Physics Walker Chapter 4 Notes

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Copyright © 2010 Pearson Education, Inc. Chapter 4 Two-Dimensional Kinematics

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Transcript of Physics Walker Chapter 4 Notes

  • Copyright 2010 Pearson Education, Inc.

    Chapter 4

    Two-Dimensional

    Kinematics

  • Copyright 2010 Pearson Education, Inc.

    Units of Chapter 4

    Motion in Two Dimensions

    Projectile Motion: Basic Equations

    Zero Launch Angle

    General Launch Angle

    Projectile Motion: Key Characteristics

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    4-1 Motion in Two Dimensions

    motion along a

    straight line with

    constant velocity

    =

    = cos = sin

    = = 0

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    Vector equations

    =

    is equivalent to

    = =

    Two vectors are equal when their components

    are equal

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    4-1 Motion in Two Dimensions

    Rule: motion in the x- and y-directions is solved

    separately !

    Vector notation:

    = + +

    ; = +

    Component notation: = , , = ,

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    4-2 Projectile Motion: Basic Equations

    Assumptions:

    ignore air resistance

    Acceleration due to gravity g = 9.81 m/s2,

    downward

    ignore Earths rotation

    If y-axis points upward, acceleration in x-direction is

    zero and acceleration in y-direction is -9.81 m/s2

    = = = .

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    4-2 Projectile Motion: Basic Equations

    The acceleration is independent of the direction

    of the velocity:

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    4-2 Projectile Motion: Basic Equations

    These, are the basic equations of projectile motion:

    X direction:

    = + = =

    Y direction:

    = +

    12

    2

    =

    = ( )

    X Motion with

    constant velocity

    Y Motion with

    constant acceleration

    A problem is set by initial conditions: , , ,

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    4-3 Zero Launch Angle

    Launch angle: direction of initial velocity with

    respect to horizontal, =

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    4-3 Zero Launch Angle

    In this case, the initial velocity in the y-direction

    is zero. Here are the equations of motion, with

    = , = , = , = :

    X direction:

    = = =

    Y direction:

    = 12 2

    =

    = ( )

    Motion with constant Drop from height

  • Question 4.2 Dropping a Package

    You drop a package from

    a plane flying at constant

    speed in a straight line.

    Without air resistance, the

    package will:

    a) quickly lag behind the plane

    while falling

    b) remain vertically under the

    plane while falling

    c) move ahead of the plane while

    falling

    d) not fall at all

  • You drop a package from

    a plane flying at constant

    speed in a straight line.

    Without air resistance, the

    package will:

    a) quickly lag behind the plane

    while falling

    b) remain vertically under the

    plane while falling

    c) move ahead of the plane while

    falling

    d) not fall at all

    Both the plane and the package have

    the same horizontal velocity at the

    moment of release. They will maintain

    this velocity in the x-direction, so they

    stay aligned.

    Follow-up: what would happen if air resistance is present?

    Question 4.2 Dropping a Package

  • Question 4.3a Dropping the Ball I

    From the same height (and

    at the same time), one ball

    is dropped and another ball

    is fired horizontally. Which

    one will hit the ground

    first?

    a) the dropped ball

    b) the fired ball

    c) they both hit at the same time

    d) it depends on how hard the ball

    was fired

    e) it depends on the initial height

  • From the same height (and

    at the same time), one ball

    is dropped and another ball

    is fired horizontally. Which

    one will hit the ground

    first?

    a) the dropped ball

    b) the fired ball

    c) they both hit at the same time

    d) it depends on how hard the ball

    was fired

    e) it depends on the initial height

    Both of the balls are falling vertically under the influence of

    gravity. They both fall from the same height. Therefore, they will

    hit the ground at the same time. The fact that one is moving

    horizontally is irrelevantremember that the x and y motions are

    completely independent !!

    Follow-up: is that also true if there is air resistance?

    Question 4.3a Dropping the Ball I

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    4-3 Zero Launch Angle

    This is the trajectory of a projectile

    launched horizontally: = ( )

    Landing = at

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    4-3 Zero Launch Angle

    Eliminating t and solving for y as a function

    of x:

    This has the form y = a + bx2, which is the

    equation of a parabola.

    The landing point can be found by setting

    y = 0 and solving for x:

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    4-4 General Launch Angle

    Initial conditions:

    = , = , = cos , = sin

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    4-4 General Launch Angle

    In general, v0x = v0 cos and v0y = v0 sin

    This gives the equations of motion:

    X direction:

    = ( cos ) = cos

    Y direction:

    = ( sin )

    12

    2

    = sin

    = (sin )

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    4-5 Projectile Motion: Key Characteristics

    Hang time (time spent in the air):

    = sin

    = sin

    =

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    4-5 Projectile Motion: Key Characteristics

    Height (max):

    =( sin )

  • Which of the

    three punts

    has the

    longest hang

    time?

    Question 4.4a Punts I

    d) all have the same hang time

    a b c

    h

  • Which of the

    three punts

    has the

    longest hang

    time? d) all have the same hang time

    a b c

    h

    The time in the air is determined by the vertical motion!

    Because all of the punts reach the same height, they all

    stay in the air for the same time.

    Follow-up: Which one had the greater initial velocity?

    Question 4.4a Punts I

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    4-5 Projectile Motion: Key Characteristics

    Range: the horizontal distance a projectile

    travels

    If the initial and final elevation are the same:

  • a b d c

    Question 4.5 Cannon on the Moon

    For a cannon on Earth, the cannonball would follow path 2.

    Instead, if the same cannon were on the Moon, where g =

    1.6 m/s2, which path would the cannonball take in the same

    situation?

  • a b d c

    The ball will spend more

    time in flight because

    gMoon < gEarth. With more

    time, it can travel farther

    in the horizontal

    direction.

    For a cannon on Earth, the cannonball would follow path 2.

    Instead, if the same cannon were on the Moon, where g =

    1.6 m/s2, which path would the cannonball take in the same

    situation?

    Follow-up: which path would it take in outer space?

    Question 4.5 Cannon on the Moon

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    Summary of Chapter 4

    Components of motion in the x- and y-directions can be treated independently

    In projectile motion, the acceleration is g

    If the launch angle is zero, the initial velocity has only an x-component

    The path followed by a projectile is a parabola

    The range is the horizontal distance the projectile travels