OP Amp Exp2 3March23 2010

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    Inverting & non

    -

    inverting

    OP

    -

    Amplifiers

    RFIC Laboratory

    Academic Advisor : Prof. Nam-Young Kim

    Kwangwoon Univ.

    ITRC RFIC Center17thMar, 2009

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    Contents

    Objectives

    Theory of Non-inverter OP Amplifier

    Theory of inverter OP Amplifier

    Applications of Operational Amplifiers

    Simulation and Results

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    Objectives

    1. To Familiarize the Application of Op-amp as a Non-Inverting Amplifier

    2. To Familiarize the Application of Op-amp as an

    Inverting Amplifier

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    Non-inverting Amplifier

    Vi

    V

    V

    d

    2

    +

    - Vo

    R

    R

    2

    1

    The voltage at both inputs must be equal.

    No current flows into either of the op-amps inputs, so potential divider

    R1 and R2 determine the voltage at the inverting input.

    So voltage Vi applied to the non-inverting input causes the output

    voltage to become positive until the fraction at the inverting input is equal.

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    Non-inverter Op-Amplifier

    Non-inverter OP Amplifier

    Vi

    V

    V

    d

    2

    +

    - Vo

    R

    R

    2

    1

    2 1

    2

    1

    2

    1

    0 for

    1

    O

    IO I

    O

    I

    vv v A

    A

    vv v RR

    v R

    v R

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    Non-inverting Amplifier

    Vi

    V

    V

    d

    2

    +

    - Vo

    R

    R

    2

    1

    In another way,

    If, V0= AVd

    Vd= ViV2

    Then, V2= V0xR2/(R1+R2)

    Considering that,

    V2 = V0

    So, = V2/V0= R2/(R1+R2)

    Then, V0 = A Vd = A (Vi - V0)

    Hence, the closed loop gain of the amplifier becomes,

    ACL= VO/Vi = A /(1 + A)

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    1

    2

    2

    1

    211

    11

    11

    0

    RR

    vv

    RR

    vRivv

    Rv

    Rvvi

    I

    O

    IO

    II

    +

    Closed-loopOpen-loop

    A -R2 /R1

    Poor Good

    Gain

    Accuracy

    Inverting type Amplifier

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    Inverter Op-Amplifier

    Inverting type OP Amplifier

    Vi

    +

    -

    Vo

    R

    R

    2

    1

    V d

    I = (VdV0)/R2= (VdAVd)/R2= (1-A)Vd/R2

    Vi = IR1

    And, V0 = - IR2

    So, Closed loop gain of Inverting amplifier becomes,

    ACL= V0/Vi= -IR2/IR1= - R2/R1

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    Application of Op-amps

    Analog Calculators

    Voltage Comparator

    Digital to analog Converter (DAC)

    Analog to digital Converter (ADC)

    Summers

    Differentiators

    Integrators

    Precision Rectifiers

    Voltage Clampers

    Amplifiers with various gain Oscillators and

    Waveform Generators etc..

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    Application of Op-Amp: Weighted Summer

    1 2

    1 2

    1 2

    1 2

    1 21 2

    , , ...,

    ...

    0

    ...

    nn

    n

    n

    O f f

    f f f

    O nn

    vv vi i i

    R R Ri i i i

    v iR iR

    R R R

    v v v vR R R

    +

    -

    -

    +

    Ov

    1R

    fR

    2R

    nR

    1i

    2i

    ni

    i

    0 V

    1v

    2v

    nv

    i

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    Modified Inverting Configuration for HigherRi

    3

    4

    2

    4

    1

    2

    1 R

    R

    R

    R

    R

    R

    v

    v

    GI

    O

    For G= 100 andRi= 1 MW

    R1= 1 MW,R2=R4= 1 MW,R3=10.2 kW

    Compared toR1= 1 MW, andR2= 100 MWfor the conventional case

    +

    -

    +

    -+

    -

    -

    +Iv

    1v

    1i

    2i

    3i

    4i

    Ov

    1R

    2R

    3R

    4R

    0

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    Non-Inverting Amplifier Simulation

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    Non-Inverting Amplifier Simulation Result

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    Inverting Amplifier Simulation

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    Inverting Amplifier Simulation Result

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    Thank You!

    Any Questions Please.

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    I have some questions.

    Why is it named Operational Amplifier (Op-amp)?

    What is the meaning of open-loop gain?

    What do you mean by closed-loop gain?

    Why Op-amp is also called versatile amplifier?