Physics 151: Lecture 37, Pg 1 Physics 151: Lecture 37 Today’s Agenda l Topics çTemperature and...
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Transcript of Physics 151: Lecture 37, Pg 1 Physics 151: Lecture 37 Today’s Agenda l Topics çTemperature and...
Physics 151: Lecture 37, Pg 1
Physics 151: Lecture 37 Physics 151: Lecture 37 Today’s AgendaToday’s Agenda
TopicsTemperature and Zeroth Law of Thermodynamics Temperature scalesThermal expansionIdeal gas
Physics 151: Lecture 37, Pg 2
TemperatureTemperature Temperature: measure of the motion of the individual atoms and
molecules in a gas, liquid, or solid. related to average kinetic energy of constituents
High temperature: constituents are moving around energetically In a gas at high temperature the individual gas molecules are
moving about independently at high speeds. In a solid at high temperature the individual atoms of the solid
are vibrating energetically in place. The converse is true for a "cold" object.
In a gas at low temperature the individual gas molecules are moving about sluggishly.
There is an absolute zero temperature at which the motions of atoms and molecules practically stop.
There is an absolute zero temperature at which the classical motions of atoms and molecules practically stop
Animation
Physics 151: Lecture 37, Pg 3
HeatHeat
Solids, liquids or gases have internal energyKinetic energy from random motion of molecules
translation, rotation, vibration
At equilibrium, it is related to temperature Heat: transfer of energy from one object to another as a
result of their different temperatures Thermal contact: energy can flow between objects
T1T2
U1U2
>
Physics 151: Lecture 37, Pg 4
Zeroth Law of ThermodynamicsZeroth Law of Thermodynamics
Thermal equilibrium: when objects in thermal contact cease heat transfersame temperature
T1T2
U1 U2
=
If objects A and B are separately in thermal equilibrium with a third object C, then objects A and B are in
thermal equilibrium with each other.
AC
B
Animation
Physics 151: Lecture 37, Pg 5
ThermometersThermometers
A thermometer is a device that is used to measure the temperature of a system
Thermometers are based on the principle that some physical property of a system changes as the system’s temperature changes
These properties include: The volume of a liquid The dimensions of a solid The pressure of a gas at a constant volume The volume of a gas at a constant pressure The electric resistance of a conductor The color of an object
A temperature scale can be established on the basis of any of these physical properties
Physics 151: Lecture 37, Pg 6
Thermometer, Liquid in GlassThermometer, Liquid in Glass
A common type of thermometer is a liquid-in-glass
The material in the capillary tube expands as it is heated
The liquid is usually mercury or alcohol
A thermometer can be calibrated by placing it in contact with some natural systems that remain at constant temperature
Physics 151: Lecture 37, Pg 7
Thermometer, Celsius ScaleThermometer, Celsius Scale
A thermometer can be calibrated by placing it in contact with some natural systems that remain at constant temperature
Common systems involve water A mixture of ice and water at atmospheric pressure
» Called the ice point of water A mixture of water and steam in equilibrium
» Called the steam point of water
Celsius Scale : The ice point of water is defined to be 0o C The steam point of water is defined to be 100o C
Physics 151: Lecture 37, Pg 8
Constant Volume Gas ThermometerConstant Volume Gas Thermometer
The physical change exploited is the variation of pressure of a fixed volume gas as its temperature changes
The volume of the gas is kept constant by raising or lowering the reservoir B to keep the mercury level at A constant
Physics 151: Lecture 37, Pg 9
Absolute ZeroAbsolute Zero The thermometer readings are virtually independent of the gas used If the lines for various gases are extended, the pressure is always zero when
the temperature is –273.15o C This temperature is called
absolute zero
Absolute zero is used as the basis of the absolute temperature scale The size of the degree on the absolute scale is the same as the size
of the degree on the Celsius scale To convert: TC = T – 273.15
Physics 151: Lecture 37, Pg 10
Temperature scalesTemperature scales
Three main scales
212
Farenheit
100
Celcius
32 0 273.15
373.15
Kelvin
Water boils
Water freezes
0-273.15-459.67Absolute Zero
Physics 151: Lecture 37, Pg 11
Some interesting factsSome interesting facts In 1724, Gabriel Fahrenheit made thermometers
using mercury. The zero point of his scale is attained by mixing equal parts of water, ice, and salt. A second point was obtained when pure water froze (originally set at 30oF), and a third (set at 96oF) “when placing the thermometer in the mouth of a healthy man”.
