Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March...

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 1 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3 07 - Transformers

Transcript of Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March...

Page 1: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 1 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

07 - Transformers

Page 2: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 2 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

The intent of this presentation is to present enough information to provide the reader with a fundamental knowledge of transformers used within Michelin and to better understand basic

system and equipment operations.

Page 3: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 3 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Ideal Transformer Characteristics

The basic transformer consists of two coils electrically insulated from each other and wound upon a common core. Magnetic coupling is used to transfer electric energy from one coil to another. The coil, which receives energy from the AC source, is called the primary. The coil, which delivers energy to the AC load, is called the secondary. The core of transformers used at low frequencies is generally made of magnetic material, usually sheet steel. Cores of transformers used at higher frequencies are made of powdered iron and ceramics, or nonmagnetic materials. Some coils are simply wound on nonmagnetic hollow forms such as cardboard or plastic so that the core material is actually air.

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R L

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 4 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

If a transformer is assumed to be operating under an ideal or perfect condition, the transfer of energy from one voltage to another is accompanied by no losses.

 

Voltage Relationship

The voltage (V) on the coils of a transformer is directly proportional to the number (N) of turns on the coils. This voltage relationship is expressed by the formula:

Where: Vpri = voltage on primary coil, V

Vsec = voltage on secondary coil, V

Npri = number of turns on primary coil

Nsec = number of turns on secondary coil

Vpri / Vsec = Npri / Nsec

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R L

Page 5: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 5 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Step-up and Step-down transformers

A voltage ratio of 1:4 (read as 1 to 4) means that for each volt on the transformer primary, there is 4 volts on the secondary. When the secondary voltage is greater than the primary voltage, the transformer is a step-up transformer. A voltage ratio of 4:1 means that for every 4 volts on the primary, there is only 1 volt on the secondary. When the secondary voltage is less than the primary voltage, the transformer is called a step-down transformer. The voltage relationship discussed previously will apply to both step-up and step-down transformers.

 

 

Current Relationship

The current (I) in the coils of a transformer is inversely proportional to the voltage (V) on the coils. This current relationship is expressed by the formula:

Where: Vpri = voltage on primary coil, V

Vsec = voltage on secondary coil, V

Ipri = current in the primary coil, A

Isec = current in the secondary coil, A

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pri

pri

V

V = I

Isec

sec

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 6 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Efficiency

The efficiency of a transformer is equal to the ratio of the power output of the secondary winding to power input of the primary winding. An ideal transformer is 100% efficient because it delivers all the energy it receives. Because of core and copper losses, the efficiency of even the best practical transformer is less than 100%. Efficiency expressed as an equation is:

Where: Eff = efficiency

Psec = power output from the secondary coil, W

Ppri = power input to the primary coil, W

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Eff = output power

input power = P

P pri

sec

Page 7: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 7 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Transformer Power Ratings

Transformer capacity is rated in kilo-volt-amperes (KVA). This transformer rating is sometimes represented by the letter S. Since power in an AC circuit depends on the power factor of the load and the current in the load, an output rating in kilowatts must specify the power factor.

 

For an ideal transformer we would assume efficiency to be 100%. Since our calculations will deal with ideal transformers, we can state the following relationships:

Where: VApri = power input to the primary coil, VA

VAsec = power output from the secondary coil, VA

Vpri = primary voltage

Ipri = primary current

Vsec = secondary voltage

Isec = secondary current

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pri pri pri

pri

VA = V I

VA = V I

VA = VA

sec sec sec

sec

Page 8: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 8 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Dual Voltage Primary Wiring Diagram

Low Voltage Connection

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H1 H3 H2 H4

240v 240v

240v

X260vX1 60v

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 9 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

High Voltage Connection

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H1 H3 H2 H4

240v 240v

480v

X260vX1 60v

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 10 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Single Phase Transformer Calculations

Given: Npri = 1500 turns

Nsec = 1000 turns

Vpri = 100 V

 

Find: Vsec =

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NsecNpri

Vpri Vsec

I pri I sec

Solution: Npri / Nsec = Vpri / Vsec1500 / 1000 = 100 / xX = 66.67 Volts

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 11 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Single Phase Transformer Calculations

Given: Npri = 4000 turns

Nsec = 400 turns

Isec = 6 A

Find: Ipri =

What is the turn’s ratio?

