Physics/Notes 6.2
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Transcript of Physics/Notes 6.2
![Page 1: Physics/Notes 6.2](https://reader036.fdocuments.us/reader036/viewer/2022082804/547969905806b5a3048b469f/html5/thumbnails/1.jpg)
Chapter 6Motion in Two Dimensions
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Section 6.2Circular Motion
How do I explain why an object that is moving in a circle at constant velocity has acceleration?
How can I calculate centripetal acceleration?
How can I identify the forces that cause centripetal acceleration?
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Uniform Circular MotionA mass being rotated at a constant velocity
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Uniform Circular MotionVelocity is constant
The velocity vector is constantly changing direction
This change in direction provides an acceleration towards the center of the circle
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Centripetal Acceleration
This acceleration results from the spinning action, it does not cause the spinning
If the stopper’s speed is 1.5 m/s and the radius is 0.56 m, what is the centripetal acceleration?
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Circular VelocityWhat if they do not give you velocity in m/s?
How about 33 rpm?
T = Period = the time needed to turn 1 complete revolution
What is the T for a 33 rpm record?
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Centripetal Acceleration
What if a penny was placed on the outside of a record being played at 33 rpm, what would its acceleration be? Use 0.15 m for the radius.
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Centripetal ForceSince the acceleration points towards the center,
the centripetal force points towards the center
F = ma, so Fc = ?
Fc is the result of another force that turns the object in a circle
This force can be supplied by tension or friction
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Centripetal ForceSupplied by tension
A 13 g stopper is attached to a 0.93 m string. The stopper is swung in a horizontal circle, making one revolution in 1.18 s. Find the tension force exerted by the string on the stopper.
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Centripetal ForceSupplied by friction
A car traveling 15 m/s is going around a turn of radius 30 m. What is necessary for the car to stay on the road?
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