Practice Final a Solutions
-
Upload
alkaustariyah-lubis -
Category
Documents
-
view
228 -
download
0
description
Transcript of Practice Final a Solutions
-
You should allow yourself exactly three hoursto take this exam.
Last Name:
First Name:
Section TF:
Important Notes:
1. This exam consists of 16 problems on 16 pages, plus this cover sheet, and two pages for scratch workat the end of the exam.
2. All answers must be written in the spaces provided. Do not write anything in red ink. Answerswritten on the back of a page will not be graded. Anything written on the scratch page will not be graded.
3. You are allowed to use a set of molecular models for this exam.
SOLUTIONS
-
1 Name:1. Each of the following transformations can be carried out in three or fewer steps. Fill in the reagentsrequired for each step. If a step is not needed, please put an "X" next to that number. Be sure to consider thestereochemistry (if relevant)!
a)
b)
c)
d)
2.
3.
1.
2.
3.
1.
2.
3.
1.
2.
3.
1.
Br
OO
Cl
OMe
(+/-)
CN
(+/-)
Mg0, Et2Oor
Li (2 equiv.)NaSH
H2O
X
Raney Ni
X
MgBr
H+ workup
CrO3
MeOH,
X
X
NBS, CCl4
NaCN
X
also: 1. KOtBu, tBuOH2. H2, Pd/C
-
2 Name:1. Each of the following transformations can be carried out in three or fewer steps. Fill in the reagentsrequired for each step. If a step is not needed, please put an "X" next to that number. Be sure to consider thestereochemistry (if relevant)!
a)
b)
c)
d)
2.
3.
1.
2.
3.
1.
2.
3.
1.
2.
3.
1.
CH3 CH3
(+/-)
Br
Br
O
O
O
O
OO
OHO
HO
O
(+/-)
Na0, NH3
CH2I2, Zn/Cu
X
Br2
X
HBr
KOtBu,tBuOH
Br2
H3O+conc.H2SO4
conc.H2SO4
Br2
O,
OsO4
NaHSO4, H2O
NBS, CCl4
KOtBu, tBuOH
mCPBA
-
3 Name:3. Fill in each box with the major organic product of the indicated transformation. Be sure to give thestereochemistry of each if it is relevant (e.g., whether it is racemic / single enantiomer)! Any chiral startingmaterials are pure, single enantiomers unless otherwise specified.
a)
b)
c)
d)
OH1. SOCl2, pyridine
2. KI
OTs
KOtBu
tBuOH
D2O
cat. D2SO450 C
D2O
cat. D2SO478 C
I
DOD
D
OD
(+/-)
-
4 Name:4. Fill in each box with the starting material of the indicated transformation. Be sure to give thestereochemistry of each if it is relevant (e.g., whether it is racemic / single enantiomer)! Any chiral productsare pure, single enantiomers unless otherwise specified.
a)
b)
c)
d)
1. BH3, THF
2. NaOH, H2O2
1. NaNH2, NH3
2.3. Na0, NH3
Br
(1 equiv.)
conc. H2SO4 O
O
O
CH3
H OH
CH2CH3
HH3C
H3C
O
O
HOOH
or
HO
-
5 Name:
5. Consider the alkene below.
a. Provide the best possible systematic name for this alkene in the box below. You may ignore R/Sdesignations.
c. Assign R/S configurations or hybridizations, as appropriate, to each of the atoms circled in the moleculebelow.
N
O
H3C
H
O
O
Ph
OH
b. In the box below, provide the best possible systematic name of a compound that would be adiastereomer of the alkene shown above. You may ignore R/S designations.
(circle one)R S
(circle one)R S
(circle one)
sp sp2 sp3
(circle one)
sp sp2 sp3
(E)-4-isopropyl-5,6,6-trimethyl-3-heptene
(Z)-4-isopropyl-5,6,6-trimethyl-3-heptene
-
6 Name:6. Carefully consider the structures of each of the compounds depicted below.
(a) Draw this compound in its most stable conformation.
OH
(b) Draw this compound in its most stable conformation.
