Phase Changes Physics 102 Professor Lee Carkner Lecture 4 Session: 104884.
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Transcript of Phase Changes Physics 102 Professor Lee Carkner Lecture 4 Session: 104884.
Phase Changes
Physics 102Professor Lee
CarknerLecture 4
Session: 104884
PAL #4 Kinetic Theory 50 liters of a gas at 20 C and 2 atm How many moles?
PV=nRT, n = PV/RT Convert to SI units
Vi = 50 L /1000 L/m3 = 0.05 m3
Ti = 20 C +273.15 = 293.15 K P = (2 atm)(101300 Pa/atm) = 202600 Pa n = (202600)(0.05) / (8.31)(293.15) =
4.16 moles
PAL #4 Kinetic Theory Compressed to 40 liters, temp raised to 40
C What will the new pressure be?
Vf = 40/1000 = 0.04 m3
Tf = 40 + 273.15 = 313.15 K PV= nRT, P = nRT/V Pf = (4.16)(8.31)(313.15) / (0.04) = 270637 Pa
Does this make sense? If you compress a gas and raise the
temperature there are more molecule hitting each square inch and they have more energy so pressure should increase
Phase Change
Once ice starts to melt its temperature does not change.
solid to liquid -- melting How much energy does this take? Each substance has a latent heat
Represented by L
Heat and Temperature
Phase Change and Heat
heat of fusion
heat of vaporization Amount of heat:
Q = mL
Q = cmT
Q = mL Must add all heats together
Note that you must make mL gained positive and mL lost negative !
The Final State
Its hard to know what terms to put in your heat balance since you are not sure if you will get a phase change
e.g. liquid water at 120 C or ice at 5 C Can also do some quick initial computations to
try and find the final state
n.b., when a phase change happens, the specific heat changes e.g., once ice melts it becomes water
Phase Change Calorimetry
1. 2. Write down a “Q” for each heat
necessary to reach the final state3. Make sure you:
Write T = Tf –Ti
Assign a sign to each mL term Check units
Melting Ice Cube Consider a 10 g ice cube at -10 C in 100 g of water at 10 C, what is
final T? Assume ice does not melt (0.01)(2090)(Tf-(-10) + (0.1)(4186)(Tf-10) =0
Wrong! Ice can’t be at greater than 0 C (0.01)(2090)(0-(-10)) +(0.01)(33.5X104)+ (0.01)(4186)(Tf-0)+(0.1)(4186)(Tf-
10) = 0
This T is OK since all that is left is water If we got a T less that 0 it would mean that only a fraction of the ice melted
(set Tf = 0 and solve for mmelt)
Phase Change and Pressure
Boiling point depends on both
temperature and pressure Examples:
pressure cooker
Easier for molecules to escape to vapor phase
Change in Boiling Point with Pressure
Phase Diagram
Usually high P, low T produces a solid and low P, high T produces gas
Water is an exception, increasing pressure on ice produces water This causes ice skates to melt ice and freezing
water to expand and produce frost heaves
Beyond the critical point there is no distinction between a liquid and gas Just have a fluid
Liquid and gas phases separated by a vaporization curve
Solid and gas phases separated by a sublimation curve
Velocity Distribution for Water
Evaporation How can water evaporate (become gas) if it is
not at the boiling point?
Evaporation only works if the air above is not saturated with vapor Pressure is too high
This is why it is hard to cool off on humid days and easier on windy days
Next Time
Read: 15.1-15.3 Homework: Ch 14: P 25, 28, Ch 15: P
1, 2
If a fixed amount of gas at constant temperature undergoes a increase in volume, what happens to the pressure?
a) It goes upb) It goes downc) It stays the samed) It depends on the value of Re) It depends on the number of moles
If a fixed amount of gas at constant pressure undergoes an increase in volume, what happens to the temperature?
a) It goes upb) It goes downc) It stays the samed) It depends on the value of Re) It depends on the number of moles
Consider two rooms of a house, room A and room B. If the (otherwise identical) molecules in room B have twice as much average kinetic energy than the ones in A, how does the temperature of room A compare to the temperature of room B?
A) TA = TB
B) TA = 2 TB
C) TA = ½ TB
D) TA = √2 TB
E) TA = (3/2) TB
How does the rms velocity of the molecules in room A compare to the rms velocity of the molecules in room B?
A) vA = vB
B) vA = 2 vB
C) vA = ½ vB
D) vA = √2 vB
E) vA = (3/2) vB