Periodic Trends

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Periodic Trends Still all about + and – charges!

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Periodic Trends. Still all about + and – charges!. Which of the following atoms is the largest?. Mg Ca Sr How the fluorine should I know?. Which of the following atoms is the largest?. Mg Al Cl. Periodic for a Reason. - PowerPoint PPT Presentation

Transcript of Periodic Trends

Page 1: Periodic Trends

Periodic Trends

Still all about + and – charges!

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Which of the following atoms is the largest?

A. MgB. CaC. SrD. How the fluorine should I know?

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Which of the following atoms is the largest?

A. MgB. AlC. Cl

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Periodic for a Reason

It is a “periodic” table because of the “periodic trends” that make it up.

We saw that the electron configurations are periodic (s-block, p-block, d-block, etc.) and I suggested that the Chemistry associated with the atoms followed the electron configuration.

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Other Periodic Properties

Electron configuration isn’t the only periodic trend in the table.

The other important trends are all rationalizable based on the most important trend – atomic size!

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Atomic Size

Suppose we want to compare the atomic radius of two atoms on the periodic table, for example Na and K.

Which would you think is bigger?

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What does an atom look like?

Bohr Model

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The Bohr Model

Nucleusp

p p nn

nn

e-

e-e-

So, what determines the size of the atom?

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The size is determined by…

…where the last electron lies.

So, which is bigger Na or K?

K – it is Na with a whole extra shell of electrons!

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Na vs. K

Na: 1s22s22p63s1

K: 1s22s22p63s23p64s1

This is a general trend. As you go down a column in the periodic table, the atomic radius increases.

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What about the rows?

Suppose I ask the same question about Na and Mg; which is larger?

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Na vs. Mg

Na: 1s22s22p63s1

Mg: 1s22s22p63s2

Does this help us any?

They have the same valence shell (n=3). The same highest orbital (3s).

Does this mean they are the same size?

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Those pesky charges

What are the differences between Na and Mg?

One extra electron One extra proton

Does that help?

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The Bohr Model - Na

11 p

12 nfull

e-full

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The Bohr Model - Mg

12 p

12 nfull

e-full e-

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The Bohr Model – Na vs. Mg

12 p12 nfull

e-full e-

11 p

12 nfulle-

full

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Na vs. Mg

Same outer shell of the electrons (- charge).

More + charges in nucleus.

What do you think happens?

Mg is actually slightly smaller than Na due to the extra + charge in the nucleus pulling the – electrons in closer!

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Periodic Trend – atomic radius

This pair of observations describes the general trend of atomic size:

Larger as you go down a column (large effect)

Smaller as you go across the row (small effect)

Note: There are exceptions due to special cases (1/2 full orbitals, etc.)

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Rank from Largest to smallest

A. Sn, In, Ga, AsB. In Sn As GaC. In Sn Ga AsD. In Ga Sn As

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Periodic Trend – atomic radius

Both of these trends are related to the charged species:

Larger as you go down a column (more electron shells – adding layers)

Smaller as you go across the row (stronger attraction between more + protons and the outer electrons)

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Other Trends

Understanding the trend in atomic radius and keeping the charge issues in mind make it easy to understand and predict some other periodic trends.

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Ionization Energy

Ionization energy is the amount of energy required to remove an electron from an atom:

Na + energy Na+ + e-

(You simply raise the electron from n=valence to n=∞)

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Ionization Energy

Na + energy Na+ + e-

If you are going to remove an electron, what is the relevant issue?

Charge – what a surprise!

What Charge?

The nuclear charge! - At least in part

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Na vs. Mg

Compare the Ionization Energy of Na to that of Mg.

Which do you think would be larger?

Na or Mg

Why?

They have the same outer orbital, but Mg has a larger nuclear charge (sound familiar) – Mg should have the larger ionization energy!

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Larger Ionization Energy

A. SodiumB. MagnesiumC. I have no frigging idea

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Na vs. K

Compare Na to K, what is relevant?

K is bigger than Na – why?

Because K has more shells and larger radius. Electrons are farther from nucleus.

Same argument for ionization energy. Electron, farther away, less attracted to nucleus, smaller ionization energy!

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Ionization Energy vs. Atomic Radius

It is the same arguments, with the same results.

Ionization energy has a trend that tracks the radius. Smaller atoms, larger ionization energy!

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Electron Affinity

Electron Affinity is complementary to ionization energy. Rather than give up an electron, the atom receives it:

Na + e- → Na-

What will determine if an atom wants an electron?

Attraction for the nucleus – so electron affinity will also track atomic radius

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Electron Affinity

Na vs. K

K will have a smaller electron affinity – K is larger, a new electron is farther away, less attracted to nucleus

Na vs. Mg

Na will have a smaller electron affinity – same radius, smaller charge, less attraction for the electron.

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Electronegativity

Electronegativity is the ability of an atom to attract electrons to itself. (Kind of like electron affinity, but on a different scale)

Electronegativity is important in predicting whether a bond is ionic or covalent.

Electronegativity will have the same trend as electron affinity.