H
H
H H
(c) Draw this compound using a clear 3-D representation.
O O
O
O
OH
H
OCH3
CH3
O
O
O
-
7 Name:
7. Consider the following synthetic transformation:
Two E-2a students proposed different synthetic routes to the indicated product:
b. Briefly explain why only that synthetic route worked. Your explanation must include both chairconformation drawings and "cartoon" orbital sketches for full credit. You do not need to draw any curved-arrow mechanisms.
HOH
H H
H
Barney suggested: 1. TsCl, pyridine; 2. KOtBu, tBuOH
Phil suggested: 1. SOCl2, pyridine; 2. KOtBu, tBuOH
a. Only one of these proposals gave the desired product. Which student was successful?
(circle one)
Barney Phil
Barney: TsCl gives a leaving group with retention of stereochemistry, which allows the idealorbital overlap for an E2 elimination.
OTsH
H
H
H
OTs
H
OTs*CO
CH
Phil: SOCl2, pyridine gives a leaving group with inversion of stereochemistry, and thus it cannotpossess any antiperiplanar orbital overlap!
ClH
H
H
H
Cl No periplanar orbitals!
-
8 Name:
8a. Provide a complete curved-arrow mechanism for the following transformation.
b. For the molecules shown below, draw a "cartoon" orbital sketch of the indicated frontier molecularorbitals (HOMO and LUMO) in the boxes provided.
O
ONO2O2N
NO2
NO2
LUMO LUMO
HOMO HOMO
For adiene: For a
dienophile:
+ CO2
O
O
NO2
NO2
O NO2
NO2
O
-
9 Name:
9. In the presence of a secondary amine, the reagent N-iodosuccinimide (NIS), is observed to react withalkenes as shown below:
a. Provide a complete curved-arrow mechanism for this transformation and, for every step, identify all thefrontier molecular orbital (donor/acceptor) interactions involved. Note that you only need to name theorbitals; you do not need to draw either energy-level diagrams or "cartoon" orbital sketches. Keep in mindthat this reaction is observed to be both stereospecific (giving only anti addition) and regiospecific (givingonly the product with the iodine on the secondary carbon); the mechanism you propose must be consistentwith these observations.
b. Based on your answer above, provide a complete curved-arrow mechanism for the followingtransformation. You need not identify the frontier molecular orbital interactions for this part.
+ NI
O
O
HN(CH3)2
I
N(CH3)2+ N H
O
ON-iodosuccinimide
(NIS)
(as a racemic mixture)
HO
H
NI
O
O
N H
O
OO
I+ +
NI
O
O
I
(+/-)
HN(CH3)2
I
N(CH3)2
(+/-)
H
Products
:N
O
O
Donor1: CCAcceptor1: *NIDonor2: nIAcceptor2: *CC
Donor: nNAcceptor: *CI
Donor: nN-Acceptor: *NH
HO
IO
I
H
:N
O
O
-
10 Name:
10. The following transformation should look at least somewhat familiar to you.
a. Provide a complete curved-arrow mechanism for this transformation. You may invoke solvent ("Sol:") fordeprotonations where necessary.
b. Draw the product of the following analogous reaction in the box below in its most stable conformation.You do not need to draw a curved-arrow mechanism.
Hg(OAc)2, H2SO4
HOOH
O
O
CH3
H3CHO OH
Hg(OAc)2, H2SO4
Hg
OAc
OAc
Hg
OAc
HOOH
HOO
H
PhH
HgOAc
:sol
HOO
PhH
HgOAc
H+HOO
PhH
HgOAcPh
O
HO
H+
O
PhOHO
O
CH3 H :solO
O
CH3
OO
-
11. You have just synthesized a new compound, and the following spectroscopic data is obtained: From the mass spectrum, you deduce that the molecular formula is: C15H24
The proton NMR spectrum (with expansions) is:
The infrared spectrum is:
Draw your best choice for the structure of this molecule in the box below.