On that scale, water boiled at 212. Later, Fahrenheit moved the freesing point of
water to 32 (so that the scale had 180 increments).
In 1745, Carolus Linnaeus of Upsula, Sweden, described a scale in which the freezing point of water was zero, and the boiling point 100, making it a centigrade (one hundred steps) scale. Anders Celsius (1701-1744) used the reverse scale in which 100 represented the freezing point and zero the boiling point of water, still, of course, with 100 degrees between the two defining points.
T (K)
108
107
106
105
104
103
100
10
1
0.1
Hydrogen bomb
Sun’s interior
Solar corona
Sun’s surface
Copper melts
Water freezes
Liquid nitrogen
Liquid hydrogen
Liquid helium
Lowest T~ 10-9K
Physics 151: Lecture 37, Pg 12
Thermal expansionThermal expansion
In most liquids or solids, when temperature risesmolecules have more kinetic energy
» they are moving faster, on the averageconsequently, things tend to expand
amount of expansion depends on…change in temperature Toriginal length L coefficient of thermal expansion
» L0 + L = L0 + L0 T
L = L0 T (linear expansion)
V = L0 T (volume expansion)
L0 L
V
V + V
Physics 151: Lecture 37, Pg 14
Bimetallic stripBimetallic strip A bimetallic strip is made of two
ribbons of dissimilar metals bonded together.
Assume that the strip is originally straight. As they are heated, the metal with the greater average coefficient of expansion (2) expands more than the other, forcing the strip into an arc, with the outer radius having a greater circumference (as in the Fig). A compact spiral bimetallic strip is used in a home thermostat. Find the angle () through which the free end of the strip turns when the temperature changes by 1°C for such bimetalic strip with the initial length L= 21.0 cm and the separation of the centers of the strips (r = r2 - r1 = 0.410 mm). The two metals are bronze and invar.
(2 - 1 )L (dT/dr)
1.06o
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Physics 151: Lecture 37, Pg 15
Lecture 37Lecture 37,, ACT 1ACT 1Thermal expansionThermal expansion
As you heat a block of aluminum from 0 oC to 100 oC, its density
(a) increases (b) decreases (c) stays the same
• SolutionHere is positive
Volume increases
Density decreases
T = 0 C
M, V0
0 = M / V0
T = 100 C
M, V100
100 = M / V100
< 0
Answer: (b)
Physics 151: Lecture 37, Pg 16
Lecture 37: Lecture 37: ACT 2ACT 2Thermal expansionThermal expansion
An aluminum plate has a circular hole cut in it. A copper ball (solid sphere) has exactly the same diameter as the hole when both are at room temperature, and hence can just barely be pushed through it. If both the plate and the ball are now heated up to a few hundred degrees Celsius, how will the ball and the hole fit ?
(a) ball won’t fit (b) fits more easily (c) same as before
Physics 151: Lecture 37, Pg 17
Lecture 37: Lecture 37: ACT 2ACT 2SolutionSolution
Both objects have positive thermal coefficients all dimensions increase plate and ball both get larger
Before
(b) fits more easily
After
Physics 151: Lecture 37, Pg 18
Special system: WaterSpecial system: Water
Most liquids increase in volume with increasing T
water is specialdensity increases from
0 to 4 oC !ice is less dense than
liquid water at 4 oC: hence it floats
water at the bottom of a pond is the denser, i.e. at 4 oC
Water has its maximum density at 4 degrees.
999.55
999.60
999.65
999.70
999.75
999.80
999.85
999.90
999.95
1000.00
0 2 4 6 8 10
Density
(kg/m3)
T (oC)
Reason: chemical bonds of H20 (see your chemistry courses !)
