PowerPoint Presentation · Title: PowerPoint Presentation Author: Alice Breazeale Created Date:...

Pre-ClassDirections:

1) Login to the Edulastics

app.

2) Choose

3) This is open notes and you

have 10 minutes!!!

Let’s Review!

7.NS.1D

Pre-ClassDirections:

1) Login to the Edulastics

app.

2) Choose

3) This is open notes and you

have 10 minutes!!!

Let’s Review!

7.NS.1C

You have reached mastery when you know…1. Subtracting a positive number is the same as

adding a negative number.

Example: 1 – 2 = 1 + (-2)

2. The distance between two rational numbers on a

number line is the absolute value of their

difference. Example: The distance between -2 and

3 is the same as −2 − 3 or 3 − (−2) .

Let’s learn a

new skill!

Essential Question: How can mathematicians use

variables to represent and solve real-world problems?

Focus Question: How can I construct and solve

equations to solve mathematical problems?

By the end of the lesson, you will be able to say…

• I can construct and solve equations.

Teacher Input

Steps to Constructing Equations

1. Read the problem carefully and figure out

what it is asking you to find.

2. Assign a variable to the quantity you are

trying to find.

3. Write down what the variable represents.

4. Re-read the problem and write an equation

for the quantities given in the problem.

5. Solve the equation.

6. Answer the question in the problem.

7. Check your solution.

Steps to Solving Equations

Distribute

Combine like terms

Add/Subtract

Multiply/Divide

Don’t Confuse Aunt Sally My Dear

D

C

AS

MD

1) The length of Ms. Ford’s kitchen


2) l


2) l

3) l = length of the kitchen


2) l


4) 2(12.25) + 2l + 5 = 62.5

2(12.25) + 2l + 5 = 62.5

2(12.25) + 2l + 5 = 62.5

24.5

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

29.5

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

29.5 + 2l = 62.5

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

29.5 + 2l = 62.5-29.5 -29.5

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

29.5 + 2l = 62.5-29.5 -29.5

2l = 33

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

29.5 + 2l = 62.5-29.5 -29.5

2l = 332 2

2(12.25) + 2l + 5 = 62.5

24.5 + 2l + 5 = 62.5

29.5 + 2l = 62.5-29.5 -29.5

2l = 332 2

l = 16.5 feet


2) l


4) 2(12.25) + 2l + 5 = 62.5

5) l = 16.5 feet


2) l


4) 2(12.25) + 2l + 5 = 62.5

5) l = 16.5 feet


in 16.5 feet.


2) l


4) 2(12.25) + 2l + 5 = 62.5

5) l = 16.5 feet


in 16.5 feet.

7) 2(12.25) + 2(16.5) + 5 = 62.5

1) The number of months Chelsey

can be a member at a fitness club.



2) m



2) m

3) m = months Chelsey can be a

member at the fitness club.



2) m



4) 55 + 19.5m = 250

55 + 19.5m = 250

55 + 19.5m = 250-55 -55

55 + 19.5m = 250

19.5m = 195

-55 -55

55 + 19.5m = 250

19.5m = 195

-55 -55

19.5 19.5

55 + 19.5m = 250

19.5m = 195

-55 -55

m = 10

19.5 19.5



2) m



4) 55 + 19.5m = 250

5) m = 10



2) m



4) 55 + 19.5m = 250

5) m = 10

6) She can be a member for 10

months.



2) m



4) 55 + 19.5m = 250

5) m = 10


months.

7) 55 + 19.5(10) = 250

1) The equations that can

represent Gopal’s number.



