Power Point ARC 2
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Transcript of Power Point ARC 2
1
Arc Flash
Conrad St.Pierre
Arc-Flash Hazard Evaluation Provides Safer and More
Efficient Workplace
Requirements of 2003 NEC• Article 110.16 states ‘Flash protection is required when
examining, adjusting, servicing, or maintaining energized equipment. The equipment shall be field marked to warn qualified persons of potential electric arc flash hazards’ ‘Flash protection is required when examining, adjusting, servicing, or maintaining energized equipment. The equipment shall be field marked to warn qualified persons of potential electric arc flash hazards’
• NEC is generally not retro-active, but for safety reasons should apply to all to all electrically equipment.
Dupont Nameplate
NFPA 70E
“Flash hazard analysis shall be done before a person approaches any exposed electrical conductor or circuit part that has not been placed in an electrically safe work condition.
The flash hazard analysis shall determine the flash protection boundary and the personal protective equipment that people within the arc flash boundary must use.”
Clothing RequiredMin. PPE Rating
Range of Calculated incident energy
Flash Hazard Risk Category
Cotton underclothing plus FR shirt, pants, plus multi-layer switching suit or equivalent
100 cal/cm240+ to 100 cal/cm25
Cotton underclothing plus FR shirt, pants, plus double layer switching coat and pants
40 cal/cm225+ to 40 cal/cm24
Cotton underclothing plus FR shirt, pants, overalls or equivalent
25 cal/cm28+ to 25 cal/cm23
Cotton underclothing plus FR shirt and pants
8 cal/cm25+ to 8 cal/cm22
FR shirt and pants5 cal/cm21.2+ to 5 cal/cm21
4.5-14.0 oz/yd2 untreated cottonN/A0 to 1.2 cal/cm20
Minimum Thermal Recommended Protection(Based on proposed updates to NFPA 70E)
2
An arc flash can be ExpensiveRecovery and rehabilitation costs can be staggering
• Cost for an incident involving one fatalityand two injured employees has exceeded$12 million.
• Another company’s expenses for three serious incidents in a three year periodhave exceeded $875,000.
Reality of Arc Flash HazardArc current creates: – A brilliant flash of light– A loud noise– Intense heat– Fast moving pressure wave
Products of arcing fault are:– Ionized gases– Metal vapors– Molten metal droplets– Shrapnel
Development of Arc Flash Calculations
• In 1982 Ralph Lee presented an IEEE paperon Arc Flash Hazard
• NFPA 70E – 2000 Recommended Arc Flash Calcs
• IEEE-1584-2002 - Published Calc Methods
• IEEE 1584 Standard refers to Lee’s work as Lee’s Method.
• Equation use VLL and Ibolted fault and givesworking distance
Vs
Source
Zs
Arc Volts
Zcable
One Line Diagram
What is in IEEE 1584?
