Panel Methods: Theory and Method - nuaa.edu.cnaircraftdesign.nuaa.edu.cn/aca/2008/04-Panel...
Transcript of Panel Methods: Theory and Method - nuaa.edu.cnaircraftdesign.nuaa.edu.cn/aca/2008/04-Panel...
Panel Methods: Theory and Method
A Solution for Incompressible Potential Flow
Introduction• Incompressible Potential Flow
– The viscous effects are small in the flowfield
– The speed of the flow must be low everywhere (M < 0.4)
– The flow must be irrotational
• Governing Equations– Laplace’s Equation
– Prandtl-Glauert Equation • For higher subsonic Mach numbers with small disturbances to the
freestream flow
• P-G equation can be converted to Laplace’s equation by a transformation
0)1( 2 =+− ∞ yyxxM φφ
0=+ yyxx φφ
Introduction• The advantages of Panel Method
– Flexibility• Be capable of treating the range of geometries
– Economy• Get results within a relative short time
• A Story about the creation of Panel Method– A.M.O.Smith, “The initial development of panel
methods” in Applied Computational Aerodynamics, P.A. Henne, ed., AIAA, Washington, 1990.
Outline• Some Potential Theory
• Derivation of the Integral Equation for the Potential
• Classic Panel Method
• Program PANEL
• Subsonic Airfoil Aerodynamics
• Issues in the Problem formulation for 3D flow over aircraft
• Example applications of panel methods
• Using Panel Methods
• Advanced panel methods
Some Potential Theory
• Laplace’s Equation
– Since the equation is linear, superposition of solutions can be used.
02 =∇ φ
• Solution to Governing Equations– Field Method
– Singularity Method
Some Potential Theory
• What is “singularities” ?
These are algebraic functions which satisfy Laplace’s equation, and can be combined to construct flow-fields.
The most familiar singularities are the point source, doublet and vortex
• Review on the singularities – Point source– Vortex– Doublet
• Producing a streamline pattern using a uniform flow and a point source
+
• We could superimpose many sources and sinks to get nearly any flow pattern we desired.
• What are the singularity methods ?– The solution is found by distributing “singularities” of
unknown strength over discretized portions of the surface: panels.
– The unknown strengths of the singularities is found by solving a linear set of algebraic equations to determine.
– The equation governing the flow-field is converted from a 3D problem throughout the field to a 2D problem for finding the potential on the surface.
• Boundary Conditions– Dirichlet Problem:
φ on Σ+ k design problem
– Neuman Problem:
∂φ/ ∂n on Σ+ k analysis problem
• Some other key properties of potential flow theory– If either φ or ∂φ/ ∂n is zero everywhere on Σ+
k then φ = 0 at all interior points.
– φ cannot have a maximum or minimum at any interior point.
• Its maximum value can only occur on the surface boundary, and therefore the minimum pressure (and maximum velocity) occurs on the surface.
Derivation of the Integral Equation for the Potential
• Motivation– To obtain an expression for the potential anywhere in the flowfield
in terms of values on the surface bounding the flowfield.
• Gauss Divergence Theorem– The relation between a volume integral and a surface integral
dSdVdivR S
nAA ⋅=∫∫∫ ∫∫
dSgradgraddVR S
n∫∫∫ ∫∫ ⋅−=∇−∇ )()( 22 ωχχωωχχω
• The derivation
Gauss Divergence Theorem
+Laplace’s equation
The integral expression for the potential
• The integral expression for the potential
• Comments on the integral expressionThe problem is to find the values of the unknown source and doublet strengths σ and μ for a specific geometry and given freestream, φ∞.
The requirement to find the solution over the entire flowfield (a 3D problem) is replaced with the problem of finding the solution for the singularity distribution over a surface (a 2D problem).
dSrnr
pBS
)]1(1[)( 41' ∫∫ ∂
∂−−= ∞ μσφφ π
• More comments on the integral expressionAn integral equation to solve for the unknown surface singularity distributions instead of a partial differential equation.The problem is linear, allowing us to use superposition to construct solutions.We have the freedom to pick whether to represent the solution as a distribution of sources or doublets distributed over the surface.The theory can be extended to include other singularities.
• The basic idea of panel method– Approximating the surface by a series of line segments (2D) or
panels (3D)
– Placing distributions of sources and vortices or doublets on each panel.
– Possible differences in approaches to the implementation
• various singularities
• various distributions of the singularity strength over each panel
• panel geometry
• Advantage– No need to define a grid
throughout the flowfield
The Classic Hess and Smith Method
• Starting with the 2D version and using a vortex singularity in place of the doublet singularity
Where θ = tan-1(y/x)
' 14
1 13 : ( ) [ ( )]BS
D p dSr n rπφ φ σ μ∞
∂= − −
∂∫∫
' 14
( ) ( )2 : ( ) [ ln ]2 2s
q s sD p r dsπγφ φ θ
π π∞= − −∫Uniform onset flow
cos sinV x V yα α∞ ∞+ q is the 2D source strength
This is a vortex singularity of strength γ
• The idea of Approach– Break up the surface into straight line segments
– Assume the source strength is constant over each line segment (panel) but has a different value for each panel
– The vortex strength is constant and equal over each panel.
