1 Chapter 9 Mole Factors Calculations with Equations Limiting Reactions Percent Yield.
Percent Yield Lab
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Transcript of Percent Yield Lab
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5/27/2018 Percent Yield Lab
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Intro -
This report discusses an experiment to study a reaction between Copper (II)
Sulfate and Iron (CuSO4+ e)! the purpose of this experiment was to find the percent yield of
Copper (Cu)" In the e#uation
CuSO4 + e + $%&O ' eSO4+ Cu&+ $%&O
Copper (II) Sulfate reacts with Iron and ater producin Iron (III) Sulfate! Copper (II) and ater!ma*in this reaction a sinle replacement reaction" Thins one may need to *now about the
yield in a chemical e#uation are that there are two types of yield! theoretical and percent" hile
theoretical yield is the yield that the amount of product! while percent yield is the percent of the
theoretical yield that was actually formed throuh the reaction" hile the theoretical yield is
neer reached! a reason for that to happen could be the limitin reactant" , limitin reaction is
the reactant that limits that amount of product that can be made from a sinle reaction"
Materials:
alance (.lectronic) raduated cylinder! /012 and /0012
ea*ers! /00 12 and &$0 12 Iron powder
%ot plates ,pron
Copper (II) Sulfate crystals Safety 3oles
3lass stirrin rod distilled water
Procedure:
1easure the mass of a dry! clean /00 ml bea*er" 5ecord it in the data table"
1easure out 6"00 (the amount should be approximately 6 rams! thouh you must recordthe amount that you measure out precisely) of copper sulfate crystals and add them to the
bea*er"
,dd $0 ml of water to the crystals in the bea*er" 1easure the water usin a raduatedcylinder"
7lace the mixture on the hot plates on low heat 8 do not allow mixture to boil"
Continue heatin and stirrin mixture with the stirrin rod until all the crystals are dissoledcompletely" hen this occurs! turn off the hot plates and remoe mixture from the hot plates"
1easure out approximately /"00 (record precisely what you use) of iron powder" ,dd theiron powder! a little at a time! to the hot copper (II) sulfate solution! continuously stirrin" ,llow
the bea*er to cool for /0 minutes"
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9ecant the li#uid into a &$0 ml bea*er by ently pourin the li#uid down the stirrin rod intothe bea*er" 9o not disturb the solid in the /00 ml bea*er"
,dd approximately /0 ml of water to the solid in the /00 ml bea*er! stirrin bris*ly" ,llow thesolid to settle then decant aain"
Spread the solid oer the bottom of the bea*er! and then allow the solid to dry oerniht"
ind the mass of the bea*er and the solid copper once it is completely dry the followin day"5ecord the mass in the data table"
1ass of /00 ml bea*er $/"::
1ass of copper sulfate crystals 6";$ 1ass of iron powder /"00
1ass of bea*er < solid copper $;"4:
1ass of solid copper /"$0
Data Tableof determinin percent yield in a chemical reaction=
Calculations 8
7lease see the attached paper"
,nalysis-
5eactions neer ie the /00> yield that they could ie! the reason for this is
because there is no such thin as a perfect reaction" This could possibly be caused by the
impurities in the reactants and by human error (reactants not measured exactly! a process in the
reaction wasn?t done perfectly! ect")" If the reactants are impure then the reaction can?t o
throuh completely" hile human error can cause the lac* of /00> yield due to the fact of a
part of the experiment not bein done perfectly the yield can be thrown off" Sources of error in
experiments can possibly be caused by a person who didn?t perform an action properly and@or
the measurements not bein correct in the experiment"
(Aeeds to be rewor*s)
Conclusion-
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