• Results based on tests
• Arc Flash in Open Space, on Cables, MV Swgr, LV Swgr, MCC, Dist. Panels
• Voltages 208 to 1000V, 1000 to 5000V5000-15000-V, >15-kV>15-kV uses Lee’s Method
• Grounded and Ungrounded Systems
• Faults cleared by CLF Equations
Video 1
3
Video 2Results of Experiments
• Best fit for arcing current: equations with terms of • bolted fault current• voltage• gap between conductors• open air or box
• Best fit for incident energy: equations with terms• arcing current• gap between conductors • open air or box• grounded or ungrounded
Getting from Incident Energy to PPE
• Utilizing PPE with Cal/cm2 values of 1.2, 4, 8, 25, 40 the IEEE Equations resulted in adequate levels of PPE in 95% of the arc-flash tests
• In 5% of the tests, the PPE chosen was one level too low
Arc CurrentLV Ia = 10 [K + 0.662 log(Ib) + 0.0966 V
+ 0.000526 G + 0.5588 log(Ib) V – 0.00304 log(Ib) G]
MV Ia = 10 [0.00402 +0.983 log (Ibf)]where:
Ia = arcing current (kA)K = – 0.153 for open configuration
or – 0.097 for box configurationlog(Ib) = log10 of sym RMS bolted fault current (kA)Voltage = system voltage (kV)G = distance between buses (mm)
LV Equation - Incident Energy Normalized
En =10 K1 + K2 + 1.081 log(Ia) + 0.0011 G
whereEn = incident energy normalized to
0.2 seconds and 610 mm distanceK1 = -0.792 for open configurations
or -0.555 for box configurations K2 = 0 for ungrounded and high resistance
grounded systems,or -0.113 for grounded systems
G = bus bar spacing or gap (mm)
Incident Energy
E = Cf 10 log(En)(t /0.2)( 610X / DX)
whereE is incident energy in cal/cm2
Cf is calculation factor of 1.0 for Voltage > 1kV,or 1.5 for Voltage < 1kV
t is time in secondsD is working distance in mmX is the distance exponent from table based on
enclosure size and voltage
4
Man without
PPEProtection
Human ConductorCausing
Arc
Racking Out Breaker• Grounded Definition• Incident Energy verses Voltage and Test Data
0 – 1000V have voltage term in equation
1000+ to 15000 V do not have voltage term in equation. Two grouping 1-5-kV, 5-15-kV
15000 V+ has voltage in equation
Questionable Items
Standard K2 = 0 for ungnded and hi-resistance gnded systemsK2 = –0.113 for grounded systems
SpreadsheetUngded, Res Gnding, Other Imp gnded K2 = 0Solid Grounded K2 = -0.113
-0.113-0.113Solid0.0-0.113Low Imp0.00.0Hi-Imp0.00.0UnGnd
SpreadsheetStandardGrounding
Grounded Definition
600-V
480-V
13.8-kV
2.4-kV
4.16-kV
13.8-kV
34.5-kV
0.0
2.0
4.0
6.0
8.0
10.0
12.0
14.0
Inci
dent
Ene
rgy
(Cal
/cm
^2)
0 10 20 30 40 50 60
Bolt Fault Current in kA
0
25
50
75
100
125
150
175
200
Inci
dent
Ene
rgy
(Cal
/cm
^2)
0 10 20 30 40 50 60
Bolted Fault Current in kA
Time = 0.1 sec, Working distance = 24 inches, Arc gap per IEEE 1584 for switchgea, Grounded
*
Incident Energy verses Bolted Fault Currentfrom IEEE 1584 Equation
5
2
0 10 20 30 40 50 60 70 80Bolted kA
0
10
20
30
40
50
60
Cal
/cm
IEEE Lee's Method
IEEE 1584 Equations
Test Data Points
Comparison of IEEE Equations to 600 Volt Open Air Arc Test DataIEEE 1584 Eq, based on 24 inch to subject, 1.25 Inch Arc Gap, 1.0 sec
Incident Energy verses Voltage and Test Data
IEEE Lee's Method
IEEE 1584 Equations
Test Data Points
0 10 20 30 40 50 60Bolted kA
0
50
100
150
200
250
300
Cal
/cm
2
Comparison of IEEE Equations to 4160 Volt Open Air Arc Test DataIEEE 1584 Eq, based on 24 inch to subject, 4.0 Inch Arc Gap, 1.0 sec
Incident Energy verses Voltage and Test Data2
IEEE 1584 Equations
Test Data Points
IEEE Lee's Method
0
100
200
300
400
500
Cal
/cm
0 10 20 30 40 50 60Bolted kA
IEEE 1584 Eq, based on 24 inch to subject, 6.0 Inch Arc Gap, 1.0 sec
Comparison of IEEE Equations to 13,800 Volt Open Air Arc Test
Incident Energy verses Voltage and Test Data
MCC or PANELBOARD
LV SWITCHGEAR
SMALL
LARGE
BOX APPLICATION
165x165 cm
254x254 cm
OPENING
191 cm
508 cm
DEEP
38 cm
10 cm
ELECTRODEELECTRODE
SMALL BOX
LARGE BOX
Test Cubicles (Box)
