Nut Calories – Pretzel Calories
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Transcript of Nut Calories – Pretzel Calories
Nut Calories – Pretzel Calories
Nut Calories – Pretzel Calories
Mass = 4.12g
Nut Calories – Pretzel Calories
Mass = 4.12gMass Al Cup= 27.65 g
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al and water = 96.54g
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al and water = 96.54g
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al and water = 96.54gInitial Temp =22 oC
Nut Calories – Pretzel Calories
Mass = 4.12g
Mass of Al and water = 96.54gInitial Temp 22 C
Heat
Nut Calories – Pretzel Calories
Mass = 4.12g
Mass of Al and water = 96.54gInitial Temp 22 C
Heat
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al and water = 96.54gInitial Temp 22 oC
Heat
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al and water = 96.54gInitial Temp 22 oC
Heat
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change) ( mass of water)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change) ( mass of water) (specific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released =( water temp change)( mass of water)(H2Ospecific heat capacity) + ( Al temp change) ( mass ofAl ) (specific heat capacity of Al)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= (96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C) +
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C)
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C))
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C))
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cak / g C))
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) ( 1 cal / g C)) + (( 27.65g ) (48 C – 22 C ) (.21 cal / g C))
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) * ( 1 cal / g C)) + (( 27.65g ) * (48 C – 22 C ) *(.21 cal / g C)) = 1942.109 cal = 1.9 x103 cal
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) * ( 1 cal / g C)) + (( 27.65g ) * (48 C – 22 C ) *(.21 cal / g C)) = 1942.109 cal = 1.9 x103 cal
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released= ((96.54g-27.65g)(48 C – 22 C ) * ( 1 cal / g C)) + (( 27.65g ) * (48 C – 22 C ) *(.21 cal / g C)) = 1942.109 cal = 1.9 x103 cal
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released per gram = 1.9 x103 cal / 4.12 g =
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released per gram = 1.9 x103 cal / 4.12 g =
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released per gram = 1.9 x103 cal =461.16 cal/g 4.12 g
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released per gram = 1.9 x103 cal =461.16 cal/g=4.6x102cal/g 4.12 g
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released per gram = 1.9 x103 cal / 4.12 g = 461 cal / g=4.6x102cal/g 461 cal/g ( 1 kcal / 1000 cal ) = .46 kcal
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
Heat released per gram = 1.9 x103 cal / 4.12 g = 461 cal / g461 cal/g ( 1 kcal / 1000 cal ) = .46 kcalAccepted Value from package = 110 Kcal / 28.3 g = 3.9Kal/g
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
461 cal/g ( 1 kcal / 1000 cal ) = .46 kcalAccepted Value from package = 110 Kcal / 28.3 g = 3.9Kal/g% difference = (experimental – accepted ) / accepted * 100
Nut Calories – Pretzel Calories
Mass = 4.12gMass of Al =27.65g Mass of Al and water = 96.54gInitial Temp 22 oCFinal Temp = 48oCHeat
461 cal/g ( 1 kcal / 1000 cal ) = .46 kcalAccepted Value from package = 110 Kcal / 28.3 g = 3.9Kal/g% difference = (experimental – accepted ) / accepted * 100% = (.46 Kcal/g -3.9 Kcal/g ) / 3.9 kcal/g * 100 = - 88 %
Results: The following data can be used to:
Mass of cashew=1.34g
Mass of aluminium cup = 19.83g
Mass of aluminium cup and water=90.76g
Initial temperature of Al cup and H2O=21.2oC
Final temperature of Al cup and H2O=68.8oC
Specific heat capacity of water = 1.0 cal / g oC
Specific heat capacity of Al = .21 cal / g oC
1 Cal = 1 kcal = 1000 cal
1 cal = 4.18 J
1 kJ = 1000 J
.Calculations / Conclusions
1. The heat released by the nut was absorbed by the Water and the Al cup.
The amount of energy absorbed by a substance is dependent on its specific heat capacity, its mass , and its temperature change.
Q= (mw tw * 1 cal / g oC) + (mAl tAl * .21 cal / g o
C)
Q = (90.76g – 19.83g) (68.8oC – 21.2oC) ( 1 cal/g oC) +
((19.83g) (68.8oC – 21.2oC) ( .21 cal/g oC))
Q= 3574.48 cal 3570 cal 3.57x103 cal
2. Determine the number of calories per gram of food burned.
cal = 3570 cal = 2664.179 cal / g 2.66x103cal/g
g (1.34g )
3. Convert the number of calories per gram to Calories or kcal per gram.
2.66x103cal/g ( 1 kcal) = 2.66 kcal / g
(1000cal)
4. Convert the number of cal per gram to J per gram.
2.66x103cal/g ( 4.18 J) = 11,118.8 J / g 1.11x104 J/g
( 1 cal)
5. Convert the number of cal per gram to KJ per gram
1.11x104 J/g ( 1 KJ ) = 11.1 KJ/g
(1000 J)
6. According to the packaging the nut should release 250 kcal per 42 grams.(cashews)
=5.95kcal/g
a) What is your percent error in your experiment?
% error = ( your value – accepted value ) * 100 =
( accepted value )
% error = (2.66 kcal/g – (5.95kcal/g))*100 = -55.3% error
(5.95 kcal/g )