s Probabilistic Primality test was by Rabin, based on Miller’s idea. This algorithm provides a fast method of determining of primality of a number with a controllably small probability of error.
Given (b, n), where n is the number to be tested for primality, and b is randomly chosen in [1, n-1]. Let n-1 = (2^q)*m, where m is an odd integer. B^m = 1(mod n) i[0, q-1] such that b^(m2)^i = -1(mod n)
Algorithm (Cont.) If the testing number satisfies either cases, it
will be said as “inconclusive”. That means it could be a prime number.
From Fermat’s Theorem, it concludes 341 is a prime but it is 11 * 31!
Now try to use Rabin-Miller’s Algorithm. Let n be 341, b be 2. then assume: q = 2 and m = 85 (since, n -1 = 2^q*m) 2^85 mod 341 = 32 Since it is not equal to 1, 341 is composite! Time complexity is O(log N)
RSA Algorithm
The scheme was developed by Rivest, Shamir, and Adleman.
The scheme was used to encrypt plaintext into blocks in order to prevent third party to gain access to private message.
RSA in action:
1. Pick two large prime numbers namely p and q and compute their product and set it as n.
n = p*q
RSA in action (cont.):
2. Set public key to send the message. public key (e, n)
such that: gcd((n), e) = 1; [1<e< (n)]
sender uses public key to encrypt the message before sending it to the
recipient.
RSA in action (cont.):
3. Retrieve message using private key.
at the recipient’s side, private key(d, n), such that ed = 1mod (n), need to be obtained in order to get the original message through decryption.
Demonstration for RSA: Pick 2 primes: p=7, q=17
n = p*qn = 119
Compute: (n) = (119)
= (7*17) = (7) * (17) = 6 * 16 = 96
Find e such that gcd((n), e) = 1; [1<e< (n)]gcd(e, 96) = 1
e = 5 public key(e, n) Find d such that ed = 1mod (n)
5d = 1mod965d = 96 * k +1, where k is some constant5d = 96 * 4 + 1, assume k = 45d = 385d = 77 private key(d, n)
Demonstration for Encryption:! Base on RSA and the result we got ! Encryption . . . (message = 19)
C = M^e mod n = 19^5 mod 119 = 2476099 mod 119 = 66 <the original message will be encrypted with the value of 66>
Demonstration for Decryption
! Base on RSA and the result we got ! Decryption . . .
M = C^d mod nM = 66^77 mod 119M = 1.27 * 10^140 mod 119M = 19 <the original will now be recovered>
Reference:
An Online Calculator by Ulf Wostner from CCSF http://wiz.ccsf.edu/~uwostner/calculator/number_theory.php
Definition of Rabin-Miller’s Probabilistic Primality Testing http://www.ma.iup.edu/MAA/proceedings/vol1/higgins.pdf
Definition of Primality Testing http://mathworld.wolfram.com/AKSPrimalityTest.html
Primality Test for Applications
http://www-math.mit.edu/phase2/UJM/vol1/DORSEY-F.PDF