– The potential equation become
1
( )( cos sin ) [ ln ]2 2
N
j panel j
q sV x y r dSγφ α α θπ π∞
=
= + + −∑ ∫
Definition of Each Panel
– Nodes: ith and i+1th
– Inclination to the x axis: θ– Normal and tangential unit vectors:
jitjin iiiiii θθθθ sincos,cossin +=+−=
Where:
i
iii
i
iii l
xxl
yy −=
−= ++ 11 cos,sin θθ
• Representation of Boundary Condition (1)– The flow tangency condition
The coordinates of the midpoint of control point
2
21
1
+
+
+=
+=
iii
iii
yyy
xxx
The velocity components at the control point
),(,),( iiiiii yxvvyxuu ==
Niieachforvuorvu
iiii
iiii
,,1,,0cossin0)cossin()(0…==+−
=+−⋅+⇒=⋅θθ
θθ jijinV
• Representation of Boundary Condition (2)
– The Kutta condition• The flow must leave the trailing edge smoothly.
• Here we satisfy the Kutta condition approximately by equating velocity components tangential to the panels adjacent to the trailing edge on the upper and lower surface.
– The solution is extremely sensitive to the flow details at the trailing edge.
– Make sure that the last panels on the top and bottom are small and of equal length.
tNt uu =1
NtVtV ⋅−=⋅ 1
• Representation of Boundary Condition (3)– The Kutta condition
NtVtV ⋅−=⋅ 1
NNNN
NNNN
vuvuor
vuvu
θθθθ
θθθθ
sincossincos
)sincos()()sincos()(
1111
1111
+−=+
+−⋅+−=+−⋅+ jijijiji
– The boundary conditions derived above are used to construct a system of linear algebraic equations for the strengths of the sources and the vortex.
• Steps to determine the solution1. Write down the velocities, ui, vi, in terms of contributions from all the
singularities.
includes qi, γ from each panel and the influence coefficients which are a function of the geometry only.
2. Find the algebraic equations defining the “influence” coefficients.
3. Write down flow tangency conditions in terms of the velocities (N eqn’s., N+1 unknowns).
4. Write down the Kutta condition equation to get the N+1 equation.
5. Solve the resulting linear algebraic system of equations for the qi, γ.
6. Given qi, γ , write down the equations for uti, the tangential velocity at each panel control point.
7. Determine the pressure distribution from Bernoulli’s equation using the tangential velocity on each panel.
• Step 1. Velocities– The velocity components at any point i are given by
contributions from the velocities induced by the source and vortex distributions over each panel.
∑ ∑
∑ ∑
= =∞
= =∞
++=
++=
N
j
N
jvsji
N
j
N
jvsji
ijij
ijij
vvqVv
uuqVu
1 1
1 1
sin
cos
γα
γα
where qi and γ are the singularity strengths, and the usij, vsij, uvij, and vvij are the influence coefficients.
As an example, the influence coefficient usij is the x-component of velocity at xi due to a unit source distribution over the jth panel.
• Step 2. Influence coefficientsLocal panel coordinate system The influence coefficients
due to the sources:
The influence coefficients due to the vortex distribution:
πβ
π
2
)ln(21
*
1,*
ijS
ij
jis
ij
ij
v
rr
u
=
−= +
)ln(212
1,*
*
ij
jiv
ijv
rr
v
u
ij
ij
+=
=
π
πβ
• Step 3. Flow tangency conditions to get N equations
Nivu iiii ,,1,0cossin …==+− θθ
∑=
+ ==+N
jiNijij NibAqA
11, ,1…γ
where
• Step 4. Kutta Condition to get equation N+1
NNNN vuvu θθθθ sincossincos 1111 +−=+
∑=
++++ =+N
jNNNjjN bAqA
111,1,1 γ
where
• Step 5. Solve the system for qi, γ
∑=
+ ==+N
jiNijij NibAqA
11, ,1…γ
∑=
++++ =+N
jNNNjjN bAqA
111,1,1 γ
• Step 6. Given qi, and γ , write down the equations for the tangential velocity at each panel control point.
• Step 7. Find the surface pressure coefficient
2)(1∞
−=Vu
C i
i
tP
Summary of Classic Panel Method
• Key points1.Write down the velocities, ui, vi, in terms of
contributions from all the singularities,namely qi, γ.
2.Get N eqn’s using flow tangency conditions in terms of the velocities.
3.Get the N+1 equation using the Kutta condition.
4.Solve the resulting linear algebraic system of equations for the qi, γ.