16 october 2013 to 22 october 2013, hindu sabha varta, year 37, issue-28
October 28, 2013
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Transcript of October 28, 2013
Solving Compound and Absolute Value Inequalities
Warm Up
1)Three –fourths of the difference between a number and six is no more than the quotient of that number and four
2. 4x + 1 > x - 2
2 3
4. Glynn has to drive 450 miles. His car has an 18 gallon gas tank and he would like to make the trip on one tank of gas. What is the minimum miles per gallon his car would have to get to make the trip on one tank? Write an inequality to show .
5. Solve for x if ax + by = c
Warm Up
6. -3(2x - 3) + 7x = -4(x - 5) + 6x – 2
7. Simplify: -6 - (-3) + (-2) * 4 =
8.
10. -2|x - 7|- 4 = -22
A compound inequality consists of two inequalities joinedby the word and or the word or.
To solve a compound inequality, you must solve each part of the inequality separately. Conjunctions are solved when both parts of the inequality are true
A. Conjunctions: Two inequalities joined by the word ‘and’.
For example: -1 < x and x < 4; This can also be written -1 < x < 4
x
-1 4
-1 < x < 4; x > -1 < 4
The graph of a compound inequality containing the word ‘and’ is the intersection of the solution set of the two inequalities. TheIntersection is the solution for the compound inequality.
Solving Compound and Absolute Value Inequalities
All compound inequalities divide the number line into three separate regions.
Solving Compound and Absolute Value Inequalities
x
y z
A compound inequality containing the word and is trueif and only if (iff), both inequalities are true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
1x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word and is trueif and only if (iff), both inequalities are true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
1x
2x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word and is true if and only if (iff), both inequalities are true.
A compound inequality containing the word and is true if and only if (iff), both inequalities are true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
1x
2x
2
1
x
and
x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word and is trueif and only if (iff), both inequalities are true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
2
1
x
and
x
Solving Compound and Absolute Value Inequalities
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
1x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word or is true one or more, of the inequalities is true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
1x
3x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word or is true one or more, of the inequalities is true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
1x
3x
3
1
x
or
x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word or is true one or more, of the inequalities is true.
x
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Example:
3
1
x
or
x
Solving Compound and Absolute Value Inequalities
A compound inequality containing the word or is true one or more, of the inequalities is true.
x
A compound inequality divides the number line into three separate regions.
The solution set will be found:
in the blue (middle) region
zy
or
in the red (outer) regions.
Solving Compound and Absolute Value Inequalities
Solve an Absolute Value Inequality (<)
You can interpret |a| < 4 to mean that the distance between a and 0 on a number
line is less than 4 units.
Solving Compound and Absolute Value Inequalities
Solve an Absolute Value Inequality (<)
You can interpret |a| < 4 to mean that the distance between a and 0 on a number
line is less than 4 units.
To make |a| < 4 true, you must substitute numbers for a that are fewer than 4 units
from 0.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (<)
You can interpret |a| < 4 to mean that the distance between a and 0 on a number
line is less than 4 units.
To make |a| < 4 true, you must substitute numbers for a that are fewer than 4 units
from 0.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (<)
You can interpret |x| < 4 to mean that the distance between a and 0 on a number
line is less than 4 units.
To make |a| < 4 true, you must substitute numbers for x that are fewer than 4 units
from 0.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (<)
You can interpret |x| < 4 to mean that the distance betweenax and 0 on a number line is less than 4 units.
To make |x| < 4 true, you must substitute numbers for x that are fewer than 4 units
from 0.
Notice that the graph of |x| < 4 is the sameas the graph x > -4 and x < 4.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (<)
You can interpret |x| < 4 to mean that the distance between xa and 0 on a number
line is less than 4 units.
To make |x| < 4 true, you must substitute numbers for x that are fewer than 4 units
from 0.
Notice that the graph of |x| < 4 is the sameas the graph x > -4 and x < 4.
All of the numbers between -4 and 4 are less than 4 units from 0.The solution set is { x | -4 < x < 4 }
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (<)
You can interpret |a| < 4 to mean that the distance between a and 0 on a number
line is less than 4 units.
To make |a| < 4 true, you must substitute numbers for a that are fewer than 4 units
from 0.
Notice that the graph of |a| < 4 is the same
as the graph a > -4 and a < 4.
All of the numbers between -4 and 4 are less than 4 units from 0.
The solution set is { a | -4 < a < 4 }
For all real numbers a and b, b > 0, the following statement is true:
If |a| < b then, -b < a < b
Solving Compound and Absolute Value Inequalities
x
A compound inequality divides the number line into three separate regions.
The solution set will be found:
in the blue (middle) region
y z
or
in the red (outer) regions.
Solving Compound and Absolute Value Inequalities
Solve an Absolute Value Inequality (>)
Solving Compound and Absolute Value Inequalities
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
Solving Compound and Absolute Value Inequalities
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
To make |a| > 2 true, you must substitute numbers for a that are more than 2 units
from 0.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
To make |a| > 2 true, you must substitute numbers for a that are more than 2 units
from 0.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
To make |a| > 2 true, you must substitute numbers for a that are more than 2 units
from 0.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
To make |a| > 2 true, you must substitute numbers for a that are more than 2 units
from 0.
Notice that the graph of |a| > 2 is the same
as the graph a < -2 or a > 2.
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
To make |a| > 2 true, you must substitute numbers for a that are more than 2 units
from 0.
Notice that the graph of |a| > 2 is the same
as the graph a < -2 or a > 2.
All of the numbers not between -2 and 2 are greater than 2 units from 0.
The solution set is { a | a > 2 or a < -2 }
Solving Compound and Absolute Value Inequalities
5-4 -2 0 2 4-5 -3 1 5-1-5 3
Solve an Absolute Value Inequality (>)
You can interpret |a| > 2 to mean that the distance between a and 0 on a number
line is greater than 2 units.
To make |a| > 2 true, you must substitute numbers for a that are more than 2 units
from 0.
Notice that the graph of |a| > 2 is the same
as the graph a < -2 or a > 2.
All of the numbers not between -2 and 2 are greater than 2 units from 0.
The solution set is { a | a > 2 or a < -2 }
For all real numbers a and b, b > 0, the following statement is true:
If |a| > b then, a < -b or a > b
Solving Compound and Absolute Value Inequalities
Solving Compound and Absolute Value Inequalities
Credits
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Using Glencoe’s Algebra 2 text,
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