Physics 111: Lecture 9 - ieu.edu.trhomes.ieu.edu.tr/hozcan/Phys100/Lect09.pdfPhysics 211: Lecture 9,...

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Physics 211: Lecture 9, Pg 1 Physics 111: Lecture 9 Today’s Agenda Work & Energy Discussion Definition Work of a constant force Work/kinetic energy theorem Work of multiple constant forces Comments

Transcript of Physics 111: Lecture 9 - ieu.edu.trhomes.ieu.edu.tr/hozcan/Phys100/Lect09.pdfPhysics 211: Lecture 9,...

Page 1: Physics 111: Lecture 9 - ieu.edu.trhomes.ieu.edu.tr/hozcan/Phys100/Lect09.pdfPhysics 211: Lecture 9, Pg 3 Forms of Energy Kinetic: Energy of motion. A car on the highway has kinetic

Physics 211: Lecture 9, Pg 1

Physics 111: Lecture 9

Today’s Agenda

Work & Energy

Discussion

Definition

Work of a constant force

Work/kinetic energy theorem

Work of multiple constant forces

Comments

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Work & Energy

One of the most important concepts in physics

Alternative approach to mechanics

Many applications beyond mechanics

Thermodynamics (movement of heat)

Quantum mechanics...

Very useful tools

You will learn new (sometimes much easier) ways to solve problems

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Forms of Energy

Kinetic: Energy of motion.

A car on the highway has kinetic energy.

We have to remove this energy to stop it.

The brakes of a car get HOT!

This is an example of turning one form of energy into another (thermal energy).

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Energy Conservation

Energy cannot be destroyed or created.

Just changed from one form to another.

We say energy is conserved!

True for any closed system.

i.e. when we put on the brakes, the kinetic energy of the car is turned into heat using friction in the brakes. The total energy of the “car-brakes-road-atmosphere” system is the same.

The energy of the car “alone” is not conserved...

» It is reduced by the braking.

Doing “work” on an isolated system will change its “energy”...

Returning

Can

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Definition of Work:

Ingredients: Force (F), displacement (r)

Work, W, of a constant force F

acting through a displacement r

is:

W = F r = F r cos = Fr r

F

r Fr

“Dot Product”

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Definition of Work...

Only the component of F along the displacement is doing work.

Example: Train on a track.

F

r

F cos

Hairdryer

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Back to the definition of Work:

Work, W, of a force F acting

through a displacement r is:

W = F r F

r

Inclined Plane

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Lecture 9, Act 1 Work & Energy

A box is pulled up a rough (m > 0) incline by a rope-pulley-weight arrangement as shown below.

How many forces are doing work on the box?

(a) 2

(b) 3

(c) 4

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Lecture 9, Act 1 Solution

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Physics 211: Lecture 9, Pg 15

Work: 1-D Example (constant force)

A force F = 10 N pushes a box across a frictionless floor for a distance x = 5 m.

x

F

Work done by F on box :

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Units:

N-m (Joule) Dyne-cm (erg)

= 10-7 J

BTU = 1054 J

calorie = 4.184 J

foot-lb = 1.356 J

eV = 1.6x10-19 J

cgs other mks

Force x Distance = Work

Newton x

[M][L] / [T]2

Meter = Joule

[L] [M][L]2 / [T]2

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Work & Kinetic Energy:

A force F pushes a box across a frictionless floor for a distance x. The speed of the box is v1 before the push and v2 after the push.

x

F

v1 v2

i

m

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Work & Kinetic Energy...

Since the force F is constant, acceleration a will be constant. We have shown that for constant a:

v22 - v1

2 = 2a(x2-x1) = 2ax.

multiply by 1/2m: 1/2mv22 - 1/2mv1

2 = max

But F = ma 1/2mv22 - 1/2mv1

2 = Fx

x

F

v1 v2

a

i

m

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Work & Kinetic Energy...

So we find that

1/2mv2

2 - 1/2mv12 = Fx = WF

Define Kinetic Energy K: K = 1/2mv2

K2 - K1 = WF

WF = K (Work/kinetic energy theorem)

x

F a

i

m

v2 v1

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Work/Kinetic Energy Theorem:

{Net Work done on object}

=

{change in kinetic energy of object}

KWnet

12 KK

2

1

2

2 mv2

1mv

2

1

We’ll prove this for a variable force later.

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Lecture 9, Act 2 Work & Energy

Two blocks have masses m1 and m2, where m1 > m2. They are sliding on a frictionless floor and have the same kinetic energy when they encounter a long rough stretch (i.e. m > 0) which slows them down to a stop. Which one will go farther before stopping?

(a) m1 (b) m2 (c) they will go the same distance

m1

m2

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Lecture 9, Act 2 Solution

m

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Lecture 9, Act 2 Solution

m

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Physics 211: Lecture 9, Pg 24

Lecture 9, Act 2 Solution

m

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A simple application: Work done by gravity on a falling object

What is the speed of an object after falling a distance H, assuming it starts at rest?

H

v0 = 0

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What about multiple forces?

Suppose FNET = F1 + F2 and the

displacement is r.

The work done by each force is:

W1 = F1 r W2 = F2 r

WTOT = W1 + W2

= F1 r + F2 r

= (F1 + F2 ) r

WTOT = FTOT r It’s the total force that matters!!

FNET

r F1

F2

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Comments:

Time interval not relevant

Run up the stairs quickly or slowly...same W

Since W = F r

No work is done if:

F = 0 or

r = 0 or

= 90o

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Comments...

W = F r

No work done if = 90o.

No work done by T.

No work done by N.

T

v

v

N

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Lecture 9, Act 3 Work & Energy

An inclined plane is accelerating with constant acceleration a. A box resting on the plane is held in place by static friction. How many forces are doing work on the block?

a

(a) 1 (b) 2 (c) 3

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Lecture 9, Act 3 Solution

a

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Lecture 9, Act 3 Solution

a

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Physics 211: Lecture 9, Pg 32

EXTRA EXAMPLE 1

Return to ACT 2:

m

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EXTRA EXAMPLE 2a

Consider an inclined plane with no friction:

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Physics 211: Lecture 9, Pg 34

EXTRA EXAMPLE 2a

Consider an inclined plane with no friction:

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EXTRA EXAMPLE 2b

Consider an inclined plane with friction:

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EXTRA EXAMPLE 2b

Consider an inclined plane with friction:

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EXTRA EXAMPLE 2c

Consider an inclined plane with friction:

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EXTRA EXAMPLE 2c

Consider an inclined plane with friction:

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Recap of today’s lecture

Work & Energy (Text: 6-1 and 7-4)

Discussion

Definition (Text: 6-1)

Work of a constant force (Text: 7-1 and 7-2)

Work/kinetic energy theorem (Text: 6-1)

Properties (units, time independence, etc.)

Work of a multiple forces

Comments