2) x



2) x

3) x = Gopal’s number



2) x


4)𝟑

𝟒(x + 8) = -12

𝟑

𝟒(x + 8) = -12

𝟑

𝟒(x + 8) = -12

𝟑

𝟒(𝒙

𝟏+

𝟖

𝟏) = -12

𝟑

𝟒(x + 8) = -12

𝟑

𝟒x +

𝟐𝟒

𝟒= -12

𝟑

𝟒x + 6 = -12



2) x


4)𝟑

𝟒(x + 8) = -12

𝟑

𝟒x + 6 = -12

𝟑

𝟒(x + 8) = -12

𝟑

𝟒x +

𝟐𝟒

𝟒= -12

𝟑

𝟒x + 6 = -12

𝟑

𝟒(x + 8) = -12

𝟑

𝟒x +

𝟐𝟒

𝟒= -12

𝟑

𝟒x + 6 = -12

-6 -6

𝟑

𝟒(x + 8) = -12

𝟑

𝟒x +

𝟐𝟒

𝟒= -12

𝟑

𝟒x + 6 = -12

-6 -6

𝟑

𝟒x = -18

𝟑

𝟒(x + 8) = -12

𝟑

𝟒x +

𝟐𝟒

𝟒= -12

𝟑

𝟒x + 6 = -12

-6 -6

𝟑

𝟒x = -18

𝟒

𝟑• •

𝟒

𝟑

𝟑

𝟒(x + 8) = -12

𝟑

𝟒x +

𝟐𝟒

𝟒= -12

𝟑

𝟒x + 6 = -12

-6 -6

𝟑

𝟒x = -18

𝟒

𝟑• •

𝟒

𝟑

x =−𝟕𝟐

𝟑

x = - 24



2) x


4)𝟑

𝟒(x + 8) = -12

𝟑

𝟒x + 6 = -12

5) x = -24



2) x


4)𝟑

𝟒(x + 8) = -12

𝟑

𝟒x + 6 = -12

5) x = -24

6) Gopal’s number is -24.



2) x


4)𝟑

𝟒(x + 8) = -12

𝟑

𝟒x + 6 = -12

5) x = -24

6) Gopal’s number is -24.

7) 𝟑

𝟒(-24) + 6 = -12

1) amount Kyle earns each week

2) k

3) k = amount Kyle earns each week

4) 45.50 + 0.15(10k) = 90.50

5) m = 10


months.

7) 55 + 19.5(10) = 250

45.50 + 0.15(10k) = 90.50

45.50 + 0.15(10k) = 90.50

1.5k

45.50 + 0.15(10k) = 90.50

45.50 + 1.5k = 90.50

45.50 + 0.15(10k) = 90.50

45.50 + 1.5k = 90.50

-45.50 -45.50

45.50 + 0.15(10k) = 90.50

45.50 + 1.5k = 90.50

-45.50 -45.50

1.5k = 45

45.50 + 0.15(10k) = 90.50

45.50 + 1.5k = 90.50

-45.50 -45.50

1.5k = 45

1.5 1.5

45.50 + 0.15(10k) = 90.50

45.50 + 1.5k = 90.50

-45.50 -45.50

1.5k = 45

1.5 1.5

k = 30


2) k


4) 45.50 + 0.15(10k) = 90.50

5) m = 30


2) k


4) 45.50 + 0.15(10k) = 90.50

5) m = 30

6) Kyle earns $30 a week.


2) k


4) 45.50 + 0.15(10k) = 90.50

5) m = 30

6) Kyle earns $30 a week.

7) 45.50 + 0.15(10 •30) = 90.50

30 • 0.15 = 4.50

1) how much April saved


2) s


2) s and x

3) x = money April saved and

s = sale price


2) s and x


s = sale price

4) 250 – 20% – 10% = s

250 – s = x


2) s and x


s = sale price

4) 250 – 20% – 10% = s

250 – s = x

5) x = 70


2) s and x

3) x = money April saved

and s = sale price

4) 250 – 20% – 10% = s

250 – s = x

5) x = 70

6) April will pay $69 less

than the original price.

Exit Ticket

Directions: Construct and solve an equation to

solve the problem.

Sue wants to join a fitness club. The

fitness club charges an initial

membership fee of $25 and a monthly

fee of $24.50 per month. She has

$392.50 to spend on a membership at

the fitness club. Write and solve an

equation to find the number of months

Sue can be a member of the fitness

club.

PowerPoint Presentation · Title: PowerPoint Presentation Author: Alice Breazeale Created Date:...

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