From the infrared spectrum, circle the functionalgroups that are definitely present:
From the infrared spectrum, circle the functionalgroups that are definitely absent:
O H C O C C C N/C O C C
11 Name:
C CC N/C C/N H O H/N H
ppm
0540060080001002100410061008100020022004200620082000300230043006300830004WAVENUMBERS
0
10
20
30
40
50
60
70
80
90
100
%TRANSMITTANCE
12 11 10 9 8 7 6 5 4 3 2 1 0
1H
1H
6H
2.86 1.25
-
12. You have just synthesized a new compound, and the following spectroscopic data is obtained: From the mass spectrum, you deduce that the molecular formula is: C6H11NO2
The proton NMR spectrum (with expansions) is:
The infrared spectrum is:
Draw your best choice for the structure of this molecule in the box below.
From the infrared spectrum, circle the functionalgroups that are definitely present:
From the infrared spectrum, circle the functionalgroups that are definitely absent:
O H C O C C C N/C O C C
12 Name:
C CHC N/C C/N H O H/N H
ppm
0540060080001002100410061008100020022004200620082000300230043006300830004WAVENUMBERS
0
10
20
30
40
50
60
70
80
90
100
%TRANSMITTANCE
12 11 10 9 8 7 6 5 4 3 2 1 0
1H 2H2H
6H
4.45 2.41 1.94
OCH3
H3CO CN
-
13. You have just synthesized a new compound, and the following spectroscopic data is obtained: From the mass spectrum, you deduce that the molecular formula is: C4H6O2
The proton NMR spectrum (with expansions) is:
The infrared spectrum is:
Draw your best choice for the structure of this molecule in the box below.
From the infrared spectrum, circle the functionalgroups that are definitely present:
From the infrared spectrum, circle the functionalgroups that are definitely absent:
O H C O C C C N/C O C C
13 Name:
C CHC N/C C/N H O H/N H
ppm12 11 10 9 8 7 6 5 4 3 2 1 0
1H
1H
1H
4.2 2.5 2.3
0540060080001002100410061008100020022004200620082000300230043006300830004WAVENUMBERS
0
10
20
30
40
50
60
70
80
90
100
%TRANSMITTANCE
O
O
-
14
Starting Materials:
Name:
14. Provide a complete synthesis of the following desired product from the indicated starting material,cyclopropanol, plus any alkynes with four or fewer carbons. You may use any inorganic reagents you wish.The correct answer will require six or fewer total steps.
Desired Product
OH
cyclopropanol
O
Cl
(as a racemic mixture)
plus any hydrocarbonswith four or fewer carbons
HC CHH2
Lindlar cat.H2C CH2
HBrBr
Compound A
1. NaNH2, NH3
2. Cmpd. A
H2
Lindlar cat.
OH
Cl2,
-
15
Starting Material:
Name:
15. Provide a complete synthesis of the following desired product from the indicated starting material, plusany inorganic and organic reagents you wish, but all carbons from the starting material must end up in theproduct. You may ignore stereochemistry. The best answer will require five or fewer total steps.
Desired Product
OEt
EtO
1. O3
2. Me2S
CHO
CHO
NaBH4
MeOH
OH
OH
1. NaH (xs or 2 equiv.)2. EtBr (xs or 2 equiv.)
PBr3 (or otherleaving groups
are OK)
Br
Br
NaOEt,EtOH
-
16
Starting Material:
Name:
16. Provide a complete synthesis of the following desired product from the indicated starting material,fumaric acid. You may use any organic or inorganic reagents you wish. The correct answer will require threeor fewer total steps.
Desired Product
(as a racemic mixture)
HOOH
O
Ofumaric acid
OHHO
O
OOHO
OHO
CO2H
CO2H
(+/-)
1. O32. H2O2
PFA-00-Ans.pdfPFA-01-AnsPFA-02-AnsPFA-03-AnsPFA-04-AnsPFA-05-AnsPFA-06-AnsPFA-07-AnsPFA-08-AnsPFA-09-AnsPFA-10-AnsPFA-11-AnsPFA-12-AnsPFA-13-AnsPFA-14-AnsPFA-15-AnsPFA-16-Ans