Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

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Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265

Transcript of Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

Page 1: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

Newton’s Law of Gravitation

Chapter 7, Section 3

Pg. 263-265

Page 2: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

Newton’s Universal Law of GravitationNewton’s Universal Law of Gravitation

EarthMOON

Fg

To keep two moving bodies from shooting off in a straight line, a mutual gravitational force attraction occurs between them.

FEmFmE

Page 3: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

The amount of gravitational force that occurs between two masses depends on the distance between the two masses.

Newton’s universal law of gravitation

Fg = (G m1m2 )/r²

G = constant of universal gravitation

G = 6.673 x 10-11 Nm²/kg²

Page 4: Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.

Sample Problem 2Find the distance between a 0.300 kg billiard ball and a 0.400 kg billiard ball if the magnitude of the gravitational force is 8.92 x 10-11 N.

r = ?m1 = 0.300 kg m2 = 0.400 kg

Fg = (G m1m2) /r²Fg = 8.92 x 10-11 N

r² = (G m1m2) / Fg

r = √(G m1m2) / Fg

r = √[6.673 x 10-11 Nm²/kg² (0.4 kg) (0.3kg)]/8.92x10-11 N

r = 3.00 x 10-1 m

G = 6.673 x 10-11 Nm²/kg²