Physics 151: Lecture 37, Pg 19
Lecture 37: Lecture 37: ACT 3ACT 3
Not being a great athlete, and having lots of money to spend, Gill Bates decides to keep the lake in his back yard at the exact temperature which will maximize the buoyant force on him when he swims. Which of the following would be the best choice?
(a) 0 oC (b) 4 oC (c) 32 oC (d) 100 oC (e) 212 oC
Physics 151: Lecture 37, Pg 20
Lecture 37: Lecture 37: ACT 3ACT 3SOLUTIONSOLUTION
The buoyancy force is
since his volume and g are constant, only is changing
Water has its maximum density at 4 degrees.
999.55
999.60
999.65
999.70
999.75
999.80
999.85
999.90
999.95
1000.00
0 2 4 6 8 10
Density
FB = lVg
(a) 0 oC
Physics 151: Lecture 37, Pg 21
Lecture 37: Lecture 37: Problem 1Problem 1
For a typical system, such as a mercury thermometer, why is it a good approximation to neglect the expansion of the shell ?
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h =(Vi /A) ( - 3) T
(for glass) << (for mercury), so ( -3 within 5%.
A liquid with a coefficient of volume expansionjust fills a spherical shell of volume Vi at a temperature of Ti (see Fig. to the right). The shell is made of a material that has an average coefficient of linear expansion . The liquid is free to expand into an open capillary of area A projecting from the top of the sphere.
When the temperature increases by T how high does the liquid rises in the capillary ( h ) ?
Physics 151: Lecture 37, Pg 22
Ideal gasIdeal gas
Consider a gas in a container of volume V, at pressure P, and at temperature T
Equation of stateLinks these quantitiesGenerally very complicated: but not for ideal gas
n = m/M : number of moles m=mass M=mass of one mole
One mole contains NA=6.022 X 1023 particles : Avogadro’s number
PV = nRT
• Equation of state for an ideal gas
R is called the universal gas constant
In SI units, R =8.315 J / mol·K
Physics 151: Lecture 37, Pg 23
Boltzmann’s constantBoltzmann’s constant
In terms of the total number of particles N
P, V, and T are the thermodynamics variables
PV = nRT = (N/NA ) RT
kB is called the Boltzmann’s constant
In SI units, with R =8.315 J / mol·K, we get
kB = R/NA = 1.38 X 10-23 J/K
PV = N kB T
Animation (p,T)
Animation (p,V)
Animation (p,N)
Physics 151: Lecture 37, Pg 24
Lecture 37: Lecture 37: Problem 2Problem 2 A vertical cylinder of cross-
sectional area A=0.001 m2 is fitted with a tight-fitting, frictionless piston of mass m = 20.0 kg (see the Fig. To the right)
If n = 0.200 moles of an ideal gas are in the cylinder at a temperature of T = 350 K, what is the height h at which the piston is in equilibrium under its own weight ?
h = n R T/(mg + PA)
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h = 1.94 m
Physics 151: Lecture 37, Pg 25
Lecture 37: Lecture 37: Problem 3Problem 3
The mass of a hot-air balloon and its cargo (not including the air inside) is 200 kg. The air outside is at 10.0°C and 101 kPa. The volume of the balloon is 400 m3. To what temperature must the air in the balloon be heated before the balloon will lift off ?
(Air density at 10.0°C is 1.25 kg/m3.)
T = 472 K !
m
V, T
mg
B = To V g
TVg
To
Physics 151: Lecture 37, Pg 26
Lecture 37: Lecture 37: Problem 2bProblem 2b
A cylinder is closed by a piston connected to a spring of constant 2.0 x 103 N/m (as on the Fig.). With the spring relaxed, the cylinder is filled with 5.00 L of gas at a pressure of 1.00 atm and a temperature of 20.0°C.
If the piston has a cross-sectional area of 0.010 m2 and a negligible mass, how high will it rise when the temperature is raised to 250°C ?
V=Vo +A h
h = 0.169 m
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p=po +kh / A
poVo / To = pV / T