Notes 2 Forces & Moments

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    F2009abn

    three

    forces and

    moments

    ARCHITECTURAL STRUCTURES:

    FORM, BEHAVIOR, ANDDESIGNARCH 331

    DR. ANNENICHOLS

    FALL 2013

    Forces & Moments 1

    Lecture 3

    Architectural Structures

    ARCH 331

    lecture

    Structural Planning 32Lecture 3 Foundations StructuresARCH 331 F2008abn

    Structural Math

    quantify environmental loads

    how big is it?

    evaluate geometry and angles where is it?

    what is the scale?

    what is the size in a particular direction?

    quantify what happens in the structure

    how big are the internal forces?

    how big should the beam be?

    Structural Planning 33Lecture 3

    Foundations StructuresARCH 331

    F2008abn

    Structural Math

    physics takes observable phenomena

    and relates the measurement with rules:

    mathematical relationships need

    reference frame

    measure of length, mass, time, direction,

    velocity, acceleration, work, heat,

    electricity, light

    calculations & geometry

    Structural Planning 34Lecture 3

    Foundations StructuresARCH 331

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    Physics for Structures

    measures

    US customary & SI

    litergallonVolume

    Temperature

    Force

    Mass

    Length

    Units

    CF

    N, kNlb force

    g, kglb mass

    mm, cm, min, ft, mi

    SIUS

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    Structural Planning 35Lecture 3

    Foundations StructuresARCH 331

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    Physics for Structures

    scalars any quantity

    vectors - quantities with direction

    like displacements

    summation results in

    the straight line path

    from start to end

    normal vector is perpendicular to

    something

    y

    x

    z

    Structural Planning 36

    Lecture 3

    Foundations Structures

    ARCH 331

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    Language

    symbols for operations: +,-, /, x

    symbols for relationships: (), =,

    algorithms cancellation

    factors

    signs

    ratios and proportions

    power of a number

    conversions, ex. 1X = 10 Y

    operations on both sides of equality

    3

    1

    32

    2

    6

    2

    6

    5

    5

    2

    3

    1

    6

    x

    1000103

    110

    1

    1

    10

    Y

    Xor

    X

    Y

    F2008abnStructural Planning 37Lecture 3

    Architectural StructuresARCH 331

    On-line Practice

    eCampus / Study Aids

    Structural Planning 38Lecture 3

    Foundations StructuresARCH 331

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    Geometry

    angles

    right = 90

    acute < 90

    obtuse > 90

    = 180

    triangles

    area

    hypotenuse

    total of angles = 180

    2

    hb

    222 BCACAB

    A

    B

    C

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    Structural Planning 39Lecture 3

    Foundations StructuresARCH 331

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    Geometry

    lines and relation to angles

    parallel lines cant intersect

    perpendicular lines cross at 90

    intersection of two lines is a point

    opposite angles are equal when

    two lines cross

    Structural Planning 40

    Lecture 3

    Foundations Structures

    ARCH 331

    F2008abn

    Geometry

    intersection of a line with

    parallel lines results in identical

    angles

    two lines intersect in the same

    way, the angles are identical

    Structural Planning 41

    Lecture 3

    Foundations Structures

    ARCH 331

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    Geometry

    sides of two angles are parallel and

    intersect opposite way, the angles are

    supplementary - the sum is 180

    two angles that sum to 90 are said to be

    complimentary

    90

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    90

    Geometry

    sides of two angles bisect a right angle

    (90), the angles are complimentary

    right angle bisects a straight line,

    remaining angles

    are complimentary

    Forces & Moments 12

    Lecture 3

    Foundations Structures

    ARCH 331

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    Structural Planning 43

    Lecture 3

    Foundations Structures

    ARCH 331

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    similar triangles have proportional sides

