Notes 2 Forces & Moments
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7/27/2019 Notes 2 Forces & Moments
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1
F2009abn
three
forces and
moments
ARCHITECTURAL STRUCTURES:
FORM, BEHAVIOR, ANDDESIGNARCH 331
DR. ANNENICHOLS
FALL 2013
Forces & Moments 1
Lecture 3
Architectural Structures
ARCH 331
lecture
Structural Planning 32Lecture 3 Foundations StructuresARCH 331 F2008abn
Structural Math
quantify environmental loads
how big is it?
evaluate geometry and angles where is it?
what is the scale?
what is the size in a particular direction?
quantify what happens in the structure
how big are the internal forces?
how big should the beam be?
Structural Planning 33Lecture 3
Foundations StructuresARCH 331
F2008abn
Structural Math
physics takes observable phenomena
and relates the measurement with rules:
mathematical relationships need
reference frame
measure of length, mass, time, direction,
velocity, acceleration, work, heat,
electricity, light
calculations & geometry
Structural Planning 34Lecture 3
Foundations StructuresARCH 331
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Physics for Structures
measures
US customary & SI
litergallonVolume
Temperature
Force
Mass
Length
Units
CF
N, kNlb force
g, kglb mass
mm, cm, min, ft, mi
SIUS
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Structural Planning 35Lecture 3
Foundations StructuresARCH 331
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Physics for Structures
scalars any quantity
vectors - quantities with direction
like displacements
summation results in
the straight line path
from start to end
normal vector is perpendicular to
something
y
x
z
Structural Planning 36
Lecture 3
Foundations Structures
ARCH 331
F2008abn
Language
symbols for operations: +,-, /, x
symbols for relationships: (), =,
algorithms cancellation
factors
signs
ratios and proportions
power of a number
conversions, ex. 1X = 10 Y
operations on both sides of equality
3
1
32
2
6
2
6
5
5
2
3
1
6
x
1000103
110
1
1
10
Y
Xor
X
Y
F2008abnStructural Planning 37Lecture 3
Architectural StructuresARCH 331
On-line Practice
eCampus / Study Aids
Structural Planning 38Lecture 3
Foundations StructuresARCH 331
F2008abn
Geometry
angles
right = 90
acute < 90
obtuse > 90
= 180
triangles
area
hypotenuse
total of angles = 180
2
hb
222 BCACAB
A
B
C
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Structural Planning 39Lecture 3
Foundations StructuresARCH 331
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Geometry
lines and relation to angles
parallel lines cant intersect
perpendicular lines cross at 90
intersection of two lines is a point
opposite angles are equal when
two lines cross
Structural Planning 40
Lecture 3
Foundations Structures
ARCH 331
F2008abn
Geometry
intersection of a line with
parallel lines results in identical
angles
two lines intersect in the same
way, the angles are identical
Structural Planning 41
Lecture 3
Foundations Structures
ARCH 331
F2008abn
Geometry
sides of two angles are parallel and
intersect opposite way, the angles are
supplementary - the sum is 180
two angles that sum to 90 are said to be
complimentary
90
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90
Geometry
sides of two angles bisect a right angle
(90), the angles are complimentary
right angle bisects a straight line,
remaining angles
are complimentary
Forces & Moments 12
Lecture 3
Foundations Structures
ARCH 331
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Structural Planning 43
Lecture 3
Foundations Structures
ARCH 331
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similar triangles have proportional sides
Geometry
B
C
E
A
A
BC
A
C
B
DE
BC
AE
AC
AD
AB
CB
BC
CA
AC
BA
AB
D
Structural Planning 44
Lecture 3
Foundations Structures
ARCH 331
F2008abn
Trigonometry
for right triangles
C
B
A
CBAB
hypotenusesideopposite sinsin
CB
AC
hypotenuse
sideadjacent coscos
AC
AB
sideadjacent
sideopposite tantan
SOHCAHTOA
Structural Planning 45Lecture 3
Foundations StructuresARCH 331
F2008abn
Trigonometry
cartesian coordinate system
origin at 0,0
coordinates
in (x,y) pairs
x & y have
signs
-6
-5
-4
-3
-2
-1
0
1
2
3
4
5
6
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
X
Y
Quadrant IQuadrant II
Quadrant III Quadrant IV
Structural Planning 46
Lecture 3
Foundations Structures
ARCH 331
F2008abn
Trigonometry
for angles starting at positive x
sin is y side
cos is x side
-6
-5
-4
-3
-2
-1
0
1
2
3
4
5
6
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
X
Y
sin
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Structural Planning 47
Lecture 3
Foundations Structures
ARCH 331
F2008abn
Trigonometry
for all triangles
sides A, B & C are opposite
angles , &
LAW of SINES
LAW of COSINES
CBA
sinsinsin
cos2222 BCCBA
A
C
B
Structural Planning 48Lecture 3 Foundations StructuresARCH 331 F2008abn
Algebra
equations (something = something)
constants
real numbers or shown with a, b, c... unknown terms, variables
names like R, F, x, y
linear equations
unknown terms have no exponents
simultaneous equations
variable set satisfies all equations
Structural Planning 49Lecture 3
Foundations StructuresARCH 331
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Algebra
solving one equation
only works with one variable
ex: add to both sides
divide both sides
get x by itself on a side
012 x 10112 x
21x2
1
2
2
x
12 x
Structural Planning 50Lecture 3 Foundations StructuresARCH 331 F2008abn
Algebra
solving one equations
only works with one variable
ex: subtract from both sides
subtract from both sides
divide both sides
get x by itself on a side
5412 xx
xxxx 254212
55251 x
2
2
2
23
2
6
x
3x
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Structural Planning 51Lecture 3
Foundations StructuresARCH 331
F2008abn
Algebra
solving two equation
only works with two variables
ex: look for term similarity
can we add or subtract to eliminate one term?
