Node dan supeposisi
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Transcript of Node dan supeposisi
![Page 1: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/1.jpg)
![Page 2: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/2.jpg)
Tentukan VN
201087
0202
jI
R1=7 XL=8
R2=4
XL=5
R3=8
XC=10
E2=20 0
I1=10 20
I1=10 20I2=10 20
Z1 Z2
Z3
Z4
![Page 3: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/3.jpg)
Z1 Z2
Z3
Z4
Z1=7+j8 Z2=4+j5 Z3=-j10 Z4=8
Penyelesaian
V1(Y1+Y2+Y3) – V2(Y3) = +I2
V2(Y3+Y4) – V1(Y3) = +I1
I1=10 20I2=10 20 Z1 Z2
Z3
Z4
V1 V2
Y1= 1/Z1 Y2 = 1/Z2 Y3 = 1/Z3 Y4 = 1/Z4
V1(Y1+Y2+Y3) – V2(Y3) = +I2
– V1(Y3) + V2(Y3+Y4) = +I1
![Page 4: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/4.jpg)
8
1
10
1
54
1
87
14321 Y
jY
jY
jY
![Page 5: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/5.jpg)
Berpatokan pada satu sumber
Tentukan arah arus
Mengitung besar arus pada masing2 beban
Z1 Z2
Z3 VBVA
![Page 6: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/6.jpg)
VB
Z1 Z2
Z3VA
1. Berpatokan Pada VA, VB di short
=0Besar arus yang mengalir ?
32
3211
.
ZZ
ZZZZG
1
3I
1
1I1
2I
1
1
1
G
A
Z
VI
1
1
32
31
2xI
ZZ
ZI
1
1
32
21
3 xIZZ
ZI
![Page 7: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/7.jpg)
2. Berpatokan Pada VB, VA di short
Besar arus yang mengalir ?III3
III1
III2
2
2
G
BII
Z
VI
IIII xIZZ
ZI 2
21
1
3
IIII xIZZ
ZI 2
31
31
VA =0
3. Besar arus mengalir tiap cabang
jika I1I >I1
II, maka I1 =I1I – I1
II I2 =I2I – I2
II I3 =I3I + I3
II
![Page 8: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/8.jpg)
XL=6 R=6
XC=8V1=20 30 I2=2 0
Contoh 1
Jawab
V1=20 30 I2=2 0
Z1 Z2
Z1 = j6
Z2 = 6 – j8
I
Tentukan besar I pada Xc
Ubah rangkaian dalam bentuk impedansi
![Page 9: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/9.jpg)
Z1 Z2
V1=20 30 I2=2 0
1. Patokan pada sumber arus dan sumber tegangan dihubung singkat
866
26
jj
xjI i
T
ii
Z
VI 1
43,1832,6
9012
26
12
j
j
21
11.
ZZ
IZI i
43,1832,6
3020
= 1,9 108,43
2. Patokan pada sumber tegangan dan sumber arus dihubung singkat
Z1 Z2
V1=20 30 I2=2 0
= 3,16 48,43
Ii
Iii
![Page 10: Node dan supeposisi](https://reader038.fdocuments.us/reader038/viewer/2022100518/559913671a28ab93798b45e5/html5/thumbnails/10.jpg)
Total arus yang melewati resistor 6Ω
I = Ii + Iii
= 1,9 108,43 + 3,16 48,43
= (-0,6+j1,8) + (2,10 + j2,32)
= 1,5 + j 4,16
= 4,42 70,2