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NsecNpri

Vpri Vsec

I pri I sec

Solution: Npri / Nsec = turns ratio4000 / 40 = 10

Np / Ns = Is / Ip4000 / 400 = 6 / xx = 0.6 A

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 12 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformer Calculations

Given: Vpri = 300 V

Vsec = 24 V

Isec = 1 A

Npri = 1000 turns

 

Find: Nsec = Ipri =

Solution: Nsec = 80; Ipri = 0.08 A

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NsecNpri

Vpri Vsec

I pri I sec

Given: VApri = 100Vpri = 460 VVsec = 110 V

 Find: Ipri =

Isec =

Solution: Ipri = 0.217 A; Isec = 0.909 A

Page 13: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 13 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Single Phase Transformer Calculations

Given: Npri = 1000 turns

Nsec= 500 turns

Vpri = 200 volts

Find: Vsec

Solution: Vsec = 100 V

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Given: Npri = 5000 turnsNsec= 500 turnsIsec = 5 amps

 Find: Ipri

 Solution: Ipri = 0.5 A

R LV SecV Pri

ISecIPri

N Pri N Sec

Page 14: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 14 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Single Phase Transformer Calculations

Given: Npri = 1000 turns

Vpri = 200 volts

Vsec= 24 volts

Isec = 2 amps

Find: Nsec

Ipri

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Given: Vsec = 110 voltsSsec =1100 VANsec = 55 turnsVpri = 200 volts

Find: Isec; Ipri; Npri; Spri

Ratio of the transformer

R LV SecV Pri

ISecIPri

N Pri N Sec

Page 15: Presentation : IMS – Tech Managers ConferenceAuthor : IMS StaffCreation date : 08 March 2012Classification : D3Conservation :Page : ‹#› 07 - TransformersAuthor.

Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 15 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Single Phase Transformers

Single Phase Transformer Calculations

Given: Vpri = 200 volts

Ipri = 5 amps

Npri= 1000 turns

Nsec = 200 turns

 Find: Vsec

Isec

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R LV SecV Pri

ISecIPri

N Pri N Sec

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 16 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Transformer Nameplate Data

Introduction

The data found on a typical transformer nameplate is shown below. Note that the transformer capacity is rated in KVA and not KW. The load connected to the secondary windings will determine the power factor, and thus, the apparent power for the output circuit of the transformer. Further, the KVA rating represents the full load output of the transformer and not the input. The other data on the nameplate usually includes the voltage rating of the high and low voltage windings, the frequency, number of phases, percent impedance, polarity, maximum temperature rise and the gallons of transformer oil required, if oil filled.

 

Control Transformer

Below is an example of a control transformer utilizing a dual voltage primary windings and a single voltage secondary winding. The primary voltage should be either 240 volts or 480 volts. The primary windings must be connected in parallel for 240 volts and connected in series for 480 volts. The secondary should always produce 24 volts.

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 17 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Transformer Nameplate Data

The power rating is 0.1 kVA or 100VA.

Below is an example of a control transformer utilizing a multi-tap primary winding and a single voltage secondary winding. The primary voltage could be a variety of voltages ranging from 208 volts up to 480 volts. The primary windings must be connected according to the correct voltage applied to the primary winding. The secondary should always produce 24 volts.

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 18 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Troubleshooting Single Phase Transformers

The transformer below is a single phase control transformer connected for high voltage on the primary (480volts) and 120 volts on the secondary. To troubleshoot the transformer with an ohm-meter you should check the ohmic value for the primary and then the ohmic value for the secondary. You must make sure that the wires connecting the primary and secondary windings are not connected to any other device that would cause a reading through them. The ohmic valve will depend on the size of the transformer. The reading will usually be a low ohmic value which should show continuity through the windings.

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480v/120v

H1 H3 H2 H4

X1 X2

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Presentation : IMS – Tech Managers Conference Author : IMS Staff Creation date : 08 March 2012 Classification : D3 Conservation : Page : 19 07 - Transformers Author : IMS Stafff Creation date : 01 Nov 2012 Classification : D3

Troubleshooting Single Phase Transformers

The transformer below is a single phase power transformer connected for high voltage on the primary (480volts) and 240 volts on the secondary. To troubleshoot the transformer with an ohm-meter you should check the ohmic value for the primary and then the ohmic value for the secondary. You must make sure that the wires connecting the primary and secondary windings are not connected to any other device that would cause a reading through them. The ohmic value will depend on the size of the transformer. The reading will usually be a low ohmic value which should show continuity through the windings.

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X1X2

H1 H2

480v/240v