add
get x by itself on a side
832 yx6312 yx
6831232 yxyx
1414 x
114
14
14
14 x
x
Point Equilibrium 2Lecture 4 Foundations StructuresARCH 331 F2008abn
Forces
statics
physics of forces and reactions on bodies
and systems equilibrium (bodies at rest)
forces
something that exerts on an object:
motion
tension
compression
Point Equilibrium 3Lecture 4
Foundations StructuresARCH 331
F2008abn
Force
action of one body on another that
affects the state of motion or rest of the
body
Newtons 3rd law:
for every force of action
there is an equal and
opposite reaction along
the same line
http://www.physics.umd.edu
Point Equilibrium 4Lecture 4 Foundations StructuresARCH 331 F2008abn
Force Characteristics
applied at a point
magnitude
Imperial units: lb, k (kips) SI units: N (newtons), kN
direction
(tail) (tip)
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Point Equilibrium 5
Lecture 4
Foundations Structures
ARCH 331
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for statics, the bodies are ideally rigid
can translate
and rotate internal forces are
in bodies
between bodies (connections)
external forces act on bodies
Forces on Rigid Bodies
translate rotate
Point Equilibrium 6
Lecture 4
Foundations Structures
ARCH 331
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the force stays on the same line ofaction
truck cant tell the difference
only valid for EXTERNAL forces
Transmissibility
=
Point Equilibrium 7Lecture 4
Foundations StructuresARCH 331
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Force System Types
collinear
Point Equilibrium 8Lecture 4 Foundations StructuresARCH 331 F2008abn
Force System Types
coplanar
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Point Equilibrium 9Lecture 4
Foundations StructuresARCH 331
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Force System Types
space
Point Equilibrium 10Lecture 4
Foundations StructuresARCH 331
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Adding Vectors
graphically
parallelogram law
diagonal long for 3 or more vectors
tip-to-tail
more convenient
with lots of vectors
F
P
R
F
P
R
Point Equilibrium 11Lecture 4
Foundations StructuresARCH 331
F2008abn
Force Components
convenient to resolve into 2 vectors
at right angles
in a
nice
coordinate system
is between Fxand F from FxFy
Fx
F
x
y
Fy
Fx
F
Fy
Fx
F
cosFFx
sinFFy
22
yx FFF
x
y
F
Ftan
Point Equilibrium 12Lecture 4 Foundations StructuresARCH 331 F2008abn
Trigonometry
Fx is negative
90 to 270
Fy is negative 180 to 360
tan is positive
quads I & III
tan is negative
quads II & IV -6-5
-4
-3
-2
-1
0
1
2
3
45
6
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
X
Y
Quadrant IQuadrant II
Quadrant III Quadrant IV
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Point Equilibrium 13Lecture 4
Foundations StructuresARCH 331
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Component Addition
find all x components
find all y components
find sum of x components, Rx(resultant)
find sum of y components, Ry
22
yx RRR
x
y
R
Rtan
Fy
Fx
R
Py
Px
Rx
Ry
Point Equilibrium 14Lecture 4 Foundations StructuresARCH 331 F2008abn
Alternative Trig for Components
doesnt relate angle to axis direction
is small angle between F and
EITHER Fxor Fy
no sign out of calculator!
have to choose RIGHT
trig function, resulting
direction (sign) and
component axis
+/-? Fy
+/-? Fx
F
x
y
Point Equilibrium 23Lecture 4 Foundations StructuresARCH 331 F2008abn
Friction
resistance to movement
contact surfaces determine
proportion of normal force () opposite to slide direction
static > kinetic
NF
Point Equilibrium 24Lecture 4 Foundations StructuresARCH 331 F2008abn
Cables
simple
uses
suspension bridges roof structures
transmission lines
guy wires, etc.
