Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.
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Transcript of Newton’s Law of Gravitation Chapter 7, Section 3 Pg. 263-265.
Newton’s Law of Gravitation
Chapter 7, Section 3
Pg. 263-265
Newton’s Universal Law of GravitationNewton’s Universal Law of Gravitation
EarthMOON
Fg
To keep two moving bodies from shooting off in a straight line, a mutual gravitational force attraction occurs between them.
FEmFmE
The amount of gravitational force that occurs between two masses depends on the distance between the two masses.
Newton’s universal law of gravitation
Fg = (G m1m2 )/r²
G = constant of universal gravitation
G = 6.673 x 10-11 Nm²/kg²
Sample Problem 2Find the distance between a 0.300 kg billiard ball and a 0.400 kg billiard ball if the magnitude of the gravitational force is 8.92 x 10-11 N.
r = ?m1 = 0.300 kg m2 = 0.400 kg
Fg = (G m1m2) /r²Fg = 8.92 x 10-11 N
r² = (G m1m2) / Fg
r = √(G m1m2) / Fg
r = √[6.673 x 10-11 Nm²/kg² (0.4 kg) (0.3kg)]/8.92x10-11 N
r = 3.00 x 10-1 m
G = 6.673 x 10-11 Nm²/kg²