Notes 15 - Signal Flow Graph Analysis
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Transcript of Notes 15 - Signal Flow Graph Analysis
8/10/2019 Notes 15 - Signal Flow Graph Analysis
http://slidepdf.com/reader/full/notes-15-signal-flow-graph-analysis 1/24
Prof. David R. Jackson
Dept. of ECE
Notes 15
ECE 5317-6351
Microwave Engineering
Fall 2011
Signal-Flow Graph
Analysis
1
8/10/2019 Notes 15 - Signal Flow Graph Analysis
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This is a convenient technique to represent and analyze circuits characterized by S -parameters.
• It allows one to “see” the “flow” of signals throughout a circuit.
•
Signals are represented by wavefunctions (i.e., ai and bi).
Signal-flow graphs are also used for a number of other engineering
applications (e.g., in control theory).
Signal-Flow Graph Analysis
Note: In the signal-flow graph, ai(0) and bi(0) are denoted as ai and bi for simplicity.
2
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Signal-Flow Graph Analysis (cont.)
3
Construction Rules for signal-flow graphs
1) Each wave function (ai and bi) is a node.
2) S -parameters are represented by branches between nodes.
3) Branches are uni-directional.
4) A node value is equal to the sum of the branches entering it.
S o u r c e
N e
t w o r k
L
o a d g b
g a 1
b La
Lb2
a
2b
1a
In this circuit there are eight nodes in the signal flow graph.
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0 Z L
Z
La
Lb
L L Lb a
L
1
1
L
a
L L Lb a
0
0
L L
L
Z Z
Z Z
Example (Single Load)
Signal flow graphSingle load
4
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g a
Th Z
g b
g a
s
0 Z
ThV
+
sb 1 1
1
g b
-
0
0 0
1
g g s Th
Th
Z V
Z
b a
Z Z
0
0
Th s
Th
Z Z
Z Z
g s g sb b a
Example (Source)
Hence
0
0
s Th
Th
Z
b V Z Z
g g s sb a b
5
where
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1a
1b
1 1
11
22S
12S
21S
11S
1b
2a
2b
1a
0 Z
2b
2a
0 Z
Example (Two-Port Device)
6
1 11 1 12 2
2 21 1 22 2
b S a S a
b S a S a
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1a
1b
22S
12S
21S
11S
2b
2a g a
g b sb
L s
11
1 1
La
Lb
Complete Signal-Flow Graph
A source is connected to a two-port device, which is terminated by a load.
7
S o u r c e
N e t w o r k
L o a d g b
g a1
b La
Lb2
a
2b
1a
When cascading devices, we simply connect the signal-flow graphs together.
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a) Mason’s non-touching loop rule:
Too difficult, easy to make errors, lose physical understanding.
b) Direct solution:
Straightforward, must solve linear system of equations, lose physicalunderstanding.
c) Decomposition:
Straightforward graphical technique, requires experience, retains physical
understanding.
Solving Signal-Flow Graphs
8
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1a
1b
22S
12S
21S
11S
2b
2a
L
1a
1b
Example: Direct Solution Technique
1
1
in
b
a
A two-port device is connected to a load.
9
N e t w o r k
L o a d
1b
La
Lb
2a
2b
1a
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1a
1b
22S
12S
21S
11S
2b
2a
L
1a
1b
Example: Direct Solution Technique (cont.)
1
1
in
b
a
2 1 21 22 2
2 2
1 11 1 12 2
L
b a S S a
a bb S a S a
1 21 12
11
1 221
Lin
L
b S S
S a S
Solve :
10
For a given a1, there are three equations and three unknowns (b1, a2, b2).
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1a
2a
3a
1a
3a
21S
32S
1
21 32S S
1
1 1
Decomposition Techniques
1) Series paths
3 21 32 1a S S a
2 21 1
3 32 2
a S a
a S a
Note that we have removed the node a2.