Arc Pressure
• In 1987 Ralph Lee presented an IEEE paperon Arc Pressure
• Arc Pressure = 11.5*kA lbs/ft2(Distance. from arc in feet)0.9
• for 50-kA fault at 2 feet = 308 lb/ft2
Video 3
6
1. Low voltage remote trip and close
2. Use a remote or longer operating arms when racking in or opening/closing breakers
3. Place a shield between the technician and the device being placed in service or racked in
4. Review protective devices to see if they canbe lowered in time and pick-up.
Limiting Flash Hazard
5. On double ended load centers with normally closed tie, open an incoming breaker or th tie breaker
6. Determine if smaller fuses can be used
7. Change relay settings when working onequipment
Limiting Flash Hazard
Hi-impact plastic shield with arm holds
Breaker
Switchgear Cubicle
Protective Shield
Breaker
Relay withInst. Set
Switchgear Bus
Feeder
CT
Safety On/Off
Time OvercurrentRelay Trip Contact
O/CO/C CT
Relay withInst. Set
Breaker Main
FeederBreaker
To - DC busTo Main BreakerTrip Circuit
Lt Inst. OvercurrentTrip Contact
Switch
Relay without Inst. SetCT O/C
Main Breaker Control Circuit + DC Bus
Circuit to Reduce Arc Fault Time
Arc Heat
53 51 3 5 10 100 3 5 1000 3
10
50
100
1000
500300
30
53
1
.5
.3
.1
.05
.03
.01
SECONDS
101 3 5 100 3 5 33 5 51000
.01
.03
.05
.3
.5
3
.1
1
5
10
30
50
1000
300500
100
SECONDS
CURRENT IN AMPS X 100 @ 480 VOLTS
ARC-1 FDRGeneral Electric RMS-9Low Voltage PowerSensor = 800 Plug = 600Curr Set = 1.0 Trip = 600LTBand = 1 Inst = 10.0STpu = 4.0 I^2t = IN Bd = Min
250E
1600A
600A
480V
4160V
1000 kVA
MainGeneral Electric RMS-9Low Voltage PowerSensor = 1600 Plug = 1600Curr Set = 1.0 Trip = 1600LTBand = 1 Inst = NoneSTpu = 2.0 I^2t = IN Bd = Min
Transf Amps
85% Transf Amps
1000 kVAS&CSMU-40 4.8 KVStd Speed250E SF= 1
17.6
1.2
5.3
8.8
1.4
4.4
Cal/Cm^2
17.3 0.42
1.014.3Fuse
0.0519.7Feeder
0.3014.3Main
85% fault
Fuse
0.0523.2Feeder
0.2117.3Main
Time(sec)
kALocation
100% Fault
7
Slide the tab to run Short Circuit.
W A R N IN GW A R N IN GA p p ro p r ia te P P E R e q u ire d
V o lts M ax S h o rt C ircu it k A
R eq u ire d XN o t R e q u ire d
B u s E le c tr ic a l S h o c k a nd F la s h H a z a rd
5 .04 80 0
E q u ip m en t N a m e: 01P ro jec t: T 12 3
A rc F la s h b o u n d a ry a t e n e rg y < 1 .2 c a l/c m ^ 2
W h e n L iv e P a r ts a re E x p o s e d (R e s t r ic te d S h o c k H a za r d D is ta n c e = 2 6 in c h )
C lo th in gL e v e l 0 F a c e
S h ie ld X
G lo v eC la s s 0 E y e
P ro te c tio nX
In s u la te dT o o ls X H a ir /B e a rd N e t
N o t A llo w e d X
P P E B as ed o n 1 7 .9 in c h W o rkin g D is tan c eA rc F las h b ou n d ary , P P E re q u ire d w i th in 1 3 .2 in c h es )
Warning Label Plot of Incident Energy