How genes effects Physical Performance ?. Phenotypes and Genotypes Giro vite.
Predicting Genotypes and Phenotypes. Punnett Squares -used to predict genotypes and phenotypes of...
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Transcript of Predicting Genotypes and Phenotypes. Punnett Squares -used to predict genotypes and phenotypes of...
Predicting Genotypes and Phenotypes
Punnett Squares-used to predict genotypes and phenotypes of
offspring based on the parents genotype
Punnett SquaresMonohybrid crosses- 1 heterozygous trait is crossed
(Bb X Bb)
Dihybrid crosses- 2 heterozygous traits are crossed
(BbSs X BbSs)
Punnett Squares (parent generation)Eye Color mom BB
B B
b
dad
bb
b
Offspring 1 Offspring 2
Offspring 3 Offspring 4
Bb
Bb Bb
Bb
Genotypic Ratio Phenotypic Ratio
Punnett Squares (F1)Eye Color mom Bb
B b
B
dad
Bb
b
Offspring 1 Offspring 2
Offspring 3 Offspring 4
BB
bb Bb
Bb
Genotypic Ratio? Phenotypic Ratio?
Punnett SquaresEye Color and Height mom BbSs
BS Bs bS bs
BS
Dad
BbSs Bs
bS
bs
BBSS BBSs BbSS BbSs
BBSs BBss BbSs Bbss
bbSsbbSSBbSs
BbSs
BbSS
Bbss bbSs bbss
Genotypic Ratio? Phenotypic Ratio?
Laws of Probability • Used to predict genotype or phenotype• -Multiplication rule-to determine the probability of
different events happening in combination, multiply the probability of each event.
• -Addition rule-to determine the probability of the same events happening add the probability of even event.
• See examples
Forkline Method
• this is just another way to be able to predict genotype and phenotype ratios in dihybrid problems
• this way you don’t have to write the box
• but it does require you to know the basic ratios that arise from monohybrids
• based on the idea that: in a dihybrid, the two traits sort INDEPENDENTLY of one another
• i.e. what happens with one trait is completely unrelated to what happens with the other trait
PpYy x PpYy
for example, the following dihybrid cross:
normally to solve this we would1. use FOIL for the gametes, then 2. assemble the Punnet square, then 3. count up the genotypic and phenotypic ratios.However, we can make use of two simple concepts:1. the traits (flower color and seed color) sort out
independently of each other2. there are essentially only three different ratios that can
result in a monohybrid cross (it doesn’t matter what the traits are; I’ve used P here, but it could be anything):
heterozyg x heterozyg: Pp x Pp: ¼ PP ½ Pp ¼ pp
heterozyg x homozyg: Pp x PP -----------> ½ Pp ½ PPor Pp x pp ---------------------------------------------> ½ Pp ½ PP
homozyg x homozyg: PP x PP -----------> 100% PPor pp x pp -–-----------------------------------------> 100% pp
1
3
2
PpYy x PpYyso to solve this dihybrid, separate the two traits (since they sort independently):
Pp x Pp will give:
¼ pp
½ Pp
¼ PP
PpYy x PpYy
so to solve this dihybrid, separate the two traits (since they sort independently):
Pp x Pp will give:
¼ pp
½ Pp
¼ PP
similarly, Yy x Yy will give:
¼ yy½ Yy¼ YY
PpYy x PpYy
so to solve this dihybrid, separate the two traits (since they sort independently):
Pp x Pp will give:
¼ pp
½ Pp
¼ PP¼ yy½ Yy¼ YY
multiply fractions1/16 PPYY1/8 PPYY1/16 PPYY
Yy x Yy will give:
¼ yy½ Yy¼ YY
PpYy x PpYy
so to solve this dihybrid, separate the two traits (since they sort independently):
Pp x Pp will give:
¼ pp
½ Pp
¼ PP¼ yy½ Yy¼ YY
multiply fractions1/16 PPYY1/8 PPYy1/16 PPyy
¼ yy½ Yy¼ YY 1/8 PpYY
1/4 PpYy1/8 Ppyy
¼ yy½ Yy¼ YY 1/16 ppYY
1/8 ppYy1/16 ppyy
PpYy x PpYy
so to solve this dihybrid, separate the two traits (since they sort independently):
Pp x Pp will give:
¼ pp
½ Pp
¼ PP¼ yy½ Yy¼ YY
multiply fractions1/16 PPYY1/8 PPYy1/16 PPyy
¼ yy½ Yy¼ YY 1/8 PpYY
1/4 PpYy1/8 Ppyy
¼ yy½ Yy¼ YY 1/16 ppYY
1/8 ppYy1/16 ppyy
121242121
convert all to 16ths for consistency