have same tension all along
cant stand compression
http:// nisee.berkeley.edu/godden
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Point Equilibrium 25
Lecture 4
Foundations Structures
ARCH 331
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Cables Structures
use high-strength steel
need
towers
anchors
dont want movement
http:// nisee.berkeley.edu/godden
Point Equilibrium 26Lecture 4 Foundations StructuresARCH 331 F2008abn
Cable Structures
Point Equilibrium 27Lecture 4
Foundations StructuresARCH 331
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Cable Loads
straight line
between forces
with one force concurrent
symmetric
Point Equilibrium 28Lecture 4
Foundations StructuresARCH 331
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Cable Loads
shape directly
related to the
distributed load
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Point Equilibrium 30
Lecture 4
Foundations Structures
ARCH 331
F2008abn
Cable-Stayed Structures
diagonal cables support horizontal
spans
typically symmetrical Patcenter,
Rogers 1986
www.columbia.edu
Point Equilibrium 31Lecture 4 Foundations StructuresARCH 331 F2008abn
Patcenter, Rogers 1986
column free space
roof suspended
solid steel ties
steel frame supports masts
Point Equilibrium 32Lecture 4
Foundations StructuresARCH 331
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Patcenter, Rogers 1986
dashes cables pulling
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Moments
forces have the tendency to make abody rotate about an axis
same translation but different rotation
Forces & Moments 44
Lecture 3
Foundations Structures
ARCH 331
http://www.physics.umd.edu
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Moments
Forces & Moments 45
Lecture 3
Foundations Structures
ARCH 331 Rigid Body Equilibrium 4
Lecture 6
Foundations Structures
ARCH 331
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Moments
a force acting at a different point causes
a different moment:
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Moments
defined by magnitude and direction
units: Nm, kft
direction:
+ ccw (right hand rule)
- cw
value found from Fand distance
d also called lever or moment arm
Forces & Moments 47
Lecture 3
Foundations Structures
ARCH 331
F
A
C
B
F
d
Rigid Body Equilibrium 6
Lecture 6
Foundations Structures
ARCH 331
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Moments
with same F:
21 dFMdFM AA (bigger)
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Rigid Body Equilibrium 7
Lecture 6
Foundations Structures
ARCH 331
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Moments
additive with sign convention
can still move the force
along the line of action
=
+MA = Fd
MB = Fd
d
F
A
Bd
MA = Fd
MB = Fd
d
F
A
B
d
F2009abn
Moments
Varignons Theorem
resolve a force into components at a point
and finding perpendicular distances calculate sum of moments
equivalent to original moment
makes life easier!
geometry
when component runs through point, d=0
Forces & Moments 50
Lecture 3
Foundations Structures
ARCH 331
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Moments of a Force
moments of a force
introduced in Physics as
Torque Acting on a Particle
and used to satisfy rotational equilibrium
Forces & Moments 51Lecture 3
Foundations StructuresARCH 331 F2009abn
Physics and Moments of a Force
my Physics book:
Forces & Moments 52Lecture 3
Foundations StructuresARCH 331
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Rigid Body Equilibrium 11
Lecture 6
Foundations Structures
ARCH 331
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2 forces
same size
opposite direction distance d apart
cw or ccw
not dependant on point of application
Moment Couples
d
F
A
d1
d2
F
dFM
21
dFdFM
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Moment Couples
equivalent couples
same magnitude and direction
F & d may be different
Forces & Moments 54
Lecture 3
Foundations Structures
ARCH 331
100 mm
300 N
300 N
150 mm200 N
200 N
250 mm
120 N120 N
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Moment Couples
added just like moments caused by one
force
can replace two couples with a single
couple
Forces & Moments 55
Lecture 3
Foundations Structures
ARCH 331
+=
100 mm
300 N
300 N
150 mm200 N
200 N
250 mm
240 N240 N
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Moment Couples
moment couples in structures
Forces & Moments 56
Lecture 3
Foundations Structures
ARCH 331
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Equivalent Force Systems
two forces at a point is equivalent to theresultant at a point
resultant is equivalent to twocomponents at a point
resultant of equal & opposite forces at apoint is zero
put equal & opposite forces at a point(sum to 0)
transmission of a force along action line
Forces & Moments 57
Lecture 3
Foundations Structures
ARCH 331 Rigid Body Equilibrium 16
Lecture 6
Foundations Structures
ARCH 331
F2008abn
single force causing a moment can be
replaced by the same force at a
different point by providing the momentthat force caused
moments are shown as arched arrows
Force-Moment Systems
-F
FF
d
A
AF
A
A
Rigid Body Equilibrium 17Lecture 6
Foundations StructuresARCH 331
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Force-Moment Systems
a force-moment pair can be replaced by
a force at another point causing the
original moment
F
d
-F
F
A
AF
A
A
F M=Fd
A
A
Rigid Body Equilibrium 18Lecture 6 Foundations StructuresARCH 331 F2008abn
Parallel Force Systems
forces are in the same direction
can find resultant force
need to find location for equivalentmoments
R=A+B
C Dx
AB
ab
a
B
xBA )(
C D