Point and Distributed Loading
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Transcript of Point and Distributed Loading
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Point and Distributed Loading
Tip deflection errors and sensitivity results.
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Point Loading Cases
F1 F2Sensor 1 Sensor 2
x1
x2
a
Tip Deflection
b
Case 1: a = L/2, b = L. F1 > 0, F2 > F1.Case 2: a = L/2, b = L. F1 > 0, F1 > F2.Case 3: a = L/2, b = L. F1 < 0, F2 > abs(F1).
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Deflection Errors at Tip
Case 1F1 = 2e-3*9.81F2 = 5e-3*9.81
Case 2F1 = 5e-3*9.81F2 = 2e-3*9.81
Case 3F1 = -2e-3*9.81F2 = 5e-3*9.81
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Sensitivity of Deflection Errors with Respect to x1
Case 1F1 = 2e-3*9.81F2 = 5e-3*9.81
Case 2F1 = 5e-3*9.81F2 = 2e-3*9.81
Case 3F1 = -2e-3*9.81F2 = 5e-3*9.81
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Sensitivity of Deflection Errors with Respect to x2
Case 1F1 = 2e-3*9.81F2 = 5e-3*9.81
Case 2F1 = 5e-3*9.81F2 = 2e-3*9.81
Case 3F1 = -2e-3*9.81F2 = 5e-3*9.81
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Deflection and Curvatures when x1 = 25, x2 = 82.
Case 1F1 = 2e-3*9.81F2 = 5e-3*9.81
Case 2F1 = 5e-3*9.81F2 = 2e-3*9.81
Case 3F1 = -2e-3*9.81F2 = 5e-3*9.81
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Conclusions:
• Opposing loads lead to the same results as loads in the same direction (if magnitude is the same.)
• If the load at the inflection point is larger than the load at the end, the range of deflection error and sensitivities are greater.
• For all cases when a = L/2, the lowest deflection error at the tip is when x1 = 45 and x2 = 125.
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Distributed Loading Cases
Sensor 1
x1
x2
a
Tip Deflection
b
q
Sensor 2
Case 1: a = L/2, b = L - a
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Case 1: q = 10e-3*9.81/75Deflection Error at Tip Sensitivity w/Respect to x1 Sensitivity w/Respect to x2
When x1 = 25, x2 = 82:
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Conclusions:
• For Case 1, deflection error at tip when x1 = 25, x2= 82 is 0.0574.
• The best region for sensor placement seems to be when x1 = 28, x2 is in the range [122:138]. However, this is sensitive to x1.
• If one sensor is at L/2 (start of loading), the position of the second sensor is not important in improving the accuracy of the curvature readings (hence the displacement error).
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Two Distributed Loads
x1
x2
a
Tip Deflection
b
q2
Sensor 2Sensor 1
q1
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One Distributed Load and End Point Load
x1
x2
a
Tip Deflection
b
Sensor 2Sensor 1
q F
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Three Loading Types
• Given two point loads, distributed loads were found such that the curvature at x = 0 and x = L/2 was the same.
• The distributed loading caused regions of similar deflection errors.
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Deflection Error at TipF1 = 2 grams, F2 = 5 grams
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Sensitivity in x1 positionF1 = 2 grams, F2 = 5 grams
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Sensitivity in x2 positionF1 = 2 grams, F2 = 5 grams
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Deflection and Curvature when x1 = 20, x2 = 80.F1 = 2 grams, F2 = 5 grams
Error at tip = -0.0279mm Error at tip = -0.0088mm Error at tip = -0.0099mm
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More Extreme Case
• F1 and F2 are in opposite directions, and
21 FF
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Deflection Error at TipF1 = -5 grams, F2 = 2 grams
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Sensitivity in x1 positionF1 = -5 grams, F2 = 2 grams
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Sensitivity in x2 positionF1 = -5 grams, F2 = 2 grams
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Deflection and Curvature when x1 = 20, x2 = 80.F1 = -5 grams, F2 = 2 grams
Error at tip = 0.0697mm Error at tip = -0.0088mm Error at tip = -0.0099mm