    Geometry

    B

    C

    E

    A

    A

    BC

    A

    C

    B

    DE

    BC

    AE

    AC

    AD

    AB

    CB

    BC

    CA

    AC

    BA

    AB

    D

    Structural Planning 44

    Lecture 3

    Foundations Structures

    ARCH 331

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    Trigonometry

    for right triangles

    C

    B

    A

    CBAB

    hypotenusesideopposite sinsin

    CB

    AC

    hypotenuse

    sideadjacent coscos

    AC

    AB

    sideadjacent

    sideopposite tantan

    SOHCAHTOA

    Structural Planning 45Lecture 3

    Foundations StructuresARCH 331

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    Trigonometry

    cartesian coordinate system

    origin at 0,0

    coordinates

    in (x,y) pairs

    x & y have

    signs

    -6

    -5

    -4

    -3

    -2

    -1

    0

    1

    2

    3

    4

    5

    6

    -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6

    X

    Y

    Quadrant IQuadrant II

    Quadrant III Quadrant IV

    Structural Planning 46

    Lecture 3

    Foundations Structures

    ARCH 331

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    Trigonometry

    for angles starting at positive x

    sin is y side

    cos is x side

    -6

    -5

    -4

    -3

    -2

    -1

    0

    1

    2

    3

    4

    5

    6

    -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6

    X

    Y

    sin

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    Structural Planning 47

    Lecture 3

    Foundations Structures

    ARCH 331

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    Trigonometry

    for all triangles

    sides A, B & C are opposite

    angles , &

    LAW of SINES

    LAW of COSINES

    CBA

    sinsinsin

    cos2222 BCCBA

    A

    C

    B

    Structural Planning 48Lecture 3 Foundations StructuresARCH 331 F2008abn

    Algebra

    equations (something = something)

    constants

    real numbers or shown with a, b, c... unknown terms, variables

    names like R, F, x, y

    linear equations

    unknown terms have no exponents

    simultaneous equations

    variable set satisfies all equations

    Structural Planning 49Lecture 3

    Foundations StructuresARCH 331

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    Algebra

    solving one equation

    only works with one variable

    ex: add to both sides

    divide both sides

    get x by itself on a side

    012 x 10112 x

    21x2

    1

    2

    2

    x

    12 x

    Structural Planning 50Lecture 3 Foundations StructuresARCH 331 F2008abn

    Algebra

    solving one equations

    only works with one variable

    ex: subtract from both sides

    subtract from both sides

    divide both sides

    get x by itself on a side

    5412 xx

    xxxx 254212

    55251 x

    2

    2

    2

    23

    2

    6

    x

    3x

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    Structural Planning 51Lecture 3

    Foundations StructuresARCH 331

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    Algebra

    solving two equation

    only works with two variables

    ex: look for term similarity

    can we add or subtract to eliminate one term?

    add

    get x by itself on a side

    832 yx6312 yx

    6831232 yxyx

    1414 x

    114

    14

    14

    14 x

    x

    Point Equilibrium 2Lecture 4 Foundations StructuresARCH 331 F2008abn

    Forces

    statics

    physics of forces and reactions on bodies

    and systems equilibrium (bodies at rest)

    forces

    something that exerts on an object:

    motion

    tension

    compression

    Point Equilibrium 3Lecture 4

    Foundations StructuresARCH 331

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    Force

    action of one body on another that

    affects the state of motion or rest of the

    body

    Newtons 3rd law:

    for every force of action

    there is an equal and

    opposite reaction along

    the same line

    http://www.physics.umd.edu

    Point Equilibrium 4Lecture 4 Foundations StructuresARCH 331 F2008abn

    Force Characteristics

    applied at a point

    magnitude

    Imperial units: lb, k (kips) SI units: N (newtons), kN

    direction

    (tail) (tip)

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    Point Equilibrium 5

    Lecture 4

    Foundations Structures

    ARCH 331

    F2008abn

    for statics, the bodies are ideally rigid

    can translate

    and rotate internal forces are

    in bodies

    between bodies (connections)

    external forces act on bodies

    Forces on Rigid Bodies

    translate rotate

    Point Equilibrium 6

    Lecture 4

    Foundations Structures

    ARCH 331

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    the force stays on the same line ofaction

    truck cant tell the difference

    only valid for EXTERNAL forces

    Transmissibility

    =

    Point Equilibrium 7Lecture 4

    Foundations StructuresARCH 331

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    Force System Types

    collinear

    Point Equilibrium 8Lecture 4 Foundations StructuresARCH 331 F2008abn

    Force System Types

    coplanar

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    Point Equilibrium 9Lecture 4