11
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1a
2a
1a
2a
aS
bS
a bS S
2) Parallel paths
2 1 1a ba S a S a
2 1a ba S S a
Decomposition Techniques (cont.)
Note that we have combined the two parallel paths.
12
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1a
2a
1a
2a
21S
bS
1a
1a 2a21
S 1a
2a
2a
21 bS S
21
1
1b
LS S
1a 2a21S L
3) Self-loop
1 1 1 21 ba a a S S
1 1
21
1
1 b
a aS S
Decomposition Techniques (cont.)
Note that we have removed the self loop.
13
1 1 2
2 1 21
ba a a S
a a S
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1a
2a
3a
1a
3a
21S
32S
42S
21 42S S
4a
4a
21 32S S
4) Splitting
4 2 42
3 2 32
2 1 21a S
a a S
a S
a
a
4 21 42 1
3 21 32 1
a S S a
a S S a
Decomposition Techniques (cont.)
Note that we have shifted the splitting point.
14
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Example
A source is connected to a two-port device, which is terminated by a load.
Solve for in = b1 / a1
15
Two-port device
Th Z
ThV +- L Z
in
S
1a
1b
0 Z 0
Z
Note: The Z 0 lines are assumed to be very short, so they do not affect the
calculation (other than providing a reference impedance for the S parameters).
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1a
1b
22S
12S
21S
11S
2b
2a
L s
sb
Example
16
Two-port device
The signal flow graph is constructed:
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22S
12S
21S
11S
2b
L s
sb1
a
2a1b
22S
12S
21S
11S
2b
L s
sb
1a
2a
1b
Consider the following decompositions:
Example (cont.)
17
The self-loop at the end is rearranged
To put it on the outside (this is optional).
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22 LS
12 LS
21S
11S
2b
s
sb
21 1S L
11S
2b
12 LS
s
sb
1a
1b
1a
1b
22S
12S
21S
11S
2b
L s
sb1
a
2a
1b
1
22
1
1 L
LS
Example (cont.)
18
Remove self-loop
Next, we apply the self-loop formula to remove it.
Rewrite self-loop
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1
11 21 1 12
1
in L
bS S L S
a
Example (cont.)
Hence:
19
1 1 11 1 21 1 12 Lb a S a S L S
21 12
11
221
Lin
L
S S S
S
122
1
1 L L S
We then have
21 1S L
11S
2b
12 LS
s
sb
1a
1b
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Example
20
A source is connected to a two-port device, which is terminated by a load.
Solve for b2 / b s
Two-port device
Th Z
ThV +- L
Z
in
S
1a
1b
2a
2b
sb 0 Z
0 Z
2 2 020 1 1 L L LV V b Z
Note :
(Hence, since we know b s, we could find the load voltage from b2/b s if we wish.)
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Example (cont.)
Using the same steps as before, we have:
21
1
22
1
1 L
LS
21 1S L
11S
2b
12 LS
s
sb1
a
1b
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21 1
S L
2b
12 LS
11 S S 2
L
2b
sb
12 LS
21 1S L
11S
2b
12 LS s
sb
1a
1b
1a
sb
s
s
1a
2 21 1 3 L S L L
2b sb
1a
21 1S L
2
2 21 1 3
2 21 1
2 21 1 121
s
L S
b L S L L
b
L S L L S L S
2
11
1
1 S
LS
Example (cont.)
22
Remove self-loop
Rewrite self-loop on the left end
3
2 21 1 12
1
1 L S
L L S L S
Remove final self-loop
1 1 11 1 21 1 12 s s s La b a S a S L S
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2 21 1 2
21 12 1 2
21
21 12
1 2
21
11 22 21 12
1
1
1 1
s L s
L s
S L L s
b S L L
b S S L L
S
S S L L
S
S S S S
Example (cont.)
Hence
23
2 21
22 11 21 121 1 s L S s L
b S
b S S S S
Two-port device
Th
Z
ThV +- L Z
in
S
1a
1b
2a
2b
sb 0
Z 0
Z
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