    Foundations StructuresARCH 331

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    Force System Types

    space

    Point Equilibrium 10Lecture 4

    Foundations StructuresARCH 331

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    Adding Vectors

    graphically

    parallelogram law

    diagonal long for 3 or more vectors

    tip-to-tail

    more convenient

    with lots of vectors

    F

    P

    R

    F

    P

    R

    Point Equilibrium 11Lecture 4

    Foundations StructuresARCH 331

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    Force Components

    convenient to resolve into 2 vectors

    at right angles

    in a

    nice

    coordinate system

    is between Fxand F from FxFy

    Fx

    F

    x

    y

    Fy

    Fx

    F

    Fy

    Fx

    F

    cosFFx

    sinFFy

    22

    yx FFF

    x

    y

    F

    Ftan

    Point Equilibrium 12Lecture 4 Foundations StructuresARCH 331 F2008abn

    Trigonometry

    Fx is negative

    90 to 270

    Fy is negative 180 to 360

    tan is positive

    quads I & III

    tan is negative

    quads II & IV -6-5

    -4

    -3

    -2

    -1

    0

    1

    2

    3

    45

    6

    -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6

    X

    Y

    Quadrant IQuadrant II

    Quadrant III Quadrant IV

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    Point Equilibrium 13Lecture 4

    Foundations StructuresARCH 331

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    Component Addition

    find all x components

    find all y components

    find sum of x components, Rx(resultant)

    find sum of y components, Ry

    22

    yx RRR

    x

    y

    R

    Rtan

    Fy

    Fx

    R

    Py

    Px

    Rx

    Ry

    Point Equilibrium 14Lecture 4 Foundations StructuresARCH 331 F2008abn

    Alternative Trig for Components

    doesnt relate angle to axis direction

    is small angle between F and

    EITHER Fxor Fy

    no sign out of calculator!

    have to choose RIGHT

    trig function, resulting

    direction (sign) and

    component axis

    +/-? Fy

    +/-? Fx

    F

    x

    y

    Point Equilibrium 23Lecture 4 Foundations StructuresARCH 331 F2008abn

    Friction

    resistance to movement

    contact surfaces determine

    proportion of normal force () opposite to slide direction

    static > kinetic

    NF

    Point Equilibrium 24Lecture 4 Foundations StructuresARCH 331 F2008abn

    Cables

    simple

    uses

    suspension bridges roof structures

    transmission lines

    guy wires, etc.

    have same tension all along

    cant stand compression

    http:// nisee.berkeley.edu/godden

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    Point Equilibrium 25

    Lecture 4

    Foundations Structures

    ARCH 331

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    Cables Structures

    use high-strength steel

    need

    towers

    anchors

    dont want movement

    http:// nisee.berkeley.edu/godden

    Point Equilibrium 26Lecture 4 Foundations StructuresARCH 331 F2008abn

    Cable Structures

    Point Equilibrium 27Lecture 4

    Foundations StructuresARCH 331

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    Cable Loads

    straight line

    between forces

    with one force concurrent

    symmetric

    Point Equilibrium 28Lecture 4

    Foundations StructuresARCH 331

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    Cable Loads

    shape directly

    related to the

    distributed load

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    Point Equilibrium 30

    Lecture 4

    Foundations Structures

    ARCH 331

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    Cable-Stayed Structures

    diagonal cables support horizontal

    spans

    typically symmetrical Patcenter,

    Rogers 1986

    www.columbia.edu

    Point Equilibrium 31Lecture 4 Foundations StructuresARCH 331 F2008abn

    Patcenter, Rogers 1986

    column free space

    roof suspended

    solid steel ties

    steel frame supports masts

    Point Equilibrium 32Lecture 4

    Foundations StructuresARCH 331

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    Patcenter, Rogers 1986

    dashes cables pulling

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    Moments

    forces have the tendency to make abody rotate about an axis

    same translation but different rotation

    Forces & Moments 44

    Lecture 3

    Foundations Structures

    ARCH 331

    http://www.physics.umd.edu

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    Moments

    Forces & Moments 45

    Lecture 3

    Foundations Structures

    ARCH 331 Rigid Body Equilibrium 4

    Lecture 6

    Foundations Structures

    ARCH 331

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    Moments

    a force acting at a different point causes

    a different moment:

    F2011abn

    Moments

    defined by magnitude and direction

    units: Nm, kft

    direction:

    + ccw (right hand rule)

    - cw

    value found from Fand distance

    d also called lever or moment arm

    Forces & Moments 47

    Lecture 3

    Foundations Structures

    ARCH 331

    F

    A

    C

    B

    F

    d

    Rigid Body Equilibrium 6

    Lecture 6

    Foundations Structures

    ARCH 331

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    Moments

    with same F:

    21 dFMdFM AA (bigger)

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    Rigid Body Equilibrium 7

    Lecture 6

    Foundations Structures

    ARCH 331

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    Moments

    additive with sign convention

    can still move the force

    along the line of action

    =

    +MA = Fd

    MB = Fd

    d

    F

    A

    Bd

    MA = Fd

    MB = Fd

    d

    F

    A

    B

    d

    F2009abn

    Moments

    Varignons Theorem

    resolve a force into components at a point

    and finding perpendicular distances calculate sum of moments

    equivalent to original moment

    makes life easier!

    geometry

    when component runs through point, d=0

    Forces & Moments 50

    Lecture 3

    Foundations Structures

    ARCH 331

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    Moments of a Force

    moments of a force

    introduced in Physics as

    Torque Acting on a Particle

    and used to satisfy rotational equilibrium

    Forces & Moments 51Lecture 3

    Foundations StructuresARCH 331 F2009abn

    Physics and Moments of a Force

    my Physics book:

    Forces & Moments 52Lecture 3

    Foundations StructuresARCH 331

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    Rigid Body Equilibrium 11

    Lecture 6

    Foundations Structures

    ARCH 331

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    2 forces

    same size

    opposite direction distance d apart

    cw or ccw

    not dependant on point of application

    Moment Couples

    d

    F

    A

    d1

    d2

    F

    dFM

    21

    dFdFM

    F2009abn

    Moment Couples

    equivalent couples

    same magnitude and direction

    F & d may be different

    Forces & Moments 54

    Lecture 3

    Foundations Structures

    ARCH 331

    100 mm

    300 N

    300 N

    150 mm200 N

    200 N

    250 mm

    120 N120 N

    F2009abn

    Moment Couples

    added just like moments caused by one

    force

    can replace two couples with a single

    couple

    Forces & Moments 55

    Lecture 3

    Foundations Structures

    ARCH 331

    +=

    100 mm

    300 N

    300 N

    150 mm200 N

    200 N

    250 mm

    240 N240 N

    F2009abn

    Moment Couples

    moment couples in structures

    Forces & Moments 56

    Lecture 3

    Foundations Structures

    ARCH 331

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    Equivalent Force Systems

    two forces at a point is equivalent to theresultant at a point

    resultant is equivalent to twocomponents at a point

    resultant of equal & opposite forces at apoint is zero

    put equal & opposite forces at a point(sum to 0)

    transmission of a force along action line

    Forces & Moments 57

    Lecture 3

    Foundations Structures

    ARCH 331 Rigid Body Equilibrium 16

    Lecture 6

    Foundations Structures

    ARCH 331

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    single force causing a moment can be

    replaced by the same force at a

    different point by providing the momentthat force caused

    moments are shown as arched arrows

    Force-Moment Systems

    -F

    FF

    d

    A

    AF

    A

    A

    Rigid Body Equilibrium 17Lecture 6

    Foundations StructuresARCH 331

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    Force-Moment Systems

    a force-moment pair can be replaced by

    a force at another point causing the

    original moment

    F

    d

    -F

    F

    A

    AF

    A

    A

    F M=Fd

    A

    A

    Rigid Body Equilibrium 18Lecture 6 Foundations StructuresARCH 331 F2008abn

    Parallel Force Systems

    forces are in the same direction

    can find resultant force

    need to find location for equivalentmoments

    R=A+B

    C Dx

    AB

    ab

    a

    B

    xBA )(

    C D